Translate the following inference to logic notation: For all x, x will drink water or x is not a cashier. There is at least one x for which if x drinks water, then x is a cashier. For all x, if x drinks water, then x is a cashier. Therefore there is at least one x for which if x were a cashier, then x is drinking water.
forall x: P(x) or ~Q(x). exists x: P(x) -> Q(x). forall x: P(x) -> Q(x). Therefore exists x: Q(x) -> P(x).