Consider the following premises. forall x_10: P_10(x_10). exists x_10: P_9(x_10) or Q_9(x_10). forall x_10: P_9(x_10) -> S_1(x_10). forall x_10: Q_9(x_10) -> S_1(x_10). forall x_10: P_10(x_10) -> U(x_10). Can we infer forall x_10: ~(U(x_10) and S_1(x_10)) from them?
 From forall x_10: P_10(x_10) -> U(x_10), forall x_10: P_10(x_10) we can infer forall x_10: U(x_10). From forall x_10: P_9(x_10) -> S_1(x_10), forall x_10: Q_9(x_10) -> S_1(x_10), exists x_10: P_9(x_10) or Q_9(x_10) we can infer exists x_10: S_1(x_10). Finally, from forall x_10: U(x_10), exists x_10: S_1(x_10) we can infer exists x_10: U(x_10) and S_1(x_10), which contradicts forall x_10: ~(U(x_10) and S_1(x_10)). Therefore, the answer is no.