Translate the following inference to logic notation: For all x, if x_6 drinks water, then x_6 is rich. For all x, x_6 is rich if and only if x_6 will climb a mountain. For all x, if x_6 climbs a mountain, then x_6 is not a taxi driver. For all x, x_6 is a taxi driver. Therefore for all x, x_6 will not drink water.
forall x: P(x) -> Q(x). forall x: Q(x) <-> R(x). forall x: R(x) -> ~S(x). forall x: S(x). Therefore forall x: ~P(x).