Compute $\dbinom{10}{4}$.
I know that there is a formula for this: $\dbinom{n}{k} = \frac{n!}{k!(n-k)!}$, where $n!$ is the factorial of n, which means the product of all positive integers up to n. In this case, $n = 10$ and $k = 4$, so I can plug these values into the formula and simplify. I get: $\dbinom{10}{4} = \frac{10!}{4!(10-4)!} = \frac{10 \times 9 \times 8 \times 7 \times 6!}{4 \times 3 \times 2 \times 6!} = \frac{10 \times 9 \times 8 \times 7}{4 \times 3 \times 2} = 210$. 