Translate the following inference to logic notation: For all x, x_6 will read a book if and only if x_6 is a scientist. For all x, if x_6 reads a book, then x_6 is running. For all x, x_6 is not a scientist. There is at least one x for which if x_6 goes running, then x_6 is reading a book. Therefore there is at least one x for which x_6 will not go running.
forall x: P(x) <-> Q(x). forall x: P(x) -> R(x). forall x: ~Q(x). exists x: R(x) -> P(x). Therefore exists x: ~R(x).