What is the value of $(x + 1 - x)! \div (x-x + 1)!$ in simplest form?
I notice that the expression inside the factorial in the numerator simplifies to $1$, since $x + 1 - x = 1$. So the numerator is just $1!$, which is $1$. The expression inside the factorial in the denominator also simplifies to $1$, since $x - x + 1 = 1$. So the denominator is also $1!$, which is $1$. Therefore, the whole fraction is just $1 \div 1$, which is $1$. 