Consider the following premises. exists x_14: S(x_14) <-> Q_14(x_14). forall x_14: Q_14(x_14). forall x_14: S(x_14) -> Q(x_14). Can we infer exists x_14: Q(x_14) from them? If possible, name the inference rules being used at each step.
 From exists x_14: S(x_14) <-> Q_14(x_14) we can infer exists x_14: Q_14(x_14) -> S(x_14) via existential biconditional elimination. From exists x_14: Q_14(x_14) -> S(x_14), forall x_14: Q_14(x_14) we can infer exists x_14: S(x_14) via existential modus ponens. Finally, from forall x_14: S(x_14) -> Q(x_14), exists x_14: S(x_14) we can infer exists x_14: Q(x_14) via existential modus ponens. Therefore, the answer is yes.