The sum of seven consecutive integers is 49. What is the smallest of the seven integers?
Let me call the smallest one x, then the next one is x + 1, and so on, up to x + 6. So I have x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6) = 49. This simplifies to 7x + 21 = 49. Subtracting 21 from both sides, I get 7x = 28. Dividing both sides by 7, I get x = 4. So the smallest integer is 4. 