Translate the following inference to logic notation: There is at least one x for which x_7 will drive a car if and only if x_7 is a carpenter. For all x, if x_7 were a carpenter, then x_7 is not playing a game. For all x, x_7 will play a game and x_7 is an electrician. Therefore there is at least one x for which x_7 will not drive a car.
exists x: P(x) <-> Q(x). forall x: Q(x) -> ~R(x). forall x: R(x) and S(x). Therefore exists x: ~P(x).