Translate the following inference to logic notation: For all x, if x_5 were a doctor, then x_5 is not poor. There is at least one x for which if x_5 were a doctor, then x_5 is drinking water. For all x, if x_5 drinks water, then x_5 is a doctor. For all x, x_5 is poor. Therefore there is at least one x for which x_5 will not drink water.
forall x: P(x) -> ~Q(x). exists x: P(x) -> R(x). forall x: R(x) -> P(x). forall x: Q(x). Therefore exists x: ~R(x).