Consider the following premises. s_4 -> ~Q_10(a_9). forall x_14: P_14(x_14) -> Q_14(x_14). forall x_14: P_14(x_14). forall x_14: Q_14(x_14) -> Q_10(x_14). Can we infer s_4 from them?
 From forall x_14: P_14(x_14) -> Q_14(x_14), forall x_14: P_14(x_14) we can infer forall x_14: Q_14(x_14). From forall x_14: Q_14(x_14) -> Q_10(x_14), forall x_14: Q_14(x_14) we can infer forall x_14: Q_10(x_14). From forall x_14: Q_10(x_14) we can infer Q_10(a_9). Finally, from s_4 -> ~Q_10(a_9), Q_10(a_9) we can infer ~s_4, which contradicts s_4. Therefore, the answer is no.