Consider the following premises. forall x_14: T(x_14) <-> Q_14(x_14). forall x_14: P_10(x_14) -> Q_14(x_14). exists x_14: P_10(x_14) <-> T(x_14). Can we infer exists x_14: T(x_14) <-> Q_14(x_14) from them?
 From forall x_14: T(x_14) <-> Q_14(x_14) we can infer forall x_14: Q_14(x_14) -> T(x_14). From exists x_14: P_10(x_14) <-> T(x_14) we can infer exists x_14: T(x_14) -> P_10(x_14). From exists x_14: T(x_14) -> P_10(x_14), forall x_14: P_10(x_14) -> Q_14(x_14) we can infer exists x_14: T(x_14) -> Q_14(x_14). Finally, from exists x_14: T(x_14) -> Q_14(x_14), forall x_14: Q_14(x_14) -> T(x_14) we can infer exists x_14: T(x_14) <-> Q_14(x_14). Therefore, the answer is yes.