Simplify $(3-i)(6+2i)$.
To simplify a product of complex numbers, I can use the distributive property and combine like terms. I get $(3-i)(6+2i) = 3(6+2i) - i(6+2i)$. Expanding further, I get $3(6+2i) - i(6+2i) = 18 + 6i - 6i - 2i^2$. Since $i^2 = -1$, I can substitute that and simplify. I get $18 + 6i - 6i - 2i^2 = 18 - 2(-1) = 18 + 2 = 20$. 