Consider the following premises. forall x_10: R_10(x_10) -> S_10(x_10). S_10(a_10) <-> q_3. Can we infer R_10(a_10) -> q_3 from them?
 From forall x_10: R_10(x_10) -> S_10(x_10) we can infer R_10(a_10) -> S_10(a_10). From S_10(a_10) <-> q_3 we can infer S_10(a_10) -> q_3. Finally, from R_10(a_10) -> S_10(a_10), S_10(a_10) -> q_3 we can infer R_10(a_10) -> q_3. Therefore, the answer is yes.