You are given a tree (i.e. a connected, undirected graph that has no cycles) consisting of `n` nodes numbered from `0` to `n - 1` and exactly `n - 1` `edges`. The **root** of the tree is the node `0`, and each node of the tree has **a label** which is a lower-case character given in the string `labels` (i.e. The node with the number `i` has the label `labels[i]`).

The `edges` array is given on the form `edges[i] = [ai, bi]`, which means there is an edge between nodes `ai` and `bi` in the tree.

Return _an array of size `n`_ where `ans[i]` is the number of nodes in the subtree of the `ith` node which have the same label as node `i`.

A subtree of a tree `T` is the tree consisting of a node in `T` and all of its descendant nodes.

**Example 1:**

**Input:** n = 7, edges = \[\[0,1\],\[0,2\],\[1,4\],\[1,5\],\[2,3\],\[2,6\]\], labels =  "abaedcd "
**Output:** \[2,1,1,1,1,1,1\]
**Explanation:** Node 0 has label 'a' and its sub-tree has node 2 with label 'a' as well, thus the answer is 2. Notice that any node is part of its sub-tree.
Node 1 has a label 'b'. The sub-tree of node 1 contains nodes 1,4 and 5, as nodes 4 and 5 have different labels than node 1, the answer is just 1 (the node itself).

**Example 2:**

**Input:** n = 4, edges = \[\[0,1\],\[1,2\],\[0,3\]\], labels =  "bbbb "
**Output:** \[4,2,1,1\]
**Explanation:** The sub-tree of node 2 contains only node 2, so the answer is 1.
The sub-tree of node 3 contains only node 3, so the answer is 1.
The sub-tree of node 1 contains nodes 1 and 2, both have label 'b', thus the answer is 2.
The sub-tree of node 0 contains nodes 0, 1, 2 and 3, all with label 'b', thus the answer is 4.

**Example 3:**

**Input:** n = 5, edges = \[\[0,1\],\[0,2\],\[1,3\],\[0,4\]\], labels =  "aabab "
**Output:** \[3,2,1,1,1\]

**Constraints:**

*   `1 <= n <= 105`
*   `edges.length == n - 1`
*   `edges[i].length == 2`
*   `0 <= ai, bi < n`
*   `ai != bi`
*   `labels.length == n`
*   `labels` is consisting of only of lowercase English letters.


def min_subsequence(nums):
    nums.sort(reverse=True)
    total_sum, current_sum = sum(nums), 0
    result = []
    for num in nums:
        current_sum += num
        result.append(num)
        if current_sum > total_sum - current_sum:
            break
    return result
