Consider the following premises. forall z_4: S(z_4). forall z_4: S(z_4) -> P_2(z_4). forall z_4: P_2(z_4) -> R_5(z_4). Can we infer ~R_5(a) from them?
 From forall z_4: S(z_4) -> P_2(z_4), forall z_4: P_2(z_4) -> R_5(z_4) we can infer forall z_4: S(z_4) -> R_5(z_4). Finally, from forall z_4: S(z_4) -> R_5(z_4), forall z_4: S(z_4) we can infer forall z_4: R_5(z_4), which contradicts ~R_5(a). Therefore, the answer is no.