Translate the following inference to logic notation: There is at least one x for which x_6 is curious and x_6 will go running. For all x, if x_6 were curious, then x_6 is an electrician. Therefore there is at least one x for which x_6 is an electrician.
exists x: P(x) and Q(x). forall x: P(x) -> R(x). Therefore exists x: R(x).