Consider the following premises. forall x_11: S_3(x_11) -> T(x_11). exists x_11: S_3(x_11) or Q_11(x_11). forall x_11: Q_3(x_11) -> ~T(x_11). forall x_11: T(x_11) or ~Q_11(x_11). Can we infer exists x_11: ~Q_3(x_11) from them?
 From forall x_11: T(x_11) or ~Q_11(x_11) we can infer forall x_11: Q_11(x_11) -> T(x_11). From forall x_11: S_3(x_11) -> T(x_11), forall x_11: Q_11(x_11) -> T(x_11), exists x_11: S_3(x_11) or Q_11(x_11) we can infer exists x_11: T(x_11). Finally, from forall x_11: Q_3(x_11) -> ~T(x_11), exists x_11: T(x_11) we can infer exists x_11: ~Q_3(x_11). Therefore, the answer is yes.