Translate the following inference to logic notation: For all x, if x were an office clerk, then x is not happy. For all x, x is an artist if and only if x is an electrician. There is at least one x for which x is happy. For all x, x is an office clerk if and only if x is an electrician. For all x, if x were an artist, then x is an electrician. Therefore there is at least one x for which x is not an artist.
forall x: P(x) -> ~Q(x). forall x: R(x) <-> S(x). exists x: Q(x). forall x: P(x) <-> S(x). forall x: R(x) -> S(x). Therefore exists x: ~R(x).