Consider the following premises. forall x_12: T(x_12) <-> S_12(x_12). w <-> S_12(a_12). w -> ~q. q. Can we infer T(a_12) from them?
 From forall x_12: T(x_12) <-> S_12(x_12) we can infer T(a_12) <-> S_12(a_12). From w -> ~q, q we can infer ~w. From w <-> S_12(a_12), ~w we can infer ~S_12(a_12). Finally, from T(a_12) <-> S_12(a_12), ~S_12(a_12) we can infer ~T(a_12), which contradicts T(a_12). Therefore, the answer is no.