Translate the following inference to logic notation: For all x, if x_12 plays squash, then x_12 is an artist. There is at least one x for which x_12 will play squash or x_12 will not read a book. For all x, if x_12 were an artist, then x_12 is playing squash. For all x, if x_12 were an artist, then x_12 is reading a book. Therefore there is at least one x for which x_12 will read a book if and only if x_12 will play squash.
forall x: P(x) -> Q(x). exists x: P(x) or ~R(x). forall x: Q(x) -> P(x). forall x: Q(x) -> R(x). Therefore exists x: R(x) <-> P(x).