Translate the following inference to logic notation: There is at least one x for which x_9 will not take a plane. For all x, if x_9 drinks water, then x_9 is taking a plane. For all x, x_9 will drink water if and only if x_9 is poor. For all x, if x_9 takes a plane, then x_9 is drinking water. Therefore there is at least one x for which x_9 is not poor.
exists x: ~P(x). forall x: Q(x) -> P(x). forall x: Q(x) <-> R(x). forall x: P(x) -> Q(x). Therefore exists x: ~R(x).