Consider the following premises. forall z: ~W_2(z). S_12(a_12) -> W_2(e). forall x_12: R_12(x_12) <-> S_12(x_12). Can we infer ~R_12(a_12) from them?
 From forall x_12: R_12(x_12) <-> S_12(x_12) we can infer R_12(a_12) <-> S_12(a_12). From forall z: ~W_2(z) we can infer ~W_2(e). From S_12(a_12) -> W_2(e), ~W_2(e) we can infer ~S_12(a_12). Finally, from R_12(a_12) <-> S_12(a_12), ~S_12(a_12) we can infer ~R_12(a_12). Therefore, the answer is yes.