Translate the following inference to logic notation: For all x, if x_9 were excited, then x_9 is not rich. For all x, x_9 is rich. For all x, x_9 is a bartender. For all x, x_9 is excited or x_9 will make tea. Therefore for all x, x_9 will make tea.
forall x: P(x) -> ~Q(x). forall x: Q(x). forall x: R(x). forall x: P(x) or S(x). Therefore forall x: S(x).