Consider the following premises. forall y: U(y) -> Q(y). forall y: S(y) <-> P(y). forall y: P(y) -> U(y). Can we infer forall y: S(y) -> Q(y) from them?
 From forall y: S(y) <-> P(y) we can infer forall y: S(y) -> P(y). From forall y: S(y) -> P(y), forall y: P(y) -> U(y) we can infer forall y: S(y) -> U(y). Finally, from forall y: S(y) -> U(y), forall y: U(y) -> Q(y) we can infer forall y: S(y) -> Q(y). Therefore, the answer is yes.