Given that $\triangle+q=59$ and $(\triangle+q)+q=106$, what is the value of $\triangle$?
So I can rewrite the second equation as $59+q=106$. Solving for $q$, I get $q=106-59=47$. Now I can plug this value of $q$ into the first equation and solve for $\triangle$. I get $\triangle+47=59$, so $\triangle=59-47=12$. 