Translate the following inference to logic notation: For all x, x_11 is not a carpenter or y will make tea. For all x, x_11 is a carpenter or x_11 is excited. For all x, x_11 is a doctor if and only if x_11 is excited. For all x, x_11 is not a doctor. Therefore there is at least one x for which y will make tea.
forall x: ~P(x) or Q(x). forall x: P(x) or R(x). forall x: S(x) <-> R(x). forall x: ~S(x). Therefore exists x: Q(x).