Consider the following premises. forall x_8: R_2(x_8) <-> P_8(x_8). exists x_8: P_8(x_8) <-> Q_8(x_8). Can we infer exists x_8: R_2(x_8) -> Q_8(x_8) from them?
 From exists x_8: P_8(x_8) <-> Q_8(x_8) we can infer exists x_8: P_8(x_8) -> Q_8(x_8). From forall x_8: R_2(x_8) <-> P_8(x_8) we can infer forall x_8: R_2(x_8) -> P_8(x_8). Finally, from forall x_8: R_2(x_8) -> P_8(x_8), exists x_8: P_8(x_8) -> Q_8(x_8) we can infer exists x_8: R_2(x_8) -> Q_8(x_8). Therefore, the answer is yes.