Translate the following inference to logic notation: For all x, x_6 is a scientist or x_6 will not climb a mountain. For all x, if x_6 were a scientist, then x_6 is a mechanic. For all x, if x_6 were a mechanic, then x_6 is climbing a mountain. Therefore for all x, if x_6 climbs a mountain, then x_6 is a scientist.
forall x: P(x) or ~Q(x). forall x: P(x) -> R(x). forall x: R(x) -> Q(x). Therefore forall x: Q(x) -> P(x).