Consider the following premises. forall x_14: P_14(x_14) <-> Q_14(x_14). exists x_14: Q_14(x_14) -> R_4(x_14). forall x_14: T(x_14) -> P_14(x_14). forall x_14: Q_1(x_14) -> R_4(x_14). forall x_14: T(x_14). Can we infer exists x_14: R_4(x_14) from them?
 From forall x_14: P_14(x_14) <-> Q_14(x_14) we can infer forall x_14: P_14(x_14) -> Q_14(x_14). From forall x_14: T(x_14) -> P_14(x_14), forall x_14: P_14(x_14) -> Q_14(x_14) we can infer forall x_14: T(x_14) -> Q_14(x_14). From forall x_14: T(x_14) -> Q_14(x_14), exists x_14: Q_14(x_14) -> R_4(x_14) we can infer exists x_14: T(x_14) -> R_4(x_14). From forall x_14: T(x_14) we can infer forall x_14: T(x_14) or Q_1(x_14). Finally, from exists x_14: T(x_14) -> R_4(x_14), forall x_14: Q_1(x_14) -> R_4(x_14), forall x_14: T(x_14) or Q_1(x_14) we can infer exists x_14: R_4(x_14). Therefore, the answer is yes.