Translate the following inference to logic notation: Elisabeth is not a sailor. For all x, if x_4 were happy, then x_4 is making tea. For all x, if x_4 makes tea, then x_4 is a sailor. For all x, if x_4 were a sailor, then x_4 is happy. Therefore Elisabeth is not happy.
~P(a). forall x: Q(x) -> R(x). forall x: R(x) -> P(x). forall x: P(x) -> Q(x). Therefore ~Q(a).