Translate the following inference to logic notation: For all x, if x_1 were excited, then x_1 is driving a car. There is at least one x for which if x_1 reads a book, then x_1 is climbing a mountain. For all x, if x_1 drives a car, then x_1 is reading a book. For all x, if x_1 climbs a mountain, then x_1 is excited. Therefore there is at least one x for which if x_1 drives a car, then x_1 is climbing a mountain.
forall x: P(x) -> Q(x). exists x: R(x) -> S(x). forall x: Q(x) -> R(x). forall x: S(x) -> P(x). Therefore exists x: Q(x) -> S(x).