Consider the following premises. forall z_4: W_4(z_4) -> Q(z_4). forall z_4: W_4(z_4) <-> T_1(z_4). exists z_4: T(z_4) -> T_1(z_4). Can we infer exists z_4: T(z_4) -> Q(z_4) from them?
 From forall z_4: W_4(z_4) <-> T_1(z_4) we can infer forall z_4: T_1(z_4) -> W_4(z_4). From forall z_4: T_1(z_4) -> W_4(z_4), forall z_4: W_4(z_4) -> Q(z_4) we can infer forall z_4: T_1(z_4) -> Q(z_4). Finally, from exists z_4: T(z_4) -> T_1(z_4), forall z_4: T_1(z_4) -> Q(z_4) we can infer exists z_4: T(z_4) -> Q(z_4). Therefore, the answer is yes.