Translate the following inference to logic notation: For all x, x_9 is not excited. For all x, x_9 is an office clerk. There is at least one x for which if x_9 were an office clerk, then x_9 is excited. Therefore there is at least one x for which x_9 is a writer.
forall x: ~P(x). forall x: Q(x). exists x: Q(x) -> P(x). Therefore exists x: R(x).