Translate the following inference to logic notation: There is at least one x for which z is a writer or z is not a cashier. For all x, z is a cashier or z is not a writer. Therefore there is at least one x for which if z were a writer, then z is a cashier.
exists x: P(x) or ~Q(x). forall x: Q(x) or ~P(x). Therefore exists x: P(x) -> Q(x).