Consider the following premises. forall x_11: U_3(x_11) <-> U(x_11). forall x_11: U(x_11) -> Q_11(x_11). exists x_11: ~Q_11(x_11). forall x_11: U(x_11) or ~Q_11(x_11). Can we infer forall x_11: U(x_11) -> Q_11(x_11) from them?
That is one of the premises. Therefore, the answer is yes.