Consider the following premises. forall x_19: P_19(x_19) <-> Q_19(x_19). forall x_19: Q_19(x_19) or U_1(x_19). exists x_19: ~P_19(x_19). forall x_19: P_3(x_19) and Q_3(x_19). Can we infer exists x_19: U_1(x_19) and P_3(x_19) from them?
 From forall x_19: P_19(x_19) <-> Q_19(x_19), exists x_19: ~P_19(x_19) we can infer exists x_19: ~Q_19(x_19). From forall x_19: Q_19(x_19) or U_1(x_19), exists x_19: ~Q_19(x_19) we can infer exists x_19: U_1(x_19). From forall x_19: P_3(x_19) and Q_3(x_19) we can infer forall x_19: P_3(x_19). Finally, from exists x_19: U_1(x_19), forall x_19: P_3(x_19) we can infer exists x_19: U_1(x_19) and P_3(x_19). Therefore, the answer is yes.