Consider the following premises. r. S_12(a_12) -> R_12(a_12). S_12(a_12) -> ~r. forall x_12: R_12(x_12) -> S_12(x_12). Can we infer R_12(a_12) from them?
 From forall x_12: R_12(x_12) -> S_12(x_12) we can infer R_12(a_12) -> S_12(a_12). From S_12(a_12) -> ~r, r we can infer ~S_12(a_12). From S_12(a_12) -> R_12(a_12), R_12(a_12) -> S_12(a_12) we can infer S_12(a_12) <-> R_12(a_12). Finally, from S_12(a_12) <-> R_12(a_12), ~S_12(a_12) we can infer ~R_12(a_12), which contradicts R_12(a_12). Therefore, the answer is no.