Consider the following premises. forall y_3: Q(y_3) -> R(y_3). forall y_3: ~R(y_3). exists y_3: R(y_3) -> Q(y_3). Can we infer exists y_3: ~Q(y_3) from them?
 From forall y_3: Q(y_3) -> R(y_3), exists y_3: R(y_3) -> Q(y_3) we can infer exists y_3: Q(y_3) <-> R(y_3). Finally, from exists y_3: Q(y_3) <-> R(y_3), forall y_3: ~R(y_3) we can infer exists y_3: ~Q(y_3). Therefore, the answer is yes.