Translate the following inference to logic notation: For all x, if x_5 were an office clerk, then x_5 is reading a book. For all x, x_5 is bored. There is at least one x for which x_5 is an office clerk. Therefore there is at least one x for which x_5 is bored.
forall x: P(x) -> Q(x). forall x: R(x). exists x: P(x). Therefore exists x: R(x).