If $t(x) = 3-g(x)$ and $g(x) = \sqrt{x}$, then what is $t(g(16))$?
To find $t(g(16))$, I need to first evaluate $g(16)$ and then plug that result into the function $t$. I know that $g(x) = \sqrt{x}$, so $g(16) = \sqrt{16} = 4$. This means that $t(g(16)) = t(4)$. Now I need to apply the function $t$ to the input 4. I know that $t(x) = 3-g(x)$, so $t(4) = 3-g(4)$. To simplify this expression, I need to evaluate $g(4)$. I know that $g(x) = \sqrt{x}$, so $g(4) = \sqrt{4} = 2$. This means that $t(4) = 3-2 = 1$. 