If Quinton is standing on a cliff with a sheer vertical face and drops a stone straight down without imparting any sideways velocity to it, where will the stone land relative to the base of the cliff, assuming no other forces like wind?

Respond very briefly.
The stone will land directly at the base of the cliff, below where Quinton dropped it. Because Quinton released the stone without giving it any sideways velocity, and because the cliff face is vertical, gravity will act on the stone by pulling it straight down. Since gravity is the only force acting on the stone in the vertical direction and there are no horizontal forces (since wind and other factors are ruled out), the stone will fall on a path directly beneath the point of release.