Samson derives utility according the relation  $$\text{Utility} = \text{hours of math done} \times \text{hours of frisbee played}.$$On Monday he plays $t$ hours of frisbee and spends $8 - t$ hours doing math.  On Tuesday, he ends up getting the same amount of utility as Monday while spending $2-t$ hours playing frisbee and $t+3$ hours on math.  Find $t$.  Answer as a fraction in lowest terms.
On Monday, the utility is $(8-t) \times t$, and on Tuesday, it is $(2-t) \times (t+3)$. Since the utility is the same on both days, I can set these two expressions equal to each other and solve for $t$. I get $(8-t) \times t = (2-t) \times (t+3)$. Expanding and simplifying, I get $8t - t^2 = 2t + 6 - t^2 - 3t$. Combining like terms, I get $9t = 6$, or $t = \frac{2}{3}$. 