In a box of chocolates, there are 6 dark chocolates and 8 milk chocolates. If you randomly pick two chocolates at once without looking, what is the probability that both chocolates are dark?
The probability is 15/91.

Here's the reasoning:

1. There are a total of 14 chocolates in the box (6 dark + 8 milk).
2. When picking two chocolates at once, there are C(14,2) possible combinations, where C(n,k) represents the number of combinations of 'n' items taken 'k' at a time. C(14,2) = 14! / (2!(14-2)!) = 91 combinations.
3. To find the probability of both chocolates being dark, we need to determine the number of ways to choose 2 dark chocolates from the 6 available. This is represented as C(6,2), which equals 6! / (2!(6-2)!) = 15 combinations.
4. Therefore, the probability of both chocolates being dark is the ratio of successful outcomes (both dark) to the total possible outcomes: 15/91.