Translate the following inference to logic notation: For all x, y_2 is an electrician or y_2 will not write a letter. There is at least one x for which if y_2 were an electrician, then y_2 is climbing a mountain. For all x, if y_2 were an electrician, then y_2 is writing a letter. Therefore there is at least one x for which if y_2 writes a letter, then y_2 is climbing a mountain.
forall x: P(x) or ~Q(x). exists x: P(x) -> R(x). forall x: P(x) -> Q(x). Therefore exists x: Q(x) -> R(x).