Consider the following premises. forall y_2: W(y_2) <-> T(y_2). forall y_2: S(y_2) -> R(y_2). forall y_2: ~T(y_2). exists y_2: R(y_2) -> S(y_2). forall y_2: W(y_2) <-> R(y_2). Can we infer exists y_2: ~S(y_2) from them?
 From forall y_2: W(y_2) <-> T(y_2), forall y_2: ~T(y_2) we can infer forall y_2: ~W(y_2). From forall y_2: S(y_2) -> R(y_2), exists y_2: R(y_2) -> S(y_2) we can infer exists y_2: S(y_2) <-> R(y_2). From forall y_2: W(y_2) <-> R(y_2), forall y_2: ~W(y_2) we can infer forall y_2: ~R(y_2). Finally, from exists y_2: S(y_2) <-> R(y_2), forall y_2: ~R(y_2) we can infer exists y_2: ~S(y_2). Therefore, the answer is yes.