Consider the following premises. r <-> U_3(a_5). forall x_7: U_3(x_7) -> ~Q_7(x_7). forall x_7: Q_7(x_7). Can we infer ~r from them?
 From forall x_7: U_3(x_7) -> ~Q_7(x_7), forall x_7: Q_7(x_7) we can infer forall x_7: ~U_3(x_7). From forall x_7: ~U_3(x_7) we can infer ~U_3(a_5). Finally, from r <-> U_3(a_5), ~U_3(a_5) we can infer ~r. Therefore, the answer is yes.