Translate the following inference to logic notation: There is at least one x for which if x were an electrician, then x is an office clerk. For all x, x is an electrician if and only if x is an office clerk. For all x, x is an office clerk if and only if x is an electrician. Therefore there is at least one x for which x is an electrician if and only if x is an office clerk.
exists x: P(x) -> Q(x). forall x: P(x) <-> Q(x). forall x: Q(x) <-> P(x). Therefore exists x: P(x) <-> Q(x).