Consider the following premises. exists x_9: T_1(x_9) <-> Q_7(x_9). forall x_9: T_2(x_9) -> T_1(x_9). forall x_9: ~Q_7(x_9). forall x_9: T_1(x_9) -> T_2(x_9). Can we infer exists x_9: ~T_2(x_9) from them?
 From forall x_9: T_2(x_9) -> T_1(x_9), forall x_9: T_1(x_9) -> T_2(x_9) we can infer forall x_9: T_2(x_9) <-> T_1(x_9). From exists x_9: T_1(x_9) <-> Q_7(x_9), forall x_9: ~Q_7(x_9) we can infer exists x_9: ~T_1(x_9). Finally, from forall x_9: T_2(x_9) <-> T_1(x_9), exists x_9: ~T_1(x_9) we can infer exists x_9: ~T_2(x_9). Therefore, the answer is yes.