If $\displaystyle\frac{n+5}{n-3} = 2$ what is the value of $n$?
First, I will multiply both sides by $n-3$ to eliminate the fraction. This gives me $(n+5) = 2(n-3)$. Next, I will expand the right side by distributing the 2. This gives me $(n+5) = 2n - 6$. Now, I will subtract $n$ from both sides to get all the $n$ terms on one side. This gives me $5 = n - 6$. Finally, I will add $6$ to both sides to get the value of $n$. This gives me $11 = n$. 