Consider the following premises. forall x_8: Q_8(x_8) -> R_8(x_8). forall x_8: P_8(x_8) -> Q_8(x_8). R_8(j) -> P_8(j). Can we infer P_8(j) -> R_8(j) from them?
 From forall x_8: P_8(x_8) -> Q_8(x_8), forall x_8: Q_8(x_8) -> R_8(x_8) we can infer forall x_8: P_8(x_8) -> R_8(x_8). Finally, from forall x_8: P_8(x_8) -> R_8(x_8) we can infer P_8(j) -> R_8(j). Therefore, the answer is yes.