Translate the following inference to logic notation: For all x, if y_3 were an artist, then y_3 is poor. For all x, if y_3 were poor, then y_3 is an artist. There is at least one x for which if y_3 were poor, then y_3 is an artist. Therefore there is at least one x for which if y_3 were an artist, then y_3 is poor.
forall x: P(x) -> Q(x). forall x: Q(x) -> P(x). exists x: Q(x) -> P(x). Therefore exists x: P(x) -> Q(x).