Consider the following premises. r_1 -> T_3(a). forall x_6: T_2(x_6) -> Q_6(x_6). r_1 or T_2(a). forall x_6: Q_6(x_6) -> T_3(x_6). Can we infer T_3(a) from them?
 From forall x_6: T_2(x_6) -> Q_6(x_6), forall x_6: Q_6(x_6) -> T_3(x_6) we can infer forall x_6: T_2(x_6) -> T_3(x_6). From forall x_6: T_2(x_6) -> T_3(x_6) we can infer T_2(a) -> T_3(a). Finally, from r_1 -> T_3(a), T_2(a) -> T_3(a), r_1 or T_2(a) we can infer T_3(a). Therefore, the answer is yes.