Consider the following premises. u_2 -> t. ~t. forall x_11: R_11(x_11) <-> S_11(x_11). ~S_11(g). Can we infer ~R_11(g) and ~u_2 from them?
 From u_2 -> t, ~t we can infer ~u_2. From forall x_11: R_11(x_11) <-> S_11(x_11) we can infer R_11(g) <-> S_11(g). From R_11(g) <-> S_11(g), ~S_11(g) we can infer ~R_11(g). Finally, from ~R_11(g), ~u_2 we can infer ~R_11(g) and ~u_2. Therefore, the answer is yes.