Consider the following premises. R_16(a_16) <-> q_3. forall x_16: R_16(x_16) and S_16(x_16). Can we infer q_3 from them?
 From forall x_16: R_16(x_16) and S_16(x_16) we can infer R_16(a_16) and S_16(a_16). From R_16(a_16) and S_16(a_16) we can infer R_16(a_16). From R_16(a_16) <-> q_3 we can infer R_16(a_16) -> q_3. Finally, from R_16(a_16) -> q_3, R_16(a_16) we can infer q_3. Therefore, the answer is yes.