What is the remainder of 2004 divided by 12?
To find the remainder of a division problem, I need to use the long division algorithm. I start by writing 2004 as the dividend and 12 as the divisor, and draw a long division symbol around them. I ask myself how many times 12 goes into 20, the first two digits of the dividend. I know that 12 times 1 is 12, and 12 times 2 is 24, so 12 goes into 20 once, with a remainder of 8. I write 1 above the 0 in the quotient, and I subtract 12 from 20 to get 8. I bring down the next digit of the dividend, which is 0, and append it to the 8. Now I have 80 as the new partial dividend. I repeat the same process with 80 and 12. I know that 12 times 6 is 72, and 12 times 7 is 84, so 12 goes into 80 six times, with a remainder of 8. I write 6 above the 0 in the quotient, and I subtract 72 from 80 to get 8. I bring down the last digit of the dividend, which is 4, and append it to the 8. Now I have 84 as the final partial dividend. I do the same thing with 84 and 12. I know that 12 times 7 is 84, so 12 goes into 84 exactly seven times, with no remainder. I write 7 above the 4 in the quotient, and I subtract 84 from 84 to get 0. I have no more digits to bring down, so I am done with the long division. The quotient is 167, and the remainder is 0. 