Compute $\tan 0^\circ$.
I know that $\tan \theta = \frac{\sin \theta}{\cos \theta}$ for any angle $\theta$. So, plugging in $\theta = 0^\circ$, I get $\tan 0^\circ = \frac{\sin 0^\circ}{\cos 0^\circ}$. The unit circle is the circle with radius 1 centered at the origin. When the angle is zero degrees, the point on the unit circle is (1, 0). So, $\sin 0^\circ = 0$ and $\cos 0^\circ = 1$. Therefore, $\tan 0^\circ = \frac{0}{1} = 0$. 