Find the slope of the line that is perpendicular to the line $2x + 3y = 6$.
I know that two lines are perpendicular if their slopes are negative reciprocals of each other. That means I need to find the slope of the given line first, and then flip it over and change its sign. To find the slope of the given line, I can rearrange the equation into slope-intercept form, which is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. Now I can see that the slope of the given line is $-\frac{2}{3}$. That means I flip the fraction over and change the sign, so I get $\frac{3}{2}$. 