Consider the following premises. S_10(a_10) -> r_1. ~r_1. forall x_10: R_10(x_10) -> S_10(x_10). Can we infer R_10(a_10) from them?
 From forall x_10: R_10(x_10) -> S_10(x_10) we can infer R_10(a_10) -> S_10(a_10). From R_10(a_10) -> S_10(a_10), S_10(a_10) -> r_1 we can infer R_10(a_10) -> r_1. Finally, from R_10(a_10) -> r_1, ~r_1 we can infer ~R_10(a_10), which contradicts R_10(a_10). Therefore, the answer is no.