Consider the following premises. forall x_6: U(x_6) -> P_6(x_6). forall x_6: R_3(x_6) -> P_6(x_6). forall x_6: R_3(x_6) or U(x_6). exists x_6: P_6(x_6) -> U(x_6). Can we infer forall x_6: R_3(x_6) -> P_6(x_6) from them?
That is one of the premises. Therefore, the answer is yes.