Consider the following premises. forall x_9: Q_9(x_9) -> P_4(x_9). forall x_9: Q_3(x_9). forall x_9: Q_2(x_9) -> Q_9(x_9). exists x_9: P_4(x_9) -> ~Q_3(x_9). Can we infer forall x_9: Q_2(x_9) from them?
 From forall x_9: Q_2(x_9) -> Q_9(x_9), forall x_9: Q_9(x_9) -> P_4(x_9) we can infer forall x_9: Q_2(x_9) -> P_4(x_9). From exists x_9: P_4(x_9) -> ~Q_3(x_9), forall x_9: Q_3(x_9) we can infer exists x_9: ~P_4(x_9). Finally, from forall x_9: Q_2(x_9) -> P_4(x_9), exists x_9: ~P_4(x_9) we can infer exists x_9: ~Q_2(x_9), which contradicts forall x_9: Q_2(x_9). Therefore, the answer is no.