Consider the following premises. forall x: Q(x) -> P_3(x). exists x: ~P_3(x). forall x: W_3(x) -> Q(x). forall x: T_2(x) -> W_3(x). Can we infer forall x: T_2(x) from them?
 From forall x: T_2(x) -> W_3(x), forall x: W_3(x) -> Q(x) we can infer forall x: T_2(x) -> Q(x). From forall x: T_2(x) -> Q(x), forall x: Q(x) -> P_3(x) we can infer forall x: T_2(x) -> P_3(x). Finally, from forall x: T_2(x) -> P_3(x), exists x: ~P_3(x) we can infer exists x: ~T_2(x), which contradicts forall x: T_2(x). Therefore, the answer is no.