Translate the following inference to logic notation: For all x, z_3 will play squash or z_3 is not a politician. For all x, if z_3 were a writer, then z_3 is driving a car. There is at least one x for which if z_3 drives a car, then z_3 is a politician. Therefore there is at least one x for which if z_3 were a writer, then z_3 is playing squash.
forall x: P(x) or ~Q(x). forall x: R(x) -> S(x). exists x: S(x) -> Q(x). Therefore exists x: R(x) -> P(x).