Translate the following inference to logic notation: For all x, if x_6 were poor, then x_6 is sleeping. For all x, x_6 is an electrician if and only if x_6 will sleep. For all x, if x_6 were an electrician, then x_6 is poor. Therefore for all x, if x_6 sleeps, then x_6 is an electrician.
forall x: P(x) -> Q(x). forall x: R(x) <-> Q(x). forall x: R(x) -> P(x). Therefore forall x: Q(x) -> R(x).