Consider the following premises. exists x_8: R(x_8) -> Q_1(x_8). forall x_8: U(x_8) <-> R(x_8). forall x_8: Q_1(x_8) -> U(x_8). Can we infer exists x_8: R(x_8) <-> U(x_8) from them?
 From forall x_8: U(x_8) <-> R(x_8) we can infer forall x_8: U(x_8) -> R(x_8). From exists x_8: R(x_8) -> Q_1(x_8), forall x_8: Q_1(x_8) -> U(x_8) we can infer exists x_8: R(x_8) -> U(x_8). Finally, from exists x_8: R(x_8) -> U(x_8), forall x_8: U(x_8) -> R(x_8) we can infer exists x_8: R(x_8) <-> U(x_8). Therefore, the answer is yes.