The decimal expansion of $8/11$ is a repeating decimal. What is the least number of digits in a repeating block of 8/11?
I know that the decimal expansion of 8/11 is 0.727272..., where the 72 repeats infinitely. So the repeating block is just 72, which has two digits. Therefore, the least number of digits in a repeating block of 8/11 is 2. 