Translate the following inference to logic notation: Elisabeth is not driving a car. For all x, x_12 will work if and only if x_12 is a musician. For all x, if x_12 were a musician, then x_12 is driving a car. Therefore Elisabeth is not working.
~P(a). forall x: Q(x) <-> R(x). forall x: R(x) -> P(x). Therefore ~Q(a).