Translate the following inference to logic notation: For all x, x_1 is not an artist. There is at least one x for which x_1 is rich if and only if x_1 will play squash. For all x, if x_1 plays squash, then x_1 is an artist. Therefore there is at least one x for which x_1 is not rich.
forall x: ~P(x). exists x: Q(x) <-> R(x). forall x: R(x) -> P(x). Therefore exists x: ~Q(x).