If $a = 2$, $b = 3$ and $c = 4$, what is the numerical value of the expression $(b-c)^2 + a(b+c)$ ?
To find the value of the expression, I need to substitute the values of $a, b$ and $c$ into it and simplify using the order of operations. So I have $(3-4)^2 + 2(3+4)$. Then I multiply and add: $1 + 14$. Finally, I get the answer: $15$. 