Consider the following premises. forall x_5: P_5(x_5) or ~R(x_5). forall x_5: P_5(x_5) -> R(x_5). Can we infer R(c_1) -> P_5(c_1) from them?
 From forall x_5: P_5(x_5) or ~R(x_5) we can infer forall x_5: R(x_5) -> P_5(x_5). From forall x_5: R(x_5) -> P_5(x_5), forall x_5: P_5(x_5) -> R(x_5) we can infer forall x_5: R(x_5) <-> P_5(x_5). From forall x_5: R(x_5) <-> P_5(x_5) we can infer R(c_1) <-> P_5(c_1). Finally, from R(c_1) <-> P_5(c_1) we can infer R(c_1) -> P_5(c_1). Therefore, the answer is yes.