Translate the following inference to logic notation: There is at least one x for which if x were a scientist, then x is playing squash. For all x, x will play squash if and only if x is a scientist. Therefore there is at least one x for which if x were a scientist, then x is playing squash.
exists x: P(x) -> Q(x). forall x: Q(x) <-> P(x). Therefore exists x: P(x) -> Q(x).