Translate the following inference to logic notation: For all x, if x_7 were an artist, then x_7 is working. There is at least one x for which x_7 is an artist if and only if x_7 will work. Therefore there is at least one x for which if x_7 were an artist, then x_7 is working.
forall x: P(x) -> Q(x). exists x: P(x) <-> Q(x). Therefore exists x: P(x) -> Q(x).