Translate the following inference to logic notation: For all x, x_6 is a nurse or x_6 will listen to a song. For all x, if x_6 works, then x_6 is rich. For all x, x_6 is rich or x_6 will not listen to a song. For all x, x_6 is not a nurse or x_6 will work. Therefore for all x, x_6 is rich.
forall x: P(x) or Q(x). forall x: R(x) -> S(x). forall x: S(x) or ~Q(x). forall x: ~P(x) or R(x). Therefore forall x: S(x).