Translate the following inference to logic notation: For all x, y_2 is a bartender or y_2 is not rich. For all x, if y_2 were a bartender, then y_2 is rich. Therefore for all x, if y_2 were a bartender, then y_2 is rich.
forall x: P(x) or ~Q(x). forall x: P(x) -> Q(x). Therefore forall x: P(x) -> Q(x).