Consider the following premises. forall x_6: P_6(x_6) -> Q_6(x_6). forall x_6: ~Q_6(x_6). forall x_6: P_6(x_6) or Q_3(x_6). Can we infer exists y_2: Q_3(y_2) from them?
 From forall x_6: P_6(x_6) -> Q_6(x_6), forall x_6: ~Q_6(x_6) we can infer forall x_6: ~P_6(x_6). From forall x_6: P_6(x_6) or Q_3(x_6), forall x_6: ~P_6(x_6) we can infer forall x_6: Q_3(x_6). From forall x_6: Q_3(x_6) we can infer Q_3(h). Finally, from Q_3(h) we can infer exists y_2: Q_3(y_2). Therefore, the answer is yes.