Translate the following inference to logic notation: For all x, x is not a nurse. There is at least one x for which if x were a nurse, then x is a politician. For all x, if x were a politician, then x is driving a car. For all x, if x drives a car, then x is a nurse. Therefore there is at least one x for which x is not a politician.
forall x: ~P(x). exists x: P(x) -> Q(x). forall x: Q(x) -> R(x). forall x: R(x) -> P(x). Therefore exists x: ~Q(x).