Consider the following premises. ~S_11(a_11). q. forall x_11: R_11(x_11) <-> S_11(x_11). Can we infer R_11(a_11) from them?
 From forall x_11: R_11(x_11) <-> S_11(x_11) we can infer R_11(a_11) <-> S_11(a_11). Finally, from R_11(a_11) <-> S_11(a_11), ~S_11(a_11) we can infer ~R_11(a_11), which contradicts R_11(a_11). Therefore, the answer is no.