Consider the following premises. forall z_2: S(z_2) <-> T_3(z_2). forall z_2: S(z_2) or ~T(z_2). Can we infer forall z_2: T(z_2) -> T_3(z_2) from them?
 From forall z_2: S(z_2) <-> T_3(z_2) we can infer forall z_2: S(z_2) -> T_3(z_2). From forall z_2: S(z_2) or ~T(z_2) we can infer forall z_2: T(z_2) -> S(z_2). Finally, from forall z_2: T(z_2) -> S(z_2), forall z_2: S(z_2) -> T_3(z_2) we can infer forall z_2: T(z_2) -> T_3(z_2). Therefore, the answer is yes.