Translate the following inference to logic notation: For all x, x_5 is a nurse. There is at least one x for which if x_5 reads a book, then x_5 is not a nurse. For all x, x_5 will sleep or x_5 will read a book. For all x, x_5 will not sleep or x_5 will play squash. Therefore there is at least one x for which x_5 will play squash.
forall x: P(x). exists x: Q(x) -> ~P(x). forall x: R(x) or Q(x). forall x: ~R(x) or S(x). Therefore exists x: S(x).