Translate the following inference to logic notation: For all x, x will play squash or x is not a carpenter. For all x, x will play squash if and only if x is a carpenter. Therefore for all x, if x were a carpenter, then x is playing squash.
forall x: P(x) or ~Q(x). forall x: P(x) <-> Q(x). Therefore forall x: Q(x) -> P(x).