Translate the following inference to logic notation: For all x, if x_6 reads a book, then x_6 is running. There is at least one x for which if x_6 were a lawyer, then x_6 is running. For all x, x_6 will take a plane or x_6 is a lawyer. For all x, if x_6 drinks water, then x_6 is reading a book. For all x, x_6 will not take a plane or x_6 will drink water. Therefore there is at least one x for which x_6 will go running.
forall x: P(x) -> Q(x). exists x: R(x) -> Q(x). forall x: S(x) or R(x). forall x: T(x) -> P(x). forall x: ~S(x) or T(x). Therefore exists x: Q(x).