Consider the following premises. forall x_7: U(x_7) -> ~Q(x_7). s -> U(b). forall x_7: Q(x_7). Can we infer s from them?
 From forall x_7: U(x_7) -> ~Q(x_7), forall x_7: Q(x_7) we can infer forall x_7: ~U(x_7). From forall x_7: ~U(x_7) we can infer ~U(b). Finally, from s -> U(b), ~U(b) we can infer ~s, which contradicts s. Therefore, the answer is no.