Consider the following premises. forall x_9: Q(x_9) -> ~Q_1(x_9). forall x_9: Q_9(x_9) -> Q_1(x_9). forall x_9: Q_1(x_9) -> Q_9(x_9). forall x_9: Q_9(x_9). Can we infer forall x_9: ~Q(x_9) from them?
 From forall x_9: Q_1(x_9) -> Q_9(x_9), forall x_9: Q_9(x_9) -> Q_1(x_9) we can infer forall x_9: Q_1(x_9) <-> Q_9(x_9). From forall x_9: Q_1(x_9) <-> Q_9(x_9) we can infer forall x_9: Q_9(x_9) -> Q_1(x_9). From forall x_9: Q_9(x_9) -> Q_1(x_9), forall x_9: Q_9(x_9) we can infer forall x_9: Q_1(x_9). Finally, from forall x_9: Q(x_9) -> ~Q_1(x_9), forall x_9: Q_1(x_9) we can infer forall x_9: ~Q(x_9). Therefore, the answer is yes.