Translate the following inference to logic notation: For all x, x is a cashier or x is not a mechanic. For all x, if x reads a book, then x is a mechanic. For all x, if x were a cashier, then x is reading a book. Therefore for all x, if x were a mechanic, then x is a cashier.
forall x: P(x) or ~Q(x). forall x: R(x) -> Q(x). forall x: P(x) -> R(x). Therefore forall x: Q(x) -> P(x).