Translate the following inference to logic notation: For all x, if x_6 were a politician, then x_6 is climbing a mountain. There is at least one x for which if x_6 climbs a mountain, then x_6 is an office clerk. For all x, if x_6 were an office clerk, then x_6 is climbing a mountain. For all x, x_6 is an office clerk or x_6 is a politician. Therefore there is at least one x for which x_6 will climb a mountain.
forall x: P(x) -> Q(x). exists x: Q(x) -> R(x). forall x: R(x) -> Q(x). forall x: R(x) or P(x). Therefore exists x: Q(x).