Consider the following premises. forall x_11: U_2(x_11) <-> S_11(x_11). q. ~S_11(a_11). Can we infer q and ~U_2(a_11) from them?
 From forall x_11: U_2(x_11) <-> S_11(x_11) we can infer U_2(a_11) <-> S_11(a_11). From U_2(a_11) <-> S_11(a_11), ~S_11(a_11) we can infer ~U_2(a_11). Finally, from q, ~U_2(a_11) we can infer q and ~U_2(a_11). Therefore, the answer is yes.