Translate the following inference to logic notation: For all x, x_6 is a police officer or x_6 will not listen to a song. For all x, x_6 is rich if and only if x_6 is a police officer. Therefore for all x, if x_6 listens to a song, then x_6 is rich.
forall x: P(x) or ~Q(x). forall x: R(x) <-> P(x). Therefore forall x: Q(x) -> R(x).