Lead has $T_{\mathrm{c}}=7.19 \mathrm{~K}$ and $\mathcal{H}_{\mathrm{c}}(0)=63.9 \mathrm{kA} \mathrm{m}^{-1}$. At what temperature does lead become superconducting in a magnetic field of $20 \mathrm{kA} \mathrm{m}^{-1}$ ?
Rearrangement of eqn 39.7 gives
$$
T=T_{\mathrm{c}}\left(1-\frac{\mathcal{H}_{\mathrm{c}}(T)}{\mathcal{H}_{\mathrm{c}}(0)}\right)^{1 / 2}
$$
and substitution of the data gives
$$
T=(7.19 \mathrm{~K}) \times\left(1-\frac{20 \mathrm{kAm}^{-1}}{63.9 \mathrm{kAm}^{-1}}\right)^{1 / 2}=6.0 \mathrm{~K}
$$
That is, lead becomes superconducting at temperatures below $6.0 \mathrm{~K}$.
