Translate the following inference to logic notation: For all x, y_3 will work if and only if y_3 will drive a car. There is at least one x for which y_3 will not drive a car. For all x, y_3 will listen to a song if and only if y_3 will work. Therefore there is at least one x for which y_3 will not listen to a song.
forall x: P(x) <-> Q(x). exists x: ~Q(x). forall x: R(x) <-> P(x). Therefore exists x: ~R(x).