Translate the following inference to logic notation: For all x, if x_5 were poor, then x_5 is an astronaut. There is at least one x for which if x_5 drinks water, then x_5 is poor. For all x, if x_5 were an astronaut, then x_5 is a bartender. For all x, x_5 is not a bartender. Therefore there is at least one x for which x_5 will not drink water.
forall x: P(x) -> Q(x). exists x: R(x) -> P(x). forall x: Q(x) -> S(x). forall x: ~S(x). Therefore exists x: ~R(x).