Find $k$, if ${(3^k)}^6=3^6$.
To simplify the left-hand side, I can use the exponent rule that says ${(a^b)}^c=a^{bc}$. So I can rewrite the equation as $3^{6k}=3^6$. Now I have two powers of the same base that are equal, so the exponents must be equal too. That means I can set $6k=6$ and solve for $k$. Dividing both sides by 6, I get $k=1$. 