Translate the following inference to logic notation: For all x, if x_5 were an artist, then x_5 is not running. There is at least one x for which if x_5 were a cashier, then x_5 is an artist. For all x, if x_5 were an artist, then x_5 is a cashier. For all x, x_5 will go running. Therefore there is at least one x for which x_5 is not a cashier.
forall x: P(x) -> ~Q(x). exists x: R(x) -> P(x). forall x: P(x) -> R(x). forall x: Q(x). Therefore exists x: ~R(x).