Consider the following premises. forall x_2: W(x_2). forall x_2: W(x_2) -> Q_2(x_2). exists x_2: Q_2(x_2) -> R_2(x_2). Can we infer exists x_2: R_2(x_2) from them?
 From forall x_2: W(x_2) -> Q_2(x_2), exists x_2: Q_2(x_2) -> R_2(x_2) we can infer exists x_2: W(x_2) -> R_2(x_2). Finally, from exists x_2: W(x_2) -> R_2(x_2), forall x_2: W(x_2) we can infer exists x_2: R_2(x_2). Therefore, the answer is yes.