Consider the following premises. t_2 <-> S_10(a_10). forall x_10: R_10(x_10) -> S_10(x_10). R_10(a_10) or t_2. Can we infer ~S_10(a_10) from them?
 From forall x_10: R_10(x_10) -> S_10(x_10) we can infer R_10(a_10) -> S_10(a_10). From t_2 <-> S_10(a_10) we can infer t_2 -> S_10(a_10). Finally, from R_10(a_10) -> S_10(a_10), t_2 -> S_10(a_10), R_10(a_10) or t_2 we can infer S_10(a_10), which contradicts ~S_10(a_10). Therefore, the answer is no.