Consider the following premises. S_17(a_17) -> r. forall x_17: R_17(x_17) -> S_17(x_17). r <-> R_17(a_17). ~R_17(a_17). Can we infer ~r from them?
 From forall x_17: R_17(x_17) -> S_17(x_17) we can infer R_17(a_17) -> S_17(a_17). From r <-> R_17(a_17) we can infer r -> R_17(a_17). From R_17(a_17) -> S_17(a_17), S_17(a_17) -> r we can infer R_17(a_17) -> r. From r -> R_17(a_17), R_17(a_17) -> r we can infer r <-> R_17(a_17). Finally, from r <-> R_17(a_17), ~R_17(a_17) we can infer ~r. Therefore, the answer is yes.