Translate the following inference to logic notation: For all x, if x_10 were a mechanic, then x_10 is fast. There is at least one x for which x_10 is a mechanic or x_10 is not fast. For all x, if x_10 were a mechanic, then x_10 is a musician. Therefore there is at least one x for which if x_10 were fast, then x_10 is a musician.
forall x: P(x) -> Q(x). exists x: P(x) or ~Q(x). forall x: P(x) -> R(x). Therefore exists x: Q(x) -> R(x).