Given a `wordlist`, we want to implement a spellchecker that converts a query word into a correct word.

For a given `query` word, the spell checker handles two categories of spelling mistakes:

*   Capitalization: If the query matches a word in the wordlist (**case-insensitive**), then the query word is returned with the same case as the case in the wordlist.
    *   Example: `wordlist = [ "yellow "]`, `query = "YellOw "`: `correct = "yellow "`
    *   Example: `wordlist = [ "Yellow "]`, `query = "yellow "`: `correct = "Yellow "`
    *   Example: `wordlist = [ "yellow "]`, `query = "yellow "`: `correct = "yellow "`
*   Vowel Errors: If after replacing the vowels `('a', 'e', 'i', 'o', 'u')` of the query word with any vowel individually, it matches a word in the wordlist (**case-insensitive**), then the query word is returned with the same case as the match in the wordlist.
    *   Example: `wordlist = [ "YellOw "]`, `query = "yollow "`: `correct = "YellOw "`
    *   Example: `wordlist = [ "YellOw "]`, `query = "yeellow "`: `correct = " "` (no match)
    *   Example: `wordlist = [ "YellOw "]`, `query = "yllw "`: `correct = " "` (no match)

In addition, the spell checker operates under the following precedence rules:

*   When the query exactly matches a word in the wordlist (**case-sensitive**), you should return the same word back.
*   When the query matches a word up to capitlization, you should return the first such match in the wordlist.
*   When the query matches a word up to vowel errors, you should return the first such match in the wordlist.
*   If the query has no matches in the wordlist, you should return the empty string.

Given some `queries`, return a list of words `answer`, where `answer[i]` is the correct word for `query = queries[i]`.

**Example 1:**

**Input:** wordlist = \["KiTe","kite","hare","Hare"\], queries = \["kite","Kite","KiTe","Hare","HARE","Hear","hear","keti","keet","keto"\]
**Output:** \["kite","KiTe","KiTe","Hare","hare","","","KiTe","","KiTe"\]

**Example 2:**

**Input:** wordlist = \["yellow"\], queries = \["YellOw"\]
**Output:** \["yellow"\]

**Constraints:**

*   `1 <= wordlist.length, queries.length <= 5000`
*   `1 <= wordlist[i].length, queries[i].length <= 7`
*   `wordlist[i]` and `queries[i]` consist only of only English letters.


def num_subarrays_with_sum(nums, goal):
    from collections import defaultdict
    prefix_sum_count = defaultdict(int)
    prefix_sum_count[0] = 1
    cumulative_sum, result = 0, 0

    for num in nums:
        cumulative_sum += num
        result += prefix_sum_count[cumulative_sum - goal]
        prefix_sum_count[cumulative_sum] += 1

    return result
