Translate the following inference to logic notation: There is at least one x for which if x_12 plays tennis, then x_12 is playing squash. For all x, x_12 is a cashier and x_12 will write a letter. For all x, x_12 will play tennis. Therefore there is at least one x for which x_12 will play squash and x_12 is a cashier.
exists x: P(x) -> Q(x). forall x: R(x) and S(x). forall x: P(x). Therefore exists x: Q(x) and R(x).