Consider the following premises. forall x_1: Q_3(x_1) -> Q_1(x_1). forall x_1: ~Q_1(x_1). forall x_1: R_2(x_1) -> Q_3(x_1). Can we infer forall x_1: ~R_2(x_1) from them?
 From forall x_1: Q_3(x_1) -> Q_1(x_1), forall x_1: ~Q_1(x_1) we can infer forall x_1: ~Q_3(x_1). Finally, from forall x_1: R_2(x_1) -> Q_3(x_1), forall x_1: ~Q_3(x_1) we can infer forall x_1: ~R_2(x_1). Therefore, the answer is yes.