Consider the following premises. forall x_8: P_8(x_8) or Q_8(x_8). forall x_8: Q(x_8) -> R_3(x_8). forall x_8: P_8(x_8) -> Q(x_8). forall x_8: Q_8(x_8) -> Q(x_8). exists x_8: U_4(x_8). Can we infer forall x_8: ~(U_4(x_8) and R_3(x_8)) from them?
 From forall x_8: P_8(x_8) -> Q(x_8), forall x_8: Q_8(x_8) -> Q(x_8), forall x_8: P_8(x_8) or Q_8(x_8) we can infer forall x_8: Q(x_8). From forall x_8: Q(x_8) -> R_3(x_8), forall x_8: Q(x_8) we can infer forall x_8: R_3(x_8). Finally, from exists x_8: U_4(x_8), forall x_8: R_3(x_8) we can infer exists x_8: U_4(x_8) and R_3(x_8), which contradicts forall x_8: ~(U_4(x_8) and R_3(x_8)). Therefore, the answer is no.