Translate the following inference to logic notation: There is at least one x for which if x_6 were bored, then x_6 is listening to a song. For all x, if x_6 were a taxi driver, then x_6 is taking a plane. For all x, x_6 is bored or x_6 will not take a plane. Therefore there is at least one x for which if x_6 were a taxi driver, then x_6 is listening to a song.
exists x: P(x) -> Q(x). forall x: R(x) -> S(x). forall x: P(x) or ~S(x). Therefore exists x: R(x) -> Q(x).