Translate the following inference to logic notation: There is at least one x for which if x_6 were an astronaut, then x_6 is writing a letter. For all x, x_6 will write a letter if and only if x_6 will make tea. For all x, x_6 will climb a mountain or x_6 will make tea. For all x, x_6 will not climb a mountain or x_6 is an astronaut. Therefore there is at least one x for which x_6 will write a letter.
exists x: P(x) -> Q(x). forall x: Q(x) <-> R(x). forall x: S(x) or R(x). forall x: ~S(x) or P(x). Therefore exists x: Q(x).