Translate the following inference to logic notation: Barbara is not reading a book. For all x, if x_4 reads a book, then x_4 is playing squash. For all x, if x_4 plays squash, then x_4 is cooking. For all x, if x_4 cooks, then x_4 is reading a book. Therefore Barbara is not playing squash.
~P(a). forall x: P(x) -> Q(x). forall x: Q(x) -> R(x). forall x: R(x) -> P(x). Therefore ~Q(a).