Consider the following premises. s -> S_14(a_14). p -> ~S_14(a_14). forall x_14: R_14(x_14) -> S_14(x_14). s or R_14(a_14). Can we infer p from them?
 From forall x_14: R_14(x_14) -> S_14(x_14) we can infer R_14(a_14) -> S_14(a_14). From s -> S_14(a_14), R_14(a_14) -> S_14(a_14), s or R_14(a_14) we can infer S_14(a_14). Finally, from p -> ~S_14(a_14), S_14(a_14) we can infer ~p, which contradicts p. Therefore, the answer is no.