Consider the following premises. forall x_9: Q(x_9) -> Q_4(x_9). exists x_9: Q_4(x_9) -> R(x_9). forall x_9: Q(x_9) or ~R(x_9). Can we infer exists x_9: Q(x_9) -> R(x_9) from them?
 From forall x_9: Q(x_9) or ~R(x_9) we can infer forall x_9: R(x_9) -> Q(x_9). Finally, from forall x_9: Q(x_9) -> Q_4(x_9), exists x_9: Q_4(x_9) -> R(x_9) we can infer exists x_9: Q(x_9) -> R(x_9). Therefore, the answer is yes.