Consider the following premises. exists x_1: S(x_1) -> U_1(x_1). forall x_1: ~Q_1(x_1). forall x_1: U_1(x_1) -> Q_1(x_1). Can we infer forall x_1: U_1(x_1) -> Q_1(x_1) from them?
That is one of the premises. Therefore, the answer is yes.