Translate the following inference to logic notation: For all x, if x_5 were an electrician, then x_5 is excited. There is at least one x for which x_5 is an electrician or x_5 is rich. For all x, if x_5 were a scientist, then x_5 is excited. For all x, if x_5 were rich, then x_5 is fast. For all x, if x_5 were fast, then x_5 is a scientist. Therefore there is at least one x for which x_5 is excited.
forall x: P(x) -> Q(x). exists x: P(x) or R(x). forall x: S(x) -> Q(x). forall x: R(x) -> T(x). forall x: T(x) -> S(x). Therefore exists x: Q(x).