Consider the following premises. ~S_12(a_12). R_12(a_12) or ~q_7. forall x_12: R_12(x_12) <-> S_12(x_12). Can we infer q_7 from them?
 From forall x_12: R_12(x_12) <-> S_12(x_12) we can infer R_12(a_12) <-> S_12(a_12). From R_12(a_12) or ~q_7 we can infer q_7 -> R_12(a_12). From R_12(a_12) <-> S_12(a_12), ~S_12(a_12) we can infer ~R_12(a_12). Finally, from q_7 -> R_12(a_12), ~R_12(a_12) we can infer ~q_7, which contradicts q_7. Therefore, the answer is no.