Consider the following premises. q_1 -> r_1. forall x_13: P_13(x_13) <-> Q_13(x_13). Q_13(a_10) -> q_1. Can we infer P_13(a_10) -> r_1 from them?
 From forall x_13: P_13(x_13) <-> Q_13(x_13) we can infer forall x_13: P_13(x_13) -> Q_13(x_13). From forall x_13: P_13(x_13) -> Q_13(x_13) we can infer P_13(a_10) -> Q_13(a_10). From Q_13(a_10) -> q_1, q_1 -> r_1 we can infer Q_13(a_10) -> r_1. Finally, from P_13(a_10) -> Q_13(a_10), Q_13(a_10) -> r_1 we can infer P_13(a_10) -> r_1. Therefore, the answer is yes.