Consider the following premises. Q_1(b) <-> s_4. s_4 or ~Q_1(b). forall z_2: ~Q_1(z_2). Can we infer ~s_4 from them?
 From forall z_2: ~Q_1(z_2) we can infer ~Q_1(b). From s_4 or ~Q_1(b) we can infer Q_1(b) -> s_4. From Q_1(b) <-> s_4 we can infer s_4 -> Q_1(b). From Q_1(b) -> s_4, s_4 -> Q_1(b) we can infer Q_1(b) <-> s_4. Finally, from Q_1(b) <-> s_4, ~Q_1(b) we can infer ~s_4. Therefore, the answer is yes.