Translate the following inference to logic notation: For all x, if x_10 were a musician, then x_10 is a lawyer. There is at least one x for which if x_10 takes a plane, then x_10 is a lawyer. For all x, x_10 will take a plane or x_10 is a musician. For all x, x_10 is not a lawyer. Therefore there is at least one x for which x_10 is excited.
forall x: P(x) -> Q(x). exists x: R(x) -> Q(x). forall x: R(x) or P(x). forall x: ~Q(x). Therefore exists x: S(x).