Consider the following premises. q_6 -> S_14(a_14). forall x_14: R_14(x_14) -> S_14(x_14). R_14(a_14) or q_6. Can we infer S_14(a_14) or t from them?
 From forall x_14: R_14(x_14) -> S_14(x_14) we can infer R_14(a_14) -> S_14(a_14). From R_14(a_14) -> S_14(a_14), q_6 -> S_14(a_14), R_14(a_14) or q_6 we can infer S_14(a_14). Finally, from S_14(a_14) we can infer S_14(a_14) or t. Therefore, the answer is yes.