Translate the following inference to logic notation: For all x, x_7 will drive a car or x_7 is not an office clerk. There is at least one x for which if x_7 makes tea, then x_7 is an office clerk. For all x, x_7 will make tea. Therefore there is at least one x for which x_7 will drive a car.
forall x: P(x) or ~Q(x). exists x: R(x) -> Q(x). forall x: R(x). Therefore exists x: P(x).