Consider the following premises. exists x_15: Q_8(x_15) -> R(x_15). forall x_15: S(x_15) <-> U(x_15). forall x_15: R(x_15) -> U(x_15). forall x_15: S(x_15) -> Q_8(x_15). Can we infer exists x_15: R(x_15) -> S(x_15) from them?
 From forall x_15: S(x_15) <-> U(x_15) we can infer forall x_15: U(x_15) -> S(x_15). From forall x_15: S(x_15) -> Q_8(x_15), exists x_15: Q_8(x_15) -> R(x_15) we can infer exists x_15: S(x_15) -> R(x_15). From forall x_15: R(x_15) -> U(x_15), forall x_15: U(x_15) -> S(x_15) we can infer forall x_15: R(x_15) -> S(x_15). From exists x_15: S(x_15) -> R(x_15), forall x_15: R(x_15) -> S(x_15) we can infer exists x_15: S(x_15) <-> R(x_15). Finally, from exists x_15: S(x_15) <-> R(x_15) we can infer exists x_15: R(x_15) -> S(x_15). Therefore, the answer is yes.