Consider the following premises. forall x_10: P_10(x_10). forall x_10: P_10(x_10) -> T_4(x_10). exists x_10: R_3(x_10) and Q_6(x_10). Can we infer forall x_10: ~(R_3(x_10) and T_4(x_10)) from them?
 From forall x_10: P_10(x_10) -> T_4(x_10), forall x_10: P_10(x_10) we can infer forall x_10: T_4(x_10). From exists x_10: R_3(x_10) and Q_6(x_10) we can infer exists x_10: R_3(x_10). Finally, from exists x_10: R_3(x_10), forall x_10: T_4(x_10) we can infer exists x_10: R_3(x_10) and T_4(x_10), which contradicts forall x_10: ~(R_3(x_10) and T_4(x_10)). Therefore, the answer is no.