Consider the following premises. forall x_13: Q_4(x_13) <-> T_3(x_13). exists x_13: T_3(x_13). forall x_13: U(x_13). Can we infer forall x_13: ~(Q_4(x_13) and U(x_13)) from them?
 From forall x_13: Q_4(x_13) <-> T_3(x_13) we can infer forall x_13: T_3(x_13) -> Q_4(x_13). From forall x_13: T_3(x_13) -> Q_4(x_13), exists x_13: T_3(x_13) we can infer exists x_13: Q_4(x_13). Finally, from exists x_13: Q_4(x_13), forall x_13: U(x_13) we can infer exists x_13: Q_4(x_13) and U(x_13), which contradicts forall x_13: ~(Q_4(x_13) and U(x_13)). Therefore, the answer is no.