Consider the following premises. forall x_6: R(x_6) -> Q_2(x_6). exists x_6: Q_2(x_6) -> T(x_6). forall x_6: Q_6(x_6) -> T(x_6). forall x_6: T_2(x_6) -> Q_6(x_6). forall x_6: R(x_6) or T_2(x_6). Can we infer forall x_6: ~T(x_6) from them?
 From forall x_6: T_2(x_6) -> Q_6(x_6), forall x_6: Q_6(x_6) -> T(x_6) we can infer forall x_6: T_2(x_6) -> T(x_6). From forall x_6: R(x_6) -> Q_2(x_6), exists x_6: Q_2(x_6) -> T(x_6) we can infer exists x_6: R(x_6) -> T(x_6). Finally, from exists x_6: R(x_6) -> T(x_6), forall x_6: T_2(x_6) -> T(x_6), forall x_6: R(x_6) or T_2(x_6) we can infer exists x_6: T(x_6), which contradicts forall x_6: ~T(x_6). Therefore, the answer is no.