Translate the following inference to logic notation: There is at least one x for which if z were a poet, then z is a sailor. For all x, z is not an office clerk. For all x, if z were a poet, then z is an office clerk. For all x, if z were a sailor, then z is a poet. Therefore there is at least one x for which z is not a sailor.
exists x: P(x) -> Q(x). forall x: ~R(x). forall x: P(x) -> R(x). forall x: Q(x) -> P(x). Therefore exists x: ~Q(x).