In a bag, there are 5 red balls and 3 green balls. If you pick one ball at random, replace it, and then pick another ball at random, what is the probability of picking two red balls in a row?
Let's reason through this problem:

1. The probability of picking a red ball on the first try is 5/8 (since there are 5 red balls out of a total of 8 balls).
2. Since we're replacing the ball after each pick, the probabilities remain the same for the second pick as well.
3. Therefore, the probability of picking a red ball on the second try is also 5/8.
4. To find the probability of both events happening consecutively, we multiply their individual probabilities: (5/8) * (5/8) = 25/64.

The answer is: The probability of picking two red balls in a row is 25/64.