Translate the following inference to logic notation: For all x, x_4 will make tea if and only if x_4 is excited. For all x, x_4 is not rich. For all x, if x_4 makes tea, then x_4 is rich. Therefore for all x, x_4 is not excited.
forall x: P(x) <-> Q(x). forall x: ~R(x). forall x: P(x) -> R(x). Therefore forall x: ~Q(x).