Translate the following inference to logic notation: There is at least one x for which if x_7 were happy, then x_7 is bored. For all x, x_7 is happy or x_7 will climb a mountain. For all x, if x_7 climbs a mountain, then x_7 is bored. For all x, x_7 will drive a car. Therefore there is at least one x for which x_7 is bored and x_7 will drive a car.
exists x: P(x) -> Q(x). forall x: P(x) or R(x). forall x: R(x) -> Q(x). forall x: S(x). Therefore exists x: Q(x) and S(x).