What is the value of $y$ in the arithmetic sequence $y + 6$, $12$, $y$?
So, if $y + 6$, $12$, $y$ is an arithmetic sequence, then there must be a common difference $d$ such that $12 = (y + 6) + d$ and $y = 12 + d$. I can solve for $d$ by subtracting $y + 6$ from both sides of the first equation: $d = 12 - (y + 6) = 6 - y$. Then, I can substitute this value of $d$ into the second equation and get $y = 12 + (6 - y)$. Expanding the parentheses and simplifying, I get $y = 18 - y$. Adding $y$ to both sides, I get $2y = 18$. Dividing both sides by 2, I get $y = 9$. Therefore, I am confident that $y = 9$ is the correct answer. 