Consider the following premises. exists z: U_3(z) <-> S_3(z). forall z: ~W_3(z). forall z: S_3(z) <-> W_1(z). forall z: W_3(z) <-> W_1(z). Can we infer forall z: U_3(z) from them?
 From forall z: S_3(z) <-> W_1(z) we can infer forall z: S_3(z) -> W_1(z). From forall z: W_3(z) <-> W_1(z), forall z: ~W_3(z) we can infer forall z: ~W_1(z). From forall z: S_3(z) -> W_1(z), forall z: ~W_1(z) we can infer forall z: ~S_3(z). Finally, from exists z: U_3(z) <-> S_3(z), forall z: ~S_3(z) we can infer exists z: ~U_3(z), which contradicts forall z: U_3(z). Therefore, the answer is no.