Consider the following premises. S_4(i_3). forall x_3: S_4(x_3) <-> T(x_3). Can we infer forall x_3: ~T(x_3) from them?
 From S_4(i_3) we can infer exists x_3: S_4(x_3). From forall x_3: S_4(x_3) <-> T(x_3) we can infer forall x_3: S_4(x_3) -> T(x_3). Finally, from forall x_3: S_4(x_3) -> T(x_3), exists x_3: S_4(x_3) we can infer exists x_3: T(x_3), which contradicts forall x_3: ~T(x_3). Therefore, the answer is no.