Consider the following premises. ~Q_12(a_11). q_3 -> S(a_11). forall x_12: Q_12(x_12) -> S(x_12). forall x_12: S(x_12) -> Q_12(x_12). Can we infer q_3 from them?
 From forall x_12: S(x_12) -> Q_12(x_12), forall x_12: Q_12(x_12) -> S(x_12) we can infer forall x_12: S(x_12) <-> Q_12(x_12). From forall x_12: S(x_12) <-> Q_12(x_12) we can infer S(a_11) <-> Q_12(a_11). From S(a_11) <-> Q_12(a_11), ~Q_12(a_11) we can infer ~S(a_11). Finally, from q_3 -> S(a_11), ~S(a_11) we can infer ~q_3, which contradicts q_3. Therefore, the answer is no.