Consider the following premises. forall x: S(x) -> W_4(x). exists x: Q_3(x) -> W_4(x). forall x: T(x). forall x: S(x). Can we infer forall x: ~(W_4(x) and T(x)) from them?
 From forall x: S(x) we can infer forall x: S(x) or Q_3(x). From forall x: S(x) -> W_4(x), exists x: Q_3(x) -> W_4(x), forall x: S(x) or Q_3(x) we can infer exists x: W_4(x). Finally, from exists x: W_4(x), forall x: T(x) we can infer exists x: W_4(x) and T(x), which contradicts forall x: ~(W_4(x) and T(x)). Therefore, the answer is no.