Translate the following inference to logic notation: For all x, x will play squash if and only if x is a scientist. There is at least one x for which if x were a scientist, then x is playing squash. Therefore there is at least one x for which if x plays squash, then x is a scientist.
forall x: P(x) <-> Q(x). exists x: Q(x) -> P(x). Therefore exists x: P(x) -> Q(x).