Translate the following inference to logic notation: For all x, if x_1 were bored, then x_1 is not drinking water. For all x, x_1 will make tea. For all x, if x_1 makes tea, then x_1 is drinking water. Therefore for all x, x_1 is not bored.
forall x: P(x) -> ~Q(x). forall x: R(x). forall x: R(x) -> Q(x). Therefore forall x: ~P(x).