Translate the following inference to logic notation: For all x, x will not play tennis. There is at least one x for which x is a scientist if and only if x is rich. For all x, if x were a scientist, then x is playing tennis. Therefore there is at least one x for which x is not rich.
forall x: ~P(x). exists x: Q(x) <-> R(x). forall x: Q(x) -> P(x). Therefore exists x: ~R(x).