Consider the following premises. forall z: R_2(z) -> T(z). r_2 -> R_2(e_1). forall z: T(z) -> R_2(z). forall z: ~T(z). Can we infer ~r_2 from them?
 From forall z: R_2(z) -> T(z), forall z: T(z) -> R_2(z) we can infer forall z: R_2(z) <-> T(z). From forall z: R_2(z) <-> T(z), forall z: ~T(z) we can infer forall z: ~R_2(z). From forall z: ~R_2(z) we can infer ~R_2(e_1). Finally, from r_2 -> R_2(e_1), ~R_2(e_1) we can infer ~r_2. Therefore, the answer is yes.