Translate the following inference to logic notation: There is at least one x for which if x_9 were fast, then x_9 is rich. For all x, x_9 is a bartender if and only if x_9 is sad. For all x, x_9 is sad or x_9 is fast. For all x, if x_9 were rich, then x_9 is a bartender. Therefore there is at least one x for which x_9 is a bartender.
exists x: P(x) -> Q(x). forall x: R(x) <-> S(x). forall x: S(x) or P(x). forall x: Q(x) -> R(x). Therefore exists x: R(x).