Compute the product of the roots of the equation \[x^3 - 12x^2 + 48x + 28 = 0.\]
I recall that for any cubic equation of the form \[ax^3 + bx^2 + cx + d = 0,\] the product of the roots is equal to \(-d/a\), by Vieta's formulas. In this case, \(a = 1\), \(b = -12\), \(c = 48\), and \(d = 28\), so the product of the roots is \(-28/1 = -28\). 