Translate the following inference to logic notation: For all x, if x_16 drives a car, then x_16 is happy. For all x, x_16 will not take a plane. For all x, x_16 is a sailor if and only if x_16 is happy. For all x, x_16 will take a plane if and only if x_16 is a sailor. There is at least one x for which x_16 is a mechanic if and only if x_16 will drive a car. Therefore there is at least one x for which x_16 is not a mechanic.
forall x: P(x) -> Q(x). forall x: ~R(x). forall x: S(x) <-> Q(x). forall x: R(x) <-> S(x). exists x: T(x) <-> P(x). Therefore exists x: ~T(x).