Consider the following premises. exists x_9: Q_9(x_9). forall x_9: Q(x_9) -> P(x_9). forall x_9: Q(x_9) -> ~Q_9(x_9). forall x_9: P(x_9) -> Q(x_9). Can we infer forall x_9: P(x_9) from them?
 From forall x_9: Q(x_9) -> ~Q_9(x_9), exists x_9: Q_9(x_9) we can infer exists x_9: ~Q(x_9). From forall x_9: Q(x_9) -> P(x_9), forall x_9: P(x_9) -> Q(x_9) we can infer forall x_9: Q(x_9) <-> P(x_9). From forall x_9: Q(x_9) <-> P(x_9) we can infer forall x_9: P(x_9) -> Q(x_9). Finally, from forall x_9: P(x_9) -> Q(x_9), exists x_9: ~Q(x_9) we can infer exists x_9: ~P(x_9), which contradicts forall x_9: P(x_9). Therefore, the answer is no.