Translate the following inference to logic notation: There is at least one x for which if x_6 were a musician, then x_6 is making tea. For all x, if x_6 were a musician, then x_6 is making tea. For all x, if x_6 makes tea, then x_6 is poor. For all x, if x_6 were poor, then x_6 is a musician. Therefore there is at least one x for which x_6 will make tea if and only if x_6 is a musician.
exists x: P(x) -> Q(x). forall x: P(x) -> Q(x). forall x: Q(x) -> R(x). forall x: R(x) -> P(x). Therefore exists x: Q(x) <-> P(x).