Translate the following inference to logic notation: For all x, z_1 is not an electrician. For all x, z_1 will work or z_1 is not an astronaut. There is at least one x for which if z_1 works, then z_1 is an electrician. Therefore there is at least one x for which z_1 is not an astronaut.
forall x: ~P(x). forall x: Q(x) or ~R(x). exists x: Q(x) -> P(x). Therefore exists x: ~R(x).