Translate the following inference to logic notation: There is at least one x for which if x_2 plays tennis, then x_2 is making tea. For all x, x_2 is an office clerk. For all x, x_2 will play tennis. Therefore there is at least one x for which x_2 will make tea and x_2 is an office clerk.
exists x: P(x) -> Q(x). forall x: R(x). forall x: P(x). Therefore exists x: Q(x) and R(x).