Consider the following premises. forall x: U(x) <-> R(x). forall x: ~T(x). forall x: T(x) <-> U(x). Can we infer forall x: ~R(x) from them?
 From forall x: T(x) <-> U(x), forall x: ~T(x) we can infer forall x: ~U(x). Finally, from forall x: U(x) <-> R(x), forall x: ~U(x) we can infer forall x: ~R(x). Therefore, the answer is yes.