Translate the following inference to logic notation: For all x, if x_5 were a nurse, then x_5 is not running. There is at least one x for which x_5 is a nurse. For all x, x_5 will go running. Therefore there is at least one x for which x_5 is an electrician.
forall x: P(x) -> ~Q(x). exists x: P(x). forall x: Q(x). Therefore exists x: R(x).