Consider the following premises. forall x_4: ~S(x_4). p <-> t. S(b) <-> p. Can we infer t from them?
 From forall x_4: ~S(x_4) we can infer ~S(b). From S(b) <-> p, ~S(b) we can infer ~p. Finally, from p <-> t, ~p we can infer ~t, which contradicts t. Therefore, the answer is no.