Consider the following premises. forall z: R_3(z) <-> R(z). forall z: Q_4(z) <-> R(z). Can we infer forall z: R_3(z) -> Q_4(z) from them?
 From forall z: R_3(z) <-> R(z) we can infer forall z: R_3(z) -> R(z). From forall z: Q_4(z) <-> R(z) we can infer forall z: R(z) -> Q_4(z). Finally, from forall z: R_3(z) -> R(z), forall z: R(z) -> Q_4(z) we can infer forall z: R_3(z) -> Q_4(z). Therefore, the answer is yes.