Consider the following premises. forall x_11: P_11(x_11). forall x_11: U(x_11) -> ~Q_3(x_11). forall x_11: Q_11(x_11) -> Q_3(x_11). exists x_11: P_11(x_11) -> Q_11(x_11). Can we infer exists x_11: P_11(x_11) -> Q_11(x_11) from them?
That is one of the premises. Therefore, the answer is yes.