Consider the following premises. forall y: ~T(y). forall y: U(y) -> Q(y). forall y: T(y) or Q_1(y). forall y: Q(y) -> ~Q_1(y). Can we infer forall y: ~U(y) from them?
 From forall y: T(y) or Q_1(y), forall y: ~T(y) we can infer forall y: Q_1(y). From forall y: Q(y) -> ~Q_1(y), forall y: Q_1(y) we can infer forall y: ~Q(y). Finally, from forall y: U(y) -> Q(y), forall y: ~Q(y) we can infer forall y: ~U(y). Therefore, the answer is yes.