Compute: $(3^2)(2^4)(37)(5^3)$
To compute this product, I can use the order of operations and the exponent rules. I can start by simplifying the powers of 3, 2, and 5. I know that $3^2 = 9$, $2^4 = 16$, and $5^3 = 125$. So, I can rewrite the product as $(9)(16)(37)(125)$. Now, I can multiply these numbers in any order, since multiplication is commutative and associative. I can start by multiplying 9 and 16, which is 144. Then, I can multiply 144 and 37, which is 5328. Finally, I can multiply 5328 and 125, which is 666000. So, the final answer is 666000. 