Translate the following inference to logic notation: For all x, if x_6 were a cashier, then x_6 is a nurse. There is at least one x for which x_6 is a cashier. For all x, x_6 is not a nurse. Therefore there is at least one x for which x_6 is an electrician.
forall x: P(x) -> Q(x). exists x: P(x). forall x: ~Q(x). Therefore exists x: R(x).