Translate the following inference to logic notation: For all x, if x_6 drinks water, then x_6 is sleeping. For all x, if x_6 sleeps, then x_6 is running. For all x, x_6 is an office clerk. For all x, if x_6 goes running, then x_6 is not an office clerk. Therefore for all x, x_6 will not drink water.
forall x: P(x) -> Q(x). forall x: Q(x) -> R(x). forall x: S(x). forall x: R(x) -> ~S(x). Therefore forall x: ~P(x).