Translate the following inference to logic notation: For all x, x_9 is not curious. For all x, if x_9 were a lawyer, then x_9 is a scientist. There is at least one x for which x_9 will play squash if and only if x_9 is a scientist. For all x, x_9 is curious or x_9 is a lawyer. Therefore there is at least one x for which x_9 is a scientist.
forall x: ~P(x). forall x: Q(x) -> R(x). exists x: S(x) <-> R(x). forall x: P(x) or Q(x). Therefore exists x: R(x).