Consider the following premises. forall x_6: Q(x_6) <-> Q_6(x_6). exists x_6: Q(x_6) -> Q_6(x_6). Can we infer exists x_6: Q_6(x_6) -> Q(x_6) from them?
 From forall x_6: Q(x_6) <-> Q_6(x_6) we can infer forall x_6: Q_6(x_6) -> Q(x_6). From exists x_6: Q(x_6) -> Q_6(x_6), forall x_6: Q_6(x_6) -> Q(x_6) we can infer exists x_6: Q(x_6) <-> Q_6(x_6). Finally, from exists x_6: Q(x_6) <-> Q_6(x_6) we can infer exists x_6: Q_6(x_6) -> Q(x_6). Therefore, the answer is yes.