Translate the following inference to logic notation: For all x, if y were fast, then y is a scientist. For all x, y is not fast. For all x, if y were a scientist, then y is fast. Therefore for all x, y is not a scientist.
forall x: P(x) -> Q(x). forall x: ~P(x). forall x: Q(x) -> P(x). Therefore forall x: ~Q(x).