Translate the following inference to logic notation: There is at least one x for which z will not read a book. For all x, if z were an astronaut, then z is reading a book. For all x, z will read a book or z is not an astronaut. For all x, if z reads a book, then z is an astronaut. Therefore there is at least one x for which z is not an astronaut.
exists x: ~P(x). forall x: Q(x) -> P(x). forall x: P(x) or ~Q(x). forall x: P(x) -> Q(x). Therefore exists x: ~Q(x).