Consider the following premises. forall x_3: R_2(x_3) <-> T_2(x_3). exists x_3: R_2(x_3) or ~T_2(x_3). Can we infer exists x_3: T_2(x_3) -> R_2(x_3) from them?
 From forall x_3: R_2(x_3) <-> T_2(x_3) we can infer forall x_3: R_2(x_3) -> T_2(x_3). Finally, from exists x_3: R_2(x_3) or ~T_2(x_3) we can infer exists x_3: T_2(x_3) -> R_2(x_3). Therefore, the answer is yes.