Consider the following premises. forall x_6: Q_6(x_6) -> R(x_6). forall x_6: R(x_6) -> Q_2(x_6). forall x_6: Q_2(x_6) -> P_6(x_6). forall x_6: P_6(x_6) -> Q_6(x_6). Can we infer forall x_6: P_6(x_6) -> R(x_6) from them?
Yes.