Translate the following inference to logic notation: For all x, x_6 is a carpenter or x_6 will drive a car. For all x, if x_6 were a carpenter, then x_6 is climbing a mountain. There is at least one x for which if x_6 drives a car, then x_6 is a lawyer. For all x, x_6 is a lawyer or x_6 will not climb a mountain. Therefore there is at least one x for which x_6 is a lawyer.
forall x: P(x) or Q(x). forall x: P(x) -> R(x). exists x: Q(x) -> S(x). forall x: S(x) or ~R(x). Therefore exists x: S(x).