Translate the following inference to logic notation: For all x, if z drinks water, then z is a police officer. For all x, z will not drink water. For all x, if z takes a plane, then z is drinking water. There is at least one x for which if z were a police officer, then z is taking a plane. Therefore there is at least one x for which z is not a police officer.
forall x: P(x) -> Q(x). forall x: ~P(x). forall x: R(x) -> P(x). exists x: Q(x) -> R(x). Therefore exists x: ~Q(x).