Translate the following inference to logic notation: For all x, x_4 will not drive a car. For all x, x_4 will play squash. There is at least one x for which x_4 will drive a car or x_4 is a doctor. Therefore there is at least one x for which x_4 will play squash and x_4 is a doctor.
forall x: ~P(x). forall x: Q(x). exists x: P(x) or R(x). Therefore exists x: Q(x) and R(x).