Translate the following inference to logic notation: For all x, if x_5 were rich, then x_5 is an electrician. For all x, if x_5 were a scientist, then x_5 is an electrician. For all x, if x_5 were a cashier, then x_5 is rich. There is at least one x for which x_5 is a scientist or x_5 will read a book. For all x, if x_5 reads a book, then x_5 is a cashier. Therefore there is at least one x for which x_5 is an electrician.
forall x: P(x) -> Q(x). forall x: R(x) -> Q(x). forall x: S(x) -> P(x). exists x: R(x) or T(x). forall x: T(x) -> S(x). Therefore exists x: Q(x).