Translate the following inference to logic notation: For all x, x_14 is not a lawyer. For all x, x_14 is a lawyer. Robert is a cashier. Therefore there is at least one x for which x_14 is a janitor and x_14 is a cashier.
forall x: ~P(x). forall x: P(x). Q(a). Therefore exists x: R(x) and Q(x).