Find the sum of all solutions to the equation $(x-6)^2=25$.
I know that if $(x-6)^2=25$, then either $x-6=5$ or $x-6=-5$, since both 5 and -5 are square roots of 25. So I have two possible values for x: $x=6+5=11$ or $x=6-5=1$. To find the sum of all solutions, I just need to add these two values: $11+1=12$. 