Translate the following inference to logic notation: Patricia is sleeping. For all x, if z were a musician, then z is playing tennis. For all x, z will play squash or z is a musician. For all x, if z plays squash, then z is playing tennis. Therefore there is at least one x for which z will play tennis and z will sleep.
P(a). forall x: Q(x) -> R(x). forall x: S(x) or Q(x). forall x: S(x) -> R(x). Therefore exists x: R(x) and P(x).