Consider the following premises. forall x_10: ~Q_10(x_10). s -> S_3(j_4). forall x_10: P_10(x_10) -> Q_10(x_10). forall x_10: S_3(x_10) <-> P_10(x_10). Can we infer ~s from them?
 From forall x_10: P_10(x_10) -> Q_10(x_10), forall x_10: ~Q_10(x_10) we can infer forall x_10: ~P_10(x_10). From forall x_10: S_3(x_10) <-> P_10(x_10), forall x_10: ~P_10(x_10) we can infer forall x_10: ~S_3(x_10). From forall x_10: ~S_3(x_10) we can infer ~S_3(j_4). Finally, from s -> S_3(j_4), ~S_3(j_4) we can infer ~s. Therefore, the answer is yes.