Consider the following premises. forall x: T_1(x) <-> S_1(x). forall x: S_1(x) -> S(x). forall x: S(x) -> T_1(x). Can we infer forall x: T_1(x) -> S(x) from them?
 From forall x: T_1(x) <-> S_1(x) we can infer forall x: T_1(x) -> S_1(x). Finally, from forall x: T_1(x) -> S_1(x), forall x: S_1(x) -> S(x) we can infer forall x: T_1(x) -> S(x). Therefore, the answer is yes.