Consider the following premises. forall x_16: Q_1(x_16) -> P(x_16). forall x_16: ~Q_16(x_16). exists x_16: P(x_16) -> P_16(x_16). forall x_16: U(x_16) -> Q_1(x_16). forall x_16: P_16(x_16) <-> Q_16(x_16). Can we infer exists x_16: ~U(x_16) from them?
 From forall x_16: P_16(x_16) <-> Q_16(x_16), forall x_16: ~Q_16(x_16) we can infer forall x_16: ~P_16(x_16). From exists x_16: P(x_16) -> P_16(x_16), forall x_16: ~P_16(x_16) we can infer exists x_16: ~P(x_16). From forall x_16: U(x_16) -> Q_1(x_16), forall x_16: Q_1(x_16) -> P(x_16) we can infer forall x_16: U(x_16) -> P(x_16). Finally, from forall x_16: U(x_16) -> P(x_16), exists x_16: ~P(x_16) we can infer exists x_16: ~U(x_16). Therefore, the answer is yes.