Translate the following inference to logic notation: For all x, if z drinks water, then z is a musician. For all x, if z were a musician, then z is making tea. There is at least one x for which z will not drink water. For all x, if z were a musician, then z is drinking water. For all x, if z makes tea, then z is a musician. Therefore there is at least one x for which z will not make tea.
forall x: P(x) -> Q(x). forall x: Q(x) -> R(x). exists x: ~P(x). forall x: Q(x) -> P(x). forall x: R(x) -> Q(x). Therefore exists x: ~R(x).