Translate the following inference to logic notation: For all x, if y_2 were a doctor, then y_2 is drinking water. For all x, if y_2 were a police officer, then y_2 is a doctor. For all x, y_2 will drive a car or y_2 will not drink water. There is at least one x for which if y_2 were poor, then y_2 is a police officer. Therefore there is at least one x for which if y_2 were poor, then y_2 is driving a car.
forall x: P(x) -> Q(x). forall x: R(x) -> P(x). forall x: S(x) or ~Q(x). exists x: T(x) -> R(x). Therefore exists x: T(x) -> S(x).