Translate the following inference to logic notation: For all x, x is curious if and only if x will read a book. There is at least one x for which if x were a doctor, then x is curious. Therefore there is at least one x for which if x were a doctor, then x is reading a book.
forall x: P(x) <-> Q(x). exists x: R(x) -> P(x). Therefore exists x: R(x) -> Q(x).