Translate the following inference to logic notation: For all x, x_11 is a writer or x_11 will not drink water. For all x, if x_11 were a writer, then x_11 is curious. There is at least one x for which if x_11 were an office clerk, then x_11 is a nurse. For all x, if x_11 were a nurse, then x_11 is drinking water. Therefore there is at least one x for which if x_11 were an office clerk, then x_11 is curious.
forall x: P(x) or ~Q(x). forall x: P(x) -> R(x). exists x: S(x) -> T(x). forall x: T(x) -> Q(x). Therefore exists x: S(x) -> R(x).