Consider the following premises. forall x_17: R(x_17) <-> T(x_17). forall x_17: T(x_17) <-> T_2(x_17). exists x_17: T_2(x_17) -> Q_17(x_17). forall x_17: P_3(x_17) <-> R(x_17). forall x_17: ~Q_17(x_17). Can we infer exists x_17: T_2(x_17) -> Q_17(x_17) from them?
That is one of the premises. Therefore, the answer is yes.