Consider the following premises. ~w. S_15(a_15) <-> w. forall x_15: R_15(x_15) -> S_15(x_15). p <-> R_15(a_15). Can we infer p from them?
 From forall x_15: R_15(x_15) -> S_15(x_15) we can infer R_15(a_15) -> S_15(a_15). From S_15(a_15) <-> w, ~w we can infer ~S_15(a_15). From R_15(a_15) -> S_15(a_15), ~S_15(a_15) we can infer ~R_15(a_15). Finally, from p <-> R_15(a_15), ~R_15(a_15) we can infer ~p, which contradicts p. Therefore, the answer is no.