Consider the following premises. exists x_9: ~R_9(x_9). forall x_9: T(x_9) or Q(x_9). forall x_9: T(x_9) -> Q_9(x_9). forall x_9: Q_9(x_9) -> R_9(x_9). Can we infer exists x_9: Q(x_9) from them?
 From forall x_9: T(x_9) -> Q_9(x_9), forall x_9: Q_9(x_9) -> R_9(x_9) we can infer forall x_9: T(x_9) -> R_9(x_9). From forall x_9: T(x_9) -> R_9(x_9), exists x_9: ~R_9(x_9) we can infer exists x_9: ~T(x_9). Finally, from forall x_9: T(x_9) or Q(x_9), exists x_9: ~T(x_9) we can infer exists x_9: Q(x_9). Therefore, the answer is yes.