Translate the following inference to logic notation: For all x, if x_10 drinks water, then x_10 is playing squash. For all x, x_10 is a writer if and only if x_10 will play squash. For all x, x_10 will not drink water. For all x, if x_10 goes running, then x_10 is a writer. For all x, if x_10 were a writer, then x_10 is running. For all x, if x_10 plays squash, then x_10 is drinking water. Therefore for all x, x_10 will not go running.
forall x: P(x) -> Q(x). forall x: R(x) <-> Q(x). forall x: ~P(x). forall x: S(x) -> R(x). forall x: R(x) -> S(x). forall x: Q(x) -> P(x). Therefore forall x: ~S(x).