Consider the following premises. exists x_10: Q_10(x_10) -> S(x_10). forall x_10: R_3(x_10). forall x_10: P(x_10) or Q_10(x_10). forall x_10: P(x_10) -> S(x_10). Can we infer exists x_10: S(x_10) from them?
Yes.