Translate the following inference to logic notation: For all x, if y works, then y is a doctor. For all x, y is not a sailor. For all x, if y were a musician, then y is working. For all x, if y were a doctor, then y is a musician. For all x, y is a sailor if and only if y is a doctor. Therefore for all x, y is not a musician.
forall x: P(x) -> Q(x). forall x: ~R(x). forall x: S(x) -> P(x). forall x: Q(x) -> S(x). forall x: R(x) <-> Q(x). Therefore forall x: ~S(x).