Consider the following premises. T_3(f) <-> s. forall x: ~T_3(x). ~s -> t_1. Can we infer t_1 from them?
 From forall x: ~T_3(x) we can infer ~T_3(f). From T_3(f) <-> s, ~T_3(f) we can infer ~s. Finally, from ~s -> t_1, ~s we can infer t_1. Therefore, the answer is yes.