Translate the following inference to logic notation: For all x, if x_6 were a musician, then x_6 is a mechanic. For all x, if x_6 climbs a mountain, then x_6 is not making tea. For all x, x_6 will make tea. For all x, x_6 is a mechanic if and only if x_6 will climb a mountain. Therefore for all x, x_6 is not a musician.
forall x: P(x) -> Q(x). forall x: R(x) -> ~S(x). forall x: S(x). forall x: Q(x) <-> R(x). Therefore forall x: ~P(x).