Translate the following inference to logic notation: For all x, if x_9 were a doctor, then x_9 is a lawyer. For all x, x_9 is a doctor if and only if x_9 is curious. For all x, if x_9 were a lawyer, then x_9 is a doctor. Therefore for all x, if x_9 were curious, then x_9 is a lawyer.
forall x: P(x) -> Q(x). forall x: P(x) <-> R(x). forall x: Q(x) -> P(x). Therefore forall x: R(x) -> Q(x).