Consider the following premises. forall x: T(x) <-> Q_3(x). forall x: R(x) -> Q_3(x). forall x: Q_3(x) -> R(x). forall x: ~T(x). Can we infer forall x: ~R(x) from them?
 From forall x: T(x) <-> Q_3(x), forall x: ~T(x) we can infer forall x: ~Q_3(x). From forall x: Q_3(x) -> R(x), forall x: R(x) -> Q_3(x) we can infer forall x: Q_3(x) <-> R(x). Finally, from forall x: Q_3(x) <-> R(x), forall x: ~Q_3(x) we can infer forall x: ~R(x). Therefore, the answer is yes.