Translate the following inference to logic notation: For all x, x_5 is an office clerk or x_5 is a soldier. For all x, if x_5 were rich, then x_5 is an office clerk. There is at least one x for which if x_5 were a soldier, then x_5 is rich. For all x, if x_5 were an office clerk, then x_5 is rich. Therefore there is at least one x for which x_5 is rich.
forall x: P(x) or Q(x). forall x: R(x) -> P(x). exists x: Q(x) -> R(x). forall x: P(x) -> R(x). Therefore exists x: R(x).