Expand the product $(x+1)^2 \cdot x$.
I recognize that $(x+1)^2$ is a special case of the binomial expansion formula, where $a = x$ and $b = 1$. So I can rewrite it as $(x+1)^2 = x^2 + 2x + 1$. Now I have to multiply this by $x$. I can use the distributive property to do this: $(x^2 + 2x + 1) \cdot x = x^3 + 2x^2 + x$. This is the expanded form of the product. 