Consider the following premises. forall z: Q_3(z) or S_1(z). forall z: S_1(z) -> R(z). forall z: R(z) -> Q(z). forall z: Q_3(z) -> R(z). q_2 and w_2. Can we infer Q(a_2) and q_2 from them?
 From forall z: Q_3(z) -> R(z), forall z: S_1(z) -> R(z), forall z: Q_3(z) or S_1(z) we can infer forall z: R(z). From q_2 and w_2 we can infer q_2. From forall z: R(z) -> Q(z), forall z: R(z) we can infer forall z: Q(z). From forall z: Q(z) we can infer Q(a_2). Finally, from Q(a_2), q_2 we can infer Q(a_2) and q_2. Therefore, the answer is yes.