Consider the following premises. forall x_15: S_3(x_15) or ~Q_15(x_15). forall x_15: P_4(x_15) -> S_3(x_15). forall x_15: P_4(x_15) or Q_15(x_15). exists x_15: P_8(x_15) or Q_8(x_15). forall x_15: ~P_8(x_15). Can we infer forall x_15: ~(S_3(x_15) and Q_8(x_15)) from them?
 From forall x_15: S_3(x_15) or ~Q_15(x_15) we can infer forall x_15: Q_15(x_15) -> S_3(x_15). From exists x_15: P_8(x_15) or Q_8(x_15), forall x_15: ~P_8(x_15) we can infer exists x_15: Q_8(x_15). From forall x_15: P_4(x_15) -> S_3(x_15), forall x_15: Q_15(x_15) -> S_3(x_15), forall x_15: P_4(x_15) or Q_15(x_15) we can infer forall x_15: S_3(x_15). Finally, from forall x_15: S_3(x_15), exists x_15: Q_8(x_15) we can infer exists x_15: S_3(x_15) and Q_8(x_15), which contradicts forall x_15: ~(S_3(x_15) and Q_8(x_15)). Therefore, the answer is no.