Refactor the following code to use the most Pythonic approach:

```
for i in range(0, list_items_len):
    if list_items[i] == target_item:
        index = i
        break
```
list_items = ['a', 'b', 'c', 'd', 'e']
target_item = 'c'
list_items = ['a', 'b', 'c', 'd', 'e']
target_item = 'c'

index = list_items.index(target_item) if target_item in list_items else None