Translate the following inference to logic notation: There is at least one x for which x_6 will read a book if and only if x_6 is poor. For all x, if x_6 plays a game, then x_6 is reading a book. For all x, x_6 is poor. Therefore there is at least one x for which x_6 will read a book.
exists x: P(x) <-> Q(x). forall x: R(x) -> P(x). forall x: Q(x). Therefore exists x: P(x).