Consider the following premises. forall z: T(z) <-> Q(z). forall z: Q(z) -> ~R(z). forall z: Q(z) -> T(z). forall z: R(z). Can we infer forall z: ~T(z) from them?
 From forall z: Q(z) -> ~R(z), forall z: R(z) we can infer forall z: ~Q(z). From forall z: T(z) <-> Q(z) we can infer forall z: T(z) -> Q(z). From forall z: Q(z) -> T(z), forall z: T(z) -> Q(z) we can infer forall z: Q(z) <-> T(z). Finally, from forall z: Q(z) <-> T(z), forall z: ~Q(z) we can infer forall z: ~T(z). Therefore, the answer is yes.