Alice, Bob, and Carol each have a bag containing apples and oranges. Alice has 8 apples and 12 oranges, Bob has 15 apples and 5 oranges, and Carol has 7 apples and 13 oranges. If one fruit is picked at random from each person's bag, what is the probability that all three fruits picked are apples?
To solve this problem, let's calculate the probabilities for each person separately and then multiply them together:
1. Alice has 20 fruits in total (8 apples + 12 oranges). The probability of picking an apple from her bag is 8/20 = 0.4.
2. Bob has 20 fruits in total (15 apples + 5 oranges). The probability of picking an apple from his bag is 15/20 = 0.75.
3. Carol has 20 fruits in total (7 apples + 13 oranges). The probability of picking an apple from her bag is 7/20 = 0.35.

Now, we need to multiply these probabilities together: 0.4 * 0.75 * 0.35 ≈ 0.105.

The final answer is a 10.5% chance or 0.105 probability that all three fruits picked are apples.