Consider the following premises. Q(a_1) -> T_2(a_1). forall y: Q(y) <-> T_2(y). Can we infer T_2(a_1) -> Q(a_1) from them?
 From forall y: Q(y) <-> T_2(y) we can infer Q(a_1) <-> T_2(a_1). Finally, from Q(a_1) <-> T_2(a_1) we can infer T_2(a_1) -> Q(a_1). Therefore, the answer is yes.