Consider the following premises. forall x: S(x) <-> U_4(x). forall x: ~S(x). t_2 -> U_4(a_2). Can we infer t_2 from them?
 From forall x: S(x) <-> U_4(x), forall x: ~S(x) we can infer forall x: ~U_4(x). From forall x: ~U_4(x) we can infer ~U_4(a_2). Finally, from t_2 -> U_4(a_2), ~U_4(a_2) we can infer ~t_2, which contradicts t_2. Therefore, the answer is no.