Translate the following inference to logic notation: There is at least one x for which x_14 is not a police officer. For all x, x_14 will sleep if and only if x_14 is a police officer. For all x, x_14 will sleep. For all x, if x_14 were a police officer, then x_14 is sleeping. Therefore there is at least one x for which x_14 will cook.
exists x: ~P(x). forall x: Q(x) <-> P(x). forall x: Q(x). forall x: P(x) -> Q(x). Therefore exists x: R(x).