Consider the following premises. forall x_7: P_7(x_7) <-> Q_7(x_7). exists x_7: Q(x_7) -> Q_7(x_7). forall x_7: T_2(x_7) or Q(x_7). forall x_7: T_2(x_7) -> P_7(x_7). Can we infer exists x_7: Q_7(x_7) from them?
 From forall x_7: P_7(x_7) <-> Q_7(x_7) we can infer forall x_7: P_7(x_7) -> Q_7(x_7). From forall x_7: T_2(x_7) -> P_7(x_7), forall x_7: P_7(x_7) -> Q_7(x_7) we can infer forall x_7: T_2(x_7) -> Q_7(x_7). Finally, from forall x_7: T_2(x_7) -> Q_7(x_7), exists x_7: Q(x_7) -> Q_7(x_7), forall x_7: T_2(x_7) or Q(x_7) we can infer exists x_7: Q_7(x_7). Therefore, the answer is yes.