Translate the following inference to logic notation: There is at least one x for which if x_10 were a cashier, then x_10 is making tea. For all x, x_10 is a cashier or x_10 is an electrician. For all x, if x_10 were an electrician, then x_10 is excited. For all x, if x_10 makes tea, then x_10 is excited. For all x, x_10 is a carpenter. Therefore there is at least one x for which x_10 is a carpenter and x_10 is excited.
exists x: P(x) -> Q(x). forall x: P(x) or R(x). forall x: R(x) -> S(x). forall x: Q(x) -> S(x). forall x: T(x). Therefore exists x: T(x) and S(x).