Consider the following premises. forall x_10: S(x_10). exists x_10: S_3(x_10) -> Q_10(x_10). forall x_10: S_3(x_10) or Q_7(x_10). forall x_10: Q_7(x_10) -> T(x_10). forall x_10: Q_10(x_10) -> T(x_10). Can we infer forall x_10: ~(S(x_10) and T(x_10)) from them?
 From exists x_10: S_3(x_10) -> Q_10(x_10), forall x_10: Q_10(x_10) -> T(x_10) we can infer exists x_10: S_3(x_10) -> T(x_10). From exists x_10: S_3(x_10) -> T(x_10), forall x_10: Q_7(x_10) -> T(x_10), forall x_10: S_3(x_10) or Q_7(x_10) we can infer exists x_10: T(x_10). Finally, from forall x_10: S(x_10), exists x_10: T(x_10) we can infer exists x_10: S(x_10) and T(x_10), which contradicts forall x_10: ~(S(x_10) and T(x_10)). Therefore, the answer is no.