Consider the following premises. ~P_4(a_2). forall x_9: P_4(x_9) -> Q_9(x_9). forall x_9: P_9(x_9) or ~Q_9(x_9). forall x_9: P_9(x_9) -> P_4(x_9). Can we infer ~Q_9(a_2) from them?
 From forall x_9: P_9(x_9) or ~Q_9(x_9) we can infer forall x_9: Q_9(x_9) -> P_9(x_9). From forall x_9: Q_9(x_9) -> P_9(x_9), forall x_9: P_9(x_9) -> P_4(x_9) we can infer forall x_9: Q_9(x_9) -> P_4(x_9). From forall x_9: P_4(x_9) -> Q_9(x_9), forall x_9: Q_9(x_9) -> P_4(x_9) we can infer forall x_9: P_4(x_9) <-> Q_9(x_9). From forall x_9: P_4(x_9) <-> Q_9(x_9) we can infer P_4(a_2) <-> Q_9(a_2). Finally, from P_4(a_2) <-> Q_9(a_2), ~P_4(a_2) we can infer ~Q_9(a_2). Therefore, the answer is yes.