Given an integer number `n`, return the difference between the product of its digits and the sum of its digits.

**Example 1:**

**Input:** n = 234
**Output:** 15 
**Explanation:** 
Product of digits = 2 \* 3 \* 4 = 24 
Sum of digits = 2 + 3 + 4 = 9 
Result = 24 - 9 = 15

**Example 2:**

**Input:** n = 4421
**Output:** 21
**Explanation:** 
Product of digits = 4 \* 4 \* 2 \* 1 = 32 
Sum of digits = 4 + 4 + 2 + 1 = 11 
Result = 32 - 11 = 21

**Constraints:**

*   `1 <= n <= 10^5`


def can_make_pali_queries(s, queries):
    result = []
    for left, right, k in queries:
        count = [0] * 26
        for i in range(left, right + 1):
            count[ord(s[i]) - ord('a')] += 1
        odd_count = sum(c % 2 for c in count)
        result.append(odd_count // 2 <= k)
    return result
