Consider the following premises. forall x_10: P_10(x_10) -> R_10(x_10). forall x_10: Q_1(x_10). forall x_10: P_10(x_10) or Q_10(x_10). exists x_10: Q_10(x_10) -> R_10(x_10). Can we infer exists x_10: R_10(x_10) from them?
Yes.