Consider the following premises. p -> u_3. forall x_15: R_15(x_15) -> S_15(x_15). S_15(a_15) -> r_6. u_3 -> R_15(a_15). Can we infer p -> r_6 from them?
 From forall x_15: R_15(x_15) -> S_15(x_15) we can infer R_15(a_15) -> S_15(a_15). From R_15(a_15) -> S_15(a_15), S_15(a_15) -> r_6 we can infer R_15(a_15) -> r_6. From u_3 -> R_15(a_15), R_15(a_15) -> r_6 we can infer u_3 -> r_6. Finally, from p -> u_3, u_3 -> r_6 we can infer p -> r_6. Therefore, the answer is yes.