Translate the following inference to logic notation: For all x, x will make tea or x is a police officer. There is at least one x for which x is a politician if and only if x is an artist. For all x, x is a politician if and only if x will make tea. For all x, x is not an artist. Therefore there is at least one x for which x is a police officer.
forall x: P(x) or Q(x). exists x: R(x) <-> S(x). forall x: R(x) <-> P(x). forall x: ~S(x). Therefore exists x: Q(x).