Translate the following inference to logic notation: There is at least one x for which x_8 will not play squash. For all x, x_8 is poor or x_8 will not play squash. For all x, x_8 is poor if and only if x_8 will play squash. Therefore there is at least one x for which x_8 is not poor.
exists x: ~P(x). forall x: Q(x) or ~P(x). forall x: Q(x) <-> P(x). Therefore exists x: ~Q(x).