Translate the following inference to logic notation: For all x, x_13 is an astronaut. There is at least one x for which x_13 is a taxi driver. For all x, if x_13 were bored, then x_13 is an office clerk. For all x, x_13 is an office clerk if and only if x_13 will make tea. For all x, x_13 will make tea or x_13 is bored. Therefore there is at least one x for which x_13 is an office clerk and x_13 is a taxi driver.
forall x: P(x). exists x: Q(x). forall x: R(x) -> S(x). forall x: S(x) <-> T(x). forall x: T(x) or R(x). Therefore exists x: S(x) and Q(x).