Translate the following inference to logic notation: For all x, if x_6 were an artist, then x_6 is an electrician. For all x, x_6 is an artist or x_6 is not bored. For all x, if x_6 were an electrician, then x_6 is bored. Therefore for all x, x_6 is bored if and only if x_6 is an electrician.
forall x: P(x) -> Q(x). forall x: P(x) or ~R(x). forall x: Q(x) -> R(x). Therefore forall x: R(x) <-> Q(x).