If $x$ satisfies $\frac{1}{2}-\frac{1}{3}=\frac{3}{x}$, then what is the value of $x$ ?
To solve for $x$, I need to isolate it on one side of the equation by using inverse operations. First, I notice that the left side of the equation has a common denominator of 6, so I can rewrite it as $\frac{3}{6}-\frac{2}{6}=\frac{1}{6}$. Now I have $\frac{1}{6}=\frac{3}{x}$, and I can cross-multiply to get $x=18$. To check my answer, I can plug it back into the original equation and see if it makes it true: $\frac{1}{2}-\frac{1}{3}=\frac{3}{18} \implies \frac{1}{6}=\frac{1}{6}$, which is true. Therefore, the value of $x$ is 18. 