Consider the following premises. P_16(a_14) -> s. forall x_16: P_16(x_16) or ~Q_16(x_16). Q_16(a_14). Can we infer s from them?
 From forall x_16: P_16(x_16) or ~Q_16(x_16) we can infer forall x_16: Q_16(x_16) -> P_16(x_16). From forall x_16: Q_16(x_16) -> P_16(x_16) we can infer Q_16(a_14) -> P_16(a_14). From Q_16(a_14) -> P_16(a_14), Q_16(a_14) we can infer P_16(a_14). Finally, from P_16(a_14) -> s, P_16(a_14) we can infer s. Therefore, the answer is yes.