Consider the following premises. P_13(h) or u. forall x_13: P_13(x_13) -> Q_13(x_13). Q_13(h) or ~u. forall x_13: Q_13(x_13) -> P_13(x_13). Can we infer ~Q_13(h) from them?
 From forall x_13: P_13(x_13) -> Q_13(x_13), forall x_13: Q_13(x_13) -> P_13(x_13) we can infer forall x_13: P_13(x_13) <-> Q_13(x_13). From forall x_13: P_13(x_13) <-> Q_13(x_13) we can infer P_13(h) <-> Q_13(h). From Q_13(h) or ~u we can infer u -> Q_13(h). From P_13(h) <-> Q_13(h) we can infer P_13(h) -> Q_13(h). Finally, from P_13(h) -> Q_13(h), u -> Q_13(h), P_13(h) or u we can infer Q_13(h), which contradicts ~Q_13(h). Therefore, the answer is no.