Translate the following inference to logic notation: For all x, x_4 is a scientist or x_4 is a server. For all x, x_4 will play squash if and only if x_4 is a scientist. There is at least one x for which x_4 is a bartender. For all x, if x_4 were a server, then x_4 is playing squash. Therefore there is at least one x for which x_4 will play squash and x_4 is a bartender.
forall x: P(x) or Q(x). forall x: R(x) <-> P(x). exists x: S(x). forall x: Q(x) -> R(x). Therefore exists x: R(x) and S(x).