Translate the following inference to logic notation: There is at least one x for which x_14 is not an artist. For all x, x_14 will drive a car if and only if x_14 is an electrician. For all x, x_14 is an artist if and only if x_14 will drive a car. For all x, x_14 is happy if and only if x_14 is an electrician. Therefore there is at least one x for which x_14 is not happy.
exists x: ~P(x). forall x: Q(x) <-> R(x). forall x: P(x) <-> Q(x). forall x: S(x) <-> R(x). Therefore exists x: ~S(x).