Consider the following premises. P_14(a_14). forall x_14: P_13(x_14) <-> P_14(x_14). Can we infer exists x_14: P_13(x_14) or Q(x_14) from them?
 From P_14(a_14) we can infer exists x_14: P_14(x_14). From forall x_14: P_13(x_14) <-> P_14(x_14) we can infer forall x_14: P_14(x_14) -> P_13(x_14). From forall x_14: P_14(x_14) -> P_13(x_14), exists x_14: P_14(x_14) we can infer exists x_14: P_13(x_14). Finally, from exists x_14: P_13(x_14) we can infer exists x_14: P_13(x_14) or Q(x_14). Therefore, the answer is yes.