Translate the following inference to logic notation: For all x, x_16 is a lawyer if and only if x_16 will drink water. For all x, x_16 will sleep or x_16 is a carpenter. For all x, x_16 will sleep if and only if x_16 is a lawyer. There is at least one x for which x_16 will not drink water. Therefore there is at least one x for which x_16 is a carpenter.
forall x: P(x) <-> Q(x). forall x: R(x) or S(x). forall x: R(x) <-> P(x). exists x: ~Q(x). Therefore exists x: S(x).