Consider the following premises. forall x_6: Q_6(x_6) -> R_6(x_6). u_3 -> R_6(a_5). forall x_6: U(x_6) -> Q_6(x_6). u_3 or U(a_5). Can we infer R_6(a_5) from them?
 From forall x_6: U(x_6) -> Q_6(x_6), forall x_6: Q_6(x_6) -> R_6(x_6) we can infer forall x_6: U(x_6) -> R_6(x_6). From forall x_6: U(x_6) -> R_6(x_6) we can infer U(a_5) -> R_6(a_5). Finally, from u_3 -> R_6(a_5), U(a_5) -> R_6(a_5), u_3 or U(a_5) we can infer R_6(a_5). Therefore, the answer is yes.