Translate the following inference to logic notation: For all x, if x plays squash, then x is a politician. For all x, if x were rich, then x is playing squash. There is at least one x for which x is rich or x will not take a plane. Therefore there is at least one x for which if x takes a plane, then x is a politician.
forall x: P(x) -> Q(x). forall x: R(x) -> P(x). exists x: R(x) or ~S(x). Therefore exists x: S(x) -> Q(x).