Consider the following premises. R_14(a_14) <-> p. forall x_25: R_25(x_25) and S_25(x_25). forall x_14: ~R_14(x_14). Can we infer ~R_25(a_25) from them?
 From forall x_25: R_25(x_25) and S_25(x_25) we can infer R_25(a_25) and S_25(a_25). Finally, from R_25(a_25) and S_25(a_25) we can infer R_25(a_25), which contradicts ~R_25(a_25). Therefore, the answer is no.