Translate the following inference to logic notation: For all x, z will work or z is not a musician. For all x, if z plays tennis, then z is working. There is at least one x for which z will not drink water or z will play tennis. For all x, if z works, then z is playing tennis. For all x, z will drink water or z is a musician. Therefore there is at least one x for which z will work.
forall x: P(x) or ~Q(x). forall x: R(x) -> P(x). exists x: ~S(x) or R(x). forall x: P(x) -> R(x). forall x: S(x) or Q(x). Therefore exists x: P(x).