Translate the following inference to logic notation: There is at least one x for which if x_2 were a police officer, then x_2 is working. For all x, if x_2 works, then x_2 is not climbing a mountain. For all x, x_2 will climb a mountain. Therefore there is at least one x for which x_2 is not a police officer.
exists x: P(x) -> Q(x). forall x: Q(x) -> ~R(x). forall x: R(x). Therefore exists x: ~P(x).