Translate the following inference to logic notation: For all x, if x_14 were a lawyer, then x_14 is a nurse. For all x, x_14 will not read a book. For all x, if x_14 were a nurse, then x_14 is a lawyer. There is at least one x for which x_14 will read a book or x_14 is a lawyer. Therefore there is at least one x for which x_14 is a nurse.
forall x: P(x) -> Q(x). forall x: ~R(x). forall x: Q(x) -> P(x). exists x: R(x) or P(x). Therefore exists x: Q(x).