Consider the following premises. forall x_10: U(x_10) -> S_10(x_10). ~S_10(a_10). r <-> U(a_10). Can we infer ~r from them?
 From forall x_10: U(x_10) -> S_10(x_10) we can infer U(a_10) -> S_10(a_10). From U(a_10) -> S_10(a_10), ~S_10(a_10) we can infer ~U(a_10). Finally, from r <-> U(a_10), ~U(a_10) we can infer ~r. Therefore, the answer is yes.