Consider the following premises. Q_1(e) -> t_4. forall x_13: R(x_13) -> Q_1(x_13). forall x_13: R(x_13) or Q_13(x_13). forall x_13: Q_13(x_13) -> Q_1(x_13). Can we infer ~t_4 from them?
 From forall x_13: R(x_13) -> Q_1(x_13), forall x_13: Q_13(x_13) -> Q_1(x_13), forall x_13: R(x_13) or Q_13(x_13) we can infer forall x_13: Q_1(x_13). From forall x_13: Q_1(x_13) we can infer Q_1(e). Finally, from Q_1(e) -> t_4, Q_1(e) we can infer t_4, which contradicts ~t_4. Therefore, the answer is no.