Translate the following inference to logic notation: For all x, if x_5 were a cashier, then x_5 is reading a book. There is at least one x for which if x_5 plays squash, then x_5 is reading a book. For all x, x_5 will play squash or x_5 is a cashier. For all x, if x_5 reads a book, then x_5 is a cashier. Therefore there is at least one x for which x_5 will read a book.
forall x: P(x) -> Q(x). exists x: R(x) -> Q(x). forall x: R(x) or P(x). forall x: Q(x) -> P(x). Therefore exists x: Q(x).