Consider the following premises. r <-> q_10. forall x_7: R_7(x_7) <-> S_7(x_7). ~r. S_7(a_7) -> q_10. Can we infer R_7(a_7) from them?
 From r <-> q_10, ~r we can infer ~q_10. From forall x_7: R_7(x_7) <-> S_7(x_7) we can infer R_7(a_7) <-> S_7(a_7). From S_7(a_7) -> q_10, ~q_10 we can infer ~S_7(a_7). Finally, from R_7(a_7) <-> S_7(a_7), ~S_7(a_7) we can infer ~R_7(a_7), which contradicts R_7(a_7). Therefore, the answer is no.