Translate the following inference to logic notation: There is at least one x for which z will play tennis or z is not a police officer. For all x, z is a carpenter or z will not play tennis. Therefore there is at least one x for which if z were a police officer, then z is a carpenter.
exists x: P(x) or ~Q(x). forall x: R(x) or ~P(x). Therefore exists x: Q(x) -> R(x).