Consider the following premises. forall x_9: P_9(x_9) or ~S(x_9). P_9(g) -> S(g). Can we infer S(g) -> P_9(g) from them?
 From forall x_9: P_9(x_9) or ~S(x_9) we can infer forall x_9: S(x_9) -> P_9(x_9). Finally, from forall x_9: S(x_9) -> P_9(x_9) we can infer S(g) -> P_9(g). Therefore, the answer is yes.