Translate the following inference to logic notation: There is at least one x for which if x_11 were bored, then x_11 is drinking water. For all x, if x_11 drinks water, then x_11 is bored. For all x, x_11 will drink water or x_11 is not sad. Therefore there is at least one x for which if x_11 were sad, then x_11 is bored.
exists x: P(x) -> Q(x). forall x: Q(x) -> P(x). forall x: Q(x) or ~R(x). Therefore exists x: R(x) -> P(x).