Translate the following inference to logic notation: There is at least one x for which x_6 is a police officer or x_6 is bored. For all x, x_6 will work. For all x, x_6 is not a police officer. Therefore there is at least one x for which x_6 is bored.
exists x: P(x) or Q(x). forall x: R(x). forall x: ~P(x). Therefore exists x: Q(x).