Translate the following inference to logic notation: There is at least one x for which if x_9 plays squash, then x_9 is a scientist. For all x, x_9 is a writer or x_9 will play squash. For all x, if x_9 were a scientist, then x_9 is running. For all x, x_9 will go running if and only if x_9 is a writer. Therefore there is at least one x for which x_9 will go running.
exists x: P(x) -> Q(x). forall x: R(x) or P(x). forall x: Q(x) -> S(x). forall x: S(x) <-> R(x). Therefore exists x: S(x).