Consider the following premises. forall x_15: P_15(x_15) and Q_15(x_15). forall x_15: S_4(x_15) or ~P_15(x_15). forall x_15: S_4(x_15) -> T(x_15). Can we infer ~T(b) from them?
 From forall x_15: P_15(x_15) and Q_15(x_15) we can infer forall x_15: P_15(x_15). From forall x_15: S_4(x_15) or ~P_15(x_15) we can infer forall x_15: P_15(x_15) -> S_4(x_15). From forall x_15: P_15(x_15) -> S_4(x_15), forall x_15: P_15(x_15) we can infer forall x_15: S_4(x_15). Finally, from forall x_15: S_4(x_15) -> T(x_15), forall x_15: S_4(x_15) we can infer forall x_15: T(x_15), which contradicts ~T(b). Therefore, the answer is no.