Consider the following premises. forall z: P_2(z). forall z: W_3(z) -> U_1(z). forall z: P_1(z) -> W_4(z). forall z: W_3(z) or T(z). forall z: T(z) -> U_1(z). forall z: P_1(z). Can we infer exists z: ~(W_4(z) and U_1(z)) from them?
 From forall z: P_1(z), forall z: P_2(z) we can infer forall z: P_1(z) and P_2(z). From forall z: P_1(z) and P_2(z) we can infer forall z: P_1(z). From forall z: P_1(z) -> W_4(z), forall z: P_1(z) we can infer forall z: W_4(z). From forall z: W_3(z) -> U_1(z), forall z: T(z) -> U_1(z), forall z: W_3(z) or T(z) we can infer forall z: U_1(z). Finally, from forall z: W_4(z), forall z: U_1(z) we can infer forall z: W_4(z) and U_1(z), which contradicts exists z: ~(W_4(z) and U_1(z)). Therefore, the answer is no.