The equation of the line that passes through the points $(-3,5)$ and $(0,-4)$ can be expressed in the form $y=mx+b$. What is the value of $m+b$?
To find the equation of the line, I need to know its slope $m$ and its y-intercept $b$. I can use the slope formula to find $m$: $m=\frac{y_2-y_1}{x_2-x_1}$, where $(x_1,y_1)$ and $(x_2,y_2)$ are any two points on the line. I can use the given points $(-3,5)$ and $(0,-4)$ as $(x_1,y_1)$ and $(x_2,y_2)$, respectively. Plugging them into the slope formula, I get: $m=\frac{-4-5}{0-(-3)}=\frac{-9}{3}=-3$. So the slope of the line is $-3$. To find the y-intercept $b$, I can use any point on the line and plug it into the equation $y=mx+b$. For example, I can use the point $(0,-4)$ and get: $-4=-3(0)+b$, which implies that $b=-4$. So the y-intercept of the line is $-4$. Therefore, the equation of the line is $y=-3x-4$. The question asks for the value of $m+b$, which is $-3+(-4)=-7$. 