Translate the following inference to logic notation: There is at least one x for which if x_6 were a nurse, then x_6 is sleeping. For all x, x_6 will play a game if and only if x_6 will sleep. For all x, if x_6 drives a car, then x_6 is a nurse. Therefore there is at least one x for which if x_6 drives a car, then x_6 is playing a game.
exists x: P(x) -> Q(x). forall x: R(x) <-> Q(x). forall x: S(x) -> P(x). Therefore exists x: S(x) -> R(x).