Consider the following premises. forall x_11: Q_11(x_11) -> Q(x_11). forall x_11: U(x_11). exists x_11: P_11(x_11) or Q_11(x_11). forall x_11: P_11(x_11) -> Q(x_11). Can we infer exists x_11: Q(x_11) from them?
Yes.