Translate the following inference to logic notation: For all x, if x_7 were rich, then x_7 is an office clerk. There is at least one x for which if x_7 sleeps, then x_7 is an office clerk. For all x, x_7 will sleep or x_7 is rich. Therefore there is at least one x for which x_7 is an office clerk or x_7 will write a letter.
forall x: P(x) -> Q(x). exists x: R(x) -> Q(x). forall x: R(x) or P(x). Therefore exists x: Q(x) or S(x).