Translate the following inference to logic notation: For all x, if x_10 were a mechanic, then x_10 is an office clerk. There is at least one x for which x_10 is a nurse and x_10 is excited. For all x, if x_10 were a nurse, then x_10 is a mechanic. Therefore there is at least one x for which x_10 is an office clerk.
forall x: P(x) -> Q(x). exists x: R(x) and S(x). forall x: R(x) -> P(x). Therefore exists x: Q(x).