Translate the following inference to logic notation: For all x, if x_4 were an artist, then x_4 is rich. There is at least one x for which if x_4 were an artist, then x_4 is rich. For all x, if x_4 were rich, then x_4 is an artist. Therefore there is at least one x for which if x_4 were rich, then x_4 is an artist.
forall x: P(x) -> Q(x). exists x: P(x) -> Q(x). forall x: Q(x) -> P(x). Therefore exists x: Q(x) -> P(x).