Translate the following inference to logic notation: There is at least one x for which x_12 will climb a mountain or x_12 is not an astronaut. For all x, if x_12 were an astronaut, then x_12 is climbing a mountain. For all x, if x_12 climbs a mountain, then x_12 is an astronaut. Therefore there is at least one x for which if x_12 were an astronaut, then x_12 is climbing a mountain.
exists x: P(x) or ~Q(x). forall x: Q(x) -> P(x). forall x: P(x) -> Q(x). Therefore exists x: Q(x) -> P(x).