Translate the following inference to logic notation: There is at least one x for which if y_1 were a musician, then y_1 is playing squash. For all x, if y_1 plays squash, then y_1 is a musician. Therefore there is at least one x for which if y_1 were a musician, then y_1 is playing squash.
exists x: P(x) -> Q(x). forall x: Q(x) -> P(x). Therefore exists x: P(x) -> Q(x).