Consider the following premises. R_6(a_5) -> s_2. forall x_16: P_10(x_16) -> P_16(x_16). forall x_16: P_16(x_16) <-> Q_16(x_16). forall x_16: Q_16(x_16) -> R_6(x_16). Can we infer P_10(a_5) -> s_2 from them?
 From forall x_16: P_16(x_16) <-> Q_16(x_16) we can infer forall x_16: P_16(x_16) -> Q_16(x_16). From forall x_16: P_10(x_16) -> P_16(x_16), forall x_16: P_16(x_16) -> Q_16(x_16) we can infer forall x_16: P_10(x_16) -> Q_16(x_16). From forall x_16: P_10(x_16) -> Q_16(x_16), forall x_16: Q_16(x_16) -> R_6(x_16) we can infer forall x_16: P_10(x_16) -> R_6(x_16). From forall x_16: P_10(x_16) -> R_6(x_16) we can infer P_10(a_5) -> R_6(a_5). Finally, from P_10(a_5) -> R_6(a_5), R_6(a_5) -> s_2 we can infer P_10(a_5) -> s_2. Therefore, the answer is yes.