Consider the following premises. forall z: T(z) or ~P(z). exists z: P(z) <-> R(z). Can we infer exists z: R(z) -> T(z) from them?
 From forall z: T(z) or ~P(z) we can infer forall z: P(z) -> T(z). From exists z: P(z) <-> R(z) we can infer exists z: R(z) -> P(z). Finally, from exists z: R(z) -> P(z), forall z: P(z) -> T(z) we can infer exists z: R(z) -> T(z). Therefore, the answer is yes.