Translate the following inference to logic notation: There is at least one x for which x_2 will not drive a car. For all x, x_2 will drive a car or x_2 is not an office clerk. Therefore there is at least one x for which x_2 is not an office clerk.
exists x: ~P(x). forall x: P(x) or ~Q(x). Therefore exists x: ~Q(x).