Consider the following premises. forall x_1: R_1(x_1) -> ~U_3(x_1). exists x_1: S_3(x_1) -> U_3(x_1). forall x_1: R_4(x_1) or S_3(x_1). forall x_1: R_4(x_1) -> U_3(x_1). Can we infer forall x_1: R_1(x_1) from them?
 From forall x_1: R_4(x_1) -> U_3(x_1), exists x_1: S_3(x_1) -> U_3(x_1), forall x_1: R_4(x_1) or S_3(x_1) we can infer exists x_1: U_3(x_1). Finally, from forall x_1: R_1(x_1) -> ~U_3(x_1), exists x_1: U_3(x_1) we can infer exists x_1: ~R_1(x_1), which contradicts forall x_1: R_1(x_1). Therefore, the answer is no.