Consider the following premises. forall x_8: T(x_8) <-> S_1(x_8). forall x_8: S_1(x_8) -> Q_2(x_8). exists x_8: Q_2(x_8) -> T(x_8). Can we infer forall x_8: S_1(x_8) -> Q_2(x_8) from them?
That is one of the premises. Therefore, the answer is yes.