Translate the following inference to logic notation: For all x, if y drives a car, then y is a lawyer. For all x, y is rich if and only if y will drive a car. For all x, y is rich or y is not a lawyer. Therefore for all x, if y were a lawyer, then y is driving a car.
forall x: P(x) -> Q(x). forall x: R(x) <-> P(x). forall x: R(x) or ~Q(x). Therefore forall x: Q(x) -> P(x).