Consider the following premises. forall x_11: U_1(x_11) <-> S_11(x_11). q. ~S_11(a_11). Can we infer ~U_1(a_11) and q from them?
 From forall x_11: U_1(x_11) <-> S_11(x_11) we can infer U_1(a_11) <-> S_11(a_11). From U_1(a_11) <-> S_11(a_11), ~S_11(a_11) we can infer ~U_1(a_11). Finally, from ~U_1(a_11), q we can infer ~U_1(a_11) and q. Therefore, the answer is yes.