In a kennel with 60 dogs, 9 dogs like watermelon, 48 dogs like salmon, and 5 like both salmon and watermelon.  How many dogs in the kennel will not eat either?
To answer this question, I need to figure out how many dogs like either salmon or watermelon, or both, and then subtract that from the total number of dogs in the kennel. I can use the formula for the union of two sets: |A ∪ B| = |A| + |B| - |A ∩ B|, where A is the set of dogs that like watermelon, B is the set of dogs that like salmon, and A ∩ B is the set of dogs that like both. Plugging in the given values, I get |A ∪ B| = 9 + 48 - 5 = 52. That means 52 dogs like either salmon or watermelon, or both. To find how many dogs do not like either, I need to subtract 52 from the total number of dogs, which is 60. Therefore, the answer is 60 - 52 = 8. 