Consider the following premises. forall x_11: Q_11(x_11) -> R_11(x_11). forall x_11: S(x_11) -> Q_11(x_11). S(j_4) or ~u. Can we infer u -> R_11(j_4) from them?
 From forall x_11: S(x_11) -> Q_11(x_11), forall x_11: Q_11(x_11) -> R_11(x_11) we can infer forall x_11: S(x_11) -> R_11(x_11). From forall x_11: S(x_11) -> R_11(x_11) we can infer S(j_4) -> R_11(j_4). From S(j_4) or ~u we can infer u -> S(j_4). Finally, from u -> S(j_4), S(j_4) -> R_11(j_4) we can infer u -> R_11(j_4). Therefore, the answer is yes.