Consider the following premises. forall x_15: P(x_15) <-> T(x_15). forall x_15: Q_15(x_15). forall x_15: P(x_15) -> T(x_15). forall x_15: S(x_15) -> ~Q_15(x_15). exists x_15: P(x_15) -> S(x_15). Can we infer forall x_15: T(x_15) from them?
 From forall x_15: S(x_15) -> ~Q_15(x_15), forall x_15: Q_15(x_15) we can infer forall x_15: ~S(x_15). From exists x_15: P(x_15) -> S(x_15), forall x_15: ~S(x_15) we can infer exists x_15: ~P(x_15). From forall x_15: P(x_15) <-> T(x_15) we can infer forall x_15: T(x_15) -> P(x_15). From forall x_15: T(x_15) -> P(x_15), forall x_15: P(x_15) -> T(x_15) we can infer forall x_15: T(x_15) <-> P(x_15). Finally, from forall x_15: T(x_15) <-> P(x_15), exists x_15: ~P(x_15) we can infer exists x_15: ~T(x_15), which contradicts forall x_15: T(x_15). Therefore, the answer is no.