Consider the following premises. forall x_14: Q_14(x_14) -> R_14(x_14). forall x_14: ~Q_10(x_14). forall x_14: R_14(x_14) -> Q_10(x_14). u_2 <-> Q(j_2). forall x_14: Q(x_14) -> Q_14(x_14). Can we infer ~u_2 from them?
 From forall x_14: Q(x_14) -> Q_14(x_14), forall x_14: Q_14(x_14) -> R_14(x_14) we can infer forall x_14: Q(x_14) -> R_14(x_14). From forall x_14: R_14(x_14) -> Q_10(x_14), forall x_14: ~Q_10(x_14) we can infer forall x_14: ~R_14(x_14). From forall x_14: Q(x_14) -> R_14(x_14), forall x_14: ~R_14(x_14) we can infer forall x_14: ~Q(x_14). From forall x_14: ~Q(x_14) we can infer ~Q(j_2). Finally, from u_2 <-> Q(j_2), ~Q(j_2) we can infer ~u_2. Therefore, the answer is yes.