Translate the following inference to logic notation: For all x, if x_5 drinks water, then x_5 is running. There is at least one x for which x_5 will read a book if and only if x_5 will go running. Therefore there is at least one x for which if x_5 drinks water, then x_5 is reading a book.
forall x: P(x) -> Q(x). exists x: R(x) <-> Q(x). Therefore exists x: P(x) -> R(x).