Translate the following inference to logic notation: For all x, x_1 is not a scientist. There is at least one x for which if x_1 were poor, then x_1 is a scientist. For all x, x_1 is poor or x_1 will drive a car. Therefore there is at least one x for which x_1 will drive a car.
forall x: ~P(x). exists x: Q(x) -> P(x). forall x: Q(x) or R(x). Therefore exists x: R(x).