Consider the following premises. forall x_13: P_2(x_13). forall x_13: P_13(x_13) or Q_13(x_13). forall x_13: Q_13(x_13) -> S(x_13). exists x_13: P_2(x_13) -> Q_2(x_13). forall x_13: P_13(x_13) -> S(x_13). Can we infer forall x_13: ~(S(x_13) and Q_2(x_13)) from them?
 From forall x_13: P_13(x_13) -> S(x_13), forall x_13: Q_13(x_13) -> S(x_13), forall x_13: P_13(x_13) or Q_13(x_13) we can infer forall x_13: S(x_13). From exists x_13: P_2(x_13) -> Q_2(x_13), forall x_13: P_2(x_13) we can infer exists x_13: Q_2(x_13). Finally, from forall x_13: S(x_13), exists x_13: Q_2(x_13) we can infer exists x_13: S(x_13) and Q_2(x_13), which contradicts forall x_13: ~(S(x_13) and Q_2(x_13)). Therefore, the answer is no.