Translate the following inference to logic notation: For all x, if x_6 were a scientist, then x_6 is an artist. For all x, if x_6 were an artist, then x_6 is a cashier. For all x, if x_6 were a cashier, then x_6 is running. For all x, x_6 will not go running. For all x, if x_6 were a cashier, then x_6 is a scientist. Therefore for all x, x_6 is not an artist.
forall x: P(x) -> Q(x). forall x: Q(x) -> R(x). forall x: R(x) -> S(x). forall x: ~S(x). forall x: R(x) -> P(x). Therefore forall x: ~Q(x).