Consider the following premises. exists x_9: Q_2(x_9) <-> Q_9(x_9). forall x_9: Q_9(x_9) -> R_1(x_9). forall x_9: R_1(x_9) -> R(x_9). Can we infer exists x_9: Q_2(x_9) -> R(x_9) from them?
 From exists x_9: Q_2(x_9) <-> Q_9(x_9) we can infer exists x_9: Q_2(x_9) -> Q_9(x_9). From exists x_9: Q_2(x_9) -> Q_9(x_9), forall x_9: Q_9(x_9) -> R_1(x_9) we can infer exists x_9: Q_2(x_9) -> R_1(x_9). Finally, from exists x_9: Q_2(x_9) -> R_1(x_9), forall x_9: R_1(x_9) -> R(x_9) we can infer exists x_9: Q_2(x_9) -> R(x_9). Therefore, the answer is yes.