Consider the following premises. forall x_14: P_14(x_14) and Q_14(x_14). forall x_14: U(x_14) -> ~P_14(x_14). exists x_14: Q_11(x_14). Can we infer exists x_14: ~U(x_14) from them?
 From forall x_14: P_14(x_14) and Q_14(x_14) we can infer forall x_14: P_14(x_14). From forall x_14: P_14(x_14), exists x_14: Q_11(x_14) we can infer exists x_14: P_14(x_14) and Q_11(x_14). From exists x_14: P_14(x_14) and Q_11(x_14) we can infer exists x_14: P_14(x_14). Finally, from forall x_14: U(x_14) -> ~P_14(x_14), exists x_14: P_14(x_14) we can infer exists x_14: ~U(x_14). Therefore, the answer is yes.