Consider the following premises. forall x: R(x). forall z: S(z) -> R(z). forall z: R(z) -> S(z). Can we infer ~S(a_9) from them?
 From forall x: R(x) we can infer R(a_9). From forall z: R(z) -> S(z), forall z: S(z) -> R(z) we can infer forall z: R(z) <-> S(z). From forall z: R(z) <-> S(z) we can infer R(a_9) <-> S(a_9). From R(a_9) <-> S(a_9) we can infer R(a_9) -> S(a_9). Finally, from R(a_9) -> S(a_9), R(a_9) we can infer S(a_9), which contradicts ~S(a_9). Therefore, the answer is no.