At what point does the line $3y-4x=12$ intersect the $x$-axis? Express your answer as an ordered pair.
I want to find the point where the line crosses the $x$-axis, which means that $y=0$ at that point. So I can plug in $y=0$ into the equation of the line and solve for $x$. I get $3(0)-4x=12$, which simplifies to $-4x=12$. Dividing both sides by $-4$, I get $x=-3$. So the point of intersection is $(-3,0)$. 