Consider the following premises. S_15(a_15) -> u_2. u_2 -> q_1. ~q_1. forall x_15: S(x_15) -> S_15(x_15). Can we infer S(a_15) from them?
 From forall x_15: S(x_15) -> S_15(x_15) we can infer S(a_15) -> S_15(a_15). From S(a_15) -> S_15(a_15), S_15(a_15) -> u_2 we can infer S(a_15) -> u_2. From u_2 -> q_1, ~q_1 we can infer ~u_2. Finally, from S(a_15) -> u_2, ~u_2 we can infer ~S(a_15), which contradicts S(a_15). Therefore, the answer is no.