Consider the following premises. s. forall x_14: R_14(x_14) -> S_14(x_14). ~S_14(a_14). Can we infer R_14(a_14) from them?
 From forall x_14: R_14(x_14) -> S_14(x_14) we can infer R_14(a_14) -> S_14(a_14). Finally, from R_14(a_14) -> S_14(a_14), ~S_14(a_14) we can infer ~R_14(a_14), which contradicts R_14(a_14). Therefore, the answer is no.