Translate the following inference to logic notation: For all x, if x_6 were an office clerk, then x_6 is playing a game. For all x, if x_6 plays a game, then x_6 is driving a car. There is at least one x for which x_6 is an office clerk or x_6 will not read a book. Therefore there is at least one x for which if x_6 reads a book, then x_6 is driving a car.
forall x: P(x) -> Q(x). forall x: Q(x) -> R(x). exists x: P(x) or ~S(x). Therefore exists x: S(x) -> R(x).