Consider the following premises. r -> P_2(e_3). forall x_8: P_2(x_8) <-> Q_8(x_8). Can we infer r -> Q_8(e_3) from them?
 From forall x_8: P_2(x_8) <-> Q_8(x_8) we can infer forall x_8: P_2(x_8) -> Q_8(x_8). From forall x_8: P_2(x_8) -> Q_8(x_8) we can infer P_2(e_3) -> Q_8(e_3). Finally, from r -> P_2(e_3), P_2(e_3) -> Q_8(e_3) we can infer r -> Q_8(e_3). Therefore, the answer is yes.