Translate the following inference to logic notation: For all x, if x_6 drinks water, then x_6 is driving a car. There is at least one x for which x_6 is a poet or x_6 will drink water. For all x, if x_6 takes a plane, then x_6 is driving a car. For all x, x_6 will take a plane or x_6 is not a poet. Therefore there is at least one x for which x_6 will drive a car.
forall x: P(x) -> Q(x). exists x: R(x) or P(x). forall x: S(x) -> Q(x). forall x: S(x) or ~R(x). Therefore exists x: Q(x).