Consider the following premises. forall x_7: T(x_7) <-> S_7(x_7). ~T(a_7). S_7(a_7) <-> q. Can we infer q from them?
 From forall x_7: T(x_7) <-> S_7(x_7) we can infer T(a_7) <-> S_7(a_7). From T(a_7) <-> S_7(a_7), ~T(a_7) we can infer ~S_7(a_7). Finally, from S_7(a_7) <-> q, ~S_7(a_7) we can infer ~q, which contradicts q. Therefore, the answer is no.