Consider the following premises. forall x_1: Q_1(x_1) -> R_1(x_1). forall x_1: ~R_1(x_1). exists x_1: Q_3(x_1) -> Q_1(x_1). Can we infer forall x_1: Q_3(x_1) from them?
 From exists x_1: Q_3(x_1) -> Q_1(x_1), forall x_1: Q_1(x_1) -> R_1(x_1) we can infer exists x_1: Q_3(x_1) -> R_1(x_1). Finally, from exists x_1: Q_3(x_1) -> R_1(x_1), forall x_1: ~R_1(x_1) we can infer exists x_1: ~Q_3(x_1), which contradicts forall x_1: Q_3(x_1). Therefore, the answer is no.