Translate the following inference to logic notation: For all x, if x_10 were curious, then x_10 is an office clerk. For all x, x_10 is curious or x_10 is not an office clerk. For all x, if x_10 were an office clerk, then x_10 is curious. Therefore for all x, if x_10 were curious, then x_10 is an office clerk.
forall x: P(x) -> Q(x). forall x: P(x) or ~Q(x). forall x: Q(x) -> P(x). Therefore forall x: P(x) -> Q(x).