What is the sum of all positive integers $t$ such that $1.2t \leq 9.6$?
To make it easier, I can divide both sides by $1.2$ to get $t \leq 8$. So the possible values of $t$ are $1, 2, 3, 4, 5, 6, 7, 8$. To find the sum of these values, I can use a formula for the sum of an arithmetic series. The formula is $S_n = \frac{n}{2}(a_1 + a_n)$, where $n$ is the number of terms, $a_1$ is the first term, and $a_n$ is the last term. In this case, $n = 8$, $a_1 = 1$, and $a_8 = 8$. So the sum is $S_8 = \frac{8}{2}(1 + 8) = 4(9) = 36$. 