Consider the following premises. exists x_2: Q_2(x_2) -> R_2(x_2). forall x_2: R_2(x_2) -> R(x_2). forall x_2: W_2(x_2) -> Q_2(x_2). Can we infer forall x_2: W_2(x_2) -> Q_2(x_2) from them?
That is one of the premises. Therefore, the answer is yes.