Consider the following premises. forall y: S(y). exists y: S(y) -> U_4(y). forall y: R(y). Can we infer forall y: ~(U_4(y) and R(y)) from them?
 From exists y: S(y) -> U_4(y), forall y: S(y) we can infer exists y: U_4(y). Finally, from exists y: U_4(y), forall y: R(y) we can infer exists y: U_4(y) and R(y), which contradicts forall y: ~(U_4(y) and R(y)). Therefore, the answer is no.