Translate the following inference to logic notation: There is at least one x for which y will drive a car if and only if y is a soldier. For all x, if y were a soldier, then y is driving a car. Therefore there is at least one x for which if y were a soldier, then y is driving a car.
exists x: P(x) <-> Q(x). forall x: Q(x) -> P(x). Therefore exists x: Q(x) -> P(x).