Translate the following inference to logic notation: There is at least one x for which x_10 will read a book if and only if x_10 is curious. For all x, x_10 will not play squash or x_10 is an office clerk. For all x, x_10 will play squash or x_10 is curious. For all x, x_10 will not read a book. Therefore there is at least one x for which x_10 is an office clerk.
exists x: P(x) <-> Q(x). forall x: ~R(x) or S(x). forall x: R(x) or Q(x). forall x: ~P(x). Therefore exists x: S(x).