Translate the following inference to logic notation: For all x, if z were rich, then z is reading a book. There is at least one x for which z is an electrician if and only if z is rich. Therefore there is at least one x for which if z were an electrician, then z is reading a book.
forall x: P(x) -> Q(x). exists x: R(x) <-> P(x). Therefore exists x: R(x) -> Q(x).