Find $\frac{\frac{1}{3} + \frac{1}{4}}{ \frac{2}{5} - \frac{1}{6}}$. Express your answer as a fraction in simplest form.
To simplify a complex fraction like this, I want to find a common denominator for the fractions in the numerator and the fractions in the denominator. For the fractions in the numerator, the common denominator is the least common multiple of 3 and 4, which is 12. To get 12 as the denominator of $\frac{1}{3}$, I need to multiply the numerator and denominator by 4. That gives me $\frac{4}{12}$. To get 12 as the denominator of $\frac{1}{4}$, I need to multiply the numerator and denominator by 3. That gives me $\frac{3}{12}$. So, the numerator becomes $\frac{\frac{4}{12} + \frac{3}{12}}{1}$, which I can simplify by adding the numerators and keeping the denominator. That gives me $\frac{7}{12}$. For the fractions in the denominator, the common denominator is the least common multiple of 5 and 6, which is 30. To get 30 as the denominator of $\frac{2}{5}$, I need to multiply the numerator and denominator by 6. That gives me $\frac{12}{30}$. To get 30 as the denominator of $\frac{1}{6}$, I need to multiply the numerator and denominator by 5. That gives me $\frac{5}{30}$. So, the denominator becomes $\frac{\frac{12}{30} - \frac{5}{30}}{1}$, which I can simplify by subtracting the numerators and keeping the denominator. That gives me $\frac{7}{30}$. Now, I have simplified the complex fraction to $\frac{\frac{7}{12}}{\frac{7}{30}}$. To divide two fractions, I can multiply by the reciprocal of the second fraction. That means I can rewrite this as $\frac{7}{12} \times \frac{30}{7}$. To multiply two fractions, I can multiply the numerators and multiply the denominators. That gives me $\frac{7 \times 30}{12 \times 7}$. I can simplify this fraction by canceling out the common factor of 7 in the numerator and denominator. That gives me $\frac{30}{12}$. I can reduce this fraction by dividing the numerator and denominator by the greatest common factor of 30 and 12, which is 6. That gives me $\frac{5}{2}$. This is the simplest form of the fraction, so I am done. 