Consider the following premises. u -> R_3(b_3). forall z: Q(z) <-> R_3(z). u or Q(b_3). Can we infer R_3(b_3) from them?
 From forall z: Q(z) <-> R_3(z) we can infer Q(b_3) <-> R_3(b_3). From Q(b_3) <-> R_3(b_3) we can infer Q(b_3) -> R_3(b_3). Finally, from u -> R_3(b_3), Q(b_3) -> R_3(b_3), u or Q(b_3) we can infer R_3(b_3). Therefore, the answer is yes.