Find $r$ if $3(r-5)=24$.
To solve for $r$, I need to isolate it on one side of the equation by using inverse operations. First, I will undo the multiplication by 3 by dividing both sides by 3. That gives me $r-5=8$. Next, I will undo the subtraction by 5 by adding 5 to both sides. That gives me $r=13$. To check my answer, I can plug it back into the original equation and see if it makes it true. I get $3(13-5)=24$, which simplifies to $3(8)=24$, which is true. So $r=13$ is the correct answer.

