Translate the following inference to logic notation: There is at least one x for which x_6 is not poor. For all x, x_6 will climb a mountain if and only if x_6 is a carpenter. For all x, x_6 is poor if and only if x_6 will climb a mountain. Therefore there is at least one x for which x_6 is not a carpenter.
exists x: ~P(x). forall x: Q(x) <-> R(x). forall x: P(x) <-> Q(x). Therefore exists x: ~R(x).