Consider the following premises. forall x_11: R_11(x_11) <-> S_11(x_11). q -> R_11(a_11). ~S_11(a_11). Can we infer ~q from them?
 From forall x_11: R_11(x_11) <-> S_11(x_11) we can infer R_11(a_11) <-> S_11(a_11). From R_11(a_11) <-> S_11(a_11), ~S_11(a_11) we can infer ~R_11(a_11). Finally, from q -> R_11(a_11), ~R_11(a_11) we can infer ~q. Therefore, the answer is yes.