Translate the following inference to logic notation: For all x, if x_6 were bored, then x_6 is taking a plane. For all x, x_6 is bored or x_6 is not a sailor. There is at least one x for which if x_6 takes a plane, then x_6 is reading a book. Therefore there is at least one x for which if x_6 were a sailor, then x_6 is reading a book.
forall x: P(x) -> Q(x). forall x: P(x) or ~R(x). exists x: Q(x) -> S(x). Therefore exists x: R(x) -> S(x).