Consider the following premises. exists x_3: R(x_3) <-> T(x_3). forall x_3: T(x_3) or ~R(x_3). Can we infer exists x_3: R(x_3) -> T(x_3) from them?
 From exists x_3: R(x_3) <-> T(x_3) we can infer exists x_3: T(x_3) -> R(x_3). From forall x_3: T(x_3) or ~R(x_3) we can infer forall x_3: R(x_3) -> T(x_3). From forall x_3: R(x_3) -> T(x_3), exists x_3: T(x_3) -> R(x_3) we can infer exists x_3: R(x_3) <-> T(x_3). Finally, from exists x_3: R(x_3) <-> T(x_3) we can infer exists x_3: R(x_3) -> T(x_3). Therefore, the answer is yes.