Consider the following premises. s -> R_10(a_10). S_10(a_10) -> s. forall x_10: R_10(x_10) -> S_10(x_10). Can we infer R_10(a_10) <-> s from them?
 From forall x_10: R_10(x_10) -> S_10(x_10) we can infer R_10(a_10) -> S_10(a_10). From R_10(a_10) -> S_10(a_10), S_10(a_10) -> s we can infer R_10(a_10) -> s. Finally, from R_10(a_10) -> s, s -> R_10(a_10) we can infer R_10(a_10) <-> s. Therefore, the answer is yes.