Translate the following inference to logic notation: There is at least one x for which x_5 will not make tea or x_5 will write a letter. For all x, if x_5 were a doctor, then x_5 is not driving a car. For all x, x_5 will drive a car. For all x, x_5 will make tea or x_5 is a doctor. Therefore there is at least one x for which x_5 will write a letter.
exists x: ~P(x) or Q(x). forall x: R(x) -> ~S(x). forall x: S(x). forall x: P(x) or R(x). Therefore exists x: Q(x).