Translate the following inference to logic notation: For all x, if x_11 takes a plane, then x_11 is excited. For all x, if x_11 were bored, then x_11 is excited. For all x, x_11 is not a scientist or x_11 will take a plane. There is at least one x for which x_11 is a scientist or x_11 is bored. Therefore there is at least one x for which x_11 is excited or x_11 is a mechanic.
forall x: P(x) -> Q(x). forall x: R(x) -> Q(x). forall x: ~S(x) or P(x). exists x: S(x) or R(x). Therefore exists x: Q(x) or T(x).