Translate the following inference to logic notation: For all x, x_8 will work. For all x, if x_8 were an electrician, then x_8 is drinking water. For all x, if x_8 were excited, then x_8 is not working. For all x, if x_8 were excited, then x_8 is an electrician. There is at least one x for which if x_8 drinks water, then x_8 is excited. Therefore there is at least one x for which x_8 is not an electrician.
forall x: P(x). forall x: Q(x) -> R(x). forall x: S(x) -> ~P(x). forall x: S(x) -> Q(x). exists x: R(x) -> S(x). Therefore exists x: ~Q(x).