Translate the following inference to logic notation: There is at least one x for which if x_8 makes tea, then x_8 is an office clerk. For all x, x_8 will take a plane if and only if x_8 will make tea. For all x, if x_8 were an office clerk, then x_8 is taking a plane. Therefore there is at least one x for which x_8 will take a plane if and only if x_8 is an office clerk.
exists x: P(x) -> Q(x). forall x: R(x) <-> P(x). forall x: Q(x) -> R(x). Therefore exists x: R(x) <-> Q(x).