Let $t(x) = 3x-8$ and $s(t(x)) = x^2 + 3x - 2$.  Find $s(1)$.
To find $s(1)$, I need to figure out what value of $x$ makes $t(x) = 1$. I can do this by solving for $x$ in the equation $t(x) = 1$. This gives me $3x-8 = 1$, or $x = 3$. So $s(1) = s(t(3))$. Now I can plug in $x = 3$ into the expression for $s(t(x))$. This gives me $s(t(3)) = (3)^2 + 3(3) - 2$. I can simplify this by applying the order of operations. This gives me $s(t(3)) = 9 + 9 - 2 = 16$. 