Translate the following inference to logic notation: For all x, if x_12 were an artist, then x_12 is playing squash. For all x, if x_12 climbs a mountain, then x_12 is an artist. There is at least one x for which if x_12 works, then x_12 is playing squash. For all x, x_12 will not work. For all x, if x_12 plays squash, then x_12 is climbing a mountain. For all x, if x_12 plays squash, then x_12 is working. Therefore there is at least one x for which x_12 is not an artist.
forall x: P(x) -> Q(x). forall x: R(x) -> P(x). exists x: S(x) -> Q(x). forall x: ~S(x). forall x: Q(x) -> R(x). forall x: Q(x) -> S(x). Therefore exists x: ~P(x).