Consider the following premises. forall x_7: R_7(x_7) <-> S_7(x_7). R_7(h) <-> q. ~S_7(h). Can we infer q from them?
 From forall x_7: R_7(x_7) <-> S_7(x_7) we can infer R_7(h) <-> S_7(h). From R_7(h) <-> S_7(h), ~S_7(h) we can infer ~R_7(h). Finally, from R_7(h) <-> q, ~R_7(h) we can infer ~q, which contradicts q. Therefore, the answer is no.