Find $r$ if $3(r-7) = 4(2-2r) + 4$.
To find $r$, I need to isolate it on one side of the equation by using inverse operations. First, I will distribute the 3 and the 4 on both sides to get rid of the parentheses: $3r - 21 = 8 - 8r + 4$. Next, I will simplify the right side by combining the constants: $3r - 21 = 12 - 8r$. Then, I will add 8r to both sides to get all the terms with $r$ on one side: $11r - 21 = 12$. After that, I will add 21 to both sides to get rid of the constant term on the left: $11r = 33$. Finally, I will divide both sides by 11 to get $r$ by itself: $r = 3$. 