Translate the following inference to logic notation: There is at least one x for which if x_6 were a police officer, then x_6 is an artist. For all x, if x_6 were an artist, then x_6 is happy. For all x, if x_6 were happy, then x_6 is running. For all x, if x_6 goes running, then x_6 is an artist. Therefore there is at least one x for which if x_6 were a police officer, then x_6 is happy.
exists x: P(x) -> Q(x). forall x: Q(x) -> R(x). forall x: R(x) -> S(x). forall x: S(x) -> Q(x). Therefore exists x: P(x) -> R(x).