Consider the following premises. Q_13(i_1) -> R_10(c). forall x_13: Q_13(x_13) -> Q(x_13). forall x_13: Q(x_13) -> Q_13(x_13). forall x_10: ~R_10(x_10). Can we infer Q(i_1) from them?
 From forall x_13: Q(x_13) -> Q_13(x_13), forall x_13: Q_13(x_13) -> Q(x_13) we can infer forall x_13: Q(x_13) <-> Q_13(x_13). From forall x_13: Q(x_13) <-> Q_13(x_13) we can infer Q(i_1) <-> Q_13(i_1). From forall x_10: ~R_10(x_10) we can infer ~R_10(c). From Q_13(i_1) -> R_10(c), ~R_10(c) we can infer ~Q_13(i_1). Finally, from Q(i_1) <-> Q_13(i_1), ~Q_13(i_1) we can infer ~Q(i_1), which contradicts Q(i_1). Therefore, the answer is no.