Consider the following premises. forall x_8: Q(x_8) -> Q_8(x_8). forall x_8: R(x_8) <-> Q_8(x_8). forall x_8: R(x_8) -> Q(x_8). Can we infer forall x_8: Q(x_8) -> Q_8(x_8) from them?
That is one of the premises. Therefore, the answer is yes.