A box contains 5 apples, 7 oranges, and 4 pears. You take out two fruits at random without replacement. What is the probability that you get one apple and one orange?
The probability of getting one apple and one orange is 35/120 or 7/24.

Here's the reasoning:

1. First, we need to find the total number of ways to pick two fruits from the box. This can be calculated using combinations: C(16, 2) = 16!/(14! * 2!) = 120 possible pairs of fruits.
2. Next, we need to find the number of ways to pick one apple and one orange. This can also be calculated using combinations: C(5, 1) * C(7, 1) = 5!/(4! * 1!) * 7!/(6! * 1!) = 35 possible pairs of one apple and one orange.
3. Finally, to find the probability, we divide the number of successful outcomes (one apple and one orange) by the total number of possible outcomes: 35/120 = 7/24.