Consider the following premises. r or P_13(a_10). r <-> Q_13(a_10). forall x_13: P_13(x_13) <-> Q_13(x_13). Can we infer Q_13(a_10) from them?
 From forall x_13: P_13(x_13) <-> Q_13(x_13) we can infer forall x_13: P_13(x_13) -> Q_13(x_13). From forall x_13: P_13(x_13) -> Q_13(x_13) we can infer P_13(a_10) -> Q_13(a_10). From r <-> Q_13(a_10) we can infer r -> Q_13(a_10). Finally, from r -> Q_13(a_10), P_13(a_10) -> Q_13(a_10), r or P_13(a_10) we can infer Q_13(a_10). Therefore, the answer is yes.