Consider the following premises. forall x_19: P_19(x_19) and Q_19(x_19). forall x_19: T_2(x_19) -> Q_6(x_19). forall x_19: P_11(x_19) <-> Q_6(x_19). exists x_19: P_11(x_19) -> ~P_19(x_19). Can we infer forall x_19: T_2(x_19) from them?
 From forall x_19: P_19(x_19) and Q_19(x_19) we can infer forall x_19: P_19(x_19). From exists x_19: P_11(x_19) -> ~P_19(x_19), forall x_19: P_19(x_19) we can infer exists x_19: ~P_11(x_19). From forall x_19: P_11(x_19) <-> Q_6(x_19), exists x_19: ~P_11(x_19) we can infer exists x_19: ~Q_6(x_19). Finally, from forall x_19: T_2(x_19) -> Q_6(x_19), exists x_19: ~Q_6(x_19) we can infer exists x_19: ~T_2(x_19), which contradicts forall x_19: T_2(x_19). Therefore, the answer is no.