Consider the following premises. forall x_14: R_14(x_14) -> S_14(x_14). u. R_14(a_14) or r_2. r_2 -> S_14(a_14). Can we infer ~S_14(a_14) from them?
 From forall x_14: R_14(x_14) -> S_14(x_14) we can infer R_14(a_14) -> S_14(a_14). Finally, from R_14(a_14) -> S_14(a_14), r_2 -> S_14(a_14), R_14(a_14) or r_2 we can infer S_14(a_14), which contradicts ~S_14(a_14). Therefore, the answer is no.