Translate the following inference to logic notation: For all x, if x_8 were a police officer, then x_8 is an electrician. For all x, if x_8 sleeps, then x_8 is sad. There is at least one x for which if x_8 were sad, then x_8 is a police officer. For all x, if x_8 were an electrician, then x_8 is sleeping. Therefore there is at least one x for which if x_8 sleeps, then x_8 is a police officer.
forall x: P(x) -> Q(x). forall x: R(x) -> S(x). exists x: S(x) -> P(x). forall x: Q(x) -> R(x). Therefore exists x: R(x) -> P(x).