Consider the following premises. forall x_4: Q_1(x_4) or Q(x_4). forall x_4: Q_1(x_4) -> ~Q_4(x_4). exists x_4: Q_4(x_4). Can we infer forall x_4: Q_1(x_4) or Q(x_4) from them?
That is one of the premises. Therefore, the answer is yes.