How many vertical asymptotes does the graph of $y=\frac{2}{x^2+x-6}$ have?
To find the vertical asymptotes of a rational function, I need to factor the denominator and see where it equals zero. The denominator $x^2+x-6$ can be factored as $(x+3)(x-2)$. So the denominator equals zero when $x=-3$ or $x=2$. These are the two values of $x$ that make the fraction undefined, so they are the vertical asymptotes of the graph. Therefore, the graph has two vertical asymptotes. 