Consider the following premises. forall z: W(z) -> Q(z). forall z: Q(z) -> S(z). forall z: S(z) -> Q(z). forall z: S(z) -> R(z). Can we infer forall z: W(z) -> R(z) from them?
 From forall z: S(z) -> Q(z), forall z: Q(z) -> S(z) we can infer forall z: S(z) <-> Q(z). From forall z: S(z) <-> Q(z) we can infer forall z: Q(z) -> S(z). From forall z: Q(z) -> S(z), forall z: S(z) -> R(z) we can infer forall z: Q(z) -> R(z). Finally, from forall z: W(z) -> Q(z), forall z: Q(z) -> R(z) we can infer forall z: W(z) -> R(z). Therefore, the answer is yes.