Translate the following inference to logic notation: There is at least one x for which if x_11 were a writer, then x_11 is an office clerk. For all x, x_11 is a writer if and only if x_11 will drink water. For all x, if x_11 were an office clerk, then x_11 is drinking water. Therefore there is at least one x for which if x_11 were a writer, then x_11 is drinking water.
exists x: P(x) -> Q(x). forall x: P(x) <-> R(x). forall x: Q(x) -> R(x). Therefore exists x: P(x) -> R(x).