Translate the following inference to logic notation: There is at least one x for which x_9 will play squash if and only if x_9 is a scientist. For all x, if x_9 were a server, then x_9 is playing squash. For all x, if x_9 were a scientist, then x_9 is playing a game. Therefore there is at least one x for which if x_9 were a server, then x_9 is playing a game.
exists x: P(x) <-> Q(x). forall x: R(x) -> P(x). forall x: Q(x) -> S(x). Therefore exists x: R(x) -> S(x).