Consider the following premises. R_10(b_1) <-> S_12(a_12). forall x_12: R(x_12) <-> S_12(x_12). forall x_10: ~R_10(x_10). Can we infer R(a_12) from them?
 From forall x_12: R(x_12) <-> S_12(x_12) we can infer R(a_12) <-> S_12(a_12). From forall x_10: ~R_10(x_10) we can infer ~R_10(b_1). From R_10(b_1) <-> S_12(a_12), ~R_10(b_1) we can infer ~S_12(a_12). Finally, from R(a_12) <-> S_12(a_12), ~S_12(a_12) we can infer ~R(a_12), which contradicts R(a_12). Therefore, the answer is no.