Consider the following premises. forall z_3: S_3(z_3). exists z_3: T(z_3) <-> R(z_3). forall z_3: W_2(z_3). forall z_3: R(z_3) -> ~S_3(z_3). Can we infer forall z_3: T(z_3) from them?
 From forall z_3: S_3(z_3), forall z_3: W_2(z_3) we can infer forall z_3: S_3(z_3) and W_2(z_3). From forall z_3: S_3(z_3) and W_2(z_3) we can infer forall z_3: S_3(z_3). From forall z_3: R(z_3) -> ~S_3(z_3), forall z_3: S_3(z_3) we can infer forall z_3: ~R(z_3). Finally, from exists z_3: T(z_3) <-> R(z_3), forall z_3: ~R(z_3) we can infer exists z_3: ~T(z_3), which contradicts forall z_3: T(z_3). Therefore, the answer is no.