Consider the following premises. exists x_9: T(x_9) -> Q_9(x_9). forall x_9: U_3(x_9) -> T(x_9). forall x_9: R(x_9) <-> Q_9(x_9). Can we infer forall x_9: ~(U_3(x_9) -> R(x_9)) from them?
That contradicts the premises. Therefore the answer is no.