Consider the following premises. exists x_9: ~P_6(x_9). forall x_9: U(x_9) -> R(x_9). forall x_9: R(x_9) -> U(x_9). forall x_9: P_6(x_9) <-> U(x_9). Can we infer forall x_9: R(x_9) from them?
 From forall x_9: R(x_9) -> U(x_9), forall x_9: U(x_9) -> R(x_9) we can infer forall x_9: R(x_9) <-> U(x_9). From forall x_9: P_6(x_9) <-> U(x_9), exists x_9: ~P_6(x_9) we can infer exists x_9: ~U(x_9). Finally, from forall x_9: R(x_9) <-> U(x_9), exists x_9: ~U(x_9) we can infer exists x_9: ~R(x_9), which contradicts forall x_9: R(x_9). Therefore, the answer is no.