A coin is flipped 10 times and the sequence of heads and tails is observed. What is the number of possible 10-tuplets that result in four heads and six tails?
A coin is flipped 10 times and the sequence of heads and tails is observed. The number of possible 10-tuplets that result in four heads and six tails is
$$
\left(\begin{array}{c}
10 \\
4
\end{array}\right)=\frac{10 !}{4 ! 6 !}=\frac{10 !}{6 ! 4 !}=\left(\begin{array}{c}
10 \\
6
\end{array}\right)=210 .
$$
