If you roll a fair six-sided die twice, what is the probability that the sum of the numbers rolled will be equal to 8?
When rolling a fair six-sided die, there are six possible outcomes for each roll (1, 2, 3, 4, 5, or 6). For two rolls, there are a total of 6^2 = 36 possible outcomes.

Now we need to determine the number of outcomes where the sum of the numbers rolled is equal to 8. These are:

(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)

There are 5 favorable outcomes with a sum of 8. To find the probability of getting a sum of 8 when rolling a fair six-sided die twice, divide the number of favorable outcomes by the total number of possible outcomes:

Probability = Favorable outcomes / Total outcomes
                   = 5 / 36

So, the probability of getting a sum of 8 when rolling a fair six-sided die twice is 5/36.