Consider the following premises. exists y: ~S(y). forall y: S(y) <-> W(y). forall y: T(y) -> W(y). Can we infer forall y: T(y) from them?
 From forall y: S(y) <-> W(y) we can infer forall y: W(y) -> S(y). From forall y: T(y) -> W(y), forall y: W(y) -> S(y) we can infer forall y: T(y) -> S(y). Finally, from forall y: T(y) -> S(y), exists y: ~S(y) we can infer exists y: ~T(y), which contradicts forall y: T(y). Therefore, the answer is no.