Translate the following inference to logic notation: For all x, x_6 is a scientist or x_6 will play tennis. For all x, x_6 is an electrician or x_6 is not a scientist. There is at least one x for which x_6 will drive a car. For all x, if x_6 plays tennis, then x_6 is an electrician. Therefore there is at least one x for which x_6 is an electrician and x_6 will drive a car.
forall x: P(x) or Q(x). forall x: R(x) or ~P(x). exists x: S(x). forall x: Q(x) -> R(x). Therefore exists x: R(x) and S(x).