The value of $\log_{10}{17}$ is between the consecutive integers $a$ and $b$.  Find $a+b$.
I know that $\log_{10}{10}=1$ and $\log_{10}{100}=2$, so $\log_{10}{17}$ must be between 1 and 2, since 17 is between 10 and 100. Therefore, $a=1$ and $b=2$, and $a+b=3$. 