Solve for $r$ in the equation $19-3=2+r$.
To solve for $r$, I need to isolate it on one side of the equation by using inverse operations. First, I can simplify the left side by subtracting 19 and 3, which gives me 16. So the equation becomes $16=2+r$. Next, I can subtract 2 from both sides to eliminate it from the right side. This gives me $14=r$. This is the same as $r=14$, which is the solution.

