Translate the following inference to logic notation: For all x, y is an electrician if and only if y is a carpenter. There is at least one x for which if y were an electrician, then y is not a soldier. For all x, y is a soldier. Therefore there is at least one x for which y is not a carpenter.
forall x: P(x) <-> Q(x). exists x: P(x) -> ~R(x). forall x: R(x). Therefore exists x: ~Q(x).