Consider the following premises. forall x_11: Q_3(x_11). forall x_11: Q_11(x_11) or Q_7(x_11). forall x_11: Q_7(x_11) -> P_3(x_11). forall x_11: P_3(x_11) <-> Q_11(x_11). Can we infer Q_3(a_2) from them?
 From forall x_11: P_3(x_11) <-> Q_11(x_11) we can infer forall x_11: Q_11(x_11) -> P_3(x_11). From forall x_11: Q_11(x_11) -> P_3(x_11), forall x_11: Q_7(x_11) -> P_3(x_11), forall x_11: Q_11(x_11) or Q_7(x_11) we can infer forall x_11: P_3(x_11). From forall x_11: P_3(x_11), forall x_11: Q_3(x_11) we can infer forall x_11: P_3(x_11) and Q_3(x_11). From forall x_11: P_3(x_11) and Q_3(x_11) we can infer P_3(a_2) and Q_3(a_2). Finally, from P_3(a_2) and Q_3(a_2) we can infer Q_3(a_2). Therefore, the answer is yes.