Translate the following inference to logic notation: There is at least one x for which if x_16 were bored, then x_16 is driving a car. For all x, x_16 will drive a car. For all x, if x_16 drives a car, then x_16 is bored. Therefore there is at least one x for which x_16 is bored or x_16 is excited.
exists x: P(x) -> Q(x). forall x: Q(x). forall x: Q(x) -> P(x). Therefore exists x: P(x) or R(x).