Translate the following inference to logic notation: There is at least one x for which y will write a letter. For all x, y will drive a car. For all x, if y writes a letter, then y is a mechanic. Therefore there is at least one x for which y is a mechanic and y will drive a car.
exists x: P(x). forall x: Q(x). forall x: P(x) -> R(x). Therefore exists x: R(x) and Q(x).