Expand the product ${4(x-5)(x+8)}$.
To expand a product of three factors, I can use the distributive property twice. First, I'll distribute the 4 to the other two factors: ${4(x-5)(x+8) = 4x(x+8) - 20(x+8)}$. Then, I'll distribute the 4x and the -20 to the terms inside the parentheses: ${4x(x+8) - 20(x+8) = 4x^2 + 32x - 20x - 160}$. Finally, I'll simplify the expression by combining like terms: ${4x^2 + 32x - 20x - 160 = 4x^2 + 12x - 160}$. 