Consider the following premises. p -> R(a_5). forall x_11: R(x_11) <-> P_11(x_11). forall x_11: P_11(x_11) -> ~Q_11(x_11). forall x_11: Q_11(x_11). Can we infer ~p from them?
 From forall x_11: P_11(x_11) -> ~Q_11(x_11), forall x_11: Q_11(x_11) we can infer forall x_11: ~P_11(x_11). From forall x_11: R(x_11) <-> P_11(x_11), forall x_11: ~P_11(x_11) we can infer forall x_11: ~R(x_11). From forall x_11: ~R(x_11) we can infer ~R(a_5). Finally, from p -> R(a_5), ~R(a_5) we can infer ~p. Therefore, the answer is yes.