Consider the following premises. forall x_1: W(x_1) -> Q_1(x_1). forall x_1: Q_1(x_1) -> T(x_1). forall x_1: Q_4(x_1) -> W(x_1). Can we infer exists x_1: ~(Q_4(x_1) -> T(x_1)) from them?
 From forall x_1: W(x_1) -> Q_1(x_1), forall x_1: Q_1(x_1) -> T(x_1) we can infer forall x_1: W(x_1) -> T(x_1). Finally, from forall x_1: Q_4(x_1) -> W(x_1), forall x_1: W(x_1) -> T(x_1) we can infer forall x_1: Q_4(x_1) -> T(x_1), which contradicts exists x_1: ~(Q_4(x_1) -> T(x_1)). Therefore, the answer is no.