Consider the following premises. q_3 or ~R(e). forall x: R(x) <-> Q_2(x). Can we infer Q_2(e) -> q_3 from them?
 From forall x: R(x) <-> Q_2(x) we can infer forall x: Q_2(x) -> R(x). From forall x: Q_2(x) -> R(x) we can infer Q_2(e) -> R(e). From q_3 or ~R(e) we can infer R(e) -> q_3. Finally, from Q_2(e) -> R(e), R(e) -> q_3 we can infer Q_2(e) -> q_3. Therefore, the answer is yes.