Consider the following premises. p -> S_1(b_3). forall x_8: Q_8(x_8) -> S_1(x_8). ~Q_8(b_3). forall x_8: S_1(x_8) -> Q_8(x_8). Can we infer ~p from them?
 From forall x_8: S_1(x_8) -> Q_8(x_8), forall x_8: Q_8(x_8) -> S_1(x_8) we can infer forall x_8: S_1(x_8) <-> Q_8(x_8). From forall x_8: S_1(x_8) <-> Q_8(x_8) we can infer S_1(b_3) <-> Q_8(b_3). From S_1(b_3) <-> Q_8(b_3), ~Q_8(b_3) we can infer ~S_1(b_3). Finally, from p -> S_1(b_3), ~S_1(b_3) we can infer ~p. Therefore, the answer is yes.