Consider the following premises. exists x_10: Q_10(x_10) -> R_10(x_10). forall x_10: P_7(x_10) <-> P(x_10). forall x_10: S(x_10) -> P_7(x_10). forall x_10: P(x_10) -> Q_10(x_10). Can we infer forall x_10: ~(S(x_10) -> R_10(x_10)) from them?
That contradicts the premises. Therefore the answer is no.