Consider the following premises. exists x_6: P_6(x_6) and Q_6(x_6). forall x_6: T_1(x_6) -> ~P_6(x_6). Can we infer exists x_6: ~T_1(x_6) from them?
 From exists x_6: P_6(x_6) and Q_6(x_6) we can infer exists x_6: P_6(x_6). Finally, from forall x_6: T_1(x_6) -> ~P_6(x_6), exists x_6: P_6(x_6) we can infer exists x_6: ~T_1(x_6). Therefore, the answer is yes.