Consider the following premises. forall x_6: Q_6(x_6) -> R_6(x_6). forall x_6: T(x_6) -> Q_6(x_6). ~R_6(a_5). Can we infer T(a_5) from them?
 From forall x_6: T(x_6) -> Q_6(x_6), forall x_6: Q_6(x_6) -> R_6(x_6) we can infer forall x_6: T(x_6) -> R_6(x_6). From forall x_6: T(x_6) -> R_6(x_6) we can infer T(a_5) -> R_6(a_5). Finally, from T(a_5) -> R_6(a_5), ~R_6(a_5) we can infer ~T(a_5), which contradicts T(a_5). Therefore, the answer is no.