Consider the following premises. forall x_6: Q_6(x_6) -> R_6(x_6). exists x_6: S_4(x_6). forall x_6: P_6(x_6) or Q_6(x_6). forall x_6: P_6(x_6) -> R_6(x_6). Can we infer exists x_6: S_4(x_6) from them?
That is one of the premises. Therefore, the answer is yes.