Translate the following inference to logic notation: For all x, x_7 will work or x_7 will not drive a car. There is at least one x for which x_7 will drive a car or x_7 will not climb a mountain. Therefore there is at least one x for which if x_7 climbs a mountain, then x_7 is working.
forall x: P(x) or ~Q(x). exists x: Q(x) or ~R(x). Therefore exists x: R(x) -> P(x).