Consider the following premises. forall x_14: T(x_14) -> S(x_14). exists x_14: Q_11(x_14) or P_14(x_14). forall x_14: P_14(x_14) -> Q_14(x_14). forall x_14: T(x_14) or ~Q_11(x_14). forall x_14: Q_14(x_14) -> T(x_14). Can we infer forall x_14: ~S(x_14) from them?
 From forall x_14: P_14(x_14) -> Q_14(x_14), forall x_14: Q_14(x_14) -> T(x_14) we can infer forall x_14: P_14(x_14) -> T(x_14). From forall x_14: T(x_14) or ~Q_11(x_14) we can infer forall x_14: Q_11(x_14) -> T(x_14). From forall x_14: Q_11(x_14) -> T(x_14), forall x_14: P_14(x_14) -> T(x_14), exists x_14: Q_11(x_14) or P_14(x_14) we can infer exists x_14: T(x_14). Finally, from forall x_14: T(x_14) -> S(x_14), exists x_14: T(x_14) we can infer exists x_14: S(x_14), which contradicts forall x_14: ~S(x_14). Therefore, the answer is no.