Translate the following inference to logic notation: There is at least one x for which if x_6 plays tennis, then x_6 is an office clerk. For all x, if x_6 listens to a song, then x_6 is climbing a mountain. For all x, x_6 will listen to a song or x_6 is not an office clerk. Therefore there is at least one x for which if x_6 plays tennis, then x_6 is climbing a mountain.
exists x: P(x) -> Q(x). forall x: R(x) -> S(x). forall x: R(x) or ~Q(x). Therefore exists x: P(x) -> S(x).