Consider the following premises. s -> Q_2(f). forall x_4: S(x_4) <-> T(x_4). forall x_4: S(x_4) -> Q_2(x_4). forall x_4: ~T(x_4). forall x_4: Q_2(x_4) -> S(x_4). Can we infer q from them?
We cannot infer that from the premises. Therefore the answer is no.