Translate the following inference to logic notation: For all x, if x_6 makes tea, then x_6 is not climbing a mountain. For all x, x_6 will make tea if and only if x_6 will play squash. For all x, x_6 will climb a mountain. Therefore for all x, x_6 will not play squash.
forall x: P(x) -> ~Q(x). forall x: P(x) <-> R(x). forall x: Q(x). Therefore forall x: ~R(x).