The value of $\log_{10}{579}$ is between the consecutive integers $a$ and $b$.  Find $a+b$.
I know that $\log_{10}{10} = 1$, $\log_{10}{100} = 2$, and $\log_{10}{1000} = 3$. So, $\log_{10}{579}$ must be between $2$ and $3$, since $579$ is between $100$ and $1000$. That means $a = 2$ and $b = 3$. Therefore, $a+b = 2+3 = 5$. 