Translate the following inference to logic notation: There is at least one x for which if y were happy, then y is reading a book. For all x, if y were a police officer, then y is happy. For all x, if y reads a book, then y is a police officer. Therefore there is at least one x for which if y were a police officer, then y is reading a book.
exists x: P(x) -> Q(x). forall x: R(x) -> P(x). forall x: Q(x) -> R(x). Therefore exists x: R(x) -> Q(x).