Consider the following premises. t -> ~R_13(a_9). forall x_15: ~P_15(x_15) or R_15(x_15). forall x_15: R_15(x_15) -> R_13(x_15). forall x_15: P_15(x_15) or Q_15(x_15). forall x_15: Q_15(x_15) -> R_13(x_15). Can we infer t from them?
 From forall x_15: P_15(x_15) or Q_15(x_15), forall x_15: ~P_15(x_15) or R_15(x_15) we can infer forall x_15: Q_15(x_15) or R_15(x_15). From forall x_15: Q_15(x_15) -> R_13(x_15), forall x_15: R_15(x_15) -> R_13(x_15), forall x_15: Q_15(x_15) or R_15(x_15) we can infer forall x_15: R_13(x_15). From forall x_15: R_13(x_15) we can infer R_13(a_9). Finally, from t -> ~R_13(a_9), R_13(a_9) we can infer ~t, which contradicts t. Therefore, the answer is no.