Translate the following inference to logic notation: There is at least one x for which if x were a bartender, then x is driving a car. For all x, if x were a nurse, then x is a bartender. For all x, x will drive a car if and only if x is a nurse. Therefore there is at least one x for which x will drive a car if and only if x is a nurse.
exists x: P(x) -> Q(x). forall x: R(x) -> P(x). forall x: Q(x) <-> R(x). Therefore exists x: Q(x) <-> R(x).