Translate the following inference to logic notation: There is at least one x for which x_8 will drive a car or x_8 will not play a game. For all x, x_8 will drive a car if and only if x_8 will play a game. Therefore there is at least one x for which x_8 will drive a car if and only if x_8 will play a game.
exists x: P(x) or ~Q(x). forall x: P(x) <-> Q(x). Therefore exists x: P(x) <-> Q(x).