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This reaction involves a base (NaOH) and an acid (HCl), so it's a neutralization reaction, which is a special type of double-displacement reaction. Follow this procedure to write balanced molecular equations for double displacement reactions, when you know only the formulas of the reactants:
Stage 2 Methyl orange results 6. The equation for the second stage of the reaction between sodium carbonate and hydrochloric acid is shown below again: NaHCO 3 (aq) + HCl(aq) â NaCl(aq) + CO 2 (g) + H 2 O(l) From the equation, you can see that 1 mole of NaHCO 3 will react with 1 mole of HCl.tage 2 Methyl orange results 6. The equation for the second stage of the reaction between sodium carbonate and hydrochloric acid is shown below again: NaHCO 3 (aq) + HCl(aq) â NaCl(aq) + CO 2 (g) + H 2 O(l) From the equation, you can see that 1 mole of NaHCO 3 will react with 1 mole of HCl.