Convert.ToInt32 rounds to the nearest even number?
Looking at the msdn documentation for `Convert.ToInt32()` it states:

> If value is halfway between two whole numbers, the even number is
> returned; that is, 4.5 is converted to 4, and 5.5 is converted to 6.

http://msdn.microsoft.com/en-us/library/ffdk7eyz.aspx

Why is this? Surely it would be more logical to round to the nearest whole number? Therefore 4.5 would become 5, and 5.5 would become 6.
Convert.ToInt32 rounds to the nearest even number?
===

Looking at the msdn documentation for `Convert.ToInt32()` it states:

> If value is halfway between two whole numbers, the even number is
> returned; that is, 4.5 is converted to 4, and 5.5 is converted to 6.

http://msdn.microsoft.com/en-us/library/ffdk7eyz.aspx

Why is this? Surely it would be more logical to round to the nearest whole number? Therefore 4.5 would become 5, and 5.5 would become 6.