displaying all records in separate div
Ok. I have this code.

    <?php
    
    $con = mysql_connect("localhost","root","");
    if (!$con)
    {
    die('Could not connect: ' . mysql_error());
    }
    
    mysql_select_db("juliver", $con);
    
    $result = mysql_query("SELECT * FROM items");
    
    while($row = mysql_fetch_array($result))
    {
    $ss = "<div>";
    $ss. = '<img src="'.$row['name'].'" />';  
    $ss. $row['title'];
    $ss. $row['description'];
    $ss. $row['link'];
    $ss. = "</div>";
    }

    mysql_close($con);
    ?>
    <html>
    <head>
    <style type="text/css">
    body{background:gray;}
    div{border:1px solid red;}
    </style>
    </head>
    <body>
    <? echo $ss; ?>
    </body>
    </html>

But i get an error

Parse error: syntax error, unexpected '=' in C:\xampp\htdocs\madeinusa\hi.php on line   83

I just want to display all records with separate dev.
displaying all records in separate div
===

Ok. I have this code.

    <?php
    
    $con = mysql_connect("localhost","root","");
    if (!$con)
    {
    die('Could not connect: ' . mysql_error());
    }
    
    mysql_select_db("juliver", $con);
    
    $result = mysql_query("SELECT * FROM items");
    
    while($row = mysql_fetch_array($result))
    {
    $ss = "<div>";
    $ss. = '<img src="'.$row['name'].'" />';  
    $ss. $row['title'];
    $ss. $row['description'];
    $ss. $row['link'];
    $ss. = "</div>";
    }

    mysql_close($con);
    ?>
    <html>
    <head>
    <style type="text/css">
    body{background:gray;}
    div{border:1px solid red;}
    </style>
    </head>
    <body>
    <? echo $ss; ?>
    </body>
    </html>

But i get an error

Parse error: syntax error, unexpected '=' in C:\xampp\htdocs\madeinusa\hi.php on line   83

I just want to display all records with separate dev.