call jQuery twice 
I want to use jQuery code inside content(div) is already loaded by jQuery ..
here is my Example code ..

        <!-- Slide Panel with Form Adding data  -->
    <div style="display: none;" id="slideAddForm" >
    <h2>Add Row</h2>
    from here ..
    </div>

    <div class="tabs"> <!-- Tabs -->
        <ul>
            <li><a href="#first"> frist</a></li>
            <li><a  class="secondA" href="#second"> Second </a></li>
            <li><a  class="comments_title" href="#third"> Third </a></li>
        </ul>
    </div>

    <!-- frist tab .. html data -->
    <div id="first">
    <a class="bAddRow" href="#"> Add Row  </a>   <!-- To show slideAddForm div .. it`s work OK  -->
    anything here ..
    </div>

    <!-- second tab and 3rd tab get data from server -->
    <div id="second">
      <!-- load page in this tab  -->
      <script type="text/javascript">
          $(document).ready(function() {
          $("a.secondA").click(function(){
          $("#second").load("server.php");
          });
          });
      </script>
    </div>

    <div id="third"></div>



Now , in server.php I put this :

    <a class="bAddRow" href="#"> Add Row  </a>  <!-- not work !  -->

But it dose not work ..

you can see , in the frist tab the link (Add Row) work fine, but it dose not work in the (#second) tab
because ( I think ) is loaded already by ajax .!

Don`t say put this line  

    <a class="bAddRow" href="#"> Add Row  </a>


after 

    <div id="second">

and before javascript code .. because this is a simple code to clear my problem ..
my really code is complicated .. and I have to put ( for expamle ) this line (add Row link) in the Server.php and I want it to show slideAddForm div 

Any help ?
Thanks in advance ..
Ahmad ..
call jQuery twice 
===

I want to use jQuery code inside content(div) is already loaded by jQuery ..
here is my Example code ..

        <!-- Slide Panel with Form Adding data  -->
    <div style="display: none;" id="slideAddForm" >
    <h2>Add Row</h2>
    from here ..
    </div>

    <div class="tabs"> <!-- Tabs -->
        <ul>
            <li><a href="#first"> frist</a></li>
            <li><a  class="secondA" href="#second"> Second </a></li>
            <li><a  class="comments_title" href="#third"> Third </a></li>
        </ul>
    </div>

    <!-- frist tab .. html data -->
    <div id="first">
    <a class="bAddRow" href="#"> Add Row  </a>   <!-- To show slideAddForm div .. it`s work OK  -->
    anything here ..
    </div>

    <!-- second tab and 3rd tab get data from server -->
    <div id="second">
      <!-- load page in this tab  -->
      <script type="text/javascript">
          $(document).ready(function() {
          $("a.secondA").click(function(){
          $("#second").load("server.php");
          });
          });
      </script>
    </div>

    <div id="third"></div>



Now , in server.php I put this :

    <a class="bAddRow" href="#"> Add Row  </a>  <!-- not work !  -->

But it dose not work ..

you can see , in the frist tab the link (Add Row) work fine, but it dose not work in the (#second) tab
because ( I think ) is loaded already by ajax .!

Don`t say put this line  

    <a class="bAddRow" href="#"> Add Row  </a>


after 

    <div id="second">

and before javascript code .. because this is a simple code to clear my problem ..
my really code is complicated .. and I have to put ( for expamle ) this line (add Row link) in the Server.php and I want it to show slideAddForm div 

Any help ?
Thanks in advance ..
Ahmad ..