Higher Order Function (uncurry,curry)
    enter code here

     uncurry cplus=\(a,b)->cplus a b  
     (cplus a b=a+b   ucplus(a,b)=a+b)

**strong text** As we know,(a,b) is the parameter of the function cplus, so the right side of equation is actually doing the function cplus a b. So why uncurry cplus equal to the right side of the equation?
Higher Order Function (uncurry,curry)
===

    enter code here

     uncurry cplus=\(a,b)->cplus a b  
     (cplus a b=a+b   ucplus(a,b)=a+b)

**strong text** As we know,(a,b) is the parameter of the function cplus, so the right side of equation is actually doing the function cplus a b. So why uncurry cplus equal to the right side of the equation?