Passing Quoted Posix Argument Values in bash
I have a bash script where I'm trying to pass posix style arguments with quoted values down to another script called within. On the command-line I might type:

    somescript --foo="bar baz"

This means with the argument having the key `foo`, the value is `bar baz`. Within somescript, you might think this would work:

    innerscript "$@"

However, this re-quotes the *entirety* of each argument, both key and value chunked together, not just the value. So innerscript receives `"--foo=bar baz"` and believes you are trying to pass the key named `foo=bar baz` with an *empty value*.

It's not good enough to tell bash "re-quote all the passed in arguments". I need to tell bash "re-quote all passed in arguments *exactly how they were quoted before*". Don't change the position of my quotes, bro!

Passing Quoted Posix Argument Values in bash
===

I have a bash script where I'm trying to pass posix style arguments with quoted values down to another script called within. On the command-line I might type:

    somescript --foo="bar baz"

This means with the argument having the key `foo`, the value is `bar baz`. Within somescript, you might think this would work:

    innerscript "$@"

However, this re-quotes the *entirety* of each argument, both key and value chunked together, not just the value. So innerscript receives `"--foo=bar baz"` and believes you are trying to pass the key named `foo=bar baz` with an *empty value*.

It's not good enough to tell bash "re-quote all the passed in arguments". I need to tell bash "re-quote all passed in arguments *exactly how they were quoted before*". Don't change the position of my quotes, bro!
