Escaping strings in Bash using !:q
This works too:<p><pre><code>    % cat /tmp/sh
    var=variables
    x=$(
    cat <<EOT
    This string has 'single' and "double" quotes and can interpolate '$var'
    EOT
    )
    echo $x

    % bash /tmp/sh
    This string has 'single' and "double" quotes and can interpolate 'variables'</code></pre>