When Gravity Breaks Down
As we know, the path of a photon can be bent by a large mass with gravity.<p>Okay:  Pass a photon, or electron, or other particle, through a beam splitter and, thus, get its wave function in two parts.<p>Then the question seems to be, do the parts also get bent by gravity?  Is there any doubt they won&#x27;t.<p>For a particle with mass, surely it has gravity.  So, the two parts of its wave function no longer have gravity -- is that the question she is asking?  Maybe depending on the beam splitter, the two parts of the wave function have 60% and 40% of the gravity of the whole particle?<p>Get a lot of particles, say, neutrons, that do feel and generate gravity and run them through a beam splitter.   Bunch #1 goes north and bunch #2 goes east.  So far they still generate gravity?  Some miles away from the beam splitter we put detectors, one for each bunch.  With a 50%-50% beam splitter, with the law of large numbers, we detect 50% of the particles at each detector.  That is, each detector gets a part of the wave function for ALL the particles but detects only half of the particles.<p>Suppose the detector for bunch #1 is some miles farther from the beam splitter than the detector for bunch #2.  So, the wave functions for bunch #2 hit their detector before the wave functions for bunch #1 hits their detector.<p>Now look at the wave functions for bunch #1:  About half of those wave functions have already collapsed due to detections at the detector for bunch #2.  So, the gravity generated by the remaining wave functions of bunch #1 are, from the law of large numbers, half what they would be without a detector for bunch #2.  So, for bunch #1, we have had faster than speed of light communications from the detector for bunch #2 to a measurement of the gravity of bunch #1.<p>Yes, we can&#x27;t get a gravity detector sensitive enough, but for that theory that&#x27;s not important.  Instead, for the bunches to generate gravity gets to be an issue anyway.