Suppose f(z) and g(z) are polynomials in z, and the degree of g(z) is less than the degree of f(z). If the degree of f(z) is two, what is the degree of f(z)+g(z)?
 
Given polynomials f(z) and g(z), where deg(g(z)) < deg(f(z)) and deg(f(z)) = 2: 

f(z) = a2*z^2 + a1*z + a0 

g(z) = b1*z + b0 

Then, f(z) + g(z) = a2*z^2 + (a1+b1)*z + (a0+b0). 

Therefore, the degree of f(z) + g(z) is 2.
Complete the following task based on the instruction and optional input provided.### Instruction:
Suppose f(z) and g(z) are polynomials in z, and the degree of g(z) is less than the degree of f(z). If the degree of f(z) is two, what is the degree of f(z)+g(z)?

### Output:
 
Given polynomials f(z) and g(z), where deg(g(z)) < deg(f(z)) and deg(f(z)) = 2: 

f(z) = a2*z^2 + a1*z + a0 

g(z) = b1*z + b0 

Then, f(z) + g(z) = a2*z^2 + (a1+b1)*z + (a0+b0). 

Therefore, the degree of f(z) + g(z) is 2.