Three positive integers have a sum of 72 and are in the ratio 1:3:4. What is the least of these three integers?
Let the smallest integer be x. Then the others are 3x and 4x, and the sum of the three is 8x. So x=72/8=9.
Complete the following task based on the instruction and optional input provided.### Instruction:
Three positive integers have a sum of 72 and are in the ratio 1:3:4. What is the least of these three integers?

### Output:
Let the smallest integer be x. Then the others are 3x and 4x, and the sum of the three is 8x. So x=72/8=9.