n towns are arranged in a circle sequentially. The towns are numbered from 1 to n in clockwise order. In the i-th town, there lives a singer with a repertoire of a_i minutes for each i ∈ [1, n].

Each singer visited all n towns in clockwise order, starting with the town he lives in, and gave exactly one concert in each town. In addition, in each town, the i-th singer got inspired and came up with a song that lasts a_i minutes. The song was added to his repertoire so that he could perform it in the rest of the cities.

Hence, for the i-th singer, the concert in the i-th town will last a_i minutes, in the (i + 1)-th town the concert will last 2 ⋅ a_i minutes, ..., in the ((i + k) mod n + 1)-th town the duration of the concert will be (k + 2) ⋅ a_i, ..., in the town ((i + n - 2) mod n + 1) — n ⋅ a_i minutes.

You are given an array of b integer numbers, where b_i is the total duration of concerts in the i-th town. Reconstruct any correct sequence of positive integers a or say that it is impossible.

Input

The first line contains one integer t (1 ≤ t ≤ 10^3) — the number of test cases. Then the test cases follow.

Each test case consists of two lines. The first line contains a single integer n (1 ≤ n ≤ 4 ⋅ 10^4) — the number of cities. The second line contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 10^{9}) — the total duration of concerts in i-th city.

The sum of n over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case, print the answer as follows:

If there is no suitable sequence a, print NO. Otherwise, on the first line print YES, on the next line print the sequence a_1, a_2, ..., a_n of n integers, where a_i (1 ≤ a_i ≤ 10^{9}) is the initial duration of repertoire of the i-th singer. If there are multiple answers, print any of them.

Example

Input


4
3
12 16 14
1
1
3
1 2 3
6
81 75 75 93 93 87


Output


YES
3 1 3 
YES
1 
NO
YES
5 5 4 1 4 5 

Note

Let's consider the 1-st test case of the example:

  1. the 1-st singer in the 1-st city will give a concert for 3 minutes, in the 2-nd — for 6 minutes, in the 3-rd — for 9 minutes; 
  2. the 2-nd singer in the 1-st city will give a concert for 3 minutes, in the 2-nd — for 1 minute, in the 3-rd - for 2 minutes; 
  3. the 3-rd singer in the 1-st city will give a concert for 6 minutes, in the 2-nd — for 9 minutes, in the 3-rd — for 3 minutes. 
import java.util.*;
import java.io.*;
public class Solution {
    static class FastReader {
        BufferedReader br;
        StringTokenizer st;
        public FastReader() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }
        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }
        int nextInt() {
            return Integer.parseInt(next());
        }
        long nextLong() {
            return Long.parseLong(next());
        }
        double nextDouble() {
            return Double.parseDouble(next());
        }
        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }
    static void sort(int a[]){ // int -> long
        ArrayList<Integer> arr=new ArrayList<>(); // Integer -> Long
        for(int i=0;i<a.length;i++)
        arr.add(a[i]);
        Collections.sort(arr);
        for(int i=0;i<a.length;i++)
        a[i]=arr.get(i);
        
    }
    private static long gcd(long a, long b){
        if(b==0)return a;
        return gcd(b,a%b);
    }
    private static long pow(long x,long y){
        if(y==0)return 1;
        long temp = pow(x, y/2);
        if(y%2==1){
            return x*temp*temp;
        }
        else{
            return temp*temp;
        }
    }
    static int log(long n){
        int res = 0;
        while(n>0){
            res++;
            n/=2;
        }
        return res;
    }

    static int mod = (int)1e9+7;
    static PrintWriter out;
    static FastReader sc ;
    public static void main(String[] args) throws IOException {
        sc = new FastReader();
        out = new PrintWriter(System.out);
        // primes();
        // ================================ //
        int test = sc.nextInt();
        while (test-- > 0) {
            int n = sc.nextInt();
            long[]arr =new long[n];
            for(int i=0;i<n;i++){
                arr[i] = sc.nextInt();
            }
            solver(arr, n);
        }
        // ================================ //
        // int n = sc.nextInt();
        // solver();
        // ================================ //
        out.flush();
    }

    public static void solver(long[]arr, int n) {
        long sum = 0;
        for(int i=0;i<n;i++)sum+=arr[i];
        sum = sum/(n*(n+1)/2);
        long res[] = new long[n];
        for(int i=0;i<n;i++){
            if(i==0){
                res[i] = (arr[n-1]-arr[i]+sum)/n;
                if(res[i]<1 || (arr[n-1]-arr[i]+sum)%n!=0 || res[i]>(long)1e9){
                    out.println("NO");
                    return;
                }
            }
            else{
                res[i] = (arr[i-1]-arr[i]+sum)/n;
                if(res[i]<1 || (arr[i-1]-arr[i]+sum)%n!=0 || res[i]>(long)1e9){
                    out.println("NO");
                    return;
                }
            }
        }
        out.println("YES");
        for(long e: res)out.print(e+" ");
        out.println( );
        
    }
}
