Paprika loves permutations. She has an array a_1, a_2, ..., a_n. She wants to make the array a permutation of integers 1 to n.

In order to achieve this goal, she can perform operations on the array. In each operation she can choose two integers i (1 ≤ i ≤ n) and x (x > 0), then perform a_i := a_i mod x (that is, replace a_i by the remainder of a_i divided by x). In different operations, the chosen i and x can be different.

Determine the minimum number of operations needed to make the array a permutation of integers 1 to n. If it is impossible, output -1.

A permutation is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array) and [1,3,4] is also not a permutation (n=3 but there is 4 in the array).

Input

Each test contains multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.

The first line of each test case contains an integer n (1 ≤ n ≤ 10^5).

The second line of each test case contains n integers a_1, a_2, ..., a_n. (1 ≤ a_i ≤ 10^9).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case, output the minimum number of operations needed to make the array a permutation of integers 1 to n, or -1 if it is impossible.

Example

Input


4
2
1 7
3
1 5 4
4
12345678 87654321 20211218 23571113
9
1 2 3 4 18 19 5 6 7


Output


1
-1
4
2

Note

For the first test, the only possible sequence of operations which minimizes the number of operations is: 

  * Choose i=2, x=5. Perform a_2 := a_2 mod 5 = 2. 



For the second test, it is impossible to obtain a permutation of integers from 1 to n.
8
2
2 3
3
3 4 5
1
1
1
2
1
3
1
4
1
12071207
5
5 5 5 9 14

1
2
0
-1
1
1
1
4

// Generated by Code Flattener.
// https://plugins.jetbrains.com/plugin/9979-idea-code-flattener

import java.io.Closeable;
import java.io.DataInputStream;
import java.io.IOException;
import java.util.Arrays;

public class C {
    public static void main(String[] args) throws IOException {
        FastScanner scanner = new FastScanner();
        int t = scanner.nextInt();
        cases:
        while (t-- > 0) {
            int n = scanner.nextInt();
            int[] a = new int[n];
            for (int i = 0; i < n; i++) {
                a[i] = scanner.nextInt();
            }

            Arrays.sort(a);
            boolean[] b = new boolean[n + 1];
            for (int i = 0; i < n; i++) {
                if (a[i] <= n && !b[a[i]]) {
                    b[a[i]] = true;
                    a[i] = -1;
                }
            }

            int count = 0;
            int ptr = 0;
            for (int i = 1; i < n + 1 && ptr < n; i++) {
                while (i < n + 1 && b[i]) i++;
                while (ptr < n && a[ptr] == -1) ptr++;
                if (i >= n + 1 || ptr >= n) break;
                if (a[ptr] > (i << 1)) {
                    count++;
                } else {
                    System.out.println("-1");
                    continue cases;
                }
                ptr++;
            }
            System.out.println(count);
        }
    }

    private static class FastScanner implements Closeable {
        final private int BUFFER_SIZE = 1 << 16;
        private DataInputStream din;
        private byte[] buffer;
        private int bufferPointer, bytesRead;

        public FastScanner() {
            din = new DataInputStream(System.in);
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public int nextInt() throws IOException {
            int ret = 0;
            byte c = read();
            while (c <= ' ') c = read();
            boolean neg = (c == '-');
            if (neg) c = read();
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');
            if (neg) return -ret;
            return ret;
        }

        private void fillBuffer() throws IOException {
            bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
            if (bytesRead == -1) buffer[0] = -1;
        }

        private byte read() throws IOException {
            if (bufferPointer == bytesRead) fillBuffer();
            return buffer[bufferPointer++];
        }

        @Override
        public void close() throws IOException {
            if (din == null) return;
            din.close();
        }
    }
}