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TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\n#include <iostream>\n \nusing namespace std;\n \nint f[51];\n \nint main()\n{\n int t,i,n,j,a,x;\n cin >> t;\n for (i=0; i<t; i++){\n cin >> n;\n x=0;\n for (j=0; j<n; j++){\n cin >> a;\n f[a]++;\n x=max(x, f[a]);\n }\n cout << n-x << '\\n';\n for (j=0; j<n; j++)\n f[j]=0;\n }\n return 0;\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291601945,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\n#include <iostream>\nusing namespace std;\nint main() {\n int t;\n cin>>t;\n for (int i=0;i<t;i++) {\n int n;\n cin>>n;\n int h[n];\n for (int j=0;j<n;j++) {\n cin>>h[j];\n }\n if(n==1)\n cout<<0<<endl;\n else if(n==2)\n cout<<1<<endl;\n else if (h[n/2]==h[n/2+1]==h[n/2-1])\n cout<<n-3<<endl;\n else if ((h[n/2]==h[n/2+1])||(h[n/2]==h[n/2-1]))\n cout<<n-2<<endl;\n else\n cout<<n-1<<endl;\n }\n return 0;\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 302464193,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\n#include <iostream>\nusing namespace std;\n \nint main (){\n int t; cin >> t;\n while (t--) {\n int n; cin >> n;\n int a[n + 1]; a[0] = -1;\n int x = 1;\n int y = 1;\n for (int i = 1; i <= n; i++) {\n cin >> a[i];\n if (a[i] == a[i - 1]) {\n y++; \n if (y > x) x = y;\n }\n }\n cout << n - x << endl;\n }\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 302696674,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\na=int(input())\nfor i in range(a):\n b=int(input())\n c=list(map(int,input().split()))\n if c==(sorted(c))[::-1]:\n d=len(set(c))\n if d==len(c):\n print(len(c)-1)\n else:\n print(len(c)-d)\n else:\n print(0)\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291650754,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\nt = int(input())\nfor _ in range(t):\n n = int(input())\n lst = list(map(int, input().split()))\n count = 0\n for i in range(n - 1):\n if lst[i] > lst[i + 1]:\n count += 1\n print(count)\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 296419107,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\na=int(input())\nfor i in range(a):\n b=int(input())\n c=list(map(int,input().split()))\n d=0\n for e in range(1,b):\n if c[e]<c[e-1]:\n d+=1\n print(d)\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291644011,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\nimport java.util.*;\nimport java.io.*;\n \npublic class Main {\n public static void main(String[] args) {\n Scanner scanner = new Scanner(System.in);\n int t = scanner.nextInt(); \n \n for (int i = 0; i < t; i++) {\n int n = scanner.nextInt();\n int[] heights = new int[n];\n for (int j = 0; j < n; j++) {\n heights[j] = scanner.nextInt();\n }\n \n int operations = 0;\n int lastHeight = 0;\n \n for (int j = 0; j < n; j++) {\n if (heights[j] < lastHeight) {\n operations++;\n } else {\n lastHeight = heights[j];\n }\n }\n System.out.println(operations);\n }\n \n scanner.close();\n }\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291623142,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\nimport java.util.Scanner;\n \npublic class PMMonument {\n public static void main(String[] args){\n Scanner sc = new Scanner(System.in);\n int t = sc.nextInt(); \n while (t-- > 0) {\n int n = sc.nextInt(); \n int[] h= new int[n];\n for(int i = 0; i < n; i++ ){\n h[i] = sc.nextInt();\n }\n \n int operations = 0;\n for (int i = n - 2; i >= 0; i--) {\n if (h[i] > h[i + 1]) {\n operations = h[i] - h[i + 1];\n h[i] = h[i + 1]; \n }\n }\n \n System.out.println(operations);\n }\n sc.close();\n }\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 293078205,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\n/*\n Author : kmv a.k.a kzhi\n K41 IT CHV\n*/\n#include <bits/stdc++.h>\nusing namespace std;\n \n \n//#define int long long\n#define ll long long\n#define FOR(i,a,b) for (int i = a ; i <= b; ++ i)\n#define FOD(i,a,b) for (int i = a; i >= b; -- i)\n \n \n#define BIT(mask,i) ((mask >> i) & 1)\n#define MASK(i) (1ll << (i))\n#define OFFBIT(mask,i) (mask &~(1ll<<(i)))\n#define ONBIT(mask,i) (mask | (1ll << (i)))\n#define lg2(x) (63 - __builtin_clzll(x))\n#define c_bit __builtin_popcountll\n \n#define vi vector < int >\n#define all(a) a.begin(), a.end()\n#define pb push_back\n \n#define ii pair<int,int>\n#define fi first\n#define se second\n \n#define openfile(TASK) if (fopen(TASK\".inp\",\"r\"))\\\n {freopen(TASK\".inp\",\"r\",stdin);freopen(TASK\".out\",\"w\",stdout);}\n#define endl '\\n'\n#define Faster ios_base::sync_with_stdio(false); \\\n cin.tie(0); cout.tie(0);\n \n#define mid(l,r) ((l + r) >> 1)\n#define left(id) (id << 1)\n#define right(id) ((id << 1) | 1)\n#define ci const int\n \ntemplate <class X, class Y> bool maximize(X &a, const Y &b){if(a < b) return a = b, true;return false;}\ntemplate <class X, class Y> bool minimize(X &a, const Y &b){if(a > b) return a = b, true;return false;}\n \nconst int N = 55;\n \nint n, a[N];\n \nvoid SOLVE(){\n cin >> n;\n FOR (i, 1, n)\n cin >> a[i];\n \n int cnt = 0;\n \n FOR (i, 2, n)\n if (a[i] < a[i - 1]){\n a[i] = a[i - 1];\n cnt ++;\n }\n \n cout << cnt << endl;\n}\n \nsigned main(){\n Faster\n openfile(\"test\")\n \n int q = 1;\n \n cin >> q;\n \n while (q --){\n SOLVE();\n }\n \n return 0;\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291581922,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\n#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\nint32_t main() {\n int t;\n cin>>t;\n while(t--){\n int n;\n cin>>n;\n vector <int> vec;\n \n for (int i=0; i<n; i++){\n int x=0;\n cin>>x;\n vec.push_back(x);\n }\n sort(vec.begin(), vec.end());\n vector <int> vec1(vec[n-1],0);\n for (int i=0; i<n; i++){\n vec1[vec[i]-1]++;\n }\n sort(vec1.begin(), vec1.end());\n int count=0;\n for (int i=0; i<vec1.size(); i++){\n if (vec1[vec1.size()-1]==1){\n count=1;\n break;\n }\n if (vec1[i]==vec1[vec1.size()-1] && vec1[vec1.size()-1]!=1){\n count+=vec1[i];\n }\n }\n if (n==1){\n cout<<0<<endl;\n }\n else{\n cout<<vec.size()-count<<endl;\n }\n }\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 292435140,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\ndef min_operations_to_non_decreasing(n, heights):\n operations = 0\n max_height = heights[0]\n \n # Iterate through array starting from second element\n for i in range(1, n):\n # If current height is less than previous maximum\n # We need to increase it to at least max_height\n if heights[i] < max_height:\n operations += 1\n else:\n # Update max_height if current height is larger\n max_height = heights[i]\n \n return operations\n \n# Read number of test cases\nt = int(input())\n \nfor _ in range(t):\n # Read number of pillars\n n = int(input())\n # Read heights array\n heights = list(map(int, input().split()))\n # Print minimum operations needed\n print(min_operations_to_non_decreasing(n, heights))\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291624407,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\nt=int(input())\nwhile t>0:\n t-=1\n n=int(input())\n li=list(map(int,input().split(\" \")))\n s=set(li)\n print(len(s)-1)\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291653494,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\nimport java.util.*;\nimport java.io.*;\nimport java.math.*;\n \npublic class sub {\n \n\t/*\n\t * /\\_/\\ (= ._.) / > \\>\n\t */\n\tstatic int mod = 998244353;\n \n\tpublic static void main(String args[]) {\n\t\tint t = sc.nextInt();\n\t\twhile (t-- > 0) {\n\t\t\tint n = sc.nextInt();\n\t\t\tint a[] = new int[n];\n\t\t\tfor(int i = 0;i<n;i++)a[i]=sc.nextInt();\n\t\t\tint ans = 0;\n\t\t\tfor(int i = 0;i<n-1;i++) {\n\t\t\t\tif(a[i]>a[i+1]) {\n\t\t\t\t\tans++;\n\t\t\t\t\ta[i+1]=a[i];\n\t\t\t\t}\n\t\t\t}\n\t\t\tout.println(ans);\n \n\t\t}\n\t\tout.close();\n\t}\n \n\t/*\n\t * public static long bincoef(int n, int k) { if(n < k) return 0L; return (p[n]\n\t * * pow((p[n - k] * p[k]) % mod, mod - 2,mod))%mod; }\n\t */\n\tstatic long pow(long a, long b, long mod) {\n\t\tif (b == 0) {\n\t\t\treturn 1L;\n\t\t}\n\t\tlong val = pow(a, b / 2, mod);\n\t\tif (b % 2 == 0) {\n\t\t\treturn val * val % mod;\n\t\t}\n\t\treturn val * val % mod * a % mod;\n\t}\n \n\tstatic int gcd(int a, int b) {\n\t\tif (b == 0) {\n\t\t\treturn a;\n\t\t}\n\t\treturn gcd(b, a % b);\n\t}\n \n\tstatic int lcm(int a, int b) {\n\t\treturn a * b / gcd(a, b);\n\t}\n \n\tstatic Kattio sc = new Kattio();\n\tstatic PrintWriter out = new PrintWriter(System.out);\n \n\tstatic class Kattio {\n \n\t\tstatic BufferedReader r;\n\t\tstatic StringTokenizer st;\n \n\t\tpublic Kattio() {\n\t\t\tr = new BufferedReader(new InputStreamReader(System.in));\n\t\t}\n \n\t\tpublic String next() {\n\t\t\ttry {\n\t\t\t\twhile (st == null || !st.hasMoreTokens()) {\n\t\t\t\t\tst = new StringTokenizer(r.readLine());\n\t\t\t\t}\n\t\t\t\treturn st.nextToken();\n\t\t\t} catch (Exception e) {\n\t\t\t\treturn null;\n\t\t\t}\n\t\t}\n \n\t\tpublic int nextInt() {\n\t\t\treturn Integer.parseInt(next());\n\t\t}\n \n\t\tpublic long nextLong() {\n\t\t\treturn Long.parseLong(next());\n\t\t}\n \n\t\tpublic double nextDouble() {\n\t\t\treturn Double.parseDouble(next());\n\t\t}\n\t}\n \n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 293929166,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\nimport java.util.*;\npublic class monument {\n public static void main(String[] args) {\n Scanner sc = new Scanner(System.in);\n int t=sc.nextInt();\n while(t>0)\n {\n int n=sc.nextInt();\n int A[]=new int[n];\n for(int i=0;i<n;i++)\n {\n A[i]=sc.nextInt();\n }\n Arrays.sort(A);\n int count=0;\n for(int i=0;i<n-1;i++)\n {\n if(A[i]<A[i+1])\n count++;\n }\n System.out.println(count);\n t--;\n \n }\n \n \n}\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291641317,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\n#include<bits/stdc++.h>\nusing namespace std;\nconst int N=5e5;\nint n,a[N];\n \nvoid solve(){\n\tcin>>n;\n\tmap<int,int> mp;\n\tfor(int i=1;i<=n;i++){\n\t\tcin>>a[i];\n\t\tmp[a[i]]=1;\n\t}\n\tcout<<mp.size()-1<<'\\n';\n}\n \nsigned main(){\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n \n\tint t=1;\n\tcin>>t;\n\twhile(t--){\n\t\tsolve();\n\t}\n \n\treturn 0;\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 292446597,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\n#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\nconst int N = 3e5+9;\nint a[N], b[N];\nvoid haha()\n{\n\tint n;cin >> n;int cnt =0;\n\tif(n == 1) cnt = 0;\n\telse if(n == 2) \n\t{\n\t\tif(a[1] > a[2]) cnt = 1;\n\t}\n\telse if(n >= 3)\n\t{\n\t\tfor(int i = 1; i <= n; i++)\n\t\t{\n\t\t\tcin >> a[i];\n\t\t\tb[i] = a[i];\n\t\t} \n\t\tsort(b+1, b+n+1);\n\t\tint x = b[(n+1)/2];\n\t\t//cout << x << \"\\n\";\n\t\tfor(int i = 1; i <= n/2; i++) if(a[i] > x) cnt ++;\n\t\tfor(int i = n/2+1; i <= n; i++) if(a[i] < x) cnt ++;\n\t}\n\tcout << cnt << \"\\n\";\n\treturn ;\n}\n \nsigned main()\n{\n\tios::sync_with_stdio(0),cin.tie(0),cout.tie(0);\n\tint t; cin >> t;\n\twhile(t--) haha();\n\treturn 0;\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291592780,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\nt = int(input())\n \nfor i in range(t):\n h = int(input())\n \n k = list(map(int,input().split()))\n \n print(k[0]-k[-1])\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291589053,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\nt=int(input())\nfor _ in range(t):\n n=int(input())\n h=list(map(int,input().split(\" \")))\n le=len(h)\n mle=le*-1\n if len(h)==1:\n print(0)\n continue\n else:\n c=0\n for i in range(n-1):\n if h[i]>h[i+1]:\n c+=1\n h[i],h[i+1]=h[i+1],h[i]\n else:\n continue\n print(c)\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291618569,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\nimport java.util.*;\npublic class Main {\n public static void main(String[] args) {\n Scanner sc=new Scanner(System.in);\n int t=sc.nextInt();\n while(t-- !=0){\n int n=sc.nextInt();\n int[] arr=new int[n];\n int min=Integer.MAX_VALUE;\n int max=Integer.MIN_VALUE;\n int count=0;\n for(int i=0;i<n;i++){\n arr[i]=sc.nextInt();\n min=Math.min(min,arr[i]);\n max=Math.max(max,arr[i]);\n }\n int mid=n/2;\n for(int i=0;i<n/2;i++){\n if(arr[i]>arr[i+1]){\n arr[i]=min;\n count++;\n if(i==n/2){\n break;\n }\n }\n }\n for(int i=(n/2)+1;i<n;i++){if(arr[i]<arr[i-1]){\n arr[i]=max;\n count++;\n if(i==n-1){\n break;\n }\n }\n }\n if(n==1){\n System.out.println(\"0\");\n }\n else{\n System.out.println(count);\n }\n }\n }\n }\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291666348,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Penchick and Modern Monument\ntime_limit_ms: 1000\nmemory_limit_mb: 256\nDescription: Amidst skyscrapers in the bustling metropolis of Metro Manila, the newest Noiph mall in the Philippines has just been completed! The construction manager, Penchick, ordered a state-of-the-art monument to be built with $$$n$$$ pillars.\n\nThe heights of the monument's pillars can be represented as an array $$$h$$$ of $$$n$$$ positive integers, where $$$h_i$$$ represents the height of the $$$i$$$-th pillar for all $$$i$$$ between $$$1$$$ and $$$n$$$.\n\nPenchick wants the heights of the pillars to be in non-decreasing order, i.e. $$$h_i \\le h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$. However, due to confusion, the monument was built such that the heights of the pillars are in non-increasing order instead, i.e. $$$h_i \\ge h_{i + 1}$$$ for all $$$i$$$ between $$$1$$$ and $$$n - 1$$$.\n\nLuckily, Penchick can modify the monument and do the following operation on the pillars as many times as necessary:\n\n- Modify the height of a pillar to any positive integer. Formally, choose an index $$$1\\le i\\le n$$$ and a positive integer $$$x$$$. Then, assign $$$h_i := x$$$.\n\nHelp Penchick determine the minimum number of operations needed to make the heights of the monument's pillars non-decreasing.\n\nInput: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 1000$$$). The description of the test cases follows.\n\nThe first line of each test case contains a single integer $$$n$$$ ($$$1 \\leq n \\leq 50$$$)Β β the number of pillars.\n\nThe second line of each test case contains $$$n$$$ integers $$$h_1, h_2, \\ldots, h_n$$$ ($$$1 \\le h_i \\le n$$$ and $$$h_i\\ge h_{i+1}$$$)Β β the height of the pillars.\n\nPlease take note that the given array $$$h$$$ is non-increasing.\n\nNote that there are no constraints on the sum of $$$n$$$ over all test cases.\n\nOutput: For each test case, output a single integer representing the minimum number of operations needed to make the heights of the pillars non-decreasing.\n\nExamples:\ninput:\n3\n5\n5 4 3 2 1\n3\n2 2 1\n1\n1\noutput:\n4\n1\n0\n\nNote: In the first test case, the initial heights of pillars are $$$h = [5, 4, 3, 2, 1]$$$.\n\n- In the first operation, Penchick changes the height of pillar $$$1$$$ to $$$h_1 := 2$$$.\n- In the second operation, he changes the height of pillar $$$2$$$ to $$$h_2 := 2$$$.\n- In the third operation, he changes the height of pillar $$$4$$$ to $$$h_4 := 4$$$.\n- In the fourth operation, he changes the height of pillar $$$5$$$ to $$$h_5 := 4$$$.\n\nAfter the operation, the heights of the pillars are $$$h = [2, 2, 3, 4, 4]$$$, which is non-decreasing. It can be proven that it is not possible for Penchick to make the heights of the pillars non-decreasing in fewer than $$$4$$$ operations.\n\nIn the second test case, Penchick can make the heights of the pillars non-decreasing by modifying the height of pillar $$$3$$$ to $$$h_3 := 2$$$.\n\nIn the third test case, the heights of pillars are already non-decreasing, so no operations are required.\n\nBuggy Code:\nimport java.util.*;\npublic class Main\n{\n public static void main(String args[])\n {\n Scanner sc=new Scanner(System.in);\n int t=sc.nextInt();\n while(t-->0)\n {\n int n=sc.nextInt();\n int a[]=new int[n];\n for(int i=0;i<n;i++)\n {\n a[i]=sc.nextInt();\n }\n \n \n if(n==1)\n {\n System.out.println(0);\n }\n else\n {\n int c=0;\n for(int i=0;i<n-1;i++)\n {\n if(a[i]>a[i+1])\n {\n c++;\n }\n }\n System.out.println(c);\n }\n }\n }\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2031A",
"submission_id": 291605472,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\n# include <bits/stdc++.h>\nusing namespace std;\n# define int long long\n \nvector<tuple<int,int,int>> g[100005];\nint t0, t1, t2;\nint n, m; \n \nbool ok(int time, int start, int goal){\n\tpriority_queue<pair<int,int>, vector<pair<int,int>>, greater<pair<int,int>>> q;\n\tint dis[n+1];\n\tmemset(dis, 0x3f, sizeof(dis));\n \n\tdis[start] = time;\n\tq.push({time, start});\n \n\t// cout << endl;\n\twhile(!q.empty()){\n\t\tauto [curT, u] = q.top(); q.pop();\n\t\t// cout << \" :: \" << curT << \" \" << u << endl;\n\t\tif(u == goal && curT <= t0) return true;\n\t\t\n\t\tif(t1 <= curT && curT < t2){\n\t\t\tdis[u] = t2;\n\t\t\tq.push({t2, u});\n\t\t}\n \n\t\tfor(auto [v, tbus, twalk]: g[u]){\n\t\t\t// walk\n\t\t\tif(curT+twalk < dis[v]){\n\t\t\t\tdis[v] = curT + twalk;\n\t\t\t\tq.push({dis[v], v});\n\t\t\t}\n \n\t\t\t// bus\n\t\t\tif(curT < t1 && t1 < curT+tbus) continue; // cannot board the bus due to phone call when arrive\n\t\t\tif(t1 <= curT && curT < t2) continue; // cannot board the bus because still on call\n\t\t\tif(curT+tbus < dis[v]){\n\t\t\t\tdis[v] = curT + tbus;\n\t\t\t\tq.push({dis[v], v});\n\t\t\t}\n\t\t}\n\t}\n\treturn false;\n}\n \nint solve(){\n\tcin >> n >> m;\n\tfor(int i=1; i<=n; i++) g[i].clear();\n\tcin >> t0 >> t1 >> t2;\n \n\twhile(m--){\n\t\tint u, v, tbus, twalk;\n\t\tcin >> u >> v >> tbus >> twalk;\n\t\tg[u].push_back({v, tbus, twalk});\n\t\tg[v].push_back({u, tbus, twalk});\n\t}\n \n\tint lo = 0, hi = t0, ans = -1;\n\twhile(lo <= hi){\n\t\tint mid = (lo + hi) / 2;\n\t\tif(ok(mid, 1, n)){\n\t\t\tans = mid;\n\t\t\tlo = mid+1;\n\t\t}\n\t\telse hi = mid-1;\n\t}\n \n\tcout << ans << endl;\n\treturn 0;\n}\n \nsigned main(){\n\tios_base::sync_with_stdio(false);\n\tint t; cin >> t;\n\tfor(int tc=1; tc<=t; tc++){\n\t\tint ans = solve();\n\t}\n}\n \n/*\n*/\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 276356347,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\n#include <bits/stdc++.h>\nusing namespace std;\n \nlong long inf = numeric_limits<long long>::max();\n \nint main(){\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n long long t;\n cin>>t;\n vector<int> ans(t);\n int count = 0;\n while (t--){\n count++;\n long long n,m;\n cin>>n>>m;\n if (count==461){\n cout<<n<<\" \"<<m<<endl;\n }\n long long t0,t1,t2;\n cin>>t0>>t1>>t2;\n if (count==461){\n cout<<t0<<\" \"<<t1<<\" \"<<t2<<endl;\n }\n long long temp = t2;\n t2 = t0-t1;\n t1 = t0-temp;\n vector<vector<vector<long long>>> adj_list(n+1);\n for (long long i=0;i<m;i++){\n long long u,v,l1,l2;\n cin>>u>>v>>l1>>l2;\n if (count==461){\n cout<<u<<\" \"<<v<<\" \"<<l1<<\" \"<<l2<<endl;\n }\n adj_list[u].push_back({v,l1,l2});\n adj_list[v].push_back({u,l1,l2});\n }\n \n priority_queue<pair<long long,long long>> pq;\n pq.push({0,n});\n vector<long long> dist(adj_list.size(),inf);\n dist[n] = 0;\n while (!pq.empty()){\n long long curr_time = pq.top().first;\n long long curr = pq.top().second;\n pq.pop();\n if (dist[curr]<curr_time){\n continue;\n }\n for (vector<long long> child:adj_list[curr]){\n if ((curr_time + child[1] <= t1 || t2<=curr_time) && (curr_time<= t1 || t2<=curr_time)){\n if (dist[child[0]] > dist[curr]+child[1]){\n dist[child[0]] = dist[curr]+child[1];\n pq.push({dist[child[0]],child[0]});\n }\n }\n if (curr_time<=t1 && dist[child[0]] > t2+child[1]){\n dist[child[0]] = t2+child[1];\n pq.push({dist[child[0]],child[0]});\n }\n if (dist[child[0]] > dist[curr]+child[2]){\n dist[child[0]] = dist[curr]+child[2];\n pq.push({dist[child[0]],child[0]});\n }\n }\n }\n ans[count-1] = max(t0-dist[1],-1LL);\n }\n for (int x:ans){\n cout<<x<<\"\\n\";\n }\n return 0;\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 293740538,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\n#include<bits/stdc++.h>\n \n#define int long long\nusing namespace std;\nconst int N = 1e5 + 5;\nstruct edge {\n int v;\n int w1;\n int w2;\n int nxt;\n} e[N << 1];\nint head[N], ind;\nint vis[N];\n \nstruct node {\n int v;\n int t;\n \n bool operator<(const node &a) const {\n return t < a.t;\n }\n};\n \nvoid add(int u, int v, int w1, int w2) {\n e[ind].v = v;\n e[ind].w1 = w1;\n e[ind].w2 = w2;\n e[ind].nxt = head[u];\n head[u] = ind++;\n}\n \nvoid solve() {\n int n, m;\n cin >> n >> m;\n ind = 0;\n for (int i = 0; i <= n; i++) head[i] = -1;\n \n int t, t1, t2;\n cin >> t >> t1 >> t2;\n \n for (int i = 1; i <= m; i++) {\n int u, v, w1, w2;\n cin >> u >> v >> w1 >> w2;\n add(u, v, w1, w2);\n add(v, u, w1, w2);\n }\n \n vector<node> ans;\n vector<node> ans1;//ηΊ―η\n int res = -1;\n priority_queue<node> q;//ε
ε车\n q.push({n, t});\n \n for (int i = 0; i <= n; i++) vis[i] = 0;\n while (!q.empty()) {\n auto [u, tt] = q.top();\n q.pop();\n if (u == 1) {\n res = max(res, tt);\n continue;\n }\n if (vis[u] == 1) continue;\n vis[u] = 1;\n \n for (int i = head[u]; ~i; i = e[i].nxt) {\n int v = e[i].v;\n int w = e[i].w1;\n if (vis[v] == 1) continue;\n if (tt - w >= t2) {\n q.push({v, tt - w});\n } else {\n ans.push_back({u, tt});\n ans1.push_back({u, t1});\n }\n }\n }\n \n for (auto i: ans) q.push(i);\n while (!q.empty()) {\n auto [u, tt] = q.top();\n q.pop();\n if (u == 1) {\n res = max(res, tt);\n continue;\n }\n if (vis[u] == 2) continue;\n vis[u] = 2;\n \n for (int i = head[u]; ~i; i = e[i].nxt) {\n int v = e[i].v;\n int w = e[i].w2;\n if (vis[v] == 2) continue;\n if (tt <= t1) {\n ans1.push_back({u, tt});\n } else {\n if (tt >= w) {\n q.push({v, tt - w});\n } else {\n ans1.push_back({u, t1});\n }\n }\n }\n }\n \n for (auto i: ans1) q.push(i);\n while (!q.empty()) {\n auto [u, tt] = q.top();\n q.pop();\n if (u == 1) {\n res = max(res, tt);\n continue;\n }\n if (vis[u] == 3) continue;\n vis[u] = 3;\n \n for (int i = head[u]; ~i; i = e[i].nxt) {\n int v = e[i].v;\n int w = e[i].w1;\n if (vis[v] == 3) continue;\n if (tt - w < 0) continue;\n q.push({v, tt - w});\n }\n }\n cout << res << \"\\n\";\n}\n \nsigned main() {\n#ifdef ONLINE_JUDGE\n#else\n freopen(\"in.txt\", \"r\", stdin);\n freopen(\"out.txt\", \"w\", stdout);\n#endif\n ios::sync_with_stdio(false);\n cout.tie(nullptr);\n int t = 1;\n cin >> t;\n while (t--) {\n solve();\n }\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 288448359,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\n# https://codeforces.com/contest/2000\n \nimport sys\nfrom heapq import heappush, heappop\n \ninput = lambda: sys.stdin.readline().rstrip() # faster!\n \nINF = 10 ** 18\n \n \ndef dijkstra(n, adj, start, finish, t_start, walk_call, t1, t2):\n dist = [INF] * n\n dist[start] = t_start\n queue = []\n heappush(queue, (dist[start], start))\n while queue:\n d, v = heappop(queue)\n if d == dist[v]:\n for u, l1, l2 in adj[v]:\n if d >= t2 or d + l1 <= t1:\n if d + l1 < dist[u]:\n dist[u] = d + l1\n heappush(queue, (dist[u], u))\n elif walk_call:\n if d + l2 < dist[u]:\n dist[u] = d + l2\n heappush(queue, (dist[u], u))\n else:\n if t2 + l1 < dist[u]:\n dist[u] = t2 + l1\n heappush(queue, (dist[u], u))\n return dist[finish]\n \n \ndef solve_case(t):\n n, m = map(int, input().split()) # 2 <= n <= 10**5, 1 <= m <= 10**5\n t0, t1, t2 = map(int, input().split()) # t1 < t2 < t0\n \n adj = [[] for _ in range(n)]\n for _ in range(m):\n u, v, l1, l2 = map(int, input().split())\n u -= 1\n v -= 1\n adj[u] += [(v, l1, l2)]\n adj[v] += [(u, l1, l2)]\n \n if t==24:\n return f\"{str(adj[2:4]).replace(', ','_')}\"\n \n \n \n start = 0\n finish = n - 1\n \n x = dijkstra(n, adj, start, finish, 0, True, t1, t2)\n y = dijkstra(n, adj, start, finish, 0, False, t1, t2)\n if min(x, y) > t0:\n return -1\n \n lo, hi = 0, t0\n while lo + 1 < hi:\n mid = (lo + hi) // 2\n x = dijkstra(n, adj, start, finish, mid, True, t1, t2)\n y = dijkstra(n, adj, start, finish, mid, False, t1, t2)\n xy = min(x, y)\n if xy <= t0:\n lo = mid\n else:\n hi = mid\n \n return lo\n \n \nans = []\nfor t in range(int(input())):\n ans += [str(solve_case(t))]\nprint(\"\\n\".join(ans))\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 276338442,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\nimport heapq\nimport sys, os, io\ninput = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline\n \ndef make_graph(n, m):\n l = 2 * m + n\n x, y, s = [0] * (2 * l), [0] * (2 * l), [0] * (((n + 1) << 1) + 3)\n for i in range(0, m << 2, 4):\n u, v, l1, l2 = map(int, input().split())\n for k in range(2):\n s[g(u, k) + 2] += 1\n s[g(v, k) + 2] += 1\n x[i ^ 0], x[i ^ 1], x[i ^ 2], x[i ^ 3] = g(u, 0), g(v, 0), g(u, 1), g(v, 1)\n y[i ^ 0], y[i ^ 1], y[i ^ 2], y[i ^ 3] = l1, l1, l2, l2\n k = m << 2\n for i in range(1, n + 1):\n for j in range(2):\n s[g(i, j) + 2] += 1\n x[k ^ j] = g(i, j ^ 1)\n k += 2\n for i in range(3, ((n + 1) << 1) + 3):\n s[i] += s[i - 1]\n G, W = [0] * (2 * l), [0] * (2 * l)\n for i in range(2 * l):\n j = x[i] + 1\n G[s[j]] = x[i ^ 1]\n W[s[j]] = y[i ^ 1]\n s[j] += 1\n return G, W, s\n \ndef f(u, v):\n return u << 20 ^ v\n \ndef g(u, v):\n return u << 1 ^ v\n \ndef dijkstra(s):\n dist = [-1] * (((n + 1) << 1) + 1)\n dist[s] = t0\n visit = [0] * (((n + 1) << 1) + 1)\n p = [f(inf - t0, s)]\n while p:\n d, u = inf - (p[0] >> 20), heapq.heappop(p) & 0xfffff\n if dist[u] < d:\n continue\n if d <= t1:\n x = 0\n elif t1 < d < t2:\n x = 1\n else:\n x = 2\n visit[u] = 1\n for i in range(s0[u], s0[u + 1]):\n v, nd = G[i], dist[u] - W[i]\n if nd <= t1:\n y = 0\n elif t1 < nd < t2:\n y = 1\n else:\n y = 2\n if not u & 1 and not v & 1 and x ^ y:\n nd = t1 - W[i]\n if not visit[v] and nd > dist[v]:\n dist[v] = nd\n heapq.heappush(p, f(inf - dist[v], v))\n return dist\n \nt = int(input())\nans = []\ninf = pow(10, 9) + 1\nfor _ in range(t):\n n, m = map(int, input().split())\n t0, t1, t2 = map(int, input().split())\n G, W, s0 = make_graph(n, m)\n dist = dijkstra(g(n, 0))\n ans0 = dist[2]\n ans.append(ans0)\nsys.stdout.write(\"\\n\".join(map(str, ans)))\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 276305567,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\nI = lambda : list(map(int, input().split(' ')))\nR = lambda : (int(input()))\n \nimport math\nfrom collections import defaultdict\nfrom collections import deque\n \nfrom heapq import heappop, heappush, heapify\n \ndef is_possible(node, e, t0, t1, t2):\n \n dis = [float('inf') for i in range(n + 1)]\n dis[1] = node[0][0]\n heapify(node)\n \n ind = 0\n \n while ind < len(node) :\n \n # d, curr, parent = heappop(node)\n d, curr, parent = node[ind]\n dis[curr] = min(dis[curr], d)\n \n for v, l1, l2 in e[curr]:\n \n if d <= t1:\n time_req = (d + l1) if (d + l1 <= t1) else (d + l2)\n if time_req > t2 + l1: time_req = t2 + l1\n \n elif d > t1 and d < t2:\n time_req = d + l2\n if time_req > t2 + l1: time_req = t2 + l1\n \n elif d >= t2:\n time_req = d + l1\n \n if v != n and v != parent:\n if dis[v] > time_req and dis[v] == float('inf'):\n # heappush(node, (time_req, v, curr))\n node.append((time_req, v, curr))\n dis[v] = min(time_req, dis[v])\n \n elif v == n and v != parent:\n dis[v] = min(dis[v], time_req)\n \n ind += 1\n \n return dis[n] <= t0\n \nfor kp in range(R()):\n \n n,m = I()\n t0, t1, t2 = I()\n e = [[] for i in range(n+1)]\n \n prev = -1\n low = 0\n high = t0\n \n for i in range(m):\n u,v,l1,l2 = I()\n e[u].append((v,l1,l2))\n e[v].append((u,l1,l2))\n \n while low <= high:\n mid = (low + high)//2\n is_d = is_possible( [(mid, 1, -1)] , e, t0, t1, t2)\n \n if is_d == True:\n prev = mid\n low = mid + 1\n else:\n high = mid - 1\n \n # print(high, low, mid, is_d)\n \n print(prev)\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 276291364,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\n//package Codeforces;\n \nimport java.io.BufferedOutputStream;\nimport java.io.BufferedReader;\nimport java.io.InputStreamReader;\nimport java.io.PrintWriter;\nimport java.util.Arrays;\nimport java.util.LinkedList;\nimport java.util.StringTokenizer;\nimport java.util.TreeSet;\n \nimport java.util.*;\n \npublic class CallDuringTheJourney {\n final static Scanner sc = new Scanner(System.in);\n \n public static void main(String[] args) {\n \n new Thread(null, null, \"Thread\", 1 << 27) {\n public void run() {\n try {\n s = new FastReader();\n out = new PrintWriter(new BufferedOutputStream(System.out));\n solve();\n out.close();\n } catch (Exception e) {\n e.printStackTrace();\n System.exit(1);\n }\n }\n }.start();\n }\n \n static void solve() throws Exception {\n \n int testcases = sc.nextInt();\n for (int test = 0; test<testcases; ++test) {\n int n = sc.nextInt();\n int m = sc.nextInt();\n \n Graph g = new Graph(n, m);\n \n int t0 = sc.nextInt();\n int t1 = sc.nextInt();\n int t2 = sc.nextInt();\n \n for(int i=0; i<m; ++i){\n int u = sc.nextInt();\n int v = sc.nextInt();\n int bussTime = sc.nextInt();\n int walkTime = sc.nextInt();\n g.createEdge(u, v, bussTime, walkTime);\n }\n \n int result = findTimeToReach(g, t0, t1, t2);\n out.println(result);\n }\n }\n \n private static int findTimeToReach(Graph g, int t0, int t1, int t2){\n g.populateMaxTimeToReach(t0, t1, t2);\n return g.nodes.get(0).maxTimeTorReach;\n }\n \n private static boolean isOverlappingInterval(int busTime, int maxTimeTorReach, int t1, int t2) {\n return (t2 > busTime && t1 < maxTimeTorReach);\n }\n \n public static class Graph{\n List<Node> nodes;\n // List<Edge> edges;\n Map<Node, List<Edge>> adjacencyList;\n static int edgeid = 0;\n int N;\n int M;\n \n Graph(int N, int M){\n this.N = N;\n this.M = M;\n nodes = new ArrayList<>(this.N);\n // edges = new ArrayList<>(this.M);\n adjacencyList = new HashMap<>();\n for(int i = 0; i < N; i++){\n Node u = new Node(i);\n nodes.add(u);\n adjacencyList.put(u, new ArrayList<>());\n }\n }\n \n void populateMaxTimeToReach(int t0, int t1, int t2){\n PriorityQueue<Node> pq = new PriorityQueue<>((a, b) -> b.maxTimeTorReach - a.maxTimeTorReach);\n \n// out.println(\"Checking PQ\");\n// for(int i=1; i<N; i++){\n// nodes.get(i).maxTimeTorReach = i;\n// pq.add(nodes.get(i));\n// }\n// while(!pq.isEmpty()){\n// out.println(pq.poll().maxTimeTorReach);\n// }\n// out.println(\"done\");\n \n nodes.get(N-1).maxTimeTorReach = t0;\n pq.add(nodes.get(N-1));\n \n int walkTime, busTime, currentBestTime;\n \n Set<Integer> visited = new HashSet<>();\n \n while(!pq.isEmpty()){\n Node node = pq.poll();\n pq.remove(node);\n if(visited.contains(node.id)){ continue;}\n visited.add(node.id);\n if(node.maxTimeTorReach < 0) break;\n if(node.id == 0) break;\n \n for(Edge edge: adjacencyList.get(node)){\n Node neib = edge.u;\n if(edge.u.id == node.id){\n neib = edge.v;\n }\n walkTime = node.maxTimeTorReach - edge.walkTime;\n busTime = node.maxTimeTorReach - edge.busTime;\n \n if(isOverlappingInterval(busTime, node.maxTimeTorReach, t1, t2)){\n busTime = t1 - edge.busTime;\n }\n \n currentBestTime = Math.max(walkTime, busTime);\n if(neib.maxTimeTorReach < currentBestTime){\n neib.maxTimeTorReach = currentBestTime;\n pq.add(neib);\n }\n }\n }\n }\n \n public static class Node{\n int id;\n int maxTimeTorReach;\n \n Node(int id){\n this.id = id;\n this.maxTimeTorReach = -1;\n }\n }\n \n public static class Edge{\n int id;\n Node u;\n Node v;\n int walkTime;\n int busTime;\n \n public Edge(Node u, Node v, int walkTime, int busTime) {\n this.u = u;\n this.v = v;\n this.walkTime = walkTime;\n this.busTime = busTime;\n this.id = edgeid;\n edgeid++;\n }\n }\n \n void createEdge(int u, int v, int busTime, int walkTime){\n --u; --v;\n Node uNode = nodes.get(u);\n Node vNode = nodes.get(v);\n \n Edge edge = new Edge(uNode, vNode, walkTime, busTime);\n adjacencyList.get(uNode).add(edge);\n adjacencyList.get(vNode).add(edge);\n }\n }\n \n \n \n public static FastReader s;\n public static PrintWriter out;\n \n public static class FastReader {\n BufferedReader br;\n StringTokenizer st;\n \n public FastReader() {\n br = new BufferedReader(new InputStreamReader(System.in));\n }\n \n String next() {\n while (st == null || !st.hasMoreElements()) {\n try {\n st = new StringTokenizer(br.readLine());\n } catch (Exception e) {\n e.printStackTrace();\n }\n }\n return st.nextToken();\n }\n \n int nextInt() {\n return Integer.parseInt(next());\n }\n \n double nextDouble() {\n return Double.parseDouble(next());\n }\n \n long nextLong() {\n return Long.parseLong(next());\n }\n \n int[] nextIntArray(int n) {\n int[] arr = new int[n];\n for (int i = 0; i < n; i++) {\n arr[i] = nextInt();\n }\n return arr;\n }\n \n long[] nextLongArray(int n) {\n long[] arr = new long[n];\n for (int i = 0; i < n; i++) {\n arr[i] = nextLong();\n }\n return arr;\n }\n \n String nextLine() {\n String str = \"\";\n try {\n str = br.readLine();\n } catch (Exception e) {\n e.printStackTrace();\n }\n return str;\n }\n }\n \n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 276845167,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\n//package Codeforces;\n \nimport java.io.BufferedOutputStream;\nimport java.io.BufferedReader;\nimport java.io.InputStreamReader;\nimport java.io.PrintWriter;\nimport java.util.Arrays;\nimport java.util.LinkedList;\nimport java.util.StringTokenizer;\nimport java.util.TreeSet;\n \nimport java.util.*;\n \npublic class CallDuringTheJourney {\n final static Scanner sc = new Scanner(System.in);\n \n public static void main(String[] args) {\n \n new Thread(null, null, \"Thread\", 1 << 27) {\n public void run() {\n try {\n s = new FastReader();\n out = new PrintWriter(new BufferedOutputStream(System.out));\n solve();\n out.close();\n } catch (Exception e) {\n e.printStackTrace();\n System.exit(1);\n }\n }\n }.start();\n }\n \n static void solve() throws Exception {\n \n int testcases = sc.nextInt();\n for (int test = 0; test<testcases; ++test) {\n int n = sc.nextInt();\n int m = sc.nextInt();\n \n Graph g = new Graph(n, m);\n \n int t0 = sc.nextInt();\n int t1 = sc.nextInt();\n int t2 = sc.nextInt();\n \n for(int i=0; i<m; ++i){\n int u = sc.nextInt();\n int v = sc.nextInt();\n int bussTime = sc.nextInt();\n int walkTime = sc.nextInt();\n g.createEdge(u, v, bussTime, walkTime);\n }\n \n int result = findTimeToReach(g, t0, t1, t2);\n out.println(result);\n }\n }\n \n private static int findTimeToReach(Graph g, int t0, int t1, int t2){\n g.populateMaxTimeToReach(t0, t1, t2);\n return g.nodes.get(0).maxTimeTorReach;\n }\n \n private static boolean isOverlappingInterval(int busTime, int maxTimeTorReach, int t1, int t2) {\n return (t2 > busTime && t1 < maxTimeTorReach);\n }\n \n public static class Graph{\n List<Node> nodes;\n // List<Edge> edges;\n Map<Node, List<Edge>> adjacencyList;\n static int edgeid = 0;\n int N;\n int M;\n \n Graph(int N, int M){\n this.N = N;\n this.M = M;\n nodes = new ArrayList<>(this.N);\n // edges = new ArrayList<>(this.M);\n adjacencyList = new HashMap<>();\n for(int i = 0; i < N; i++){\n Node u = new Node(i);\n nodes.add(u);\n adjacencyList.put(u, new ArrayList<>());\n }\n }\n \n void populateMaxTimeToReach(int t0, int t1, int t2){\n nodes.get(N-1).maxTimeTorReach = t0;\n PriorityQueue<Node> pq = new PriorityQueue<>();\n \n pq.add(nodes.get(N-1));\n int walkTime, busTime, currentBestTime;\n \n while(!pq.isEmpty()){\n Node node = pq.poll();\n if(node.maxTimeTorReach < 0 || node.id == 0) break;\n for(Edge edge: adjacencyList.get(node)){\n Node neib = edge.u;\n if(edge.u.id == node.id){\n neib = edge.v;\n }\n walkTime = node.maxTimeTorReach - edge.walkTime;\n busTime = node.maxTimeTorReach - edge.busTime;\n \n if(isOverlappingInterval(busTime, node.maxTimeTorReach, t1, t2)){\n busTime = t1 - edge.busTime;\n }\n \n currentBestTime = Math.max(walkTime, busTime);\n if(neib.maxTimeTorReach < currentBestTime){\n neib.maxTimeTorReach = currentBestTime;\n pq.add(neib);\n }\n }\n }\n }\n \n public static class Node implements Comparable<Node>{\n int id;\n int maxTimeTorReach;\n \n Node(int id){\n this.id = id;\n this.maxTimeTorReach = -1;\n }\n \n \n @Override\n public int compareTo(Node o) {\n return o.maxTimeTorReach - this.maxTimeTorReach ;\n }\n \n }\n \n public static class Edge{\n int id;\n Node u;\n Node v;\n int walkTime;\n int busTime;\n \n public Edge(Node u, Node v, int walkTime, int busTime) {\n this.u = u;\n this.v = v;\n this.walkTime = walkTime;\n this.busTime = busTime;\n this.id = edgeid;\n edgeid++;\n }\n }\n \n void createEdge(int u, int v, int busTime, int walkTime){\n --u; --v;\n Node uNode = nodes.get(u);\n Node vNode = nodes.get(v);\n \n Edge edge = new Edge(uNode, vNode, walkTime, busTime);\n adjacencyList.get(uNode).add(edge);\n adjacencyList.get(vNode).add(edge);\n }\n }\n \n \n \n public static FastReader s;\n public static PrintWriter out;\n \n public static class FastReader {\n BufferedReader br;\n StringTokenizer st;\n \n public FastReader() {\n br = new BufferedReader(new InputStreamReader(System.in));\n }\n \n String next() {\n while (st == null || !st.hasMoreElements()) {\n try {\n st = new StringTokenizer(br.readLine());\n } catch (Exception e) {\n e.printStackTrace();\n }\n }\n return st.nextToken();\n }\n \n int nextInt() {\n return Integer.parseInt(next());\n }\n \n double nextDouble() {\n return Double.parseDouble(next());\n }\n \n long nextLong() {\n return Long.parseLong(next());\n }\n \n int[] nextIntArray(int n) {\n int[] arr = new int[n];\n for (int i = 0; i < n; i++) {\n arr[i] = nextInt();\n }\n return arr;\n }\n \n long[] nextLongArray(int n) {\n long[] arr = new long[n];\n for (int i = 0; i < n; i++) {\n arr[i] = nextLong();\n }\n return arr;\n }\n \n String nextLine() {\n String str = \"\";\n try {\n str = br.readLine();\n } catch (Exception e) {\n e.printStackTrace();\n }\n return str;\n }\n }\n \n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 276843516,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\n#include <iostream>\n#include <stdio.h>\n#include <vector>\n#include <queue>\nusing namespace std;\nconst int maxn = 1e5 + 5, ninf = 0x80000000;\nint T, n, m, t0, t1, t2, et[maxn];\nstruct Edge{\n int to, l1, l2;\n Edge(int to, int l1, int l2){\n this->to = to;\n this->l1 = l1;\n this->l2 = l2;\n }\n};\nstruct Node{\n int idx, t;\n inline bool operator < (const Node &other) const{\n return t < other.t;\n }\n Node(int idx, int t){\n this->idx = idx;\n this->t = t;\n }\n};\nvector<Edge> to[maxn];\ninline void clear_vec(vector<Edge> &vec){\n vector<Edge> empty;\n swap(empty, vec);\n}\ninline void solve(){\n cin >> n >> m;\n cin >> t0 >> t1 >> t2;\n for(int i = 1; i <= n; ++i)\n clear_vec(to[i]);\n for(int i = 1; i <= n; ++i)\n et[i] = ninf;\n for(int i = 0; i < m; ++i){\n int u, v, l1, l2;\n cin >> u >> v >> l1 >> l2;\n to[u].push_back(Edge(v, l1, l2));\n to[v].push_back(Edge(u, l1, l2));\n }\n priority_queue<Node> pq;\n pq.push(Node(n, t0));\n int rt;\n while(!pq.empty()){\n Node top = pq.top();\n pq.pop();\n // cerr << \"VIS: \" << top.idx << ' ' << top.t << endl;\n rt = top.t;\n // cerr << et[top.idx] << endl;\n if(et[top.idx] != ninf)\n continue;\n et[top.idx] = rt;\n for(auto e: to[top.idx])\n if(et[e.to] == ninf){\n if(rt <= t1 || rt - e.l1 >= t2)\n pq.push(Node(e.to, rt - e.l1));\n else\n pq.push(Node(e.to, max(rt - e.l2, t1 - e.l1)));\n }\n }\n // for(int i = 1; i <= n; ++i)\n // cerr << et[i] << \" \";\n // cerr << endl;\n cout << max(-1, et[1]) << endl;\n}\nint main(){\n cin.tie(0)->sync_with_stdio(false);\n cin >> T;\n while(T--)\n solve();\n return 0;\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 276274261,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\nimport java.io.*;\nimport java.util.*;\n \npublic class Main {\n public static int INF = 0x3f3f3f3f, mod = 1000000007, mod9 = 998244353;\n public static void main(String args[]){\n try {\n PrintWriter o = new PrintWriter(System.out);\n boolean multiTest = true;\n // init\n if(multiTest) {\n int t = nextInt(), loop = 0;\n while (loop < t) {loop++;solve(o);}\n } else solve(o);\n o.close();\n } catch (Exception e) {e.printStackTrace();}\n }\n static List<int[]>[] G;\n static int n, m;\n static int[] t;\n static void solve(PrintWriter o) {\n try {\n n = nextInt();\n m = nextInt();\n t = new int[3];\n for(int i=0;i<3;i++) t[i] = nextInt();\n G = new ArrayList[n];\n Arrays.setAll(G, key->new ArrayList<>());\n for(int i=0;i<m;i++) {\n int u = nextInt(), v = nextInt();\n u--;v--;\n int l1 = nextInt(), l2 = nextInt();\n G[u].add(new int[]{v, l1, l2});\n G[v].add(new int[]{u, l1, l2});\n }\n int l = 0, r = t[0]+1;\n while(l < r) {\n int mi = (l+r)>>1;\n if(check(mi)) l = mi+1;\n else r = mi;\n }\n if(l == 0) {\n o.println(-1);\n return;\n }\n o.println(l-1);\n } catch (Exception e) {\n e.printStackTrace();\n }\n }\n static boolean check(int m) {\n int[] dist = new int[n];\n Arrays.fill(dist, Integer.MAX_VALUE);\n dist[0] = m;\n PriorityQueue<int[]> queue = new PriorityQueue<>((x,y)->Integer.compare(x[1], y[1]));\n queue.offer(new int[]{0, m});\n while(!queue.isEmpty()) {\n int[] it = queue.poll();\n int u = it[0], now = it[1];\n if(now > dist[u]) continue;\n if(u == n-1) {\n return true;\n }\n for(int[] it1: G[u]) {\n int v = it1[0], w1 = it1[1], w2 = it1[2];\n boolean used = false;\n if(now+w1 <= t[0]) {\n if((now < t[1] && now+w1 <= t[1] || now >= t[2]) && now+w1 < dist[v]) {\n dist[v] = now+w1;\n queue.offer(new int[]{v, now+w1});\n used = true;\n }\n }\n if(!used) {\n int comp1 = Integer.MAX_VALUE, comp2 = Integer.MAX_VALUE;\n if(now < t[2] && t[2]+w1 <= t[0] && t[2]+w1 < dist[v]) comp1 = t[2]+w1;\n if(now+w2 <= t[0] && now+w2 < dist[v]) comp2 = now+w2;\n comp1 = Math.min(comp1, comp2);\n if(comp1 < dist[v]) queue.offer(new int[]{v, comp1});\n }\n }\n }\n return false;\n }\n public static int upper_bound(int[] a, int val){\n int l = 0, r = a.length;\n while(l < r){\n int mid = l + (r - l) / 2;\n if(a[mid] <= val) l = mid + 1;\n else r = mid;\n }\n return l;\n }\n public static int lower_bound(int[] a, int val){\n int l = 0, r = a.length;\n while(l < r){\n int mid = l + (r - l) / 2;\n if(a[mid] < val) l = mid + 1;\n else r = mid;\n }\n return l;\n }\n public static long gcd(long a, long b) {\n return b == 0 ? a : gcd(b, a%b);\n }\n public static long[] extgcd(long a, long b) {\n if(b == 0) return new long[]{1, 0};\n long[] it = extgcd(b, a%b);\n long x = it[1], y = it[0];\n y -= a/b*x;\n return new long[]{x, y};\n }\n public static long lcm(long a, long b){\n return a / gcd(a,b)*b;\n }\n public static long qpow(long a, long n, int md){\n a %= md;\n long ret = 1l;\n while(n > 0){\n if((n & 1) == 1) ret = ret * a % md;\n n >>= 1;\n a = a * a % md;\n }\n return ret;\n }\n public static class FenWick {\n int n;\n long[] a;\n long[] tree;\n public FenWick(int n){\n this.n = n;\n a = new long[n+1];\n tree = new long[n+1];\n }\n private void add(int x, long val){\n while(x <= n){\n tree[x] += val;\n x += x&-x;\n }\n }\n private void addMx(int x, long val) {\n a[x] += val;\n tree[x] = a[x];\n while(x <= n) {\n for(int i=1;i<(x&-x);i<<=1) tree[x] = Math.max(tree[x], tree[x-i]);\n x += x&-x;\n }\n }\n private long query(int x){\n long ret = 0l;\n while(x > 0){\n ret += tree[x];\n x -= x&-x;\n }\n return ret;\n }\n private long queryMx(int l, int r) {\n long res = 0l;\n while(l <= r) {\n if(r-(r&-r) >= l) {\n res = Math.max(res, tree[r]);\n r -= r&-r;\n }\n else {\n res = Math.max(res, a[r]);\n r--;\n }\n }\n return res;\n }\n }\n static class DSU {\n int[] parent;\n public DSU(int n) {\n parent = new int[n];\n for(int i=0;i<n;i++) parent[i] = i;\n }\n public int find(int x) {\n if(parent[x] != x) parent[x] = find(parent[x]);\n return parent[x];\n }\n public void union(int x, int y) {\n int root_x = find(x);\n int root_y = find(y);\n if(root_x == root_y) return;\n parent[root_x] = root_y;\n }\n }\n private static BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));\n private static StringTokenizer tokenizer = new StringTokenizer(\"\");\n private static String next() throws IOException{\n while(!tokenizer.hasMoreTokens()){tokenizer = new StringTokenizer(reader.readLine());}\n return tokenizer.nextToken();\n }\n public static int nextInt() throws IOException {return Integer.parseInt(next());}\n public static Long nextLong() throws IOException {return Long.parseLong(next());}\n public static double nextDouble() throws IOException {return Double.parseDouble(next());}\n public static char nextChar() throws IOException {return next().toCharArray()[0];}\n public static String nextString() throws IOException {return next();}\n public static String nextLine() throws IOException {return reader.readLine();}\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 277476713,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\nimport math\nfrom collections import Counter\nimport sys\nimport heapq\n \n \n \n \ninput = sys.stdin.readline\n \nt = int(input())\n \n \n \n \n \n \nfor _ in range(t):\n n, m = map(int, input().split())\n eventTime, startCall, endCall = map(int, input().split())\n neighbourNodes = [[] for i in range(n)]\n \n \n for i in range(m):\n path, toPath, durationBus, durationWalk = map(int, input().split())\n path -= 1\n toPath -= 1\n neighbourNodes[path].append([toPath, durationBus, durationWalk])\n neighbourNodes[toPath].append([path, durationBus, durationWalk])\n \n \n def solve():\n \n \n \n leftPointer, rightPointer = 0, eventTime\n \n \n ans = float('inf')\n \n def isValid(startTime):\n \n heap = [[startTime, 0]]\n arrivalTime = [[float('inf'), float('inf')] for i in range(n)]\n arrivalTime[0][1 if startTime >= endCall else 0] = startTime\n while heap:\n currTime, currNode = heapq.heappop(heap)\n for node, durationBus, durationWalk in neighbourNodes[currNode]:\n if currTime + durationWalk <= startCall or currTime >= endCall:\n endTime = currTime + durationBus\n newState = 1 if endTime >= endCall else 0\n if arrivalTime[node][newState] > endTime:\n arrivalTime[node][newState] = endTime\n heapq.heappush(heap, [endTime, node])\n continue\n \n if endCall >= currTime >= startCall or currTime + durationBus > startCall:\n for endTime in [currTime + durationWalk, endCall + durationBus]:\n newState = 1 if endTime >= endCall else 0\n if arrivalTime[node][newState] > endTime:\n arrivalTime[node][newState] = endTime\n heapq.heappush(heap, [endTime, node])\n continue\n \n \n for endTime in [currTime + durationBus, currTime + durationWalk, endCall + durationBus]:\n newState = 1 if endTime >= endCall else 0\n \n if endTime <= currTime:\n continue\n if arrivalTime[node][newState] > endTime:\n arrivalTime[node][newState] = endTime\n heapq.heappush(heap, [endTime, node])\n return arrivalTime[n - 1][1] <= eventTime or arrivalTime[n - 1][0] <= endCall\n \n \n \n \n while rightPointer >= leftPointer:\n middlePointer = (leftPointer + rightPointer) // 2\n \n if isValid(middlePointer):\n ans = middlePointer\n leftPointer = middlePointer + 1\n else:\n rightPointer = middlePointer - 1\n \n return ans if ans != float('inf') else -1\n \n \n print(solve())\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 277104325,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\n# Author : Omm Praksh Sahoo\n# Calm, Down... Wrong Submission Have 10 Mins Penalty\nimport heapq\nI = lambda: input()\nII = lambda: int(input())\nMII = lambda: map(int, input().split())\nLI = lambda: list(input().split())\nLII = lambda: list(map(int, input().split()))\nLGMII = lambda: map(lambda x: int(x) - 1, input().split())\nLGLII = lambda: list(map(lambda x: int(x) - 1, input().split()))\n \n \ninf = float('inf')\n \n# #########################################################################################################\n# #-----------------------------------------------Code----------------------------------------------------#\n# #########################################################################################################\n# #\n \nimport heapq\n \ndef solve():\n n, m = MII()\n t0, t1, t2 = MII()\n \n graph = [[] for _ in range(n)]\n \n for _ in range(m):\n u, v, l1, l2 = MII()\n u -= 1\n v -= 1\n graph[u].append((v, l1, l2))\n graph[v].append((u, l1, l2))\n \n def by_bus(t_start, t_end):\n return t_end <= t1 or t_start >= t2\n \n def predicate(start_time):\n pq = [(start_time, 0)]\n dist = [inf] * n\n dist[0] = start_time\n \n while pq:\n current_time, u = heapq.heappop(pq)\n \n # Early exit if we reach the destination\n if u == n - 1 and current_time <= t0:\n return True\n \n if current_time > dist[u]:\n continue\n \n for v, l1, l2 in graph[u]:\n # Relax the edge with l1\n new_time = current_time + l1\n if by_bus(current_time, new_time) and dist[v] > new_time:\n dist[v] = new_time\n heapq.heappush(pq, (new_time, v))\n \n # Relax the edge with adjusted time\n adjusted_time = max(current_time, t2) + l1\n if dist[v] > adjusted_time:\n dist[v] = adjusted_time\n heapq.heappush(pq, (adjusted_time, v))\n \n # Relax the edge with l2\n new_time_with_l2 = current_time + l2\n if dist[v] > new_time_with_l2:\n dist[v] = new_time_with_l2\n heapq.heappush(pq, (new_time_with_l2, v))\n \n return dist[n - 1] <= t0\n \n lo, hi = 0, t0\n ans = -1\n \n while lo <= hi:\n mid = (lo + hi) // 2\n if predicate(mid):\n ans = mid\n lo = mid + 1\n else:\n hi = mid - 1\n \n return ans\n \nt1 = II()\nfor _ in range(t1):\n print(solve())\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 276326449,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\n#include <bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n \n#pragma GCC target (\"avx2\")\n#pragma GCC optimize (\"Ofast\")\n#pragma GCC optimize (\"unroll-loops\")\n \n#define f first\n#define s second\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define sz(x) ((int) (x).size())\n#define pb push_back\n#define mp make_pair\n#define int long long\n \nusing namespace std;\nusing namespace __gnu_pbds;\n \ntemplate <typename T> using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate <typename T> inline bool umin(T &a, const T &b) { if(a > b) { a = b; return 1; } return 0; }\ntemplate <typename T> inline bool umax(T &a, const T &b) { if(a < b) { a = b; return 1; } return 0; }\n \ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\n \nconst ll mod = 998244353;\nconst ll base = 1e6 + 9;\nconst ll inf = 1e18;\nconst int MAX = 2e5 + 42;\nconst int LG = 20;\n \nrandom_device rd;\nmt19937 gen(rd());\nuniform_int_distribution<ll> dis(1, inf);\n \nvoid solve() {\n int n, m;\n cin >> n >> m;\n int x, y, z;\n cin >> z >> x >> y;\n vector<vector<array<int, 3>>> g(n + 1);\n while(m--) {\n int u, v, l, r;\n cin >> u >> v >> l >> r;\n g[u].pb({v, l, r}); g[v].pb({u, l, r});\n }\n auto check = [&](int st) {\n auto dijkstra = [&](vector<pii> sources, bool flag) {\n vector<int> d(n + 1, inf);\n for(auto [v, dst] : sources) d[v] = dst;\n priority_queue<pii> q; for(int v = 1; v <= n; v++) q.push({d[v], v});\n while(sz(q)) {\n auto [dst, v] = q.top(); q.pop();\n if(d[v] != dst) continue;\n for(auto [to, a, b] : g[v]) {\n int w = (flag? b : a);\n if(d[to] > d[v] + w) {\n d[to] = d[v] + w;\n q.push({d[to], to});\n }\n }\n }\n return d;\n };\n vector<pii> sources = {mp(1, st)};\n auto d1 = dijkstra(sources, 0);\n if(d1[n] <= x) return true;\n sources.clear();\n for(int v = 1; v <= n; v++) {\n if(d1[v] <= x) sources.pb({v, d1[v]});\n }\n if(sources.empty()) sources = {mp(1, st)};\n auto d2 = dijkstra(sources, 1);\n if(d2[n] <= y) return true;\n for(int v = 1; v <= n; v++) umax(d2[v], y);\n sources.clear();\n for(int v = 1; v <= n; v++) {\n sources.pb({v, d2[v]});\n }\n auto d = dijkstra(sources, 0);\n// cout << st << \": \" << d[n] << endl;\n return d[n] <= z;\n };\n int l = 0, r = z;\n while(l <= r) {\n m = l + r >> 1;\n if(check(m)) l = m + 1;\n else r = m - 1;\n }\n cout << r << '\\n';\n}\n \nsigned main() {\n ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n int ttt = 1;\n cin >> ttt;\n while(ttt--) {\n solve();\n }\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 276231245,
"task_type": "TestCase-Eval-Task2-DO"
} |
TestCase-Eval-Task2-DO | [
{
"content": "**Task:**\nGenerate a challenging test input that exposes the bug in the buggy code of the algorithm problem:\nAlgorithm Problem:\nTitle: Call During the Journey\ntime_limit_ms: 4000\nmemory_limit_mb: 256\nDescription: You live in a city consisting of $n$ intersections and $m$ streets connecting some pairs of intersections. You can travel in either direction on each street. No two streets connect the same pair of intersections, and no street connects an intersection to itself. You can reach any intersection from any other, possibly passing through some other intersections.\n\nEvery minute, you can board a bus at intersection $u_i$ and travel for $l_{i1}$ minutes to intersection $v_i$. Conversely, you can travel from intersection $v_i$ to intersection $u_i$ in $l_{i1}$ minutes. You can only board and exit the bus at intersections. You can only board the bus at an intersection if you are currently there.\n\nYou can also walk along each street, which takes $l_{i2} > l_{i1}$ minutes.\n\nYou can make stops at intersections.\n\nYou live at intersection number $1$. Today you woke up at time $0$, and you have an important event scheduled at intersection number $n$, which you must reach no later than time $t_0$. You also have a phone call planned that will last from $t_1$ to $t_2$ minutes ($t_1 < t_2 < t_0$).\n\nDuring the phone call, you cannot ride the bus, but you can walk along any streets, make stops, or stay at home. You can exit the bus at minute $t_1$ and board the bus again at minute $t_2$.\n\nSince you want to get enough sleep, you became curious β how late can you leave home to have time to talk on the phone and still not be late for the event?\n\nInput: The first line contains an integer $t$ ($1 \\le t \\le 10^4$) β the number of test cases. The following are the descriptions of the test cases.\n\nThe first line of each test case contains two integers $n$, $m$ ($2 \\le n \\le 10^5, 1 \\le m \\le 10^5$) β the number of intersections and streets in the city.\n\nThe second line of each test case contains three integers $t_0$, $t_1$, $t_2$ ($1 \\le t_1 < t_2 < t_0 \\le 10^9$) β the start time of the event, the start time of the phone call, and its end time, respectively.\n\nThe next $m$ lines of each test case contain descriptions of the streets.\n\nThe $i$-th line contains four integers $u_i$, $v_i$, $l_{i1}$, $l_{i2}$ ($1 \\le u_i, v_i \\le n$, $u_i \\neq v_i$, $1 \\le l_{i1} < l_{i2} \\le 10^9$) β the numbers of the intersections connected by the $i$-th street, as well as the travel time along the street by bus and on foot. It is guaranteed that no two streets connect the same pair of intersections and that it is possible to reach any intersection from any other.\n\nIt is guaranteed that the sum of the values of $n$ across all test cases does not exceed $10^5$. It is also guaranteed that the sum of the values of $m$ across all test cases does not exceed $10^5$.\n\nOutput: For each test case, output a single integer β the latest time you can leave home to have time to talk on the phone and not be late for the event. If you cannot reach the event on time, output -1.\n\nExamples:\ninput:\n7\n5 5\n100 20 80\n1 5 30 100\n1 2 20 50\n2 3 20 50\n3 4 20 50\n4 5 20 50\n2 1\n100 50 60\n1 2 55 110\n4 4\n100 40 60\n1 2 30 100\n2 4 30 100\n1 3 20 50\n3 4 20 50\n3 3\n100 80 90\n1 2 1 10\n2 3 10 50\n1 3 20 21\n3 2\n58 55 57\n2 1 1 3\n2 3 3 4\n2 1\n12 9 10\n2 1 6 10\n5 5\n8 5 6\n2 1 1 8\n2 3 4 8\n4 2 2 4\n5 3 3 4\n4 5 2 6\noutput:\n0\n-1\n60\n80\n53\n3\n2\n\nNote: \n\nBuggy Code:\nimport java.util.*;\npublic class Main{\n public static void main(String args[]){\n Scanner sc=new Scanner(System.in);\n int t=sc.nextInt();\n for(int i=0;i<t;i++){\n int n=sc.nextInt(),m=sc.nextInt(),t0=sc.nextInt(),t1=sc.nextInt(),t2=sc.nextInt();\n List<int[]> path[]=new List[n+5];\n for(int j=1;j<=n;j++){\n path[j]=new ArrayList<>();\n }\n for(int j=0;j<m;j++){\n int u=sc.nextInt(),v=sc.nextInt(),l1=sc.nextInt(),l2=sc.nextInt();\n path[u].add(new int[]{v,l1,l2});\n path[v].add(new int[]{u,l1,l2});\n }\n if(find(n,0,path,t1,t2)>t0){\n System.out.println(\"-1\");\n }\n else{\n int l=0,r=(int)1e9;\n while(l<r){\n int mid=(l+r)>>1;\n if(find(n,mid,path,t1,t2)<=t0){\n l=mid;\n }\n else{\n r=mid-1;\n }\n if(l==r-1){\n if(find(n,r,path,t1,t2)<=t0){\n l=r;\n }\n break;\n }\n }\n System.out.println(l);\n }\n }\n }\n static long find(int n,int start,List<int[]> path[],int t1,int t2){\n Queue<long[]> q=new PriorityQueue<>((a,b)->Long.compare(a[1],b[1]));\n long dis[]=new long[n+5];\n Arrays.fill(dis,(long)1e18);\n dis[1]=start;\n q.add(new long[]{1,start});\n while(!q.isEmpty()){\n long a[]=q.poll();\n if(dis[(int)a[0]]<a[1]){\n continue;\n }\n for(int b[]:path[(int)a[0]]){\n long d=a[1]+b[2];\n if(dis[b[0]]>d){\n q.add(new long[]{b[0],d});\n dis[b[0]]=d;\n }\n d=a[1]+b[1];\n if(!(d<=t1||a[1]>=t2)){\n d=t2+b[1];\n }\n if(dis[b[0]]>d){\n q.add(new long[]{b[0],d});\n dis[b[0]]=d;\n }\n }\n }\n return dis[n];\n }\n}\n\n\n**Instructions:**\n- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.\n- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.\n- Output the test input directly, not code to generate it.\n\n\n**Output format:**\n```plaintext\n{test input}\n```\n\n\nOnly output the test input, no explanations.",
"role": "user"
}
]
| TestCase-Eval | null | {
"problem_id": "2000G",
"submission_id": 288835419,
"task_type": "TestCase-Eval-Task2-DO"
} |
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