Body: <p>I have a products page on which I'm filtering with Sprig.
  There are some categories in the form of checkboxes.
  These categories have some subcategories.
  The categories are a structured section with nested categories.</p>
  <p>Example:</p>
  <ul>
  <li>Category 1
  <ul>
  <li>Subcategory a</li>
  <li>Subcategory b</li>
  </ul>
  </li>
  <li>Category 2
  <ul>
  <li>Subcategory c</li>
  <li>Subcategory d</li>
  </ul>
  </li>
  </ul>
  <p>What I currently got working is to show the level 2 categories filters based on the chosen main category.
  What does not work is doing the same but for 2 main categories at the same time.</p>
  <p>When the user clicks <code>Category 1</code> I want to a query to return <code>Subcategory a</code> and <code>Subcategory b</code>.</p>
  <p>When the user clicks <code>Category 1</code> AND <code>Category 2</code> I want to a query to return <code>Subcategory a</code>, <code>Subcategory b</code>, <code>Subcategory c</code> and <code>Subcategory d</code>.</p>
  <p>My query:</p>
  <pre><code>{% set typeOptions = craft.entries()
   .section('categories')
   .orderBy('title ASC')
   .descendantOf(subcategories|join(','))
   .descendantDist(1)
  %}
  </code></pre>
  <p>The reason why I am using <code>join</code> is because <code>descendantOf</code> does not accept an array and it seems it also does not accept comma separated string.
  It does accept a non comma separated string. I'm guessing it converts it to an INT internally.</p>
  <p>How do I fix this?</p>
  
Comments.ContentLicense: CC BY-SA 4.0
Comments.CreationDate: 2023-09-22T18:25:28.773Z
Comments.Text: Can you let us know what subcategories is defined as in your codebase? Seeing how you defined it will help us know what data type it is and whether that's a factor
Comments.UserDisplayName: cherrykoda
Comments.ContentLicense: CC BY-SA 4.0
Comments.CreationDate: 2023-09-27T09:22:50.503Z
Comments.Text: It's all just a big structured section. And I'm trying to get the title field.
Comments.UserDisplayName: Matthias
Comments.ContentLicense: CC BY-SA 4.0
Comments.CreationDate: 2023-10-01T14:53:29.367Z
Comments.Text: Right, but how are you calling it? Depending how it could be an object, an ID value...
Comments.UserDisplayName: cherrykoda
Tags: <craft4><plugin-sprig><descendantof>
Title: Does descendantOf only accept a single value?
ThreadText: # Does descendantOf only accept a single value?
  
  (Asked by: username_0 on 2023-09-15)
  
  I have a products page on which I'm filtering with Sprig.
  There are some categories in the form of checkboxes.
  These categories have some subcategories.
  The categories are a structured section with nested categories.
  
  Example:
  
  * Category 1
    + Subcategory a
    + Subcategory b
  * Category 2
    + Subcategory c
    + Subcategory d
  
  What I currently got working is to show the level 2 categories filters based on the chosen main category.
  What does not work is doing the same but for 2 main categories at the same time.
  
  When the user clicks `Category 1` I want to a query to return `Subcategory a` and `Subcategory b`.
  
  When the user clicks `Category 1` AND `Category 2` I want to a query to return `Subcategory a`, `Subcategory b`, `Subcategory c` and `Subcategory d`.
  
  My query:
  
  ```
  {% set typeOptions = craft.entries()
   .section('categories')
   .orderBy('title ASC')
   .descendantOf(subcategories|join(','))
   .descendantDist(1)
  %}
  
  ```
  
  The reason why I am using `join` is because `descendantOf` does not accept an array and it seems it also does not accept comma separated string.
  It does accept a non comma separated string. I'm guessing it converts it to an INT internally.
  
  How do I fix this?
  
  **Tags:** craft4, plugin-sprig, descendantof
  
  > **Comments:**
  > **username_1**: Can you let us know what subcategories is defined as in your codebase? Seeing how you defined it will help us know what data type it is and whether that's a factor  
  > **username_0**: It's all just a big structured section. And I'm trying to get the title field.  
  > **username_1**: Right, but how are you calling it? Depending how it could be an object, an ID value...  
  
  ---
  
  ## 0 answers
  
  