Answers.Body: <p>There's a <code>positionedBefore</code> parameter for <code>craft.entries</code>. Use this with a criteria model filtered to
  show the entries you are interested in only.</p>
  
  <pre><code>{% set parent = entry.getParent() %}
  {% set siblingsIds = parent.getChildren().ids() %}
  
  {% set positionedBefore = craft.entries({
      id: siblingsIds,
      order: 'lft desc',
      positionedBefore: entry,
  }).total() %}
  </code></pre>
  
  <p>With the first two lines I'm getting the IDs of all of the entry's siblings. I then prepare a <code>craft.entries</code> criteria model using the siblings' IDs with the <code>id</code> parameter to query just for those entries, order them by <code>lft</code> in descending order (that's the db column Craft stores position info) and further filter with <code>positionedBefore</code> to get just the entries before <code>entry</code>.</p>
  
  <p>Calling the <code>total</code> method returns the number of entries found.</p>
  
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2016-01-14T11:12:50.873Z
Answers.Text: Very clever, I get it now. I didn't know about the `lft` column. Thank you again!
Answers.UserDisplayName: Gareth
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2016-01-14T10:51:48.807Z
Answers.Text: Thank you @carlcs that seems to work perfect, could you just expand on your answer a little to help me understand exactly what its doing?
Answers.UserDisplayName: Gareth
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2016-01-14T10:47:26.980Z
Answers.LastActivityDate: 2016-01-14T11:03:30.447Z
Answers.LastEditDate: 2016-01-14T11:03:30.447Z
Answers.UserDisplayName: carlcs
Body: <p>Is there a way in Craft to get the order property of the current entry when it's in a structure? For example say you have the following structure:</p>
  
  <ul>
  <li>Parent Page
  
  <ul>
  <li>Child One</li>
  <li>Child Two</li>
  <li>Child Three</li>
  </ul></li>
  </ul>
  
  <p>Is there a way to get what order property Child Two is in relation to its siblings so in this case it would be 1 (zero based)?</p>
  
  <p>In my templates I am wanting to be able to grab the order property for the current entry by doing something like <code>{{ entry.getOrder() }}</code>. </p>
  
Tags: <entrymodel><order>
Title: How to get the order number of the current entry in a structure
ThreadText: # How to get the order number of the current entry in a structure
  
  (Asked by: username_0 on 2016-01-14)
  
  Is there a way in Craft to get the order property of the current entry when it's in a structure? For example say you have the following structure:
  
  * Parent Page
    + Child One
    + Child Two
    + Child Three
  
  Is there a way to get what order property Child Two is in relation to its siblings so in this case it would be 1 (zero based)?
  
  In my templates I am wanting to be able to grab the order property for the current entry by doing something like `{{ entry.getOrder() }}`.
  
  **Tags:** entrymodel, order
  
  
  ---
  
  ## 1 answers
  
  ### Answer by username_1 on 2016-01-14. Score: 7 | Accepted answer
  
  There's a `positionedBefore` parameter for `craft.entries`. Use this with a criteria model filtered to
  show the entries you are interested in only.
  
  ```
  {% set parent = entry.getParent() %}
  {% set siblingsIds = parent.getChildren().ids() %}
  
  {% set positionedBefore = craft.entries({
      id: siblingsIds,
      order: 'lft desc',
      positionedBefore: entry,
  }).total() %}
  
  ```
  
  With the first two lines I'm getting the IDs of all of the entry's siblings. I then prepare a `craft.entries` criteria model using the siblings' IDs with the `id` parameter to query just for those entries, order them by `lft` in descending order (that's the db column Craft stores position info) and further filter with `positionedBefore` to get just the entries before `entry`.
  
  Calling the `total` method returns the number of entries found.
  
  > **Comments:**
  > **username_0**: Thank you @username_1 that seems to work perfect, could you just expand on your answer a little to help me understand exactly what its doing?  
  > **username_0**: Very clever, I get it now. I didn't know about the `lft` column. Thank you again!  
  
  ---
  
  