Answers.Body: <p>After some further research this <a href="http://craftcookbook.net/recipes/279" rel="nofollow">http://craftcookbook.net/recipes/279</a> was a better fit for my needs.  The code I ended up using based on the link is below.</p>
  
  <pre><code>{% set beer = [] %}
  {% set beerBrands = craft.categories.group('brandCategory').level(1).find() %}
      {% for category in beerBrands %}
           {% set beerRelatedCategories = craft.entries.section('beers').relatedTo(category).find() %}
           {% set beer = beer|merge(beerRelatedCategories) %}
      {% endfor %}
  </code></pre>
  
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2015-12-02T04:12:44.230Z
Answers.LastActivityDate: 2015-12-02T04:12:44.230Z
Answers.UserDisplayName: triplethreat23
Body: <p>I currently have entries from a section output simply using a variable like:</p>
  
  <pre><code>{% set beer = craft.entries.section('beverages') %}
  </code></pre>
  
  <p>All of the beer entries have brands assigned to them using the category field.  How can I display the beer entries by brand? I use that beer variable throughout my templates for entry counts, filters, etc. I'd like to try and keep that in tact if possible.</p>
  
  <p>I tried to use this but it seems to do more than what I need: <a href="http://craftcookbook.net/recipes/330" rel="nofollow">http://craftcookbook.net/recipes/330</a>.  I also tried the groupBy plugin but had no success in getting that to output anything.</p>
  
Comments.ContentLicense: CC BY-SA 3.0
Comments.CreationDate: 2015-11-26T07:02:25.660Z
Comments.Text: Is there only one category per entry, and if not, do you want to list the entry under each category assigned?
Comments.UserDisplayName: carlcs
Tags: <ordering><order>
Title: Order Entries in a Section by Category Titles
ThreadText: # Order Entries in a Section by Category Titles
  
  (Asked by: username_0 on 2015-11-25)
  
  I currently have entries from a section output simply using a variable like:
  
  ```
  {% set beer = craft.entries.section('beverages') %}
  
  ```
  
  All of the beer entries have brands assigned to them using the category field. How can I display the beer entries by brand? I use that beer variable throughout my templates for entry counts, filters, etc. I'd like to try and keep that in tact if possible.
  
  I tried to use this but it seems to do more than what I need: <http://craftcookbook.net/recipes/330>. I also tried the groupBy plugin but had no success in getting that to output anything.
  
  **Tags:** ordering, order
  
  > **Comments:**
  > **username_1**: Is there only one category per entry, and if not, do you want to list the entry under each category assigned?  
  
  ---
  
  ## 1 answers
  
  ### Answer by username_0 on 2015-12-02. Score: 1
  
  After some further research this <http://craftcookbook.net/recipes/279> was a better fit for my needs. The code I ended up using based on the link is below.
  
  ```
  {% set beer = [] %}
  {% set beerBrands = craft.categories.group('brandCategory').level(1).find() %}
      {% for category in beerBrands %}
           {% set beerRelatedCategories = craft.entries.section('beers').relatedTo(category).find() %}
           {% set beer = beer|merge(beerRelatedCategories) %}
      {% endfor %}
  
  ```
  
  
  ---
  
  