Answers.Body: <p>You have to select the "level" in the structure. Im guessing the products are always on level 4? If so you could try this:</p>
  
  <pre><code>{% set entries = craft.entries.section('yourSectionHandle').level(4) %}
  
  {% for entry in entries %}
      ...
  {% endfor %}
  </code></pre>
  
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2017-03-31T11:24:32.917Z
Answers.LastActivityDate: 2017-03-31T11:24:32.917Z
Answers.UserDisplayName: Justin Dekkers
Body: <p>I have a structure section with entry url format: "products/{slug}". 
  All entries have they urls like "/products/category1/subcategory1/product1". </p>
  
  <p>Currently, I have a header navigation which opens product category pages like "products/category1".What is the preferred way to define "/product" page? </p>
  
Tags: <sections>
Title: How to define section parent page?
ThreadText: # How to define section parent page?
  
  (Asked by: username_0 on 2017-03-31)
  
  I have a structure section with entry url format: "products/{slug}".
  All entries have they urls like "/products/category1/subcategory1/product1".
  
  Currently, I have a header navigation which opens product category pages like "products/category1".What is the preferred way to define "/product" page?
  
  **Tags:** sections
  
  
  ---
  
  ## 1 answers
  
  ### Answer by username_1 on 2017-03-31. Score: 1
  
  You have to select the "level" in the structure. Im guessing the products are always on level 4? If so you could try this:
  
  ```
  {% set entries = craft.entries.section('yourSectionHandle').level(4) %}
  
  {% for entry in entries %}
      ...
  {% endfor %}
  
  ```
  
  
  ---
  
  