Body: <p>What's the most performant way to get reverse related entries within an Element Query?</p>
  
  <p>Here's a contrived example of this.</p>
  
  <p>I have thousands of "book" entries and thousands of "collection" entries. I need to generate a list of all the books and present a comma separated list of the collections it appears in. Some books might be in 10 collections, some might be in 50+.</p>
  
  <p>Unfortunately, the code below creates the n+1 query problem. But I can't eager load this because this is a reverse relationship.</p>
  
  <p>How could I achieve this in a more performant way?</p>
  
  <pre class="lang-php prettyprint-override"><code>&lt;?php
  
  $query = Entry::find()
      -&gt;section('books')
      -&gt;all();
  
  foreach ($query as $book) {
    $data[] = [
      "title" =&gt; $book-&gt;title,
      "author" =&gt; $book-&gt;authorName,
      "inCollections" =&gt; $this-&gt;_getBookCollections($book)
    ];
  }
  
  // ... later in the class
  
  private function _getBookCollections($book)
  {
      $query = Entry::find()
        -&gt;section('collections')
        -&gt;relatedTo($book)
        -&gt;all();
  
      return implode(", ", ArrayHelper::getColumn($query, "title"));
  }
  </code></pre>
  
Comments.ContentLicense: CC BY-SA 4.0
Comments.CreationDate: 2019-03-29T21:26:09.027Z
Comments.Text: Can't copy/write the code right now but the "best" way would be to create a custom behavior that enables you to eager load them directly as Crafts default eager loading does. The only reason you can't perform it by default is because your entry doesn't contain the field so there is no property to store the elements thus using a behavior will help you out. I'll post a more detailed answer on Monday
Comments.UserDisplayName: Robin Schambach
Comments.ContentLicense: CC BY-SA 4.0
Comments.CreationDate: 2019-03-30T01:37:17.623Z
Comments.Text: Thanks for the heads up, @RobinSchambach! Yeah, if you don't mind sharing an example of such a thing when you get time that would be awesome. Really appreciate it!
Comments.UserDisplayName: Aaron Bushnell
Tags: <plugin-development><relations><performance><query><elementquery>
Title: What's the most performant way to get reverse related entries within an Element Query?
ThreadText: # What's the most performant way to get reverse related entries within an Element Query?
  
  (Asked by: username_0 on 2019-03-29)
  
  What's the most performant way to get reverse related entries within an Element Query?
  
  Here's a contrived example of this.
  
  I have thousands of "book" entries and thousands of "collection" entries. I need to generate a list of all the books and present a comma separated list of the collections it appears in. Some books might be in 10 collections, some might be in 50+.
  
  Unfortunately, the code below creates the n+1 query problem. But I can't eager load this because this is a reverse relationship.
  
  How could I achieve this in a more performant way?
  
  ```php
  <?php
  
  $query = Entry::find()
      ->section('books')
      ->all();
  
  foreach ($query as $book) {
    $data[] = [
      "title" => $book->title,
      "author" => $book->authorName,
      "inCollections" => $this->_getBookCollections($book)
    ];
  }
  
  // ... later in the class
  
  private function _getBookCollections($book)
  {
      $query = Entry::find()
        ->section('collections')
        ->relatedTo($book)
        ->all();
  
      return implode(", ", ArrayHelper::getColumn($query, "title"));
  }
  
  ```
  
  **Tags:** plugin-development, relations, performance, query, elementquery
  
  > **Comments:**
  > **username_1**: Can't copy/write the code right now but the "best" way would be to create a custom behavior that enables you to eager load them directly as Crafts default eager loading does. The only reason you can't perform it by default is because your entry doesn't contain the field so there is no property to store the elements thus using a behavior will help you out. I'll post a more detailed answer on Monday  
  > **username_0**: Thanks for the heads up, @username_1! Yeah, if you don't mind sharing an example of such a thing when you get time that would be awesome. Really appreciate it!  
  
  ---
  
  ## 0 answers
  
  