Answers.Body: <p>It needs to be:</p>
  
  <pre><code>{destination.first().slug}
  </code></pre>
  
  <p>Or if this is for Craft 3:</p>
  
  <pre><code>{destination.one().slug}
  </code></pre>
  
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2018-01-24T02:51:58.880Z
Answers.LastActivityDate: 2018-01-24T02:51:58.880Z
Answers.UserDisplayName: Brandon Kelly
Body: <p>I have a channel with an entry type which has a simple dropdown for <code>{region}</code> and an entries fieldtype which links to a channel of destinations.</p>
  
  <p>I'd like the URL format for the channel to be <code>/region/destination/slug</code>. If I do <code>/{region}/{destination.url}/{slug}</code> the output is <code>/region-name//entry-slug</code>, i.e. nothing is output for the destination.</p>
  
  <p>What should I have where I currently have <code>{destination.url}</code>?</p>
  
Tags: <url><entries-field>
Title: Setting channel url format to include value of entries fieldtype URL
ThreadText: # Setting channel url format to include value of entries fieldtype URL
  
  (Asked by: username_0 on 2018-01-24)
  
  I have a channel with an entry type which has a simple dropdown for `{region}` and an entries fieldtype which links to a channel of destinations.
  
  I'd like the URL format for the channel to be `/region/destination/slug`. If I do `/{region}/{destination.url}/{slug}` the output is `/region-name//entry-slug`, i.e. nothing is output for the destination.
  
  What should I have where I currently have `{destination.url}`?
  
  **Tags:** url, entries-field
  
  
  ---
  
  ## 1 answers
  
  ### Answer by username_1 on 2018-01-24. Score: 4 | Accepted answer
  
  It needs to be:
  
  ```
  {destination.first().slug}
  
  ```
  
  Or if this is for Craft 3:
  
  ```
  {destination.one().slug}
  
  ```
  
  
  ---
  
  