<p>Alcohol content is not the primary driver of the cost of beer and so unfortunately there is not formula for directly mapping the price of a beer to its alcohol content. There are a number of ingredients in beer, and the non-alcohol producing ingredients (hops and other flavoring ingredients) can easily cost as much or more than the ingredients that produce the alcohol (malts, adjuncts, other fermentable sugars.)</p>
<p>This is why some extremely high alcohol beverages (malt beverages, cheap vodka) can cost far less per ounce than a high quality, considerably lower alcohol beer.</p>
<p><strong>HOWEVER</strong>:  If you're not looking for a general formula, but want to compare two specific beers, the formula would be to multiply the ABV by the unit of measure for the beer (ounces here in the U.S.) and then divide the results by the price.</p>
<p><strong>EXAMPLE</strong>: So I have two beers, one that is 12oz and 4.9% ABV, and costs $0.83 per can, and a second beer that is 16oz and 9.2% ABV, and costs $3.00 per can.</p>
<p>For beer one I multiple the alcohol times the quantity 0.049 * 12 = 0.588  (It contains 0.588oz of alcohol per can.) Now I divide the price ($0.83) by the alcohol content (0.588) and I find that the first beer costs $1.42 per ounce of alcohol.</p>
<p>For beer two I multiple the alcohol times the quantity 0.092 * 16 = 1.472  (It contains 1.472oz of alcohol per can.) Now I divide the price ($3.00) by the alcohol content (1.472) and I find that the second beer costs $2.04 per ounce of alcohol.</p>
<p>So, in this specific case, the lower alcohol beer delivers more alcohol for the price.  ($1.42/oz vs. $2.04/oz.)</p>
<p><strong>GENERAL FORMULA</strong>: Units are as you give them (Use price in dollars and volume in ounces to get $/ounce -- Use price in Euros and volume in milliliters to get €/ml -- etc.)</p>
<p>Price of alcohol content = [Price of package of beer] / ([Units per package] * [Volume per unit] * [ABV])</p>

CC BY-SA 4.0
2021-04-20T22:32:38.680Z
If it’s dollars per ounce of alcohol, don’t you need to divide the price by the volume of alcohol not multiply?
Eric S
CC BY-SA 4.0
2021-04-21T13:20:09.827Z
@EricS Indeed, and I'm not sure how I missed that moving between the calculation and the write up. Thanks!
Xander
CC BY-SA 4.0
2021-04-21T14:33:04.917Z
No problem. I deleted my answer since you corrected yours. As a slight improvement it might be nice to actually show an equation. I know I like that in addition to the text description. Perhaps also an example with metric units (and euros).
Eric S
CC BY-SA 4.0
2021-04-22T17:29:33.470Z
@EricS Those are good ideas as well...I'll update when I get a few minutes, or feel free to submit an edit if you like!
Xander
CC BY-SA 4.0
2021-04-23T08:51:47.910Z
Other factors that may be a bit less easy to quantify are branding and size of the company. Small start-ups crafting small batches simply have to charge more than big corporations...
Tim Burnett - Bassist
CC BY-SA 4.0
2021-04-20T14:24:41.043Z
2021-05-27T18:11:30.550Z
2021-05-27T18:11:30.550Z
Xander
<p>Price per Alcohol content of beer formula</p>
<p>Can someone post the formula for the problem of finding an equation to determine the price of the alcohol content in a beer? I've been trying to figure it out but am having trouble figure it out. Basically I am trying to find out which beer will people drink the cheapest, its probably a a cheap blue and silver can but it could be a high ABV% IPA or something pricier per beer but with I higher ABV%.</p>

CC BY-SA 4.0
2021-04-20T16:21:10.617Z
No one I know is actually trying to get the most alcohol per dollar when they buy beer. People buy cheap beer because it's cheep and good beer because of taste.
Eric S
CC BY-SA 4.0
2021-04-22T07:18:50.127Z
The question has also been discussed at https://math.stackexchange.com/questions/1422450/alcohol-percentage/1422464
cyberixae
CC BY-SA 4.0
2021-04-27T18:53:40.437Z
Why?  What is the purpose of you knowing "*the price of the alcohol content in a beer?*"
Alaska Man
<alcohol>
Price per Alcohol content of beer formula?
chris
# Price per Alcohol content of beer formula?

(Asked by: username_0 on 2021-04-19)

Price per Alcohol content of beer formula

Can someone post the formula for the problem of finding an equation to determine the price of the alcohol content in a beer? I've been trying to figure it out but am having trouble figure it out. Basically I am trying to find out which beer will people drink the cheapest, its probably a a cheap blue and silver can but it could be a high ABV% IPA or something pricier per beer but with I higher ABV%.

**Tags:** alcohol

> **Comments:**
> **username_1**: No one I know is actually trying to get the most alcohol per dollar when they buy beer. People buy cheap beer because it's cheep and good beer because of taste.  
> **username_2**: The question has also been discussed at https://math.stackexchange.com/questions/1422450/alcohol-percentage/1422464  
> **username_3**: Why?  What is the purpose of you knowing "*the price of the alcohol content in a beer?*"  

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## 1 answers

### Answer by username_4 on 2021-04-20. Score: 2

Alcohol content is not the primary driver of the cost of beer and so unfortunately there is not formula for directly mapping the price of a beer to its alcohol content. There are a number of ingredients in beer, and the non-alcohol producing ingredients (hops and other flavoring ingredients) can easily cost as much or more than the ingredients that produce the alcohol (malts, adjuncts, other fermentable sugars.)

This is why some extremely high alcohol beverages (malt beverages, cheap vodka) can cost far less per ounce than a high quality, considerably lower alcohol beer.

**HOWEVER**: If you're not looking for a general formula, but want to compare two specific beers, the formula would be to multiply the ABV by the unit of measure for the beer (ounces here in the U.S.) and then divide the results by the price.

**EXAMPLE**: So I have two beers, one that is 12oz and 4.9% ABV, and costs $0.83 per can, and a second beer that is 16oz and 9.2% ABV, and costs $3.00 per can.

For beer one I multiple the alcohol times the quantity 0.049 \* 12 = 0.588 (It contains 0.588oz of alcohol per can.) Now I divide the price ($0.83) by the alcohol content (0.588) and I find that the first beer costs $1.42 per ounce of alcohol.

For beer two I multiple the alcohol times the quantity 0.092 \* 16 = 1.472 (It contains 1.472oz of alcohol per can.) Now I divide the price ($3.00) by the alcohol content (1.472) and I find that the second beer costs $2.04 per ounce of alcohol.

So, in this specific case, the lower alcohol beer delivers more alcohol for the price. ($1.42/oz vs. $2.04/oz.)

**GENERAL FORMULA**: Units are as you give them (Use price in dollars and volume in ounces to get $/ounce -- Use price in Euros and volume in milliliters to get €/ml -- etc.)

Price of alcohol content = [Price of package of beer] / ([Units per package] \* [Volume per unit] \* [ABV])

> **Comments:**
> **username_1**: If it’s dollars per ounce of alcohol, don’t you need to divide the price by the volume of alcohol not multiply?  
> **username_4**: @username_1 Indeed, and I'm not sure how I missed that moving between the calculation and the write up. Thanks!  
> **username_1**: No problem. I deleted my answer since you corrected yours. As a slight improvement it might be nice to actually show an equation. I know I like that in addition to the text description. Perhaps also an example with metric units (and euros).  
> **username_4**: @username_1 Those are good ideas as well...I'll update when I get a few minutes, or feel free to submit an edit if you like!  
> **username_5**: Other factors that may be a bit less easy to quantify are branding and size of the company. Small start-ups crafting small batches simply have to charge more than big corporations...  

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