<p>Simple multiplication will find that:</p>

<pre><code>0.01724138 BTC / 10 USD * 
1 DRK / 0.017669 BTC =
0.01724138/10/0.017669 DRK/USD ~=
0.975798 DRK / 10 USD
</code></pre>

<p>10 USD is just under 1 DRK.</p>

<blockquote>
  <p>Also, Is there an equivalent site like blockchain.info for each coin?</p>
</blockquote>

<p>Most altcoins do have one or more <a href="https://en.bitcoin.it/wiki/Block_chain_browser" rel="nofollow">block chain browser</a>/explorer sites. Searching for "[altcoin name] blockchain explorer" will usually find one.</p>

CC BY-SA 3.0
2014-06-13T22:35:38.027Z
2014-06-14T00:00:14.737Z
2014-06-14T00:00:14.737Z
Tim S.
<p>With <a href="https://blockchain.info/tobtc?currency=USD&amp;value=10" rel="nofollow">https://blockchain.info/tobtc?currency=USD&amp;value=10</a></p>

<p>I find that $10 = 0.01724138 BTC</p>

<p>And with <a href="https://data.bter.com/api/1/ticker/drk_btc" rel="nofollow">https://data.bter.com/api/1/ticker/drk_btc</a></p>

<p>I find that 1 DRK = 0.017669 BTC</p>

<p>How can I get from those two bits of info $10 worth of DRK?</p>

<p>Also, Is there an equivalent site like blockchain.info for each coin?</p>

<exchange-rate>
$10 worth of DRK
BENZ.404
# $10 worth of DRK

(Asked by: username_0 on 2014-06-13)

With <https://blockchain.info/tobtc?currency=USD&value=10>

I find that $10 = 0.01724138 BTC

And with <https://data.bter.com/api/1/ticker/drk_btc>

I find that 1 DRK = 0.017669 BTC

How can I get from those two bits of info $10 worth of DRK?

Also, Is there an equivalent site like blockchain.info for each coin?

**Tags:** exchange-rate


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## 1 answers

### Answer by username_1 on 2014-06-13. Score: 3 | Accepted answer

Simple multiplication will find that:
0.01724138 BTC / 10 USD * 
1 DRK / 0.017669 BTC =
0.01724138/10/0.017669 DRK/USD ~=
0.975798 DRK / 10 USD

10 USD is just under 1 DRK.

Also, Is there an equivalent site like blockchain.info for each coin?

Most altcoins do have one or more block chain browser/explorer sites. Searching for "[altcoin name] blockchain explorer" will usually find one.


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