<p>The first: BTC/day= 24 / (D * 2^32 / (H * 10^6) / 60 / 60) * C</p>
<p>The second: BTC/day=  (H*B/D) * 20.11626</p>
<p>In the first formula that I find in a discussion, I can't understand the mathematic form. In my opinion is not clear the sequences of the fraction and how I can pass from the first to the second.
Could be helpful a legend to describe what is the significate the numbers inside the formula.
Thanks in advance.</p>

CC BY-SA 4.0
2022-01-01T00:21:29.553Z
Please add more information explaining where you got those equations from and what all the variables mean. For example, what are D, H, and B. The first equation has no B in it, so they're obviously not equivalent.
meshcollider
CC BY-SA 4.0
2022-01-01T00:25:30.407Z
I've closed this as a duplicate because all the equations you mentioned are explained in the answers and comments of the question I linked.
meshcollider
CC BY-SA 4.0
2022-01-02T19:29:03.340Z
Ok I understand.
Enrico Iacobbi
<mining-profitability>
Are there someone can explain me how to go from the first to the second? Thanks
Enrico Iacobbi
# Are there someone can explain me how to go from the first to the second? Thanks

(Asked by: username_0 on 2021-12-31)

The first: BTC/day= 24 / (D \* 2^32 / (H \* 10^6) / 60 / 60) \* C

The second: BTC/day= (H\*B/D) \* 20.11626

In the first formula that I find in a discussion, I can't understand the mathematic form. In my opinion is not clear the sequences of the fraction and how I can pass from the first to the second.
Could be helpful a legend to describe what is the significate the numbers inside the formula.
Thanks in advance.

**Tags:** mining-profitability

> **Comments:**
> **username_1**: Please add more information explaining where you got those equations from and what all the variables mean. For example, what are D, H, and B. The first equation has no B in it, so they're obviously not equivalent.  
> **username_1**: I've closed this as a duplicate because all the equations you mentioned are explained in the answers and comments of the question I linked.  
> **username_0**: Ok I understand.  

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