<p>Yes, absolutely you can. I think the article intend &quot;the simplest case&quot; in the real world usage, where is highly unlikely that you have to pay the exact amount of one of your UTXO, if not they are wrong and your example is the simplest transaction you can made.</p>

CC BY-SA 4.0
2021-04-23T12:07:34.467Z
2021-04-23T12:13:33.913Z
2021-04-23T12:13:33.913Z
leevancleef
<p>While reading about the fees here <a href="https://metamug.com/article/security/bitcoin-transaction-fee-satoshi-per-byte.html" rel="nofollow noreferrer">https://metamug.com/article/security/bitcoin-transaction-fee-satoshi-per-byte.html</a></p>
<p>The article said that &quot;In the simplest case, you'll have one input and two outputs (the recipient, and change). So in=1 and out=2.&quot;</p>
<p>Does that mean that I cannot send the entire amount from one address to another? I thought that the simplest case is <code>in=1</code> and <code>out=1</code>. And that <code>in = out + fee</code></p>

<transactions><change><output>
Can you have a transaction without a change output?
igobivo
# Can you have a transaction without a change output?

(Asked by: username_0 on 2021-04-23)

While reading about the fees here <https://metamug.com/article/security/bitcoin-transaction-fee-satoshi-per-byte.html>

The article said that "In the simplest case, you'll have one input and two outputs (the recipient, and change). So in=1 and out=2."

Does that mean that I cannot send the entire amount from one address to another? I thought that the simplest case is `in=1` and `out=1`. And that `in = out + fee`

**Tags:** transactions, change, output


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## 1 answers

### Answer by username_1 on 2021-04-23. Score: 4 | Accepted answer

Yes, absolutely you can. I think the article intend "the simplest case" in the real world usage, where is highly unlikely that you have to pay the exact amount of one of your UTXO, if not they are wrong and your example is the simplest transaction you can made.


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