Answers.Body: <p>Apparently, the frames are dropped at the same cadence, but with double frequency.</p>
  
  <p>From FFmpeg's timecode drop function,</p>
  
  <pre><code>if (fps == 30) {
      drop_frames = 2;
      frames_per_10mins = 17982;
  } else if (fps == 60) {
      drop_frames = 4;
      frames_per_10mins = 35964;
  } 
  ....
  d = framenum / frames_per_10mins;
  m = framenum % frames_per_10mins;
  
  return framenum + 9*drop_frames*d + drop_frames*((m - drop_frames)/(frames_per_10mins/10));
  </code></pre>
  
  <p>and the string is</p>
  
  <pre><code>ff = framenum % fps;
  ss = framenum / fps      % 60;
  mm = framenum / (fps*60) % 60;
  hh = framenum / (fps*3600) % 24;
  </code></pre>
  
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2017-11-05T10:34:21.857Z
Answers.Text: Great idea. So from that code it really looks like the pattern of dropping every minute excepts tens of minutes is the same but dropping 4 instead of 2 frames.
Answers.UserDisplayName: Sebastian
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2017-11-02T06:09:15.387Z
Answers.LastActivityDate: 2017-11-02T06:09:15.387Z
Answers.UserDisplayName: Gyan
Body: <p>The pattern for dropping frames in 29.97 drop-frame SMPTE timecode is well documented (2 frames at every minute except when minute is a multiple of 10).</p>
  
  <p>I was wondering how it works with 59.94 fps drop-frame timecode? I guess it needs to be twice the amount of frames dropped, but what is the exact pattern?</p>
  
Tags: <timecode>
Title: How are frames in 59.94 drop-frame timecode dropped?
UserDisplayName: Sebastian
ThreadText: # How are frames in 59.94 drop-frame timecode dropped?
  
  (Asked by: username_0 on 2017-11-01)
  
  The pattern for dropping frames in 29.97 drop-frame SMPTE timecode is well documented (2 frames at every minute except when minute is a multiple of 10).
  
  I was wondering how it works with 59.94 fps drop-frame timecode? I guess it needs to be twice the amount of frames dropped, but what is the exact pattern?
  
  **Tags:** timecode
  
  
  ---
  
  ## 1 answers
  
  ### Answer by username_1 on 2017-11-02. Score: 5 | Accepted answer
  
  Apparently, the frames are dropped at the same cadence, but with double frequency.
  
  From FFmpeg's timecode drop function,
  
  ```
  if (fps == 30) {
      drop_frames = 2;
      frames_per_10mins = 17982;
  } else if (fps == 60) {
      drop_frames = 4;
      frames_per_10mins = 35964;
  } 
  ....
  d = framenum / frames_per_10mins;
  m = framenum % frames_per_10mins;
  
  return framenum + 9*drop_frames*d + drop_frames*((m - drop_frames)/(frames_per_10mins/10));
  
  ```
  
  and the string is
  
  ```
  ff = framenum % fps;
  ss = framenum / fps      % 60;
  mm = framenum / (fps*60) % 60;
  hh = framenum / (fps*3600) % 24;
  
  ```
  
  > **Comments:**
  > **username_0**: Great idea. So from that code it really looks like the pattern of dropping every minute excepts tens of minutes is the same but dropping 4 instead of 2 frames.  
  
  ---
  
  