text: Title: how to create a single field filter?
  Body: I am trying to define a field on a type that can be filtered, the field only returns 1 object so no list.
  my attempt is this:
  ```
      chat: auto = strawberry_django.field(
          field_name="chat_set",
          filters=ChatFilter,
          default_factory=lambda: None,
      )
  ```
  but it still returns a list, I wonder if there is a way to express, something like : `self.chat_set.get(filters**)` instead of `self.chat_set.filter(filters**)`?