text: Title: Inner bug: TypeError: __init__() got an unexpected keyword argument 'escape_forward_slashes'
  Body: ### Is there an existing issue for this?
  
  - [X] I have searched the existing issues
  
  ### Describe the bug
  
  i'm not sure if this is a bug, a internal exception occurred when i try to access the inspector page(http://localhost:6457/),
  
  pkgs version:
  sanic             23.3.0
  sanic-ext         23.3.0
  sanic-routing     22.8.0
  
  log:
  ```
  [ERROR] Exception occurred while handling uri: 'http://localhost:6457/'
  Traceback (most recent call last):
    File "handle_request", line 97, in handle_request
      from sanic_ext.extensions.base import Extension  # type: ignore
    File "D:\apps\Anaconda\envs\sanic\lib\site-packages\sanic\worker\inspector.py", line 82, in _info
      return await self._respond(request, self._state_to_json())
    File "D:\apps\Anaconda\envs\sanic\lib\site-packages\sanic\worker\inspector.py", line 86, in _respond
      return json(
    File "D:\apps\Anaconda\envs\sanic\lib\site-packages\sanic\response\convenience.py", line 50, in json
      return JSONResponse(
    File "D:\apps\Anaconda\envs\sanic\lib\site-packages\sanic\response\types.py", line 361, in __init__
      self._encode_body(self._use_dumps(body, **self._use_dumps_kwargs)),
    File "D:\apps\Anaconda\envs\sanic\lib\json\__init__.py", line 234, in dumps
      return cls(
  TypeError: __init__() got an unexpected keyword argument 'escape_forward_slashes'
  ```
  
  ### Code snippet
  
  _No response_
  
  ### Expected Behavior
  
  _No response_
  
  ### How do you run Sanic?
  
  As a script (`app.run` or `Sanic.serve`)
  
  ### Operating System
  
  windows
  
  ### Sanic Version
  
  Sanic 23.3.0; Routing 22.8.0
  
  ### Additional context
  
  _No response_