Question: I have a file (my\_file) and want to count how many values in column 11 have value < .05:

I try:

```
echo $($(cat my_file | cut -f 11 | awk '$1 < 5E-2'  | wc -l) / $(cat my_file | cut -f 11 |  wc -l))

```

I get `1158532: command not found`

Could anyone please help me see where I am wrong?

Answer: 
Using only `awk`:

```
awk '$11 < 0.05 {c++} END {print c}' my_file

```
```
{m,g}awk '
BEGIN {        ___=((_+=++_+_)*_+(\
           __=_*_+—-_) )^-!(_ -= _) 
} {  _+=+($__)<___ 
} END {

    printf("\n\n\tFilter hit rate :: %.*f %% ( %\47.f / %\47.f )"\
           " \n\n\t%*sFile :: %-.*s \n\n",
                    ___=__--,__*_*__/(__=NR),_,__,
             ___,____,_^=_*=_+=_^=_<_, FILENAME) } ' my_file

```

|

```
Filter hit rate :: 0.04415484271 % ( 3,588 / 8,125,949 )   

           File :: myfile 

```