Question: I'm new to Python and I'm wanting to print only the first 10 lines of a huge csv file. 

Here's my code so far that prints all of the lines in the csv file

```
import csv
with open('titanic.csv') as csvfile:
    reader = csv.DictReader(csvfile)
    for row in reader:
        print(row['survived'], row['pclass'], row['name'], row['sex'], row['age'])

```

Answer: 
Use `itertools.islice`:

```
import csv
from itertools import islice

with open('titanic.csv') as csvfile:
    reader = csv.DictReader(csvfile)
    for row in islice(reader, 10): # first 10 only
        print(row['survived'], row['pclass'], row['name'], row['sex'], row['age'])

```

While you're at it, you can also make use of `operator.itemgetter` to make the column getting a bit easier:

```
import csv
from itertools import islice
from operator import itemgetter

get_columns = itemgetter('survived', 'pclass', 'name', 'sex', 'age')

with open('titanic.csv') as csvfile:
    reader = csv.DictReader(csvfile)
    for row in islice(reader, 10): # first 10 only
        print(*get_columns(row))

```
To get top N lines from a csv file, with select fields 

```
#for python 3
import csv
from operator import itemgetter
N=11 # to get 10 rows need use 10+1=11
fname='titanic.csv'
get_columns=itemgetter('survived', 'pclass', 'name', 'sex', 'age')

with open(fname,'r') as csvfile:
    reader = csv.DictReader(csvfile.readlines()[0:N])
    [print(*get_columns(row)) for row in reader]

     # or for all fields : use [print(row)) for row in reader]

```