Question: I am practicing Selenium in Python and I wanted to fetch all the links on a web page using Selenium.

For example, I want all the links in the `href=` property of all the `<a>` tags on <http://psychoticelites.com/>

I've written a script and it is working. But, it's giving me the object address. I've tried using the `id` tag to get the value, but, it doesn't work.

My current script:

```
from selenium import webdriver
from selenium.webdriver.common.keys import Keys

driver = webdriver.Firefox()
driver.get("http://psychoticelites.com/")

assert "Psychotic" in driver.title

continue_link = driver.find_element_by_tag_name('a')
elem = driver.find_elements_by_xpath("//*[@href]")
#x = str(continue_link)
#print(continue_link)
print(elem)

```

Answer: 
I have checked and tested that there is a function named find\_elements\_by\_tag\_name() you can use. This example works fine for me.

```
elems = driver.find_elements_by_tag_name('a')
    for elem in elems:
        href = elem.get_attribute('href')
        if href is not None:
            print(href)

```
```
import requests
from selenium import webdriver
import bs4
driver = webdriver.Chrome(r'C:\chromedrivers\chromedriver') #enter the path
data=requests.request('get','https://google.co.in/') #any website
s=bs4.BeautifulSoup(data.text,'html.parser')
for link in s.findAll('a'):
    print(link)

```