Question: How do I store the following into a char array:

```
AT+CIPSTART="TCP","103.6.157.239","8085"

```

When I do the following :

```
char L []="AT+CIPSTART="TCP","103.6.157.239","8085"";

```

I get an error :

> 
> ../GPRS.c:48: error: expected ',' or ';' before 'TCP'
> 
> 
>

Answer: 
Try this

```
 char c[]="AT+CIPSTART=\"TCP\",\"103.6.157.239\",\"8085\"";

```

Micro controller escape sequences :

* \? for ?
* \\ for \
* \' for '
* \" for "
* \b for backspace
* \n for new line
* \ooo for octal number
* \t for horizontal tab
* \v for vertical tab
* \xxx for hexadecimal number
In java you can escape quotes with 'backslash' `\`. Like for storing "TCP" in string you can use

`String x= " \"TCP\" ";`

Similarly you can use this concept for storing string values in array.

More on this topic, you can refer [here](http://docs.oracle.com/javase/tutorial/java/data/characters.html).