Question: I can check, if a file exists and is a symbolic link with -L

```
for file in *; do
    if [[ -L "$file" ]]; then echo "$file is a symlink"; else echo "$file is not a symlink"; fi
done

```

and if it is a directory with -d:

```
for file in *; do
    if [[ -d "$file" ]]; then echo "$file is a directory"; else echo "$file is a regular file"; fi
done

```

But how can I test for only links to directories?

---

I simulated all cases in a test folder:

```
/tmp/test# ls
a  b  c/  d@  e@  f@

/tmp/test# file *
a: ASCII text
b: ASCII text
c: directory
d: symbolic link to `c'
e: symbolic link to `a'
f: broken symbolic link to `nofile'

```

Answer: 
Just combine the two tests with `&&`:

```bsh
if [[ -L "$file" && -d "$file" ]]
then
    echo "$file is a symlink to a directory"
fi

```

Or, for POSIX compliant-syntax, use:

```bsh
if [ -L "$file" ] && [ -d "$file" ]
...

```

*Note: the first syntax using `[[ expr1 && expr2 ]]` is valid, but only works in certain shells such as ksh (where it comes from), bash or zsh. The second syntax using `[ expr1 ] && [ expr2 ]` is POSIX-compliant and even Bourne-compatible, meaning it will work in all modern `sh` and `sh`-like shells*
A solution with `find` and using a function:

```
dosomething () {
    echo "doing something with $1"; 
}
find -L -path './*' -prune -type d| while read file; do 
    if [[ -L "$file" && -d "$file" ]];
        then dosomething "$file";
    fi; 
done

```