Question: I want make a specific element of each dictionary the first element in a list of dictionaries. How would I do this, or is it even possible given that dictionaries are unordered?

I don't want to use .sort() by itself or OrderedDict because both will not bring the desired element to the top of the keys as the keys are alphabetically ordered. Is there a way to use the lamba keyword in combination with sort in Python 2.7 to do this?

Ex:

I want `b` to be the first key 

```
{'a': 1, 'b': 2, 'c': 3}

{'b': 2, 'a': 1, 'c': 3}

```

---

CONTEXT:

I have a large set of dictionaries where each dictionary represents a bunch of info about a job. Each dictionary has a code that identifies the job. My superior would like to have this code moved to the top of its dictionary.

Answer: 
Wrap your dict in a list and move your code out. Instead of

```
data = {'code':'this is the code', 'some':'other', 'stuff':'here'}

```

do

```
data = ['this is the code', {'some':'other', 'stuff':'here'}]

```
Dicts don't have any top or bottom. You can try something like this:

```
>>> from itertools import chain
>>> dic = {'a': 1, 'b': 2, 'c': 3}
>>> key = 'b'
for k in chain(key, (dic.viewkeys()-key)):
    print k, dic[k]
...     
b 2
a 1
c 3

```

Better use an `OrderedDict`.

```
>>> from collections import OrderedDict
>>> key = 'b'
>>> dic1 = OrderedDict((k,dic[k]) for k in chain(key, (dic.viewkeys()-key)))
>>> next(iter(dic1))
'b'

```