Question: I know that with DC you can measure current by putting your meter in series with the positive supply.

I have a project running off a low voltage AC supply. Can I do the same?

Answer: 
They must mean that a smallest addressable unit is 8 bits which is called a **byte** or sometimes they even call that smallest addressable unit as a cell.By grouping these cells you get a word.

So a 64 bit computer has **8 cells**/word.So in effect they are likely x8 systems
There are so many types of memory that is hard to answer. 

What was "standardized" (wich standard ?) was the byte (octet) as a fundamental size on a computer. This means that, usually, computers have how to deal with 8 bit numbers, even if they are 32 bits. A byte is 8 bits anywhere, but the computer WORD might have other sizes, multiplies of a byte (ex.: 32bit word wich is composed of four bytes etc). It might even arrange those bytes in different orders (MSB first, LSB first etc).

But, on memories, you might find a lot of types. You might find a 8 bit EPROM, or a single bit RAM (where you need to group 8 ram chips to get a single byte, etc). Or even full 64bit memories that transfer 64bit words at a time.

But, even when all the memories have different word sizes, you can still ADDRESS all memories in 8bit boundaries.

For example :

If your "cell" was 32 bits, thats how the program would be stored in memory:

```
100 add r1, r2, r3
101 sub r3, r5, r1
102 br 100

```

If your "cell" is 8 bits, thats how it is stored in memory :

```
100 add r1, r2, r3
104 sub r3, r5, r1
108 br 100

```

In the past, some computers worked like the first example, having memories cells of 32bits (or 36, or 24 etc.), so, in that case, the "standardization" was to accept a single memory "cell" size (8bits) and work other sizes from that.

This does not mean that a computer cant access the RAM in lumps of other multiples of 8 bits (16, 32, 64, etc.). You might have instructions like

```
 MOV EAX, [BP+10000] // hipotetical, i dont know if this addressing mode exists
 // wich will transfer 4 bytes in a single cycle into the EAX.

```

But the BP+10000 in the instruction still sees the memory as made out of 8bit cells.