Question: I do not understand why nothing is showing up on the screen when I run this little program? Is the while loop even starting? 

```
#include <stdio.h>
#include <string.h>

int main()
{
  char word[20]; 
  char TryAgain[20] = "y";
  int WordLength = 0;

  while (strcmp(TryAgain, "y"))
  {
    printf("\t\t\t Word \n\n");
    printf("What is your word, bird?\n");
    scanf("%s", word);
    getchar();

    WordLength = strlen(word); 

    printf("Result: "); 
    for (int i = 0; i < WordLength; ++i)
    {
        printf("%c*", word[i]);
    }
    printf("\nWould you like to try another word? [y/n]\n");
    scanf("%s", TryAgain);
  }

  getchar();
  return 0;
}

```

Answer: 
`strcmp` returns 0 if its arguments are the same, so at the first iteration your while loop is checking `while(0)`. 0 is equivalent to `false` in boolean checks so the while loop is skipped. Try `while(!strcmp(TryAgain, "y"))`.
I prefer to change it to a do-while

```
do {
  printf("\nWould you like to try another word? [y/n]\n");
  scanf("%s", TryAgain);
} while (TryAgain=="y" || TryAgain=="Y");

```

the TryAgain must be boolean.
see ya