Question: How can I `push_back` a `struct` into a vector?

```
struct point {
    int x;
    int y;
};

std::vector<point> a;

a.push_back( ??? );

```

Answer: 
```
point mypoint = {0, 1};
a.push_back(mypoint);

```

Or if you're allowed, give `point` a constructor, so that you can use a temporary:

```
a.push_back(point(0,1));

```

Some people will object if you put a constructor in a class declared with `struct`, and it makes it non-POD, and maybe you aren't in control of the definition of `point`. So this option might not be available to you. However, you can write a function which provides the same convenience:

```
point make_point(int x, int y) {
    point mypoint = {x, y};
    return mypoint;
}

a.push_back(make_point(0, 1));

```
```
point p;
p.x = 1;
p.y = 2;

a.push_back(p);

```

Note that, since `a` is a vector of points (not pointers to them), the push\_back will create a copy of your point struct -- so `p` can safely be destroyed once it goes out of scope.