Question: The code I'm writing currently requires me to check if any item (at least one) in one dictionary is present in another dictionary.

Answer: 
How about this solution:

```
a = {"a":2, "b":4, "c":4, "d":4}
b = {"a":1, "e":1, "f":5}
print(any(a.items() & b.items()))

```

will yield output:
`False`

because there is no common items in `a` and `b`, while:

```
a = {"a":2, "b":4, "c":4, "d":4}
b = {"a":1, "b":4, "f":5}
print(any(a.items() & b.items()))

```

will yield output:
`True`

because there is one common item for `a` and `b`

It does not iterates over dictionaries directly, however as [juanpa-arrivillaga](https://stackoverflow.com/users/5014455/juanpa-arrivillaga) pointed out in comment, this solution technically uses iteration, as under the hood `any()` does iteration.
```
[item for item in dict1.items() if item in dict2.items()]

```