Question: Using operators plus, minus, multiplied by and divide by, and as many brackets as you want, can you do a formula which uses 3, 3, 5 and 7 to make 24? 

Each number must be used and can only be used once (so there will be two 3's).

So, for example, (3x7)+3 makes 24, but this isn't valid because the 5 wasn't used.

I don't know if this is possible, btw! It's in a game I'm playing.

Answer: 
I also thought about : 

> 
>  $3 \* (7 - 5) ^ 3$
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Breaks the rule but hey
Seems pretty straight forward, sorry I don't know how to hide it:

> 
> (5x7) - (3x3) = 35 - 9 = 24
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>