Question: Given to me, by a friend:

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> How would you make 20, using two threes?
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* You may use any basic operation. And others, such as square roots (the symbol), factorials, etc. Any operation is allowed.
* Just two threes, though. You can't raise a three to any digit other than three, etc.

Any out of the box, non-mathematical solutions are encouraged.

PS- Wow! That's an amazing number of responses! Quite a community, here.

EDIT: @CameronWhite and @Yly have provided, perhaps the most elegant answers. And basis your votes, I'm going ahead to mark @Cameron's answer as accepted. No issues, I hope. Although, I did think @KeyboardWielder's answer was rather crafty. And @dcyfj... Well, that would have taken some time. Awesome answer. This really isn't an edit, is this?

EDIT: Perhaps I should have specified the level of out-of-the boxness allowed. Forgive my mistake. This was, my first post, and I was surprised by the number of answers. Thanks for taking the time.

Answer: 
A little bit silly, but it gets 20 without using any *digits* other than the two '3's

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> $\lfloor3+3+\pi+\pi+\pi+e+e\rfloor$
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>  output(++(++(++3))\*(++3)); Consider this as a C expression
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