Question: I'm trying to run some basic code in C to declare 2 float variables, and then divide them and put that value in the 3rd variable. After this I print all 3.

```
#include <stdio.h>
int main ()
{
  /* variable definition: */
  float a, b, c; 
  /* variable initialization */
  a = 1.2;
  b = 2.7;  
  c = a / b;
  printf("Floats (a,b) and quotient (c) are : %d,%d,%d \n", a,b,c);  
   return 0;
}

```

I'm using the online compiler "www.ideone.com" to compile and run the code, and this is the result I'm getting:

```
Success time: 0 memory: 2156 signal:0

```

Floats (a,b) and quotient (c) are : 1073741824,1072902963,-1610612736 

Can anyone see if perhaps I made a mistake in the code? It's for a class and everything worked fine for every step of directions until I changed from int to float.

Answer: 
You want to print floats, thus change this:

```
printf("Floats (a,b) and quotient (c) are : %d,%d,%d \n", a,b,c);

```

to this:

```
printf("Floats (a,b) and quotient (c) are : %f,%f,%f \n", a,b,c);

```

For more, check the [ref](http://www.cplusplus.com/reference/cstdio/printf/).
`%d` is not a correct conversion for float, use `%f` instead

change:

```
printf("Floats (a,b) and quotient (c) are : %d,%d,%d \n", a,b,c);

```

to:

```
printf("Floats (a,b) and quotient (c) are : %f,%f,%f \n", a,b,c);

```

and you should be fine.