Question: How to cut words before the first “END” word in line, and not include the first character before the “END” word ( in our examples the character is “-“) 

Only with sed command

For example:

```
  echo AAA-BBB-CCC-END | sed ...
  AAA-BBB-CCC

  echo 1-END-3-4 | sed ...
  1     

  echo 1-2-END-3-4 | sed ...
  1-2

  echo PARAM1-PARAM2-END | sed ...
  PARAM1-PARAM2

  echo fileExample1-fileExample2-END | sed ...
  fileExample1-fileExample2

  echo xyz_123-END | sed ...
  xyz_123

```

Answer: 
```
sed "s/.END.*//"

```

This should do the trick.

It'll remove the first char before the END, and all chars after (and of course the END itself).
if your string structure always have hyphens and then the "END" word (eg -END), 

```
$ var="AAA-BBB-CCC-SEND-END"
$ echo ${var%%-END*}
AAA-BBB-CCC-SEND

```

As you can see, in case you have words like "SEND", it will still give you the correct output.

if you still prefer using sed,

```
$ echo $var | sed 's/-END.*//'
AAA-BBB-CCC-SEND

```