Question: I need help with reading the folder and opening / outputting the csv data, I have used examples other people have written but none of them have worked for me.

What I currently have is this, but it doesn't output the files:

```
$files = scandir($PathToCreate.$version."/"); //scan the folder
foreach($files as $file) { //for each file in the folder

//The following is another example I found but does not output anything I just need to open each file and be able to output / target specific data

$csv = array();
$lines = file($file, FILE_IGNORE_NEW_LINES);

foreach ($lines as $key => $value)
{
    $csv[$key] = str_getcsv($value);
} 
print_r($csv)

}

```

Answer: 
This should work for you:

(Here I first grab all files out of the directory which have the extension `*.csv` with [`glob()`](http://php.net/manual/en/function.glob.php). After this I loop through each file and read it with [`fopen()`](http://php.net/manual/en/function.fopen.php) and [`fgetcsv()`](http://php.net/manual/en/function.fgetcsv.php).)

```
<?php

    $files = glob("$PathToCreate$version/*.csv");

    foreach($files as $file) {

        if (($handle = fopen($file, "r")) !== FALSE) {
            echo "<b>Filename: " . basename($file) . "</b><br><br>";
            while (($data = fgetcsv($handle, 4096, ",")) !== FALSE) {
                echo implode("\t", $data);
            }
            echo "<br>";
            fclose($handle);
        } else {
            echo "Could not open file: " . $file;
        }

    }

?>

```
The first issue probably is that you have to ignore the two directory entries `.` and `..` which have special meaning and are not useful for you:

```
$files = scandir($PathToCreate.$version."/"); //scan the folder
foreach($files as $file) { //for each file in the folder
  if ( ! in_array($file, ['.','..'])) {
    $lines = file($file, FILE_IGNORE_NEW_LINES);
    foreach ($lines as $key => $value) {
      $csv[$key] = str_getcsv($value);
    } 
    print_r($csv)
  }
}

```