Question: I am working on an Android application. In my app I have to convert a string to JSON Object, then parse the values. I checked for a solution in Stackoverflow and found similar issue here [link](https://stackoverflow.com/questions/5245840/how-to-convert-string-to-jsonobject-in-java)

The solution is like this

```
       `{"phonetype":"N95","cat":"WP"}`
        JSONObject jsonObj = new JSONObject("{\"phonetype\":\"N95\",\"cat\":\"WP\"}");

```

I use the same way in my code . My string is

```
{"ApiInfo":{"description":"userDetails","status":"success"},"userDetails":{"Name":"somename","userName":"value"},"pendingPushDetails":[]}

string mystring= mystring.replace("\"", "\\\"");

```

And after replace I got the result as this

```
{\"ApiInfo\":{\"description\":\"userDetails\",\"status\":\"success\"},\"userDetails\":{\"Name\":\"Sarath Babu\",\"userName\":\"sarath.babu.sarath babu\",\"Token\":\"ZIhvXsZlKCNL6Xj9OPIOOz3FlGta9g\",\"userId\":\"118\"},\"pendingPushDetails\":[]}

```

when I execute `JSONObject jsonObj = new JSONObject(mybizData);`

I am getting the below JSON exception

> 
> org.json.JSONException: Expected literal value at character 1 of
> 
> 
> 

Please help me to solve my issue.

Answer: 
Remove the slashes:

```
String json = {"phonetype":"N95","cat":"WP"};

try {

    JSONObject obj = new JSONObject(json);

    Log.d("My App", obj.toString());

} catch (Throwable t) {
    Log.e("My App", "Could not parse malformed JSON: \"" + json + "\"");
}

```
May be below is better.

```
JSONObject jsonObject=null;
    try {
        jsonObject=new JSONObject();
        jsonObject.put("phonetype","N95");
        jsonObject.put("cat","wp");
        String jsonStr=jsonObject.toString();
    } catch (JSONException e) {
        e.printStackTrace();
    }

```