Question: So I have:

```
a = [["Hello", "Bye"], ["Morning", "Night"], ["Cat", "Dog"]]

```

And I want to convert it to a dictionary.

I tried using:

```
i = iter(a)  
b = dict(zip(a[0::2], a[1::2]))

```

But it gave me an error: `TypeError: unhashable type: 'list'`

Answer: 
Simply:

```
>>> a = [["Hello", "Bye"], ["Morning", "Night"], ["Cat", "Dog"]]
>>> dict(a)
{'Cat': 'Dog', 'Hello': 'Bye', 'Morning': 'Night'}

```

I love python's simplicity

You can see [here](http://docs.python.org/2/library/stdtypes.html#dict) for all the ways to construct a dictionary:

> 
> To illustrate, the following examples all return a dictionary equal to `{"one": 1, "two": 2, "three": 3}`:
> 
> 
> 

```
>>> a = dict(one=1, two=2, three=3)
>>> b = {'one': 1, 'two': 2, 'three': 3}
>>> c = dict(zip(['one', 'two', 'three'], [1, 2, 3]))
>>> d = dict([('two', 2), ('one', 1), ('three', 3)]) #<-Your case(Key/value pairs)
>>> e = dict({'three': 3, 'one': 1, 'two': 2})
>>> a == b == c == d == e
True

```
Maybe you can try this following code :

```
a = [
    ["Hello", "Bye"],
    ["Morning", "Night"],
    ["Cat", "Dog"]
    ]

b = {}
for x in a:
    b[x[0]] = x[1]
print(b)

```

And if you want your value have more than 1 value (in the form of a list),
you can slightly change the code :

```
b[x[0]] = x[1]

```

to code :

```
b[x[0]] = x[1:]

```

Hope it will help you :)