Question: I am calling a function with the signature

```
void setValue(int& data)

```

I would like to pass a literal number to it:

```
setValue(1);

```

But I get:

```
error: invalid initialization of non-const reference of type 'int&' from an rvalue of type 'int'

```

Is there a way I can make this work without changing the function (it's in a library) and without assigning each literal value to a variable?

Answer: 
Assuming `setValue` does not actually modify its argument and just has a wrong signature which you cannot change, here is an approach which is not thread-safe among other things:

```
#include <iostream>

void setValue(int &i)
{
  std::cout << "i = " << i << std::endl;
}

int& evil(int i)
{
  static int j;
  j = i;
  return j;
}

int main()
{
  setValue(evil(1));
  setValue(evil(2));
}

```
Two options:

Use the result of assignment:

```
static int _data;
void myCall() {
  setValue((_data = 3));
}

```

Write a wrapper:

```
struct setValueW {
  int _data;

  // constructor
  setValueW(int _data) : _data(_data) {
    setValue(_data);
  }

  // if you want to call it again
  void operator()() {
    setValue(_data);
  }
};

void myCall2() {
  setValueW(3);
}

```