Question: ```
String linkPattern = "\\[[A-Za-z_0-9]+\\]";  
String text = "[build]/directory/[something]/[build]/";   
RegExp reg = RegExp.compile(linkPattern,"g");  
MatchResult matchResult = reg.exec(text);  
for (int i = 0; i < matchResult.getGroupCount(); i++) {  
    System.out.println("group" + i + "=" + matchResult.getGroup(i));  
} 

```

I am trying to get all blocks which are encapsulated by squared bracets form a path string:
and I only get group0="[build]" what i want is: 
1:"[build]" 2:"[something]" 3:"[build]"

EDIT:  

just to be clear words inside the brackets are generated with random text

```
public static String genText()
{
    final int LENGTH = (int)(Math.random()*12)+4;

    StringBuffer sb = new StringBuffer();
    for (int x = 0; x < LENGTH; x++)
    {
        sb.append((char)((int)(Math.random() * 26) + 97));
    }
    String str = sb.toString();
    str = str.substring(0,1).toUpperCase() + str.substring(1);
    return str;
}

```

EDIT 2:
JDK works fine, GWT RegExp gives this problem

SOLVED:
Answer from Didier L

```
String linkPattern = "\\[[A-Za-z_0-9]+\\]";
    String result = "";
String text = "[build]/directory/[something]/[build]/";
RegExp reg = RegExp.compile(linkPattern,"g");
MatchResult matchResult = null;
while((matchResult=reg.exec(text)) != null){
    if(matchResult.getGroupCount()==1) 
        System.out.println( matchResult.getGroup(0));
}

```

Answer: 
I don't know which regex library you are using but using the one from the JDK it would go along the lines of

```
String linkPattern = "\\[[A-Za-z_0-9]+\\]";
String text = "[build]/directory/[something]/[build]/";
Pattern pat = Pattern.compile(linkPattern);
Matcher mat = pat.matcher(text);
while (mat.find()) {
    System.out.println(mat.group());
}

```

Output:

```
[build]
[something]
[build]

```
Try:

```
String linkPattern = "(\\[[A-Za-z_0-9]+\\])*";

```

EDIT:

Second try:

```
String linkPattern = "\\[(\\w+)\\]+"

```

Third try, see <http://rubular.com/r/eyAQ3Vg68N>