Question: I need to round to nearest 0.5 if possible.

10.4999 = 10.5

Here is quick code:

```
import java.text.DecimalFormat;
import java.math.RoundingMode;

public class DecimalFormat  
{  
   public static void main(String[] args)  
   {  
      DecimalFormat dFormat = new DecimalFormat("#.0");
      dFormat.setRoundingMode(RoundingMode.HALF_EVEN);

      final double test = 10.4999;

      System.out.println("Format: " + dFormat.format(test));
   }  
}  

```

This doesn't work because 6.10000... rounds to 6.1 etc...need it to round to 6.0

Thanks for any feedback.

Answer: 
A more general solution to @RobWatt's answer in case you ever want to round to something else:

```
private static double roundTo(double v, double r) {
  return Math.round(v / r) * r;
}

System.out.println(roundTo(6.1, 0.5));     // 6.0
System.out.println(roundTo(10.4999, 0.5)); // 10.5
System.out.println(roundTo(1.33, 0.25));   // 1.25
System.out.println(roundTo(1.44, 0.125));  // 1.5

```
```
public class DecimalFormat  
{  
    public static void main(String[] args)  
    {  
        double test = 10.4999;

        double round;
        int i = (int) test;
        double fraction = test - i;
        if (fraction < 0.25) {
            round = (double) i;
        } else if (fraction < 0.75) {
            round = (double) (i + 0.5);
        } else {
            round = (double) (i + 1);
        }
        System.out.println("Format: " + round);
    }  
}  

```