Question: Can someone help me with my proof?

Let p, q, r and s be propositions. Consider the hypothesis $(p\space\lor\space q \to r)$, $\lnot s$, $r \to s$ and conclude $\lnot p$.

**My Proof**

$
r \to s\\
\lnot r \to s\\
\lnot r\space\lor\space p\space\lor\space q\\ 
$ 

This is all I have so far

Answer: 
**Hint 1:** $(r \to s) \leftrightarrow (\lnot s \to \lnot r)$

**Hint 2:** $\lnot(p\space\lor\space q) \leftrightarrow (\lnot p\space\land\space \lnot q) $
That is *not* a good start.   There's no justification for any of your steps, and they cannot be obtained from the premises by any valid rules of inference.   Try again.

Here's an outline of a proof.   Can you supply the missing details?
$$\begin{align}\because~&(p\vee q)\to r, \neg s, r\to s \\ \hdashline&{\begin{array}{l|l:l}1 & (p\vee q)\to r & \textsf{Premise} \\ 2&\neg s& \textsf{Premise}\\3&r\to s& \textsf{Premise} \\[3ex] & \neg r & \textit{why?} \\[3ex] & \neg(p\vee q) & \textit{why?} \\[3ex] & \neg p \end{array}} \\ \hline \therefore~ &~ \neg p \end{align}$$

Consider what *rules of inference* you have available.