Question: ```py
# x = 1
# x = 0

if x:
    print(f'x = {x}, and therefore it\'s truthy')
else:
    print(f"x = {x}, and therefore it's falsey")

```

Hi everyone, I am a little confused with this exercise. The code doesn't have any explanation as when the system should print `truthy` or `falsey` yet it knows when to print it. Why is that?

Answer: 
I think it's just a way to show that `0` is interpreted as `False` in a boolean expression like a comparison or an `if` etc, and `1` (or any other non-zero number) is interpreted as `True`.

Edit: and like said in some comments, the fact that a value is "truthy" doesn't mean that is strictly equal to True
for example:

```py
print(1 == True) # True
print(0 == False) # True
print(2 == True) # False
print(not not 2) # True
print(not 0) # True
print(not not 0) # False
print(0 and True) # False
print(2 and False) # False
print(2 and True) # True
print(0 or 2) # True
# etc ...

```
the funny part is if you use

```
x = 0.00000000000001

```

it will also consider as true. cause it is not actually equal to zero. in math we consider this as zero for easy calculation. but computer dont do this cause this can create big problem in calculation if we consider a big picture. Example:

```
y = x ** x
print(y)

```

so if we consider x as zero, y will be also zero. but its not.
i hope you enjoyed to learn why 0.000000000001 is not equal to zero in computer.Thanks.