Question: I have a script named `test1.py` which is not in a module. It just has code that should execute when the script itself is run. There are no functions, classes, methods, etc. I have another script which runs as a service. I want to call `test1.py` from the script running as a service.

For example:

File **`test1.py`**:

```
print "I am a test"
print "see! I do nothing productive."

```

File **`service.py`**:

```
# Lots of stuff here
test1.py # do whatever is in test1.py

```

I'm aware of one method which is opening the file, reading the contents, and basically evaluating it. I'm assuming there's a better way of doing this. Or at least I hope so.

Answer: 
The usual way to do this is something like the following.

test1.py

```
def some_func():
    print 'in test 1, unproductive'

if __name__ == '__main__':
    # test1.py executed as script
    # do something
    some_func()

```

service.py

```
import test1

def service_func():
    print 'service func'

if __name__ == '__main__':
    # service.py executed as script
    # do something
    service_func()
    test1.some_func()

```
Why not just import test1? Every python script is a module. A better way would be to have a function e.g. main/run in test1.py, import test1 and run test1.main(). Or you can execute test1.py as a subprocess.