Question: ```
http://localhost/mc/site-01-up/index.php?c=lorem-ipsum

$address = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$stack = explode('/', $_SERVER["REQUEST_URI"]);
$file = array_pop($stack);
echo $file;

```

result - `index.php?c=lorem-ipsum`

How to get just file name (`index.php`) without `$_GET` variable, using `array_pop` if possible?

Answer: 
I will follow `parse_url()` like below (easy to understand):-

```
<?php
$url = 'http://localhost/mc/site-01-up/index.php?c=lorem-ipsum';

$url=   parse_url($url);
print_r($url); // to check what parse_url() will outputs
$url_path = explode('/',$url['path']); // explode the path part
$file_name =  $url_path[count($url_path)-1]; // get last index value which is your desired result

echo $file_name;
?>

```

Output:- <https://eval.in/606839>

Note:- tested with your given URL. Check for other type of URL's at your end. thanks.
Another method that can get the filename is by using parse\_url — Parses a URL and return its components

```
<?php
$url = "http://localhost/mc/site-01-up/index.php?c=lorem-ipsum";
$data = parse_url($url);
$array = explode("/",$data['path']);
$filename = $array[count($array)-1];
var_dump($filename);

```

Result

```
index.php

```

**EDIT:** 
Sorry for posting this answer as it is almost identical to the selected one. I didnt see the answer so posted. But I cannot delete this as it is seen as a bad practice by moderators.