Question: I have the following syntax:

```
echo "<img src=\"images2/" . $row['image']  . "\" alt=\"\" /><br />"; } 

```

I would like to a give a specific height and width for the image, but I can't to do it.

Answer: 
You can specify dimensions directly in your HTML `<img>` tag:

```
echo "<img src=\"images2/\" . $row['image']  . "\" alt=\"\" height=\"100\" width=\"100\" /><br />";

```

Note that your posted code has a closing curly brace (`}`) following your `echo` statement, which will cause a PHP error if there's no corresponding opening curly brace. You're also incorrectly escaping the double-quotes after `images2/`, which will result in invalid markup.

A better approach would be to enclose your entire markup in single quotes so that you don't have to escape the double quotes enclosed within:

```
echo '<img src="images2/' . $row['image'] . '" alt="" height="100" width="100" /><br />';

```

EDIT:

For modern day markup (depending on your requirements), it's considered vastly preferable to modify image dimensions in CSS, rather than in your `<img>` tag. You may want to consider implementing something akin to the following:

```
<style type="text/css">
    img {
        width: 100px;
        height: 100px;
    }

    img.large {
        width: 200px;
        height: 200px;
    }
</style>

<?php

    echo '<img src="images2/' . $row['image'] . '" alt="" /><br />'; // no class attribute, so will default to 100x100  
    echo '<img src="images2/' . $row['image'] . '" alt="" class="large" /><br />'; // class attribute is `large`, so will rescale to 200x200

```
This should work

```
echo '<img src="images2"'.$row['image'].'\ alt="" width="" height="" /><br />'; } 

```