Question: Consider two computers, one a bit-for-bit clone of the other. If I then perform any two arbitrary actions on machine A- like change the volume, then open a chrome browser, then do the same on computer B, but in reverse order, will the computers' state still be bit-for-bit identical (ram, disc, etc.)? The actions can of course also be more significant ones, like updating an application or driver.

Diving a bit deeper, I'm trying to figure out if the two machines...

* will *always* be in different states
* will *almost always* be in different states, but there are special cases that are identical
* can plausibly be either, but its impossible to tell without knowing the two exact actions

If this is a bad question - Downvotes without feedback don't help me figure out what is wrong with my question. Feedback is greatly appreciated.

Answer: 
One way they could be different is in logfiles. If the two actions cause logfile entries, they would be in different order in the logs.
These actions are not arbitrary so my answer is invalid.

Since not all math operations are commutative, it is easy to show the answer to this is NO. If I assume:
a = 1; b = 2, c = 3
The have one do

`c = a + b then c = c / b` (c = 1.5)

and the other do

`c = c / b then c = a + b` (c = 3)

You can see this clearly