Question: The program first asks the user for the number of elements to be stored in the array, then asks for the numbers.  

This is my code

```
    static void Main(string[] args)
    {
        Console.Write("How many numbers do you want to store in array: ");
        int n = Convert.ToInt32(Console.ReadLine());
        int[] numbers = new int[n];
        int min = numbers[0];
        int max = numbers[0];

        for (int i = 0; i < n; i++)
        {
            Console.Write("Enter number {0}:  ", i+1);
            numbers[i] = Convert.ToInt32(Console.ReadLine());
        }

        for (int i = 0; i < n; i++)
        {
            if (min > numbers[i]) min = numbers[i];
            if (max < numbers[i]) max = numbers[i];
        }
        Console.WriteLine("The minimum is: {0}", min);
        Console.WriteLine("The maximum is: {0}", max);
        Console.ReadKey();
    }
  }
}

```

But minimum value is always 0, why is that?

Answer: 
You are initializing `min` to 0. 

Try following

```
int min = Int32.MaxValue;

```

Also In case you are accepting negative values as input, you should initialize max to minimum integer value.

```
int max = Int32.MinValue;

```
```
        for (int i = 0; i < vector.GetLength(0); i++)
        {
            if (i == 0)
            {
                VectorMinMax[1]= vector[i];
                VectorMinMax[0]= vector[i];
            }
            else {
                if (VectorMinMax[1] > vector[i]) VectorMinMax[1] = vector[i];
                if (VectorMinMax[0] < vector[i]) VectorMinMax[0] = vector[i];
            }

        }

```