Question: ```
echo -e 'one two three\nfour five six\nseven eight nine'
one two three
four five six
seven eight nine

```

how can I do some "MAGIC" do get this output?:

```
three
six
nine

```

UPDATE:
I don't need it in this specific way, I need a general solution so that no matter how many columns are in a row, e.g.: awk always displays the last column.

Answer: 
Try:

```
echo -e 'one two three\nfour five six\nseven eight nine' | awk '{print $NF}'

```
It can also be done using `'sed'`:

```
echo -e 'one two three\nfour five six\nseven eight nine' | sed -e 's/^.* \([^ ]*\)$/\1/'

```

**Update:**

or more simply:

```
echo -e 'one two three\nfour five six\nseven eight nine' | sed -e 's/^.* //'

```