Question: I have some problem using ajax.

How can I assign all result from ajax into outside variable ?

I google it up and found this code..

```
var return_first = (function () {
    var tmp = null;
    $.ajax({
        'async': false,
        'type': "POST",
        'global': false,
        'dataType': 'html',
        'url': "ajax.php?first",
        'data': { 'request': "", 'target': arrange_url, 'method': method_target },
        'success': function (data) {
            tmp = data;
        }
    });
    return tmp;
});

```

but not work for me..

Can anybody tell what is wrong about that code ?

Answer: 
You are missing a comma after

```
'data': { 'request': "", 'target': 'arrange_url', 'method': 'method_target' }

```

Also, if you want `return_first` to hold the result of your anonymous function, you need to make a function call:

```
var return_first = function () {
    var tmp = null;
    $.ajax({
        'async': false,
        'type': "POST",
        'global': false,
        'dataType': 'html',
        'url': "ajax.php?first",
        'data': { 'request': "", 'target': 'arrange_url', 'method': 'method_target' },
        'success': function (data) {
            tmp = data;
        }
    });
    return tmp;
}();

```

Note `()` at the end.
This is all you need to do:

```
var myVariable;

$.ajax({
    'async': false,
    'type': "POST",
    'global': false,
    'dataType': 'html',
    'url': "ajax.php?first",
    'data': { 'request': "", 'target': 'arrange_url', 'method': 'method_target' },
    'success': function (data) {
        myVariable = data;
    }
});

```

> 
> **NOTE:** Use of "async" has been depreciated. See <https://xhr.spec.whatwg.org/>. 
> 
> 
>