Question: ```
def enumerator(fruits):
    for index, fruit in enumerate(fruits):
        print(f"Fruit: {fruit}, under the index: {index}.")

just_a_variable = enumerator(["apple", "banana", "lemon"]) # Im just assigning function call
# to the variable "just_a_variable"
# and boom, when I run the program the function is called. Makes no sense (it shouldn't work this way, does it?)

```

I assume this is happening because there is a print statement in the function but it still doesn't make sense. if I change the print statement to "return" it suddenly doesn't compile, that is what I was expecting from just using print. I'm I missing something here?

Answer: 
In general if you add parenthesis after a function (like one of the two examples below), it is called.

```py
function_name(arguments)
variable = function_name(arguments)

```

If you just want a variable to point to a function:

```py
variable = function

```

Then the following two statements will become identical:

```py
variable(arguments)
function(arguments)

```

Having said so, this seems a bit useless to me. With you function defined the way it currently is, there isn't a way I know to "assign" it to a variable and pass arguments at the same time.

---

This does change the structure of your code, but you can perhaps use [`yield`](https://stackoverflow.com/a/231855/10907280) instead of `return`.
The line `just_a_variable = enumerator(["apple", "banana", "lemon"])` *is* calling function `enumerator`. Technically, that is what the parenthesis after `enumerator` do.

Perhaps you noticed that simply running the file is running that line (and calling `enumerator`). As a scripting language, this is how Python works (in contrast to Java or other compiled languages).