Question: I have three vectors `centers, radiuses, metrics` all Nx1 (`centers` is Nx2, but it is not a problem at all). And I want to convert them into vector Nx1 of structures where each structure has fields: `center, radius, metric` and corresponding values of this fields, like `structArray(i).metric == metrics(i)`. What is the best and simpliest way to do this?

Answer: 
You can use the [`struct`](http://www.mathworks.com/help/matlab/ref/struct.html?refresh=true) constructor directly by converting you data to cell arrays.

```
structArray = struct('center', num2cell(centers,2), ...
                     'radius', num2cell(radiuses), ...
                     'metric', num2cell(metrics));

```

Note the use of the dimension input to [`num2cell`](http://www.mathworks.com/help/matlab/ref/num2cell.html) to convert the `centers` variable into an Nx1 array of 1x2 cells.

If we try this with some example data:

```
radiuses = rand(3,1);
metrics = rand(3,1);
centers = rand(3,2);

structArray = struct('center', num2cell(centers,2), ...
                     'radius', num2cell(radiuses), ...
                     'metric', num2cell(metrics));

structArray =

3x1 struct array with fields:

    center
    radius
    metric

```
Use the following:

```
 S = struct( 'centers', num2cell(centers), 'radiuses', num2cell(radiuses), ... 
     'metrics', num2cell(metrics) );

```

Note, that the overhead (in terms of memory consumption) of this approach is very high. If your arrays CENTERS, RADIUSES and METRICS are very large it is better to use the "flat" memory layout, i.e. to store the arrays in one struct:

```
S = struct;
S.centers = centers;
S.radiuses = radiuses;
S.metrics == metrics;

```