Question: I have 2 objects and when I move one, I want to get the angle from the other.

For example:

```
Object1X = 211.000000, Object1Y = 429.000000
Object2X = 246.500000, Object2Y = 441.500000

```

I have tried the following and every variation under the sun:

```
double radians = ccpAngle(Object1,Object2);
double degrees = ((radians * 180) / Pi); 

```

But I just get 2.949023 returned where I want something like 45 degrees etc.

Answer: 
Does this other answer help?

[How to map atan2() to degrees 0-360](https://stackoverflow.com/questions/1311049/how-to-map-atan2-to-degrees-0-360)

I've written it like this:

```
- (CGFloat) pointPairToBearingDegrees:(CGPoint)startingPoint secondPoint:(CGPoint) endingPoint
{
    CGPoint originPoint = CGPointMake(endingPoint.x - startingPoint.x, endingPoint.y - startingPoint.y); // get origin point to origin by subtracting end from start
    float bearingRadians = atan2f(originPoint.y, originPoint.x); // get bearing in radians
    float bearingDegrees = bearingRadians * (180.0 / M_PI); // convert to degrees
    bearingDegrees = (bearingDegrees > 0.0 ? bearingDegrees : (360.0 + bearingDegrees)); // correct discontinuity
    return bearingDegrees;
}

```

Running the code:

```
CGPoint p1 = CGPointMake(10, 10);
CGPoint p2 = CGPointMake(20,20);

CGFloat f = [self pointPairToBearingDegrees:p1 secondPoint:p2];

```

And this returns 45.

Hope this helps.
The vertex of the angle is the point (0,0).

Consider object1X=x1 ....object2Y=y2.

```
Angle(object1-object2) = 
   90       * (  (1 + sign(x1)) * (1 - sign(y1^2))
               - (1 + sign(x2)) * (1 - sign(y2^2)) )
 + 45       * (  (2 + sign(x1)) * sign(y1)
               - (2 + sign(x2)) * sign(y2)         )
 + 180/pi() * sign(x1*y1) * atan( (abs(x1) - abs(y1)) / (abs(x1) + abs(y1)) )
 - 180/pi() * sign(x2*y2) * atan( (abs(x2) - abs(y2)) / (abs(x2) + abs(y2)) )

```