Question: I'm trying to build a list of the first ten factorials 

```
[1,1,2,6,24,120,720,5040,40320,362880]

```

using only list comprehension. Is that possible?

I don't know generators or `lambda`.

Here's my attempt, but I absolutely know why it's wrong:

```
lst = [1] + [i for i in range(1,10)]
lst[1:10] = [lst[i-1] * i for i in range(1,10)]
print(lst)

```

Answer: 
Just for fun:

One-liner mega-hack using list comprehension and an auxililary accumulator (the resulting list itself) to reuse previously computed value

```
s=[];  s=[s[-1] for x in range(1,10) if not s.append(x*s[-1] if s else 1)]

```

result:

```
[1, 2, 6, 24, 120, 720, 5040, 40320, 362880]

```

note: The `math.factorial` answer is the way when elements are random. Here it's faster because we can reuse previous results.

There's also another drawback: the need to store all elements in a `list` because python does not allow `if` and assignment like C does. So we have to append to a list and negate the `None` it returns so `if` test is `True`

As I said: fun, but still a hack.
We could also use our own function but hey, the meaning of the comprehension lists is lost a bit but it is still functional

```
def factorialIte(n):
  factorial = 1
  for i in range(1,n+1):
    factorial = factorial*i
return factorial
# 10 is n_max
[factorialIte(n) for n in range(1,11)]
>>[1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]

```