Question: If I have the following vector : 

```
x
[1]  1  5  8  9  1  0 15 15

```

and I want to know how many elements are greater than 10, how can I proceed without using a loop ?

I would like to get : 

```
2

```

as a result

Answer: 
Use `length` or `sum`:

```
> length(x[x > 10])
[1] 2
> sum(x > 10)
[1] 2

```

In the first approach, you would be creating a vector that subsets the values that matches your condition, and then retrieving the `length` of the vector.

In the second approach, you are simply creating a logical vector that states whether each value matches the condition (`TRUE`) or doesn't (`FALSE`). Since `TRUE` and `FALSE` equate to "1" and "0", you can simply use `sum` to get your answer.

Because the first approach requires indexing and subsetting before counting, I am almost certain that the second approach would be faster than the first.
Another way to do this:

```
> length(which(as.vector(x) > 10))
[1] 2

```