Question: I'm a co-op student working on a hardware design for an industry client, and I'm trying to use a [TPS63000](http://www.ti.com/lit/ds/symlink/tps63000-q1.pdf) to get a Vout of 3.45V. Vin is 5V. When I power this circuit up, I read 5V on Vin but only 0.7V from Vout. [![TPS63000 Application Circuit](https://i.stack.imgur.com/vQ9VR.png)](https://i.stack.imgur.com/vQ9VR.png)

Here's the PCB design:
[![PCB design](https://i.stack.imgur.com/gjGLL.png)](https://i.stack.imgur.com/gjGLL.png)

I'm not sure what approach to take in troubleshooting this. Any help would be appreciated.

EDIT: Unfortunately I don't have easy access to an oscilloscope, but when I do, I will definitely try to confirm that there's a pulse across the inductor.
Yesterday I assembled another PCB, and I'm getting a very similar result. Vout actually stabilizes at 322mV, and does so with a high degree to accuracy. During startup, I do see Vout shift drastically, but always settles around 322mV. Sorry that that's not very much to go on, an oscilloscope will definitely help give a better picture. 

So it seems to me possible causes are: A. lack of R3/C3 on the Vin pin, B. narrow traces on the PCB, or C. bad chip. Thanks for all the responses so far.

Answer: 
Regardless of the following, I fail to see why your circuit does not work. \$R\_1\$ and \$R\_2\$ are correct for 3.45V. \$C\_1\$, \$C\_2\$ and \$L\_1\$ are within parameters. Why your circuit does not show some life is strange. It is scope time! Calcs have been confirmed.

Bad chip (is always lame)? Try connecting up a load during power up. Try connecting up \$W\_1\$, when your source has stabilized.

I do not think the addition of \$R\_3\$ and \$C\_3\$ is the answer. The app-note does not even mention them. But it is certainly worth a try.

From [TPS6300 datasheet](http://www.ti.com/lit/ds/symlink/tps63000.pdf):

[![Layout Example](https://i.stack.imgur.com/pYpqh.gif)](https://i.stack.imgur.com/pYpqh.gif)

> 
> As for all switching power supplies, the layout is an important step in the design, especially at high peak currents and high switching frequencies. If the layout is not carefully done, the regulator could show stability problems as well as EMI problems. Therefore, use wide and short traces for the main current path and for the power ground tracks. The input capacitor, output capacitor, and the inductor should be placed as close as possible to the IC. Use a common ground node for power ground and a different one for control ground to minimize the effects of ground noise. Connect these ground nodes at any place close to one of the ground pins of the IC.
> 
> 
> The feedback divider should be placed as close as possible to the control ground pin of the IC. To lay out the control ground, TI recommends to use short traces as well, separated from the power ground traces. This avoids ground shift problems, which can occur due to superimposition of power ground current and control ground current.
> 
> 
> 

Irregardless, you have skinny and long, as opposed to short and really, really fat, so you will definitely have production problems.
A few guesses/pointers: -

* Try fitting link W1
* Check R1 isn't 1.8 kohm (or a wrong value)
* Is exposed thermal pad properly earthed?
* Have you got too much output load?
* Check that oscillations are running about 1350 kHz
* Is your meter working correctly?

Good luck.