Question: I want to put a condition in my query where I have a column that should contain second position as an alphabet.

How to achieve this?

I've tried with `_[A-Z]%` in where clause but is not working. I've also tried `[A-Z]%`.

Any inputs please?

Answer: 
I think you want mysql query. like this

```
SELECT * FROM table WHERE column REGEXP '^.[A-Za-z]+$'

```

or sql server

```
select * from table  where  column like '_[a-zA-Z]%'

```
agree with @Gordon Linoff, your ('\_[A-Z]%') should work.
if not work, kindly add some sample data with your question.

```
Declare @Table Table
(
    TextCol     Varchar(20)
)

Insert Into @Table(TextCol) Values
    ('23423cvxc43f')
,('2eD97S9')
,('sAgsdsf')
,('3Ss08008')

Select  *
From    @Table As t
Where   t.TextCol Like '_[A-Z]%'

```