Question: Hi I want to get a number from user and only except input within a certain range.

The below appears to work but I am a noob and thought whilst it works there is no doubt a more elegant example... just trying not to fall into bad habits!

One thing I have noticed is when I run the program CTL+C will not break me out of the loop and raises the exception instead. 

```
while True:
  try:
    input = int(raw_input('Pick a number in range 1-10 >>> '))
    # Check if input is in range
    if input in range(1,10):
      break
    else:
      print 'Out of range. Try again'
  except:
    print ("That's not a number")

```

All help greatly appreciated.

Answer: 
Ctrl+C raises a [`KeyboardInterruptException`](http://docs.python.org/library/exceptions.html#exceptions.KeyboardInterrupt), your `try … except` block catches this:

```
while True:
   try:
       input = int(raw_input('Pick a number in range 1-10 >>> '))
   except ValueError: # just catch the exceptions you know!
       print 'That\'s not a number!'
   else:
       if 1 <= input < 10: # this is faster
           break
       else:
           print 'Out of range. Try again'

```

Generally, you should just catch the exceptions you expect to happen (so no side effects appear, like your Ctrl+C problem). Also you should keep the `try … except` block as short as possible.
You can use this code:

```
def read_int(prompt, min, max):
    while True:
        try:
            val = int(input(prompt))
        except ValueError:
            print('Error: wrong input')
        else:
            if(min <= val < max): # this is faster
                break
            else:
                print('Error: the value is not within permitted range (min..max)')
    return val    

v = read_int("Enter a number from -10 to 10: ", -10, 10)

print("The number is:", v)

```