Question: I tried to open pentaho spoon but it doesnt launch . The error is "System does not find the path"
I use "-Xms1024m" and C:\Program Files\Java\jre1.8.0\_261 path as an environment but still does not working. Can someone help me please?

[![enter image description here](https://i.stack.imgur.com/8hE1X.png)](https://i.stack.imgur.com/8hE1X.png)

Answer: 
The call to `foo(2, 4)` returns a *copy* of the variable `s` inside the function.

This returned (and temporary) copy will have a lifetime to the end of the full expression, which is the assignment `a = foo(2, 4).x`.

This means that the assignment to `a` is done before the lifetime of the temporary structure ends, which means that the code you show is fine and valid.

You can read more about lifetime in e.g. [this reference](https://en.cppreference.com/w/c/language/lifetime).
From the C Standard

> 
> 4 **A full expression is** an expression that is not part of another
> expression or of a declarator. Each of the following is a full
> expression: an initializer that is not part of a compound literal;
> **the expression in an expression statement**; the controlling expression of a selection statement (if or switch); the controlling
> expression of a while or do statement; each of the (optional)
> expressions of a for statement; the (optional) expression in a return
> statement. There is a sequence point between the evaluation of a full
> expression and the evaluation of the next full expression to be
> evaluated.
> 
> 
> 

The lifetime of a temporary object ends when the evaluation of the containing full expression ends.

So within this expression statement

```
a = foo(2, 4).x;

```

the returned object of the structure type is alive and the value of its data member `x` is assigned to the variable `a` that is declared in main and has the block scope of main.