Question: If I have an object implementing the `Map` interface in Java and I wish to iterate over every pair contained within it, what is the most efficient way of going through the map?

Will the ordering of elements depend on the specific map implementation that I have for the interface?

Answer: 
```
public class abcd{
    public static void main(String[] args)
    {
       Map<Integer, String> testMap = new HashMap<Integer, String>();
        testMap.put(10, "a");
        testMap.put(20, "b");
        testMap.put(30, "c");
        testMap.put(40, "d");
        for (Integer key:testMap.keySet()) {
            String value=testMap.get(key);
            System.out.println(value);
        }
    }
}

```

OR

```
public class abcd {
    public static void main(String[] args)
    {
       Map<Integer, String> testMap = new HashMap<Integer, String>();
        testMap.put(10, "a");
        testMap.put(20, "b");
        testMap.put(30, "c");
        testMap.put(40, "d");
        for (Entry<Integer, String> entry : testMap.entrySet()) {
            Integer key=entry.getKey();
            String value=entry.getValue();
        }
    }
}

```
It doesn't quite answer the OP's question, but might be useful to others who find this page:

If you only need the values and not the keys, you can do this:

```
Map<Ktype, Vtype> myMap = [...];
for (Vtype v: myMap.values()) {
  System.out.println("value: " + v);
}

```

`Ktype`, `Vtype` are pseudocode.