Question: I would like to find the index for when an array exceeds a certain value, and this value is value is exceeded for a duration, n. For examples:

```
n = 5;
dat = [1,2,2,1.5,2,4,2,1,1,3,4,6,8,4,9];

```

Here, I would like to find when 'dat' exceeds 2 for a duration greater than n for the first time. So, the solution here should lead to an answer:

```
ans = 10

```

Another example:

```
n = 7;
dat = [1,1,2,3,4,5,6,7,8,9,9,6,4,3,2,4,6,7,7,5];

```

find the first time that 'dat' exceeds or equals 5 for more than or equal to n times. 

ans = 6

Answer: 
```
n = 5;
m = 2;
dat = [1,2,2,1.5,2,4,2,1,1,3,4,6,8,4,9];

c = conv(double(dat >= m), ones(1, n))
%I think you can also do
%  c = conv((dat >= m)*1, ones(1, n))

min(find(c == n)) - n + 1

```
```
n=5
x=2;
dat = [1,2,2,1.5,2,4,2,1,1,3,4,6,8,4,9];
vec= cumsum(dat>=x);
ind=find(vec>=n);
ind=dat(ind(1));

```

`ind` will contain the answer 10