Question: I got a query result in array `Array ( [0] => stdClass Object ( [model] => Peugeot 308 SW ) [1] => stdClass Object ( [model] => Citroen C-Elysee ) [2] => stdClass Object ( [model] => Nissan Evalia ) [3] => stdClass Object ( [model] => Renault Trafic 9-os ) )`

And I want to make a single variable for every object like:

$Peugeot 308 SW  

$Citroen C-Elysee  

$Nissan Evalia

But I don't know how to do that. Thank you

Answer: 
You do not need to call `d.keys()`, so

```
if key not in d:
    d[key] = value

```

is enough. There is no clearer, more readable method.

You could update again with `dict.get()`, which would return an existing value if the key is already present:

```
d[key] = d.get(key, value)

```

but I strongly recommend against this; this is code golfing, hindering maintenance and readability.
Since **Python 3.9** you can use the *merge operator* `|` to merge two dictionaries. The dict on the right takes precedence:

```py
new_dict = old_dict | { key: val }

```

For example:

```py
new_dict = { 'a': 1, 'b': 2 } | { 'b': 42 }

print(new_dict) # {'a': 1, 'b': 42}

```

Note: this creates a new dictionary with the updated values.