Question: Trying to solve 2 equations with 2 unknown using MATLAB and it is not liking my input.

Where c is 3.06 + 2.57j, and v is 12:

```
eq1 = 'c = a/10j'
eq2 = '(6b)/50 + b/10j = a/10j + a/10'

```

Trying to solve for a and b. Any suggestions of how to properly put these in?

Answer: 
Matlab is screwed up, but the syntax is

```
sol = solve(eq1,x1,eq2,x2,..);

```

It would make more sense to make it `solve({eq1,eq2,..},{x1,x2,..})` but no, we have to write out all the arguments one by one.

Anyway the trick is that eq1, eq2, .. are symbolic expressions that must be evaluated to zero. So instead of `c = a/10j` it needs to be `eq1=sym('c-a/10j')`

So try this:

```
eq1 = sym('c - a/(10*i)');   % must evaluate to zero
eq2 = sym('(6*b)/50 + b/(10*i) -( a/(10*i) + a/10)'); %must evaluate to zero

sol = solve(eq1,'a',eq2,'b');

a = subs(sol.a,'c',3.06+2.57j)
b = subs(sol.b,'c',3.06+2.57j)

```

produces `a= -25.7000 +30.6000i` and `b=-20.6639 +29.6967i`.

Note that symbolic functions do not understand `10j`. It needs to be `10*i`. Also the notatation `6b` is missing an operator and needs to be `6*b`.

Good luck!

---

Since the problem is linear there is another way to solve it

```
equs = [eq1;eq2];
vars = [sym('a');sym('b')];
A = jacobian(equs,vars);
b = A*vars - equs;

x = A\b;
c = 3.06+2.57j;
sol = subs(x,'c',c)

```

with results

```
sol =
 -25.7000 +30.6000i
 -20.6639 +29.6967i

```
you need to tell matlab that c,eq1,eq2,a,j (is this not complex?), and b are a symbolic variables. i.e. use the command "syms a b c j eq1 eq2". Then define everything as you have done above minus your single quotes (that's a string!).

then you can just use the 'solve(eq2,'variable you want to solve for'). Easy enough.