Question: I have a CSV file like this:

```
SUPPORT 07/30/2008-10:59:54 Eastern Daylight Time
123     07/03/2009-08:56:42 Eastern Daylight Time
DC321   07/10/2009-20:16:56 Eastern Daylight Time

```

where the date is an entire column.
how can i remove the entire "Eastern Daylight Time" part of the string with awk?

Answer: 
Based on your comment in piotrsz's answer, this is how you could remove the EDT part:

```
awk '{gsub("Eastern Daylight Time", "");print}' file.csv

```
using just the shell

```
while read -r line
do
    case "$line" in
        *Eastern* )
            echo "${line%%Eastern*}"
            ;;
        *) echo "${line}"
    esac
done < "file"

```