Question: In this fiddle <http://jsfiddle.net/mjmitche/6nar4/3/>, if you drag, for example, the little blue box into the yellow box, then the big black box will turn pink. All of the 4 boxes along the left can be dragged into the boxes inside the black box. 

At the end of the fiddle, you see the code that changes the black box to pink.

However, I want to make that a ternary operator, so that if the box is black, then it turns pink, but if it's been turned pink, then I want it to go back to black. 

I know the ternary is like this

```
x ? y: z

```

So I tried this, even though I knew it wasn't probably right

```
$("#blackbox").css({'background':'pink'}); ?

    $("#blackbox").css({'background':'black'}); : 

$("#blackbox").css({'background':'pink'}); 

```

I think the first line before the question mark is causing the problem, so how to create the `if` statement?

Answer: 
I would go with such code:

```
var oBox = $("#blackbox");
var curClass = oBox.attr("class");
var newClass = (curClass == "bg_black") ? "bg_pink" : "bg_black";
oBox.removeClass().addClass(newClass);

```

To have it working, you first have to change your CSS and remove the `background` from the `#blackbox` declaration, add those two classes:

```
.bg_black { background-color: #000; }
.bg_pink { background-color: pink; }

```

And assign the class `bg_black` to the `blackbox` element initially.

Updated jsFiddle: <http://jsfiddle.net/6nar4/17/>

In my opinion it's more readable than the other answers but it's up to you to choose of course.
Here is a working example in side a function: 

```html
function setCurrency(){
   var returnCurrent;
   $("#RequestCurrencyType").is(":checked") === true ? returnCurrent = 'Dollar': returnCurrent = 'Euro';

   return returnCurrent;
}
```

In your case. Change the selector and the return values

```html
$("#blackbox").css('background-color') === 'pink' ? return "black" : return "pink";
```

lastly, to know what is the value used by the browser run the following in the console:

```html
$("#blackbox").css('background-color')
```

and use the "rgb(xxx.xxx.xxx)" value instead of the Hex for the color selection.