Question: Just trying to tidy up a little bit of code here. I have a php command to output some html. However, one of my comands is quite a large amount of html, I was wondering if it's possible to output code referenced in a different file?

For example, my current php looks like this:

```
$output .= '<div class="contact-form '.$css_class.'" >';
$output .= '<h4 class="form-title">'.$title.'</h4>';                    
$output .= 'SOME VERY LONG CODE'

```

Is it possible to do something like this:

```
$output .= include('file_with_long_code.html');

```

instead? I aven't tested this, but am curious to know if it works or what the proper way of doing it is

Answer: 
you can instead use getfilecontent function of php

```
 $output .=  file_get_contents('file_with_long_code.html'); 

```
You could do something like this:

```
    ob_start();
       include('somefile.php');
    $output = ob_get_contents();

```

Read more about output buffering in the docs: 
<http://php.net/manual/en/function.ob-start.php>

I recommend using a PHP Framework, most of them have a very good functionality for these Kinds of "Problems".