Question: I've created a branch named `<title>-changes` by:

`git checkout -b <title>-changes` and did a commit on that branch. Later I checkout to `another-branch` started working on `another-branch`. Now I want to checkout to the previous branch (`<title>-changes`) but I can't do that now through:

```
git checkout <title>-changes

```

I know this is a simple issue but can't crack. I tried:

```
git checkout \<title>-changes
git checkout /<title>-changes
git checkout '<title>-changes'

```

but no luck. Getting errors like:

```
$error: pathspec '<title' did not match any file(s) known to git.
$bash: title: No such file or directory
$error: pathspec '<title>-change-pdp ' did not match any file(s) known to git.

```

Answer: 
You have to escape both `<` and `>` because bash treats them as special symbols.

In order to do that, prepend the backward slash `\` to each of them:

```
git checkout \<title\>-changes

```

This is what I did to test this, and it worked.

```
mkdir test
cd test/
git init
git branch \<title\>-changes
touch empty
git add empty
git commit -m "Added empty file"
git branch \<title\>-changes
git checkout \<title\>-changes
touch second
git add second
git commit -m "Added second empty file"
git checkout -b another-branch
touch third
git add third
git commit -m "Added third empty file"
git checkout \<title\>-changes

```
Apart from **@Ferran Rigual**'s answer there is another solution. Like **@Matthieu Moy** said I had an extra space in the branch name. Removing it solved it too.ie,

I changed `git checkout '<title>-changes '` to `git checkout '<title>-changes'`

And for the record: `git checkout '<title>-changes' --` worked too. But I don't know `--` has any importance in the command since removal of it doesn't make any difference.