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Release DeepSeek-V3.1

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README.md ADDED
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+ ---
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+ license: mit
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+ library_name: transformers
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+ ---
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+ # DeepSeek-V3.1
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+
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+ <!-- markdownlint-disable first-line-h1 -->
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+ <!-- markdownlint-disable html -->
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+ <!-- markdownlint-disable no-duplicate-header -->
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+
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+ <div align="center">
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+ <img src="https://github.com/deepseek-ai/DeepSeek-V2/blob/main/figures/logo.svg?raw=true" width="60%" alt="DeepSeek-V3" />
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+ </div>
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+ <hr>
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+ <div align="center" style="line-height: 1;">
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+ <a href="https://www.deepseek.com/" target="_blank" style="margin: 2px;">
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+ <img alt="Homepage" src="https://github.com/deepseek-ai/DeepSeek-V2/blob/main/figures/badge.svg?raw=true" style="display: inline-block; vertical-align: middle;"/>
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+ </a>
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+ <a href="https://chat.deepseek.com/" target="_blank" style="margin: 2px;">
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+ <img alt="Chat" src="https://img.shields.io/badge/🤖%20Chat-DeepSeek%20V3-536af5?color=536af5&logoColor=white" style="display: inline-block; vertical-align: middle;"/>
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+ </a>
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+ <a href="https://huggingface.co/deepseek-ai" target="_blank" style="margin: 2px;">
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+ <img alt="Hugging Face" src="https://img.shields.io/badge/%F0%9F%A4%97%20Hugging%20Face-DeepSeek%20AI-ffc107?color=ffc107&logoColor=white" style="display: inline-block; vertical-align: middle;"/>
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+ </a>
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+ </div>
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+
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+ <div align="center" style="line-height: 1;">
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+ <a href="https://discord.gg/Tc7c45Zzu5" target="_blank" style="margin: 2px;">
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+ <img alt="Discord" src="https://img.shields.io/badge/Discord-DeepSeek%20AI-7289da?logo=discord&logoColor=white&color=7289da" style="display: inline-block; vertical-align: middle;"/>
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+ </a>
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+ <a href="https://github.com/deepseek-ai/DeepSeek-V2/blob/main/figures/qr.jpeg?raw=true" target="_blank" style="margin: 2px;">
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+ <img alt="Wechat" src="https://img.shields.io/badge/WeChat-DeepSeek%20AI-brightgreen?logo=wechat&logoColor=white" style="display: inline-block; vertical-align: middle;"/>
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+ </a>
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+ <a href="https://twitter.com/deepseek_ai" target="_blank" style="margin: 2px;">
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+ <img alt="Twitter Follow" src="https://img.shields.io/badge/Twitter-deepseek_ai-white?logo=x&logoColor=white" style="display: inline-block; vertical-align: middle;"/>
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+ </a>
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+ </div>
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+
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+ <div align="center" style="line-height: 1;">
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+ <a href="LICENSE" style="margin: 2px;">
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+ <img alt="License" src="https://img.shields.io/badge/License-MIT-f5de53?&color=f5de53" style="display: inline-block; vertical-align: middle;"/>
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+ </a>
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+ </div>
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+
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+ ## Introduction
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+
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+ DeepSeek-V3.1 is a hybrid model that supports both thinking mode and non-thinking mode. Compared to the previous version, this upgrade brings improvements in multiple aspects:
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+
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+ - **Hybrid thinking mode**: One model supports both thinking mode and non-thinking mode by changing the chat template.
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+
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+ - **Smarter tool calling**: Through post-training optimization, the model's performance in tool usage and agent tasks has significantly improved.
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+
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+ - **Higher thinking efficiency**: DeepSeek-V3.1-Think achieves comparable answer quality to DeepSeek-R1-0528, while responding more quickly.
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+
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+ DeepSeek-V3.1 is post-trained on the top of DeepSeek-V3.1-Base, which is built upon the original V3 base checkpoint through a two-phase long context extension approach, following the methodology outlined in the original DeepSeek-V3 report. We have expanded our dataset by collecting additional long documents and substantially extending both training phases. The 32K extension phase has been increased 10-fold to 630B tokens, while the 128K extension phase has been extended by 3.3x to 209B tokens. Additionally, DeepSeek-V3.1 is trained using the UE8M0 FP8 scale data format to ensure compatibility with microscaling data formats.
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+
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+ ## Model Downloads
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+
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+ <div align="center">
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+
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+ | **Model** | **#Total Params** | **#Activated Params** | **Context Length** | **Download** |
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+ | :------------: | :------------: | :------------: | :------------: | :------------: |
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+ | DeepSeek-V3.1-Base | 671B | 37B | 128K | [HuggingFace](https://huggingface.co/deepseek-ai/DeepSeek-V3.1-Base) \| [ModelScope](https://modelscope.cn/models/deepseek-ai/DeepSeek-V3.1-Base) |
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+ | DeepSeek-V3.1 | 671B | 37B | 128K | [HuggingFace](https://huggingface.co/deepseek-ai/DeepSeek-V3.1) \| [ModelScope](https://modelscope.cn/models/deepseek-ai/DeepSeek-V3.1) |
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+
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+ </div>
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+
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+ ## Chat Template
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+
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+ The details of our chat template is described in `tokenizer_config.json` and `assets/chat_template.jinja`. Here is a brief description.
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+
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+ ### Non-Thinking
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+
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+ #### First-Turn
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+
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+ Prefix:
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+ `<|begin▁of▁sentence|>{system prompt}<|User|>{query}<|Assistant|></think>`
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+
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+ With the given prefix, DeepSeek V3.1 generates responses to queries in non-thinking mode. Unlike DeepSeek V3, it introduces an additional token `</think>`.
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+
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+ #### Multi-Turn
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+ Context:
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+ `<|begin▁of▁sentence|>{system prompt}<|User|>{query}<|Assistant|></think>{response}<|end▁of▁sentence|>...<|User|>{query}<|Assistant|></think>{response}<|end▁of▁sentence|>`
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+
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+ Prefix:
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+ `<|User|>{query}<|Assistant|></think>`
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+
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+ By concatenating the context and the prefix, we obtain the correct prompt for the query.
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+
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+ ### Thinking
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+
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+ #### First-Turn
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+ Prefix:
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+ `<|begin▁of▁sentence|>{system prompt}<|User|>{query}<|Assistant|><think>`
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+
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+ The prefix of thinking mode is similar to DeepSeek-R1.
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+
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+
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+ #### Multi-Turn
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+ Context:
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+ `<|begin▁of▁sentence|>{system prompt}<|User|>{query}<|Assistant|></think>{response}<|end▁of▁sentence|>...<|User|>{query}<|Assistant|></think>{response}<|end▁of▁sentence|>`
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+
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+ Prefix:
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+ `<|User|>{query}<|Assistant|><think>`
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+
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+ The multi-turn template is the same with non-thinking multi-turn chat template. It means the thinking token in the last turn will be dropped but the `</think>` is retained in every turn of context.
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+
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+ ### ToolCall
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+ Toolcall is supported in non-thinking mode. The format is:
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+
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+ `<|begin▁of▁sentence|>{system prompt}{tool_description}<|User|>{query}<|Assistant|></think>` where the tool_description is
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+
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+ ```
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+ ## Tools
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+ You have access to the following tools:
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+
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+ ### {tool_name1}
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+ Description: {description}
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+
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+ Parameters: {json.dumps(parameters)}
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+
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+ IMPORTANT: ALWAYS adhere to this exact format for tool use:
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+ <|tool▁calls▁begin|><|tool▁call▁begin|>tool_call_name<|tool▁sep|>tool_call_arguments<|tool▁call▁end|>{{additional_tool_calls}}<|tool▁calls▁end|>
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+
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+ Where:
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+ - `tool_call_name` must be an exact match to one of the available tools
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+ - `tool_call_arguments` must be valid JSON that strictly follows the tool's Parameters Schema
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+ - For multiple tool calls, chain them directly without separators or spaces
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+ ```
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+
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+ ### Code-Agent
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+ We support various code agent frameworks. Please refer to the above toolcall format to create your own code agents. An example is shown in `assets/code_agent_trajectory.html`.
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+
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+ ### Search-Agent
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+ We design a specific format for searching toolcall in thinking mode, to support search agent.
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+
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+ For complex questions that require accessing external or up-to-date information, DeepSeek-V3.1 can leverage a user-provided search tool through a multi-turn tool-calling process.
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+
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+ Please refer to the `assets/search_tool_trajectory.html` and `assets/search_python_tool_trajectory.html` for the detailed template.
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+
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+ ## Evaluation
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+ | Category | Benchmark (Metric) | DeepSeek V3.1-NonThinking | DeepSeek V3 0324 | DeepSeek V3.1-Thinking | DeepSeek R1 0528
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+ |----------|----------------------------------|-----------------|---|---|---|
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+ | General |
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+ | | MMLU-Redux (EM) | 91.8 | 90.5 | 93.7 | 93.4
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+ | | MMLU-Pro (EM) | 83.7 | 81.2 | 84.8 | 85.0
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+ | | GPQA-Diamond (Pass@1) | 74.9 | 68.4 | 80.1 | 81.0
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+ | | Humanity's Last Exam (Pass@1) | - | - | 15.9 | 17.7
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+ |Search Agent|
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+ | | BrowseComp | - | - | 30.0 | 8.9
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+ | | BrowseComp_zh | - | - | 49.2 | 35.7
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+ | | Humanity's Last Exam (Python + Search) |- | - | 29.8 | 24.8
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+ | | SimpleQA | - | - | 93.4 | 92.3
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+ | Code |
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+ | | LiveCodeBench (2408-2505) (Pass@1) | 56.4 | 43.0 | 74.8 | 73.3
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+ | | Codeforces-Div1 (Rating) | - | - | 2091 | 1930
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+ | | Aider-Polyglot (Acc.) | 68.4 | 55.1 | 76.3 | 71.6
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+ | Code Agent|
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+ | | SWE Verified (Agent mode) | 66.0 | 45.4 | - | 44.6
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+ | | SWE-bench Multilingual (Agent mode) | 54.5 | 29.3 | - | 30.5
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+ | | Terminal-bench (Terminus 1 framework) | 31.3 | 13.3 | - | 5.7
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+ | Math |
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+ | | AIME 2024 (Pass@1) | 66.3 | 59.4 | 93.1 | 91.4
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+ | | AIME 2025 (Pass@1) | 49.8 | 51.3 | 88.4 | 87.5
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+ | | HMMT 2025 (Pass@1) | 33.5 | 29.2 | 84.2 | 79.4 |
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+
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+ Note:
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+ - Search agents are evaluated with our internal search framework, which uses a commercial search API + webpage filter + 128K context window. Seach agent results of R1-0528 are evaluated with a pre-defined workflow.
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+
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+ - SWE-bench is evaluated with our internal code agent framework.
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+
172
+ - HLE is evaluated with the text-only subset.
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+
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+ ### Usage Example
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+
176
+ ```python
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+ import transformers
178
+
179
+ tokenizer = transformers.AutoTokenizer.from_pretrained("deepseek-ai/DeepSeek-V3.1")
180
+
181
+ messages = [
182
+ {"role": "system", "content": "You are a helpful assistant"},
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+ {"role": "user", "content": "Who are you?"},
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+ {"role": "assistant", "content": "<think>Hmm</think>I am DeepSeek"},
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+ {"role": "user", "content": "1+1=?"}
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+ ]
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+
188
+ tokenizer.apply_chat_template(messages, tokenize=False, thinking=True, add_generation_prompt=True)
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+ # '<|begin▁of▁sentence|>You are a helpful assistant<|User|>Who are you?<|Assistant|></think>I am DeepSeek<|end▁of▁sentence|><|User|>1+1=?<|Assistant|><think>'
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+
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+ tokenizer.apply_chat_template(messages, tokenize=False, thinking=False, add_generation_prompt=True)
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+ # '<|begin▁of▁sentence��>You are a helpful assistant<|User|>Who are you?<|Assistant|></think>I am DeepSeek<|end▁of▁sentence|><|User|>1+1=?<|Assistant|></think>'
193
+ ```
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+
195
+ ## How to Run Locally
196
+
197
+ The model structure of DeepSeek-V3.1 is the same as DeepSeek-V3. Please visit [DeepSeek-V3](https://github.com/deepseek-ai/DeepSeek-V3) repo for more information about running this model locally.
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+
199
+ ## License
200
+
201
+ This repository and the model weights are licensed under the [MIT License](LICENSE).
202
+
203
+ ## Citation
204
+
205
+ ```
206
+ @misc{deepseekai2024deepseekv3technicalreport,
207
+ title={DeepSeek-V3 Technical Report},
208
+ author={DeepSeek-AI},
209
+ year={2024},
210
+ eprint={2412.19437},
211
+ archivePrefix={arXiv},
212
+ primaryClass={cs.CL},
213
+ url={https://arxiv.org/abs/2412.19437},
214
+ }
215
+ ```
216
+
217
+ ## Contact
218
+
219
+ If you have any questions, please raise an issue or contact us at [[email protected]]([email protected]).
assets/chat_template.jinja ADDED
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+ {% if not add_generation_prompt is defined %}
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+ {% set add_generation_prompt = false %}
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+ {% endif %}
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+ {% if not thinking is defined %}
5
+ {% set thinking = false %}
6
+ {% endif %}
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+ {% set ns = namespace(is_first=false, is_tool=false, system_prompt='', is_first_sp=true, is_last_user=false) %}
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+ {%- for message in messages %}
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+ {%- if message['role'] == 'system' %}
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+ {%- if ns.is_first_sp %}
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+ {% set ns.system_prompt = ns.system_prompt + message['content'] %}
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+ {% set ns.is_first_sp = false %}
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+ {%- else %}
14
+ {% set ns.system_prompt = ns.system_prompt + '\n\n' + message['content'] %}
15
+ {%- endif %}
16
+ {%- endif %}
17
+ {%- endfor %}
18
+ {{ bos_token }}{{ ns.system_prompt }}
19
+ {%- for message in messages %}
20
+ {%- if message['role'] == 'user' %}
21
+ {%- set ns.is_tool = false -%}
22
+ {%- set ns.is_first = false -%}
23
+ {%- set ns.is_last_user = true -%}
24
+ {{'<|User|>' + message['content']}}
25
+ {%- endif %}
26
+ {%- if message['role'] == 'assistant' and message['tool_calls'] is defined and message['tool_calls'] is not none %}
27
+ {%- if ns.is_last_user %}
28
+ {{'<|Assistant|></think>'}}
29
+ {%- endif %}
30
+ {%- set ns.is_last_user = false -%}
31
+ {%- set ns.is_first = false %}
32
+ {%- set ns.is_tool = false -%}
33
+ {%- for tool in message['tool_calls'] %}
34
+ {%- if not ns.is_first %}
35
+ {%- if message['content'] is none %}
36
+ {{'<|tool▁calls▁begin|><|tool▁call▁begin|>'+ tool['function']['name'] + '<|tool▁sep|>' + tool['function']['arguments'] + '<|tool▁call▁end|>'}}
37
+ {%- else %}
38
+ {{message['content'] + '<|tool▁calls▁begin|><|tool▁call▁begin|>' + tool['function']['name'] + '<|tool▁sep|>' + tool['function']['arguments'] + '<|tool▁call▁end|>'}}
39
+ {%- endif %}
40
+ {%- set ns.is_first = true -%}
41
+ {%- else %}
42
+ {{'<|tool▁call▁begin|>'+ tool['function']['name'] + '<|tool▁sep|>' + tool['function']['arguments'] + '<|tool▁call▁end|>'}}
43
+ {%- endif %}
44
+ {%- endfor %}
45
+ {{'<|tool▁calls▁end|><|end▁of▁sentence|>'}}
46
+ {%- endif %}
47
+ {%- if message['role'] == 'assistant' and (message['tool_calls'] is not defined or message['tool_calls'] is none) %}
48
+ {%- if ns.is_last_user %}
49
+ {{'<|Assistant|>'}}
50
+ {%- if message['prefix'] is defined and message['prefix'] and thinking %}
51
+ {{'<think>'}}
52
+ {%- else %}
53
+ {{'</think>'}}
54
+ {%- endif %}
55
+ {%- endif %}
56
+ {%- set ns.is_last_user = false -%}
57
+ {%- if ns.is_tool %}
58
+ {{message['content'] + '<|end▁of▁sentence|>'}}
59
+ {%- set ns.is_tool = false -%}
60
+ {%- else %}
61
+ {%- set content = message['content'] -%}
62
+ {%- if '</think>' in content %}
63
+ {%- set content = content.split('</think>', 1)[1] -%}
64
+ {%- endif %}
65
+ {{content + '<|end▁of▁sentence|>'}}
66
+ {%- endif %}
67
+ {%- endif %}
68
+ {%- if message['role'] == 'tool' %}
69
+ {%- set ns.is_last_user = false -%}
70
+ {%- set ns.is_tool = true -%}
71
+ {{'<|tool▁output▁begin|>' + message['content'] + '<|tool▁output▁end|>'}}
72
+ {%- endif %}
73
+ {%- endfor -%}
74
+ {%- if add_generation_prompt and ns.is_last_user and not ns.is_tool %}
75
+ {{'<|Assistant|>'}}
76
+ {%- if not thinking %}
77
+ {{'</think>'}}
78
+ {%- else %}
79
+ {{'<think>'}}
80
+ {%- endif %}
81
+ {% endif %}
assets/code_agent_trajectory.html ADDED
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+ <!doctype html>
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+ <meta charset="utf-8">
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+ <style>
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+ body { margin:16px; font-family:ui-monospace, SFMono-Regular, Menlo, Monaco, Consolas, "Liberation Mono","Courier New", monospace; white-space:pre-wrap; word-break:break-word; line-height:1.6; }
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+ .token { padding:0 2px; border-radius:4px; }
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+ .yellow { background:#FFF59D; }
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+ .green { background:#C8E6C9; }
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+ .red { background:#FFCDD2; }
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+ .blue { background:#BBDEFB; }
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+ </style>
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+ <div>You are a helpful software engineer assistant.<span class="token yellow">&lt;|User|&gt;</span>&lt;uploaded_files&gt;
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+ /testbed
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+ &lt;/uploaded_files&gt;
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+ I&#x27;ve uploaded a code repository in the directory /testbed (not in /tmp/inputs). Consider the following PR description:
15
+
16
+ &lt;pr_description&gt;
17
+ Bug in posix implementation of django/core/files/locks.py
18
+ Description
19
+
20
+ The posix version of locks (the version which supports import fcntl) has a bug. The code attempts to return True to indicate success or failure acquiring a lock, but instead it always returns False. The reason is that cpython fcntl module returns None if successful, and raises an OSError to indicate failure (see https://docs.python.org/3/library/fcntl.html#fcntl.flock).
21
+ Anyone interested in using the non-blocking (i.e. locks.LOCKS_NB) requires a valid return value to know if they have successfully acquired the lock.
22
+ I believe the correct implementation should be the following:
23
+ diff --git a/django/core/files/locks.py b/django/core/files/locks.py
24
+ index c46b00b905..4938347ea7 100644
25
+ --- a/django/core/files/locks.py
26
+ +++ b/django/core/files/locks.py
27
+ @@ -107,9 +107,15 @@ else:
28
+ return True
29
+ else:
30
+ def lock(f, flags):
31
+ - ret = fcntl.flock(_fd(f), flags)
32
+ - return ret == 0
33
+ + try:
34
+ + fcntl.flock(_fd(f), flags)
35
+ + return True
36
+ + except OSError:
37
+ + return False
38
+ def unlock(f):
39
+ - ret = fcntl.flock(_fd(f), fcntl.LOCK_UN)
40
+ - return ret == 0
41
+ + try:
42
+ + fcntl.flock(_fd(f), fcntl.LOCK_UN)
43
+ + return True
44
+ + except OSError:
45
+ + return False
46
+
47
+ &lt;/pr_description&gt;
48
+
49
+ Can you help me implement the necessary changes to the repository so that the requirements specified in the &lt;pr_description&gt; are met?
50
+ I&#x27;ve already taken care of all changes to any of the test files described in the &lt;pr_description&gt;. This means you DON&#x27;T have to modify the testing logic or any of the tests in any way!
51
+
52
+ Your task is to make the minimal changes to non-tests files in the /testbed directory to ensure the &lt;pr_description&gt; is satisfied.
53
+
54
+ You are only allowed to call **ONE** function each time!<span class="token yellow">&lt;|Assistant|&gt;</span><span class="token red">&lt;/think&gt;</span>I&#x27;ll help you implement the necessary changes to fix the bug in the posix implementation of `django/core/files/locks.py`. Let me start by examining the current state of the file.<span class="token green">&lt;|tool▁calls▁begin|&gt;</span><span class="token green">&lt;|tool▁call▁begin|&gt;</span>str_replace_editor<span class="token green">&lt;|tool▁sep|&gt;</span>{&quot;command&quot;: &quot;view&quot;, &quot;path&quot;: &quot;/testbed/django/core/files/locks.py&quot;}<span class="token green">&lt;|tool▁call▁end|&gt;</span><span class="token green">&lt;|tool▁calls▁end|&gt;</span><span class="token yellow">&lt;|end▁of▁sentence|&gt;</span><span class="token green">&lt;|tool▁output▁begin|&gt;</span>Here&#x27;s the content of /testbed/django/core/files/locks.py with line numbers (which has a total of 116 lines):
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+ 1 &quot;&quot;&quot;
56
+ 2 Portable file locking utilities.
57
+ 3
58
+ 4 Based partially on an example by Jonathan Feignberg in the Python
59
+ 5 Cookbook [1] (licensed under the Python Software License) and a ctypes port by
60
+ 6 Anatoly Techtonik for Roundup [2] (license [3]).
61
+ 7
62
+ 8 [1] http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/65203
63
+ 9 [2] https://sourceforge.net/p/roundup/code/ci/default/tree/roundup/backends/portalocker.py
64
+ 10 [3] https://sourceforge.net/p/roundup/code/ci/default/tree/COPYING.txt
65
+ 11
66
+ 12 Example Usage::
67
+ 13
68
+ 14 &gt;&gt;&gt; from django.core.files import locks
69
+ 15 &gt;&gt;&gt; with open(&#x27;./file&#x27;, &#x27;wb&#x27;) as f:
70
+ 16 ... locks.lock(f, locks.LOCK_EX)
71
+ 17 ... f.write(&#x27;Django&#x27;)
72
+ 18 &quot;&quot;&quot;
73
+ 19 import os
74
+ 20
75
+ 21 __all__ = (&#x27;LOCK_EX&#x27;, &#x27;LOCK_SH&#x27;, &#x27;LOCK_NB&#x27;, &#x27;lock&#x27;, &#x27;unlock&#x27;)
76
+ 22
77
+ 23
78
+ 24 def _fd(f):
79
+ 25 &quot;&quot;&quot;Get a filedescriptor from something which could be a file or an fd.&quot;&quot;&quot;
80
+ 26 return f.fileno() if hasattr(f, &#x27;fileno&#x27;) else f
81
+ 27
82
+ 28
83
+ 29 if os.name == &#x27;nt&#x27;:
84
+ 30 import msvcrt
85
+ 31 from ctypes import (
86
+ 32 POINTER, Structure, Union, byref, c_int64, c_ulong, c_void_p, sizeof,
87
+ 33 windll,
88
+ 34 )
89
+ 35 from ctypes.wintypes import BOOL, DWORD, HANDLE
90
+ 36
91
+ 37 LOCK_SH = 0 # the default
92
+ 38 LOCK_NB = 0x1 # LOCKFILE_FAIL_IMMEDIATELY
93
+ 39 LOCK_EX = 0x2 # LOCKFILE_EXCLUSIVE_LOCK
94
+ 40
95
+ 41 # --- Adapted from the pyserial project ---
96
+ 42 # detect size of ULONG_PTR
97
+ 43 if sizeof(c_ulong) != sizeof(c_void_p):
98
+ 44 ULONG_PTR = c_int64
99
+ 45 else:
100
+ 46 ULONG_PTR = c_ulong
101
+ 47 PVOID = c_void_p
102
+ 48
103
+ 49 # --- Union inside Structure by stackoverflow:3480240 ---
104
+ 50 class _OFFSET(Structure):
105
+ 51 _fields_ = [
106
+ 52 (&#x27;Offset&#x27;, DWORD),
107
+ 53 (&#x27;OffsetHigh&#x27;, DWORD)]
108
+ 54
109
+ 55 class _OFFSET_UNION(Union):
110
+ 56 _anonymous_ = [&#x27;_offset&#x27;]
111
+ 57 _fields_ = [
112
+ 58 (&#x27;_offset&#x27;, _OFFSET),
113
+ 59 (&#x27;Pointer&#x27;, PVOID)]
114
+ 60
115
+ 61 class OVERLAPPED(Structure):
116
+ 62 _anonymous_ = [&#x27;_offset_union&#x27;]
117
+ 63 _fields_ = [
118
+ 64 (&#x27;Internal&#x27;, ULONG_PTR),
119
+ 65 (&#x27;InternalHigh&#x27;, ULONG_PTR),
120
+ 66 (&#x27;_offset_union&#x27;, _OFFSET_UNION),
121
+ 67 (&#x27;hEvent&#x27;, HANDLE)]
122
+ 68
123
+ 69 LPOVERLAPPED = POINTER(OVERLAPPED)
124
+ 70
125
+ 71 # --- Define function prototypes for extra safety ---
126
+ 72 LockFileEx = windll.kernel32.LockFileEx
127
+ 73 LockFileEx.restype = BOOL
128
+ 74 LockFileEx.argtypes = [HANDLE, DWORD, DWORD, DWORD, DWORD, LPOVERLAPPED]
129
+ 75 UnlockFileEx = windll.kernel32.UnlockFileEx
130
+ 76 UnlockFileEx.restype = BOOL
131
+ 77 UnlockFileEx.argtypes = [HANDLE, DWORD, DWORD, DWORD, LPOVERLAPPED]
132
+ 78
133
+ 79 def lock(f, flags):
134
+ 80 hfile = msvcrt.get_osfhandle(_fd(f))
135
+ 81 overlapped = OVERLAPPED()
136
+ 82 ret = LockFileEx(hfile, flags, 0, 0, 0xFFFF0000, byref(overlapped))
137
+ 83 return bool(ret)
138
+ 84
139
+ 85 def unlock(f):
140
+ 86 hfile = msvcrt.get_osfhandle(_fd(f))
141
+ 87 overlapped = OVERLAPPED()
142
+ 88 ret = UnlockFileEx(hfile, 0, 0, 0xFFFF0000, byref(overlapped))
143
+ 89 return bool(ret)
144
+ 90 else:
145
+ 91 try:
146
+ 92 import fcntl
147
+ 93 LOCK_SH = fcntl.LOCK_SH # shared lock
148
+ 94 LOCK_NB = fcntl.LOCK_NB # non-blocking
149
+ 95 LOCK_EX = fcntl.LOCK_EX
150
+ 96 except (ImportError, AttributeError):
151
+ 97 # File locking is not supported.
152
+ 98 LOCK_EX = LOCK_SH = LOCK_NB = 0
153
+ 99
154
+ 100 # Dummy functions that don&#x27;t do anything.
155
+ 101 def lock(f, flags):
156
+ 102 # File is not locked
157
+ 103 return False
158
+ 104
159
+ 105 def unlock(f):
160
+ 106 # File is unlocked
161
+ 107 return True
162
+ 108 else:
163
+ 109 def lock(f, flags):
164
+ 110 ret = fcntl.flock(_fd(f), flags)
165
+ 111 return ret == 0
166
+ 112
167
+ 113 def unlock(f):
168
+ 114 ret = fcntl.flock(_fd(f), fcntl.LOCK_UN)
169
+ 115 return ret == 0
170
+ 116
171
+ <span class="token green">&lt;|tool▁output▁end|&gt;</span>Now I can see the issue. Looking at the current implementation in lines 109-115, the code is trying to compare the return value of `fcntl.flock()` with 0, but according to the PR description, `fcntl.flock()` returns `None` on success and raises an `OSError` on failure. This means the current implementation will always return `False` because `None == 0` is `False`.
172
+
173
+ Let me examine the specific lines that need to be changed:<span class="token green">&lt;|tool▁calls▁begin|&gt;</span><span class="token green">&lt;|tool▁call▁begin|&gt;</span>str_replace_editor<span class="token green">&lt;|tool▁sep|&gt;</span>{&quot;command&quot;: &quot;view&quot;, &quot;path&quot;: &quot;/testbed/django/core/files/locks.py&quot;, &quot;view_range&quot;: [109,116]}<span class="token green">&lt;|tool▁call▁end|&gt;</span><span class="token green">&lt;|tool▁calls▁end|&gt;</span><span class="token yellow">&lt;|end▁of▁sentence|&gt;</span><span class="token green">&lt;|tool▁output▁begin|&gt;</span>Here&#x27;s the content of /testbed/django/core/files/locks.py with line numbers (which has a total of 116 lines) with view_range=[109, 116]:
174
+ 109 def lock(f, flags):
175
+ 110 ret = fcntl.flock(_fd(f), flags)
176
+ 111 return ret == 0
177
+ 112
178
+ 113 def unlock(f):
179
+ 114 ret = fcntl.flock(_fd(f), fcntl.LOCK_UN)
180
+ 115 return ret == 0
181
+ 116
182
+ <span class="token green">&lt;|tool▁output▁end|&gt;</span>Now I&#x27;ll implement the fix as described in the PR description. The fix should wrap the `fcntl.flock()` calls in try-except blocks, returning `True` on success and `False` on `OSError`:<span class="token green">&lt;|tool▁calls▁begin|&gt;</span><span class="token green">&lt;|tool▁call▁begin|&gt;</span>str_replace_editor<span class="token green">&lt;|tool▁sep|&gt;</span>{&quot;command&quot;: &quot;str_replace&quot;, &quot;path&quot;: &quot;/testbed/django/core/files/locks.py&quot;, &quot;old_str&quot;: &quot; def lock(f, flags):\n ret = fcntl.flock(_fd(f), flags)\n return ret == 0\n\n def unlock(f):\n ret = fcntl.flock(_fd(f), fcntl.LOCK_UN)\n return ret == 0&quot;, &quot;new_str&quot;: &quot; def lock(f, flags):\n try:\n fcntl.flock(_fd(f), flags)\n return True\n except OSError:\n return False\n\n def unlock(f):\n try:\n fcntl.flock(_fd(f), fcntl.LOCK_UN)\n return True\n except OSError:\n return False&quot;}<span class="token green">&lt;|tool▁call▁end|&gt;</span><span class="token green">&lt;|tool▁calls▁end|&gt;</span><span class="token yellow">&lt;|end▁of▁sentence|&gt;</span><span class="token green">&lt;|tool▁output▁begin|&gt;</span>The file /testbed/django/core/files/locks.py has been edited successfully.<span class="token green">&lt;|tool▁output▁end|&gt;</span>Let me verify the changes by viewing the modified section:<span class="token green">&lt;|tool▁calls▁begin|&gt;</span><span class="token green">&lt;|tool▁call▁begin|&gt;</span>str_replace_editor<span class="token green">&lt;|tool▁sep|&gt;</span>{&quot;command&quot;: &quot;view&quot;, &quot;path&quot;: &quot;/testbed/django/core/files/locks.py&quot;, &quot;view_range&quot;: [109,116]}<span class="token green">&lt;|tool▁call▁end|&gt;</span><span class="token green">&lt;|tool▁calls▁end|&gt;</span><span class="token yellow">&lt;|end▁of▁sentence|&gt;</span><span class="token green">&lt;|tool▁output▁begin|&gt;</span>Here&#x27;s the content of /testbed/django/core/files/locks.py with line numbers (which has a total of 122 lines) with view_range=[109, 116]:
183
+ 109 def lock(f, flags):
184
+ 110 try:
185
+ 111 fcntl.flock(_fd(f), flags)
186
+ 112 return True
187
+ 113 except OSError:
188
+ 114 return False
189
+ 115
190
+ 116 def unlock(f):
191
+ <span class="token green">&lt;|tool▁output▁end|&gt;</span><span class="token green">&lt;|tool▁calls▁begin|&gt;</span><span class="token green">&lt;|tool▁call▁begin|&gt;</span>str_replace_editor<span class="token green">&lt;|tool▁sep|&gt;</span>{&quot;command&quot;: &quot;view&quot;, &quot;path&quot;: &quot;/testbed/django/core/files/locks.py&quot;, &quot;view_range&quot;: [116,122]}<span class="token green">&lt;|tool▁call▁end|&gt;</span><span class="token green">&lt;|tool▁calls▁end|&gt;</span><span class="token yellow">&lt;|end▁of▁sentence|&gt;</span><span class="token green">&lt;|tool▁output▁begin|&gt;</span>Here&#x27;s the content of /testbed/django/core/files/locks.py with line numbers (which has a total of 122 lines) with view_range=[116, 122]:
192
+ 116 def unlock(f):
193
+ 117 try:
194
+ 118 fcntl.flock(_fd(f), fcntl.LOCK_UN)
195
+ 119 return True
196
+ 120 except OSError:
197
+ 121 return False
198
+ 122
199
+ <span class="token green">&lt;|tool▁output▁end|&gt;</span>Perfect! The changes have been successfully implemented. Let me verify the complete file structure to ensure everything looks correct:<span class="token green">&lt;|tool▁calls▁begin|&gt;</span><span class="token green">&lt;|tool▁call▁begin|&gt;</span>str_replace_editor<span class="token green">&lt;|tool▁sep|&gt;</span>{&quot;command&quot;: &quot;view&quot;, &quot;path&quot;: &quot;/testbed/django/core/files/locks.py&quot;, &quot;view_range&quot;: [90,122]}<span class="token green">&lt;|tool▁call▁end|&gt;</span><span class="token green">&lt;|tool▁calls▁end|&gt;</span><span class="token yellow">&lt;|end▁of▁sentence|&gt;</span><span class="token green">&lt;|tool▁output▁begin|&gt;</span>Here&#x27;s the content of /testbed/django/core/files/locks.py with line numbers (which has a total of 122 lines) with view_range=[90, 122]:
200
+ 90 else:
201
+ 91 try:
202
+ 92 import fcntl
203
+ 93 LOCK_SH = fcntl.LOCK_SH # shared lock
204
+ 94 LOCK_NB = fcntl.LOCK_NB # non-blocking
205
+ 95 LOCK_EX = fcntl.LOCK_EX
206
+ 96 except (ImportError, AttributeError):
207
+ 97 # File locking is not supported.
208
+ 98 LOCK_EX = LOCK_SH = LOCK_NB = 0
209
+ 99
210
+ 100 # Dummy functions that don&#x27;t do anything.
211
+ 101 def lock(f, flags):
212
+ 102 # File is not locked
213
+ 103 return False
214
+ 104
215
+ 105 def unlock(f):
216
+ 106 # File is unlocked
217
+ 107 return True
218
+ 108 else:
219
+ 109 def lock(f, flags):
220
+ 110 try:
221
+ 111 fcntl.flock(_fd(f), flags)
222
+ 112 return True
223
+ 113 except OSError:
224
+ 114 return False
225
+ 115
226
+ 116 def unlock(f):
227
+ 117 try:
228
+ 118 fcntl.flock(_fd(f), fcntl.LOCK_UN)
229
+ 119 return True
230
+ 120 except OSError:
231
+ 121 return False
232
+ 122
233
+ <span class="token green">&lt;|tool▁output▁end|&gt;</span>Excellent! The changes have been successfully implemented. Let me run a quick test to make sure the file is syntactically correct:<span class="token green">&lt;|tool▁calls▁begin|&gt;</span><span class="token green">&lt;|tool▁call▁begin|&gt;</span>bash<span class="token green">&lt;|tool▁sep|&gt;</span>{&quot;command&quot;: &quot;cd /testbed &amp;&amp; python -m py_compile django/core/files/locks.py&quot;}<span class="token green">&lt;|tool▁call▁end|&gt;</span><span class="token green">&lt;|tool▁calls▁end|&gt;</span><span class="token yellow">&lt;|end▁of▁sentence|&gt;</span><span class="token green">&lt;|tool▁output▁begin|&gt;</span><span class="token green">&lt;|tool▁output▁end|&gt;</span>Great! The file compiles without any syntax errors.
234
+
235
+ ## Summary
236
+
237
+ I have successfully implemented the fix for the bug in the posix implementation of `django/core/files/locks.py`. The changes made are:
238
+
239
+ 1. **Modified the `lock()` function** (lines 109-114): Wrapped the `fcntl.flock()` call in a try-except block that returns `True` on success and `False` when an `OSError` is raised.
240
+
241
+ 2. **Modified the `unlock()` function** (lines 116-121): Similarly wrapped the `fcntl.flock()` call in a try-except block that returns `True` on success and `False` when an `OSError` is raised.
242
+
243
+ The fix addresses the core issue described in the PR:
244
+ - The original code incorrectly compared the return value of `fcntl.flock()` with 0, but `fcntl.flock()` returns `None` on success and raises an `OSError` on failure
245
+ - This meant the functions always returned `False` (`None == 0` is `False`)
246
+ - The new implementation properly handles the success/failure cases by using try-except blocks
247
+ - This is particularly important for non-blocking locks (`LOCK_NB`) where callers need to know if the lock was successfully acquired
248
+
249
+ The changes are minimal and focused, exactly matching the suggested fix in the PR description.<span class="token yellow">&lt;|end▁of▁sentence|&gt;</span></div>
assets/search_python_tool_trajectory.html ADDED
@@ -0,0 +1,211 @@
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1
+ <!doctype html>
2
+ <meta charset="utf-8">
3
+ <style>
4
+ body { margin:16px; font-family:ui-monospace, SFMono-Regular, Menlo, Monaco, Consolas, "Liberation Mono","Courier New", monospace; white-space:pre-wrap; word-break:break-word; line-height:1.6; }
5
+ .token { padding:0 2px; border-radius:4px; }
6
+ .yellow { background:#FFF59D; }
7
+ .blue { background:#BBDEFB; }
8
+ </style>
9
+ <div><span class="token yellow">&lt;|User|&gt;</span>The current date is 2025-08-16, Saturday. Your primary task is to solve the user&#x27;s questions, leveraging the appropriate tools as needed.
10
+ [Core Instruction: Language Consistency]
11
+ You MUST write your entire response in the same language as the user&#x27;s question.
12
+ If the user asks in Chinese, you must think and write in Chinese.
13
+ If the user asks in French, you must think and write in French.
14
+ Do not switch to English unless the user&#x27;s question was in English. This applies to your reasoning, explanations, and the final answer.
15
+ [Core Instruction: Citation Formatting]
16
+ If the search tool was used and you are referencing a specific webpage in your final answer (the content after &lt;|search▁end|&gt;), you must use the format &quot;[citation:x]&quot;, where x is the corresponding webpage number.
17
+ You must first engage in step-by-step, rigorous thinking and reasoning before using the appropriate tool or providing the final answer.
18
+
19
+
20
+ ## Tools
21
+ You have access to the following tools:
22
+
23
+ ### search
24
+ Description: Search the web for information. The result will be a string.
25
+
26
+ Parameters: {&quot;type&quot;: &quot;object&quot;, &quot;properties&quot;: {&quot;questions&quot;: {&quot;type&quot;: &quot;string&quot;, &quot;description&quot;: &quot;Generate up to 5 search queries based on the requirements below:\n\n- Separate different queries with \&quot;||\&quot;. For example: \&quot;Elon Musk lawsuit OpenAI reasons||Elon Musk lawsuit OpenAI latest updates\&quot;.\n- All search queries should use generalized, search engine-friendly, and easily retrievable keywords to improve search efficiency and the relevance of results. Avoid directly extracting phrases from the question that are difficult to retrieve effectively. For example: Avoid using relative or ambiguous terms such as “third author” or “the following year.” - Instead, use more universal expressions like “author list” or “award history.”\n- For a single search query, keep them short - remove unnecessary auxiliary words, conjunctions, and interrogative words. Primarily use keyword combinations (separated by spaces). Ideally, they should not exceed 15 characters. Avoid using special punctuation marks.\n- When seeking information from non-English primary sources, adjust search query to retrieve content in the original language (e.g., chinese), even if your initial question is in English. This improves accuracy and avoids translation-related errors.\n- You can search 1 to 5 search queries in parallel each time. If the question involves comparing multiple entities (e.g., people, places, books, movies) or contains two or more sub-questions, please split it into separate queries for each entity or sub-question.\n- Do not re-search for queries that have already been searched.&quot;}}, &quot;required&quot;: [&quot;questions&quot;]}
27
+
28
+ ### python
29
+ Description: A utility that executes Python 3.11 code. Users need to explicitly import any required libraries. The tool runs the provided Python code and returns both standard output (stdout) and standard error (stderr) from the execution. You would better print the results explicitly to see the output in the return content.
30
+
31
+ Parameters: {&quot;type&quot;: &quot;object&quot;, &quot;properties&quot;: {&quot;code&quot;: {&quot;type&quot;: &quot;string&quot;, &quot;description&quot;: &quot;The python code to be executed.&quot;}}, &quot;required&quot;: [&quot;code&quot;]}
32
+
33
+ IMPORTANT: ALWAYS adhere to this exact format for tool use:
34
+ &lt;|tool▁calls▁begin|&gt;&lt;|tool▁call▁begin|&gt;tool_call_name&lt;|tool▁sep|&gt;tool_call_arguments&lt;|tool▁call▁end|&gt;{additional_tool_calls}&lt;|tool▁calls▁end|&gt;
35
+
36
+ Where:
37
+ - `tool_call_name` must be an exact match to one of the available tools
38
+ - `tool_call_arguments` must be valid JSON that strictly follows the tool&#x27;s Parameters Schema
39
+ - For multiple tool calls, chain them directly without separators or spaces
40
+
41
+ # The user&#x27;s message is: We are designing a simple liquid-mirror telescope, as originally proposed by Isaac Newton. To do this, we first fill up a cylindrical tank (made of Kevlar) with a low melting point alloy of incompressible, inviscid gallium, and start rotating it about a vertical axis.
42
+
43
+ The rotation was initiated from a resting state at $t=0$, and is realized by constant power source such that an angular speed of $\omega(t)$ is given to the rotating fluid. Neglect surface tension effects, and we have that $|x| \ll R$, where $R$ is the radius of the Kevlar cylinder and $x$ is the $x$-coordinate on the gallium surface. It is ensured that equilibrium is maintained so that the entire mass of the liquid rotates with the same angular speed; the flow is quasi steady, there is no unsteady convection acceleration.
44
+
45
+ The focal length of the rotating fluid varies with time, and we want to find out how it changes with time. Compute $n$, where $f \propto t^n$ ($n$ is a rational number).<span class="token yellow">&lt;|Assistant|&gt;</span><span class="token yellow">&lt;/think&gt;</span><span class="token blue">&lt;|search▁begin|&gt;</span>
46
+
47
+ We are to find the exponent n such that the focal length f ∝ t^n.
48
+
49
+ Step 1: Understand the setup and the physics.
50
+ We have a cylindrical tank filled with a low melting point alloy (gallium) that is rotating about a vertical axis.
51
+ The rotation starts from rest at t=0 and is driven by a constant power source. The angular speed ω(t) is given.
52
+ The entire mass of the liquid rotates with the same angular speed (solid body rotation) and the flow is quasi-steady.
53
+
54
+ [……]
55
+
56
+ Let us use the python tool.<span class="token blue">&lt;|tool▁calls▁begin|&gt;</span><span class="token blue">&lt;|tool▁call▁begin|&gt;</span>python<span class="token blue">&lt;|tool▁sep|&gt;</span>{&quot;code&quot;:&quot;import numpy as np\nfrom scipy.integrate import solve_ivp\nimport matplotlib.pyplot as plt\n\n# Given parameters\ng = 9.8\nrho = 6000\nH = 0.1\nR = 0.5\nP = 100\n\n# Compute A and B\nA = (np.pi * rho * H * R**4) / 4\nB = (np.pi * rho * R**6) / (48 * g)\n\n# Differential equation: du/dt = P / (A + 2B*u), where u = ω^2\ndef dudt(t, u):\n return P / (A + 2*B*u)\n\n# Initial condition: at t=0, u=0\n# We start from a very small u to avoid division by zero? Actually, at t=0, u=0, but A+2B*0 = A &gt;0, so it&#x27;s finite.\n# However, we cannot start exactly at t=0 because the log-log plot requires t&gt;0. We start at t=0.001 s\nu0 = [0] # initial u=0\n\n# Time span: from t=0 to t=1000 seconds\nt_span = (0, 1000)\n\n# Solve the ODE\nsol = solve_ivp(dudt, t_span, u0, t_eval=np.logspace(-3, 3, 1000)) # t from 0.001 to 1000 seconds\n\n# Extract u = ω^2\nu = sol.y[0]\nt = sol.t\n\n# Compute focal length f = g/(2ω^2) = g/(2u)\nf = g / (2*u)\n\n# Plot log(f) vs log(t)\nlog_t = np.log10(t)\nlog_f = np.log10(f)\n\n# Fit a linear polynomial to log(f) vs log(t) to find exponent n (where f ∝ t^n)\n# We will fit for the entire range and also for small t and large t separately\n# Fit for entire range\ncoeffs_all = np.polyfit(log_t, log_f, 1)\nn_all = coeffs_all[0]\n\n# Fit for small t: t &lt; 1 second\nmask_small = t &lt; 1\nlog_t_small = np.log10(t[mask_small])\nlog_f_small = np.log10(f[mask_small])\ncoeffs_small = np.polyfit(log_t_small, log_f_small, 1)\nn_small = coeffs_small[0]\n\n# Fit for large t: t &gt; 100 seconds\nmask_large = t &gt; 100\nlog_t_large = np.log10(t[mask_large])\nlog_f_large = np.log10(f[mask_large])\ncoeffs_large = np.polyfit(log_t_large, log_f_large, 1)\nn_large = coeffs_large[0]\n\n# Output the results\nprint(f\&quot;For the entire time range: n = {n_all}\&quot;)\nprint(f\&quot;For small t (t&lt;1s): n = {n_small}\&quot;)\nprint(f\&quot;For large t (t&gt;100s): n = {n_large}\&quot;)\n\n# Plotting\nplt.figure(figsize=(10,6))\nplt.plot(log_t, log_f, label=&#x27;log(f) vs log(t)&#x27;)\nplt.plot(log_t, np.poly1d(coeffs_all)(log_t), label=f&#x27;Fit entire range: n={n_all:.3f}&#x27;)\nplt.plot(log_t_small, np.poly1d(coeffs_small)(log_t_small), label=f&#x27;Fit small t: n={n_small:.3f}&#x27;)\nplt.plot(log_t_large, np.poly1d(coeffs_large)(log_t_large), label=f&#x27;Fit large t: n={n_large:.3f}&#x27;)\nplt.xlabel(&#x27;log10(t)&#x27;)\nplt.ylabel(&#x27;log10(f)&#x27;)\nplt.legend()\nplt.title(&#x27;Focal length f vs time t (log-log scale)&#x27;)\nplt.show()\n\n# Also, we can plot f vs t on a log-log scale to see the power law\nplt.figure(figsize=(10,6))\nplt.loglog(t, f, label=&#x27;f vs t&#x27;)\nplt.xlabel(&#x27;t (s)&#x27;)\nplt.ylabel(&#x27;f (m)&#x27;)\nplt.title(&#x27;Focal length f vs time t (log-log scale)&#x27;)\nplt.legend()\nplt.show()&quot;}<span class="token blue">&lt;|tool▁call▁end|&gt;</span><span class="token blue">&lt;|tool▁calls▁end|&gt;</span><span class="token blue">&lt;|end▁of▁sentence|&gt;</span><span class="token yellow">&lt;|tool▁output▁begin|&gt;</span>For the entire time range: n = -0.8653530094963188
57
+ For small t (t&lt;1s): n = -0.9939289504693204
58
+ For large t (t&gt;100s): n = -0.5535757130138304
59
+
60
+ <span class="token yellow">&lt;|tool▁output▁end|&gt;</span>We are to find the exponent n such that the focal length f ∝ t^n.
61
+ The numerical simulation shows:
62
+ For small t (t&lt;1s): n ≈ -0.994 ≈ -1
63
+ For large t (t&gt;100s): n ≈ -0.554 ≈ -0.55
64
+ However, the problem likely expects a single rational number.
65
+
66
+ [……]
67
+
68
+ Since the tool only returns the plots and the fits, we will add some print statements.
69
+
70
+ We are also interested in the value of ω^2 at t=1000s and whether it satisfies the small deformation condition.
71
+
72
+ Let&#x27;s run the code again with additional output.<span class="token blue">&lt;|tool▁calls▁begin|&gt;</span><span class="token blue">&lt;|tool▁call▁begin|&gt;</span>python<span class="token blue">&lt;|tool▁sep|&gt;</span>{&quot;code&quot;:&quot;import numpy as np\nfrom scipy.integrate import solve_ivp\n\n# Given parameters\ng = 9.8\nrho = 6000\nH = 0.1\nR = 0.5\nP = 100\n\n# Compute A and B\nA = (np.pi * rho * H * R**4) / 4\nB = (np.pi * rho * R**6) / (48 * g)\n\n# Differential equation: du/dt = P / (A + 2B*u), where u = ω^2\ndef dudt(t, u):\n return P / (A + 2*B*u)\n\n# Initial condition: at t=0, u=0\nu0 = [0]\n\n# Time span: from t=0 to t=10000 seconds to extend the range\nt_span = (0, 10000)\n\n# Solve the ODE\nsol = solve_ivp(dudt, t_span, u0, t_eval=np.logspace(-3, 4, 10000)) # t from 0.001 to 10000 seconds\n\n# Extract u = ω^2\nu = sol.y[0]\nt = sol.t\n\n# Compute focal length f = g/(2ω^2) = g/(2u)\nf = g / (2*u)\n\n# Find index where t is closest to 1000s\nidx_1000 = np.argmin(np.abs(t - 1000))\nu_at_1000 = u[idx_1000]\nf_at_1000 = f[idx_1000]\n\n# Compute the deformation Δz = (ω^2 R^2)/(2g) at t=1000s\ndelta_z = (u_at_1000 * R**2) / (2*g)\n\n# Small deformation condition: ω^2 &lt;&lt; 2gH/R^2\nsmall_deform_cond = 2*g*H / R**2\n\n# Output the values\nprint(f\&quot;At t=1000s:\&quot;)\nprint(f\&quot; ω^2 = {u_at_1000} s^{-2}\&quot;)\nprint(f\&quot; Focal length f = {f_at_1000} m\&quot;)\nprint(f\&quot; Deformation Δz = {delta_z} m\&quot;)\nprint(f\&quot; Small deformation condition (2gH/R^2) = {small_deform_cond} s^{-2}\&quot;)\nprint(f\&quot; Ratio ω^2 / (2gH/R^2) = {u_at_1000 / small_deform_cond}\&quot;)\n\n# Fit for large t: t &gt; 1000 seconds\nmask_large = t &gt; 1000\nlog_t_large = np.log10(t[mask_large])\nlog_f_large = np.log10(f[mask_large])\ncoeffs_large = np.polyfit(log_t_large, log_f_large, 1)\nn_large = coeffs_large[0]\n\nprint(f\&quot;\\nFor large t (t&gt;1000s): n = {n_large}\&quot;)&quot;}<span class="token blue">&lt;|tool▁call▁end|&gt;</span><span class="token blue">&lt;|tool▁calls▁end|&gt;</span><span class="token blue">&lt;|end▁of▁sentence|&gt;</span><span class="token yellow">&lt;|tool▁output▁begin|&gt;</span>At t=1000s:
73
+ ω^2 = 376.98912482143055 s^-2
74
+ Focal length f = 0.012997722420563183 m
75
+ Deformation Δz = 4.80853475537539 m
76
+ Small deformation condition (2gH/R^2) = 7.840000000000001 s^-2
77
+ Ratio ω^2 / (2gH/R^2) = 48.08534755375389
78
+
79
+ For large t (t&gt;1000s): n = -0.517010188734457
80
+
81
+ <span class="token yellow">&lt;|tool▁output▁end|&gt;</span>We are designing a liquid-mirror telescope with a constant power source. The focal length f is given by f = g/(2ω^2), and we need to find how f scales with time t, i.e., f ∝ t^n.
82
+
83
+ Theoretical Analysis:
84
+ The power input P is constant and is used to increase the rotational kinetic energy K of the fluid. The kinetic energy is given by:
85
+ K = (1/2) I ω^2
86
+ where I is the moment of inertia of the fluid.
87
+
88
+ [……]
89
+
90
+ However, the search tool might help.
91
+
92
+ We will search for: &quot;liquid mirror telescope constant power focal length time dependence&quot;
93
+
94
+ But this is a very specific query. We will try.
95
+
96
+ We will also search for: &quot;Isaac Newton liquid mirror telescope constant power&quot;
97
+
98
+ However, we are not sure.
99
+
100
+ We will use the search tool.<span class="token blue">&lt;|tool▁calls▁begin|&gt;</span><span class="token blue">&lt;|tool▁call▁begin|&gt;</span>search<span class="token blue">&lt;|tool▁sep|&gt;</span>{&quot;questions&quot;: &quot;liquid mirror telescope constant power focal length time dependence||Isaac Newton liquid mirror telescope constant power||liquid mirror telescope focal length time scaling||rotating fluid mirror constant power focal length||gallium liquid mirror telescope constant power&quot;}<span class="token blue">&lt;|tool▁call▁end|&gt;</span><span class="token blue">&lt;|tool▁calls▁end|&gt;</span><span class="token blue">&lt;|end▁of▁sentence|&gt;</span><span class="token yellow">&lt;|tool▁output▁begin|&gt;</span>[webpage 4 begin]
101
+ [webpage title]Focal Length of a Rotating Liquid Mirror [closed]
102
+ [webpage url]https://physics.stackexchange.com/questions/759795/focal-length-of-a-rotating-liquid-mirror
103
+ [webpage date published]
104
+ [webpage snippet begin]
105
+ Apr 15, 2023 — The simplest way to find the focus is to find a ray that will be horizontal after reflecting from the parabola. In the point where this ...
106
+ [webpage snippet end]
107
+ [webpage content begin]
108
+ #### Stack Exchange Network
109
+
110
+ Stack Exchange network consists of 183 Q&amp;A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
111
+ Visit Stack Exchange
112
+ [……]
113
+ [webpage content end]
114
+ [webpage 4 end]
115
+ [……]
116
+ <span class="token yellow">&lt;|tool▁output▁end|&gt;</span>We are to compute the exponent n in the proportionality f ∝ t^n for the focal length of a liquid-mirror telescope.
117
+ The focal length of a parabolic mirror formed by a rotating liquid is given by:
118
+ f = g / (2 ω^2)
119
+ [……]
120
+
121
+ <span class="token blue">&lt;|search▁end|&gt;</span>
122
+
123
+ The focal length \(f\) of the liquid-mirror telescope is given by the formula[citation:4][citation:11]:
124
+ $$
125
+ f = \frac{g}{2\omega^2}
126
+ $$
127
+ where \(g\) is the acceleration due to gravity and \(\omega\) is the angular speed of the rotating fluid.
128
+
129
+ The rotation is driven by a constant power source \(P\), which is used to increase the rotational kinetic energy \(K\) of the fluid:
130
+ $$
131
+ P = \frac{dK}{dt} = \text{constant}
132
+ $$
133
+
134
+ The rotational kinetic energy \(K\) is expressed as:
135
+ $$
136
+ K = A \omega^2 + B \omega^4
137
+ $$
138
+ where:
139
+ - \(A = \frac{\pi \rho H R^4}{4}\)
140
+ - \(B = \frac{\pi \rho R^6}{48g}\)
141
+ Here, \(\rho\) is the density of the fluid, \(H\) is the initial height of the fluid in the cylindrical tank, and \(R\) is the radius of the tank.
142
+
143
+ This expression for \(K\) accounts for the change in the moment of inertia of the fluid due to the deformation of its surface into a paraboloid. The surface shape is given by:
144
+ $$
145
+ z(r) = \frac{\omega^2 r^2}{2g} + z_0
146
+ $$
147
+ where \(z_0 = H - \frac{\omega^2 R^2}{4g}\) ensures volume conservation.
148
+
149
+ Using \(u = \omega^2\), the power constraint becomes:
150
+ $$
151
+ P = \frac{dK}{dt} = (A + 2B u) \frac{du}{dt}
152
+ $$
153
+ Solving this differential equation with the initial condition \(u(0) = 0\) yields:
154
+ $$
155
+ A u + B u^2 = P t
156
+ $$
157
+ This is a quadratic in \(u\):
158
+ $$
159
+ B u^2 + A u - P t = 0
160
+ $$
161
+ with the solution:
162
+ $$
163
+ u = \frac{-A + \sqrt{A^2 + 4B P t}}{2B}
164
+ $$
165
+ Substituting this into the expression for \(f\):
166
+ $$
167
+ f = \frac{g}{2u} = \frac{g B}{-A + \sqrt{A^2 + 4B P t}}
168
+ $$
169
+
170
+ ### Time Dependence of \(f\)
171
+ The behavior of \(f\) depends on the relative sizes of the terms \(A\) and \(4B P t\) under the square root:
172
+ - **For small \(t\)** (early times), \(4B P t \ll A^2\), and:
173
+ $$
174
+ \sqrt{A^2 + 4B P t} \approx A + \frac{2B P t}{A}
175
+ $$
176
+ Thus:
177
+ $$
178
+ u \approx \frac{-A + A + \frac{2B P t}{A}}{2B} = \frac{P t}{A}
179
+ $$
180
+ and:
181
+ $$
182
+ f = \frac{g}{2u} \approx \frac{g}{2 \left( \frac{P t}{A} \right)} = \frac{g A}{2P} \frac{1}{t}
183
+ $$
184
+ This gives \(f \propto t^{-1}\), so \(n = -1\).
185
+ - **For large \(t\)** (late times), \(4B P t \gg A^2\), and:
186
+ $$
187
+ \sqrt{A^2 + 4B P t} \approx 2 \sqrt{B P t}
188
+ $$
189
+ Thus:
190
+ $$
191
+ u \approx \frac{-A + 2 \sqrt{B P t}}{2B} \approx \sqrt{\frac{P t}{B}} \quad (\text{since } 2 \sqrt{B P t} \gg A)
192
+ $$
193
+ and:
194
+ $$
195
+ f = \frac{g}{2u} \approx \frac{g}{2 \sqrt{\frac{P t}{B}}} = \frac{g \sqrt{B}}{2 \sqrt{P}} \frac{1}{\sqrt{t}}
196
+ $$
197
+ This gives \(f \propto t^{-1/2}\), so \(n = -1/2\).
198
+
199
+ ### Role of the Condition \(|x| \ll R\)
200
+ The condition \(|x| \ll R\) (where \(x\) is the radial coordinate on the fluid surface) indicates that we are considering points near the axis of rotation. This ensures that the parabolic surface shape \(z(r) = \frac{\omega^2 r^2}{2g} + z_0\) holds and that the focal length formula \(f = \frac{g}{2\omega^2}\) remains valid. However, this condition does not restrict the time evolution of \(\omega(t)\), which is governed by the constant power input and the resulting kinetic energy equation.
201
+
202
+ ### Rationale for \(n = -1/2\)
203
+ - The constant power source \(P\) drives the system toward the large-\(t\) regime, where \(4B P t \gg A^2\). In this regime, the term \(B u^2\) dominates over \(A u\) in the energy equation \(A u + B u^2 = P t\), leading to \(u \propto \sqrt{t}\) and \(f \propto t^{-1/2}\).
204
+ - The condition \(|x| \ll R\) is satisfied for points near the axis regardless of the deformation size, as the parabolic shape is exact for solid-body rotation. However, the time dependence of \(f\) is determined by the global energy balance, which includes the change in moment of inertia due to surface deformation.
205
+ - Numerical simulations (using representative parameters \(g = 9.8 \text{m/s}^2\), \(\rho = 6000 \text{kg/m}^3\), \(H = 0.1 \text{m}\), \(R = 0.5 \text{m}\), and \(P = 100 \text{W}\)) confirm that for large \(t\) (e.g., \(t &gt; 1000 \text{s}\)), the exponent \(n\) approaches approximately \(-0.517\), which is close to \(-0.5\). This supports the large-\(t\) regime where \(n = -1/2\).
206
+ - The small-\(t\) regime (\(n = -1\)) is transient and quickly transitions to the large-\(t\) regime under constant power input.
207
+
208
+ ### Conclusion
209
+ The focal length \(f\) scales with time \(t\) as \(f \propto t^n\), where \(n = -1/2\). This result holds in the large-\(t\) regime, where the deformation of the fluid surface is significant and the term \(B \omega^4\) in the kinetic energy dominates.
210
+
211
+ \boxed{n = -\dfrac{1}{2}}</div>
assets/search_tool_trajectory.html ADDED
@@ -0,0 +1,123 @@
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1
+ <!doctype html>
2
+ <meta charset="utf-8">
3
+ <style>
4
+ body { margin:16px; font-family:ui-monospace, SFMono-Regular, Menlo, Monaco, Consolas, "Liberation Mono","Courier New", monospace; white-space:pre-wrap; word-break:break-word; line-height:1.6; }
5
+ .token { padding:0 2px; border-radius:4px; }
6
+ .yellow { background:#FFF59D; }
7
+ .blue { background:#BBDEFB; }
8
+ </style>
9
+ <div><span class="token yellow">&lt;|User|&gt;</span>The current date is 2025-08-16, Saturday. Your primary task is to solve the user&#x27;s questions, leveraging the appropriate tools as needed.
10
+ [Core Instruction: Language Consistency]
11
+ You MUST write your entire response in the same language as the user&#x27;s question.
12
+ If the user asks in Chinese, you must think and write in Chinese.
13
+ If the user asks in French, you must think and write in French.
14
+ Do not switch to English unless the user&#x27;s question was in English. This applies to your reasoning, explanations, and the final answer.
15
+ [Core Instruction: Citation Formatting]
16
+ If the search tool was used and you are referencing a specific webpage in your final answer (the content after &lt;|search▁end|&gt;), you must use the format &quot;[citation:x]&quot;, where x is the corresponding webpage number.
17
+ You must first engage in step-by-step, rigorous thinking and reasoning before using the appropriate tool or providing the final answer.
18
+
19
+
20
+ ## Tools
21
+ You have access to the following tools:
22
+
23
+ ### search
24
+ Description: Search the web for information. The result will be a string.
25
+
26
+ Parameters: {&quot;type&quot;: &quot;object&quot;, &quot;properties&quot;: {&quot;questions&quot;: {&quot;type&quot;: &quot;string&quot;, &quot;description&quot;: &quot;Generate up to 5 search queries based on the requirements below:\n\n- Separate different queries with \&quot;||\&quot;. For example: \&quot;Elon Musk lawsuit OpenAI reasons||Elon Musk lawsuit OpenAI latest updates\&quot;.\n- All search queries should use generalized, search engine-friendly, and easily retrievable keywords to improve search efficiency and the relevance of results. Avoid directly extracting phrases from the question that are difficult to retrieve effectively. For example: Avoid using relative or ambiguous terms such as “third author” or “the following year.” - Instead, use more universal expressions like “author list” or “award history.”\n- For a single search query, keep them short - remove unnecessary auxiliary words, conjunctions, and interrogative words. Primarily use keyword combinations (separated by spaces). Ideally, they should not exceed 15 characters. Avoid using special punctuation marks.\n- When seeking information from non-English primary sources, adjust search query to retrieve content in the original language (e.g., chinese), even if your initial question is in English. This improves accuracy and avoids translation-related errors.\n- You can search 1 to 5 search queries in parallel each time. If the question involves comparing multiple entities (e.g., people, places, books, movies) or contains two or more sub-questions, please split it into separate queries for each entity or sub-question.\n- Do not re-search for queries that have already been searched.&quot;}}, &quot;required&quot;: [&quot;questions&quot;]}
27
+
28
+ IMPORTANT: ALWAYS adhere to this exact format for tool use:
29
+ &lt;|tool▁calls▁begin|&gt;&lt;|tool▁call▁begin|&gt;tool_call_name&lt;|tool▁sep|&gt;tool_call_arguments&lt;|tool▁call▁end|&gt;{additional_tool_calls}&lt;|tool▁calls▁end|&gt;
30
+
31
+ Where:
32
+ - `tool_call_name` must be an exact match to one of the available tools
33
+ - `tool_call_arguments` must be valid JSON that strictly follows the tool&#x27;s Parameters Schema
34
+ - For multiple tool calls, chain them directly without separators or spaces
35
+
36
+ # The user&#x27;s message is: 有一个全球旗舰店被称为“博物馆”的品牌,在2025年5月初与一家中国度假酒店集团进行的品牌联名,这次联名的宣传片的艺术指导是谁?<span class="token yellow">&lt;|Assistant|&gt;</span><span class="token yellow">&lt;/think&gt;</span><span class="token blue">&lt;|search▁begin|&gt;</span>
37
+
38
+ 我们将逐步解决这个问题。首先,我们需要找到符合以下条件的品牌:
39
+
40
+ 1. 全球旗舰店被称为“博物馆”的品牌。
41
+ 2. 在2025年5月初与一家中国度假酒店集团进行品牌联名。
42
+ 3. 联名宣传片的艺术指导是谁?
43
+
44
+ ### 第一步:全球旗舰店被称为“博物馆”的品牌
45
+
46
+ 首先,我们需要找到全球旗舰店被称为“博物馆”的品牌。可能的候选包括:
47
+
48
+ [……]
49
+
50
+ ### 搜索符合条件的品牌
51
+
52
+ 我将先搜索符合条件的品牌。<span class="token blue">&lt;|tool▁calls▁begin|&gt;</span><span class="token blue">&lt;|tool▁call▁begin|&gt;</span>search<span class="token blue">&lt;|tool▁sep|&gt;</span>{&quot;questions&quot;:&quot;全球旗舰店被称为博物馆的品牌||全球旗舰店博物馆||Aesop全球旗舰店博物馆||Aesop旗舰店博物馆||Nike全���旗舰店博物馆&quot;}<span class="token blue">&lt;|tool▁call▁end|&gt;</span><span class="token blue">&lt;|tool▁calls▁end|&gt;</span><span class="token blue">&lt;|end▁of▁sentence|&gt;</span><span class="token yellow">&lt;|tool▁output▁begin|&gt;</span>[webpage 0 begin]
53
+ [webpage title]始祖鸟在它的“博物馆”里如何讲户外故事?
54
+ [webpage url]https://wap.eastmoney.com/a/202405213082252819.html
55
+ [webpage date published]
56
+ [webpage snippet begin]
57
+ 2024年5月21日 — 如何低门槛投资美股? 5月18日,位于上海南京西路的始祖鸟全球旗舰店正式开业,而这家店的另一个名称是“始祖鸟博物馆”。一楼和二楼则是多种产品线的零售 ...
58
+ [webpage snippet end]
59
+ [webpage content begin]
60
+ [……]
61
+ [webpage content end]
62
+ [webpage 0 end]
63
+ [……]
64
+ <span class="token yellow">&lt;|tool▁output▁end|&gt;</span>根据搜索结果,符合条件的品牌是始祖鸟(Arc&#x27;teryx)。其全球旗舰店被称为“始祖鸟博物馆”,位于上海南京西路。
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+
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+ ### 第二步:品牌联名
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+
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+ 根据问题描述,始祖鸟在2025年5月初与一家中国度假酒店集团进行品牌联名。我们需要找到这次联名的宣传片艺术指导。
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+
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+ #### 关键点:
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+
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+ 1. **时间**:2025年5月初(由于当前时间是2025年8月16日,而联名发生在2025年5月初,因此可能需要搜索相关新闻或公告)。
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+ 2. **联名对象**:一家中国度假酒店集团。
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+ 3. **联名内容**:品牌联名,宣传片的艺术指导。
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+
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+ ### 第三步:始祖鸟的联名活动
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+
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+ 我需要先找到始祖鸟在2025年5月初与中国度假酒店集团的联名活动。可能的度假酒店集团包括:
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+
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+ 1. **松赞酒店**:始祖鸟曾与松赞酒店合作过(根据之前的文章提到)。
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+ 2. **安缦酒店**:高端度假酒店。
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+ 3. **悦榕庄**:度假酒店集团。
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+ 4. **Club Med**:度假村集团。
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+ 5. **华住集团**:旗下有度假酒店品牌,但可能不符合“度假酒店集团”的描述。
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+ 6. **开元酒店集团**:度假酒店品牌。
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+ 7. **柏联酒店**:高端度假酒店。
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+
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+ 根据之前的文章提到,始祖鸟曾与松赞酒店合作过联名服饰。因此,松赞酒店可能是联名对象之一。
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+
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+ ### 第四步:搜索联名活动
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+
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+ 我需要搜索始祖鸟在2025年5月初与中国度假酒店集团的联名活动。我将先尝试搜索相关新闻。<span class="token blue">&lt;|tool▁calls▁begin|&gt;</span><span class="token blue">&lt;|tool▁call▁begin|&gt;</span>search<span class="token blue">&lt;|tool▁sep|&gt;</span>{&quot;questions&quot;:&quot;始祖鸟2025年5月联名||始祖鸟2025年5月酒店联名||始祖鸟度假酒店联名||始祖鸟宣传片艺术指导||始祖鸟松赞联名2025&quot;}<span class="token blue">&lt;|tool▁call▁end|&gt;</span><span class="token blue">&lt;|tool▁calls▁end|&gt;</span><span class="token blue">&lt;|end▁of▁sentence|&gt;</span><span class="token yellow">&lt;|tool▁output▁begin|&gt;</span>[webpage 19 begin]
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+ [webpage title]始祖鸟× 松赞相约纳木错
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+ [webpage url]https://socialbeta.com/campaign/24810
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+ [webpage date published]
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+ [webpage snippet begin]
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+ 始祖鸟与中国高端旅行品牌松赞再次携手,推出以「圣湖」纳木措为灵感的全新联名系列。这已是双方继以两座神山——卡瓦格博与南迦巴瓦为灵感之后的第三次 ...
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+ [webpage snippet end]
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+ [webpage content begin]
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+ [……]
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+ [webpage content end]
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+ [webpage 19 end]
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+ [……]
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+ <span class="token yellow">&lt;|tool▁output▁end|&gt;</span>根据搜索结果,始祖鸟在2025年5月初与松赞酒店集团进行了联名合作。这次联名以纳木措湖为灵感,推出了联名系列产品,并拍摄了概念影片《见水知蓝·纳木措》。
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+
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+ ### 第五步:宣传片的艺术指导
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+
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+ 根据搜索结果,宣传片《见水知蓝·纳木措》的艺术指导是国际摄影大师杜可风(Christopher Doyle)。
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+
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+ ### 最终答案
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+
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+ 根据搜索结果,始祖鸟与松赞酒店集团的联名宣传片《见水知蓝·纳木措》的艺术指导是杜可风(Christopher Doyle)。
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+
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+ <span class="token blue">&lt;|search▁end|&gt;</span>
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+
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+ 根据搜索结果,始祖鸟(Arc&#x27;teryx)在2025年5月初与中国度假酒店集团松赞(Songtsam)进行了品牌联名,推出了以纳木措湖为灵感的联名系列[citation:19][citation:21]。此次联名的宣传片《见水知蓝·纳木措》的艺术指导是国际摄影大师**杜可风**(Christopher Doyle)[citation:21]。
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+
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+ ### 联名背景:
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+ - **合作对象**:始祖鸟 × 松赞(第三次合作,聚焦纳木措湖)[citation:19][citation:21]
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+ - **宣传片**:《见水知蓝·纳木措》,以纳木措湖的“开湖”时刻为灵感,采用16:9宽幅画面和沉浸式叙事手法,展现高原自然与人文的共生哲学[citation:21]。
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+ - **艺术指导**:杜可风(Christopher Doyle)担任艺术指导,将其标志性的蓝调美学融入影片,强调自然光影和真实记录[citation:21]。
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+
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+ 如需进一步了解联名详情或宣传片内容,可以查阅或[citation:19][citation:21]。</div>