Correctly uses to write 5a M1 3.1b 5th problems of Correctly finds =(m s−2) or 2.8125 (m s−2). Accept awrt a A1 1.1b connected 2.8 (m s−2). particles using pulleys. (2) Demonstrates an understanding that the resultant force acting 5b M1 3.1b 5th on sphere is 1.2g B T. – Solve problems of connected Uses = to F ma M1 3.3 particles using Correctly solves to find =(N) or 8.385 (N). Accept 8.4 (N). pulleys. T A1 ft 1.1b (3) 5c Demonstrates an understanding that the resultant acting M1 3.1b 5th on box is A T F. – Solve problems of connected Uses = to write 3.3 M1 F ma particles using pulleys. Correctly solves to find = (N) or 6.135 (N). Accept 6.1 (N). A1ft 1.1b F (3) 5d Uses = + to write M1 3.1b 5th v u at Solve problems of Solves to find = or 2.25 m s−1. A1 ft 1.1b v connected particles using Uses = to write = 0.8a or 0.8a M1 3.1b F ma –F −= pulleys. Solves to find =m s−2 or 7.66…( m s−2). A1 ft 1.1b a Uses to M1 2.2a Solves to find =(m) or 0.33… (m). Accept awrt 0.33 (m). A1 ft 1.1b s States that the total distance travelled will be 1.23 m 3.2 B1 ft (0.9 + 0.33).
5a Correctly uses to write M1 3.1b 5th problems of connected particles using pulleys. Correctly finds a =(m s−2) or 2.8125 (m s−2). Accept awrt 2.8 (m s−2). A1 1.1b (2) 5b Demonstrates an understanding that the resultant force acting on sphere B is 1.2g – T. M1 3.1b 5th Solve problems of connected particles using pulleys. Uses F = ma to M1 3.3 Correctly solves to find T =(N) or 8.385 (N). Accept 8.4 (N). A1 ft 1.1b (3) 5c Demonstrates an understanding that the resultant acting on box A is T – F. M1 3.1b 5th Solve problems of connected particles using pulleys. Uses F = ma to write M1 3.3 Correctly solves to find F = (N) or 6.135 (N). Accept 6.1 (N). A1ft 1.1b (3) 5d Uses v = u + at to write M1 3.1b 5th Solve problems of connected particles using pulleys. Solves to find v = or 2.25 m s−1. A1 ft 1.1b Uses F = ma to write –F = 0.8a or −= 0.8a M1 3.1b Solves to find a =m s−2 or 7.66…( m s−2). A1 ft 1.1b Uses to M1 2.2a Solves to find s =(m) or 0.33… (m). Accept awrt 0.33 (m). A1 ft 1.1b States that the total distance travelled will be 1.23 m (0.9 + 0.33). B1 ft 3.2
as_maths_mechanics_unit_8_ms.docx