A1 for 2 comparable figures, eg 33π and 100π 33 and 100 103 to 103.7 and 314 to or or 314.2 or 103 to 103.7 and 104.6 to 104.8 C1 statement eg No because it should be and their accurate figures Allow use of = 3 or better π 5 (a) 365 M1 with consistent within intervals eg 200 × 1 , 300 × 11 , 400 × 5 , 500 × 0 , fx x 600 × 3, if 200, 3300, 2000, 0, 1800 are seen without working then condone 1 error M1 (dep) eg ÷ 20 Ʃfx÷Ʃf “7300” A1 cao (b) Comment C1 for comment about outliers affecting mean 6 Shows M1 equation 48÷3 (=16) 3(2x + 6) = 48 or reasoning to eg 2x + 6 = 5x 9 3(5x 9) = 48, condone – – reach missing bracket y=3 M1 isolates and number forms equation 2x+6=“16” Isolates and number x x terms or 5x 9= terms 6x = or – “16” “30” 3x = 15 15x = “75” M1 substitutes into side isolates and number terms forms the second x “5” length 2x= or 5x = equation “10” “25” eg 2 × 5 + 6 (=16) A1 48÷16=3 or 16×3=48 shows for both solutions from 2 different x=5 x=5 equations. Paper: 1MA1/1H Question Working Answer Mark Notes 7 Comment B1 for correct mathematical comment eg line segments not a curve or should draw freehand or should not use a ruler, or should be a curve NB Do not accept statements about scale or plotting accuracy. 8 0.246, 0.4 M1 for correct use of recurring symbol eg 0.2 = 0.24646… or 3 terms in the correct 0.2 0.24 relative position A1 cao 9 22.5 P1 for process to find James’ speed eg 50÷2.5(=20) or 50 ÷ 150 (=) P1 for process to find James’ time for 15 km eg 15 ÷ (=0.75) or 15 ÷ (=45) “20”
A1 for 2 comparable figures, eg 33π and 100π or 33 and 100 or 103 to 103.7 and 314 to 314.2 or 103 to 103.7 and 104.6 to 104.8 C1 statement eg No because it should be and their accurate figures Allow use of π = 3 or better 5 (a) 365 M1 fx with x consistent within intervals eg 200 × 1 , 300 × 11 , 400 × 5 , 500 × 0 , 600 × 3, if 200, 3300, 2000, 0, 1800 are seen without working then condone 1 error M1 (dep) Ʃfx÷Ʃf eg “7300” ÷ 20 A1 cao (b) Comment C1 for comment about outliers affecting mean 6 Shows reasoning to reach y=3 M1 equation eg 2x + 6 = 5x – 9 48÷3 (=16) 3(2x + 6) = 48 or 3(5x – 9) = 48, condone missing bracket M1 isolates x and number terms 3x = 15 forms equation 2x+6=“16” or 5x – 9= “16” Isolates x and number terms 6x = “30” or 15x = “75” M1 substitutes “5” into side length eg 2 × 5 + 6 (=16) isolates x and number terms 2x= “10” or 5x = “25” forms the second equation A1 48÷16=3 or 16×3=48 shows x=5 for both solutions x=5 from 2 different equations. Paper: 1MA1/1H Question Working Answer Mark Notes 7 Comment B1 for correct mathematical comment eg line segments not a curve or should draw freehand or should not use a ruler, or should be a curve NB Do not accept statements about scale or plotting accuracy. 8 0.246, 0.4 0.2 0.24 M1 for correct use of recurring symbol eg 0.2 = 0.24646… or 3 terms in the correct relative position A1 cao 9 22.5 P1 for process to find James’ speed eg 50÷2.5(=20) or 50 ÷ 150 (=) P1 for process to find James’ time for 15 km eg 15 ÷ “20” (=0.75) or 15 ÷ (=45)
08b_1ma1_1h_-_november_2017_mark_scheme.docx