Pearson Progression Step Q Scheme Marks AOs and Progress descriptor 1a Clearly states that A1 1.1b 5th Integrate Makes an attempt to integrate the remaining two terms. Raising M1 1.1b a power by 1 would constitute an attempt. States the fully correct answer A1 1.1b (3) 1b Makes an attempt to substitute the limits into the expression. M1 1.1b 5th For example,is seen. Integrate Begins to simplify this expression. For example, is seen. M1 1.1b States the fully correct answeror states , = 6 and 1.1b A1 n Also acceptor equivalent. (3) (6 marks) Notes Pearson Progression Step Q Scheme Marks AOs and Progress descriptor 2 Makes an attempt to find M1 2.2a Writingor writingconstitutes an attempt. Correctly states A1 2.2a Makes an attempt to substitute the limits = ln and = ln 2 M1 ft 1.1b x b x into For example,and is seen. Uses laws of logarithms to begin to simplify the expression. M1 ft 2.2a Eitheror is seen. Correctly states the two answers as and 1.1b A1 ft States that M1 ft 2.2a
Q Scheme Marks AOs Pearson Progression Step and Progress descriptor 1a Clearly states that A1 1.1b 5th Integrate Makes an attempt to integrate the remaining two terms. Raising a power by 1 would constitute an attempt. M1 1.1b States the fully correct answer A1 1.1b (3) 1b Makes an attempt to substitute the limits into the expression. For example,is seen. M1 1.1b 5th Integrate Begins to simplify this expression. For example, is seen. M1 1.1b States the fully correct answeror states , n = 6 and Also acceptor equivalent. A1 1.1b (3) (6 marks) Notes Q Scheme Marks AOs Pearson Progression Step and Progress descriptor 2 Makes an attempt to find Writingor writingconstitutes an attempt. M1 2.2a Correctly states A1 2.2a Makes an attempt to substitute the limits x = ln b and x = ln 2 into For example,and is seen. M1 ft 1.1b Uses laws of logarithms to begin to simplify the expression. Eitheror is seen. M1 ft 2.2a Correctly states the two answers as and A1 ft 1.1b States that M1 ft 2.2a
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