p-value = < .287 or > .313) P(p’ p’ = 2*normalcdf(-10^99,.287,.3,)= 0.7216 Make a decision. The level of significance is the preset Since is not given, α. α assume that = 0.05. α < p-value. The Decision is do not reject because there is not Ho α sufficient evidence to conclude that the proportion of households that have three cell phones is not 30%. NOTE: Hypothesis testing problems consist of multiple steps. To help you do the problems, solution sheets are provided for your use. Look
p-value = P(p’ < .287 or p’ > .313) = 2*normalcdf(-10^99,.287,.3,)= 0.7216 Make a decision. The level of significance is the preset α. Since α is not given, assume that α = 0.05. α < p-value. The Decision is do not reject Ho because there is not sufficient evidence to conclude that the proportion of households that have three cell phones is not 30%. NOTE: Hypothesis testing problems consist of multiple steps. To help you do the problems, solution sheets are provided for your use. Look
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