oe Due to different values of an answer between π 523.3 and 523.7 gets full marks ft If both Ms awarded and one value is correct. A1 ft [5] Breaks down into areas of rectangles and areas of (quarter) circles M12. Any combination of rectangles and circles or 12.56... or is enough evidence for area of circles NB 12.56 from 2 × × 2, if seen is M0 π NB 3.14 on its own is not evidence of the area of a quarter circle as it is π M1 Uses an method (method 1) and finds ‘addition’ Area of one (or 5) quadrants ‘external’ or or Uses a method (methods 2 and 3) and finds ‘subtraction’ 5 × area one quadrant or M1 dep = 0.8584..., {0.9, 0.86, 0.858} or = (× 5) 4.292... {4.3, 4.29} 15.71, 15.7 A1 52.3 or 52.29... 68 5π – Allow 52 if 52.3 or 52.29... or a full method seen A1 [4]
oe Due to different values of π an answer between 523.3 and 523.7 gets full marks ft If both Ms awarded and one value is correct. A1 ft [5] M12. Breaks down into areas of rectangles and areas of (quarter) circles Any combination of rectangles and circles or 12.56... or is enough evidence for area of circles NB 12.56 from 2 × π × 2, if seen is M0 NB 3.14 on its own is not evidence of the area of a quarter circle as it is π M1 Uses an ‘addition’ method (method 1) and finds Area of one (or 5) ‘external’ quadrants or or Uses a ‘subtraction’ method (methods 2 and 3) and finds 5 × area one quadrant or M1 dep = 0.8584..., {0.9, 0.86, 0.858} or = (× 5) 4.292... {4.3, 4.29} 15.71, 15.7 A1 52.3 or 52.29... 68 – 5π Allow 52 if 52.3 or 52.29... or a full method seen A1 [4]
AllUnit3QnsandmarkschemeWordversion.docx