Volume increases by 6 × so claim justified. Allow but not quite’ ‘Almost A1 [5] M36. Use of Must use 4 or 8 as radius. M1 (Volume hemisphere =) 133.9 to 134.1 (inclusive) 133.97 if = 3.14 used. π A1 (Volume paperweight =) 500+(their 134) (=634) If Ml awarded. A1 ft cm3 This mark is independent B1 [4] M37. Area semicircle area circle – Accept × 102 ÷ 2 and/or × 52 for M1 π π M1 ÷ 2 (= 12.5π 6.25π = 39.27 19.63) π52 – π(2.5)2 – – Accept fractions, decimals or in terms of π A1 19.6(....)(= 6.25π) ft on one error only, e.g. Accept fractions, decimals or in terms of π. Use of as 3.14 gives 19.625 Al π Common errors e.g. × 102 ÷ 2 × 52 = 157.1 78.5 = 78.6 π – π – = Ml,A0,A0ft.
Volume increases by 6 × so claim justified. Allow ‘Almost but not quite’ A1 [5] M36. Use of Must use 4 or 8 as radius. M1 (Volume hemisphere =) 133.9 to 134.1 (inclusive) 133.97 if π = 3.14 used. A1 (Volume paperweight =) 500+(their 134) (=634) If Ml awarded. A1 ft cm3 This mark is independent B1 [4] M37. Area semicircle – area circle Accept π × 102 ÷ 2 and/or π × 52 for M1 M1 π52 ÷ 2 – π(2.5)2 (= 12.5π – 6.25π = 39.27 – 19.63) Accept fractions, decimals or in terms of π A1 19.6(....)(= 6.25π) ft on one error only, e.g. Accept fractions, decimals or in terms of π. Use of π as 3.14 gives 19.625 Al Common errors e.g. π × 102 ÷ 2 – π × 52 = 157.1 – 78.5 = 78.6 = Ml,A0,A0ft.
AllUnit3QnsandmarkschemeWordversion.docx