Detennine the following: ci>:. (a) (b) venical forces of200 N aod 400 N for sample B <1>;nt dilation at vertical forces of 200 and 400 for sample (c) The angle N N B To obtain the desired values, it is best to plot a graph of vertical Strategy force venu.s horizontal force. 5.3 Solution Step Plot a g1'3pb of the verllcal forces venus failure horizontal forces 1: for each sample.See Fig. E5.3. cf>;.. Extract Slcp 2: All the plotted points for sample fall on a straight line through A the origin. Sample nondilatant soil, possibly loose sand is a a A or n normally consolidated effective friclion is clay.The angle <1>:. 30'. q,;. Step Determine 3: 200 N N B The horizontal forces at and 400 for sample do not lie 4>:.- on the straight line correspondang to Therefore.each of c >; these forces has a associated with it. G ) (o>;),00 tJJn- N e • 41.2" Co>;).,. tan-•(!:)= 31.8" N • a,- ;- Step Determine a,. 4: (u),..,. 41.2 - 30 11.2' = • 31.8 - 30 (a)4110 1.8" = ,. • a,decreases. Note that as the normal force mcreases 500 .--- . - - - - .,....-.,.--, 1 0 O0 X 200 "00 600 800 'twta...l ftn:l! (H)
Detennine the following: (a) ci>:. (b) <1>;nt venical forces of200 N aod 400 N for sample B (c) The dilation angle at vertical forces of 200 N and 400 N for sample B Strategy To obtain the desired values, it is best to plot a graph of vertical force venu.s horizontal force. Solution 5.3 Step 1: Plot a g1'3pb of the verllcal forces venus failure horizontal forces for each sample.See Fig. E5.3. Slcp 2: Extract cf>;.. All the plotted points for sample A fall on a straight line through the origin. Sample A is a nondilatant soil, possibly a loose sand or n normally consolidated clay.The effective friclion angle is <1>:. 30'. Step 3: Determine q,;. The horizontal forces at 200 N and 400 N for sample B do not lie on the straight line correspondang to 4>:.- Therefore.each of these forces has a c >; associated with it. (o>;),00 N • tJJn- G ) e 41.2" Co>;).,. N • tan-•(!:)= 31.8" Step 4: Determine a,. a,- ;- (u),..,. • 41.2 - 30 = 11.2' (a)4110 ,. • 31.8 - 30 = 1.8" Note that as the normal force mcreases a,decreases. 500 .--- . - - - - .,....-.,.--, 1 0 X O0 200 "00 600 800 'twta...l ftn:l! (H)
AED%20Design%20Requirements%20-%20Geotechnical%20Investigations_Jan_10.docx