Undefined Terms Hypothesis Conclusion Reason no formal definition C-D-E CD+ DE= CF Betweenness can only be represented or described BC= CD Segment BC is Congruence can also be dealt with through their properties congruent to which are taken up as postulates segment CD C is the midpoint Segment BC is Midpoint of segment BD congruent to Point segment CD Segment AC is AB= CF Congruent Line congruent to Segment segment CF Line Segment Ray FG bisects C is the midpoint Bisector Ray segment BC of segment BD Opposite Rays Half Lines Plane Basic Terms Hypothesis Conclusion Reason W-A-Z WA+ AZ= WZ Betweenness Problem Figure Final Answer Segment SA is XA= AY Congruent If DT= 60, find x= 16 congruent to Segments the value of x, DS DS= 24 segment AY and ST ST= 36 A is the midpoint Segment WA = Betweenness C is the midpoint AB= 22 of segment WZ segment AZ of Segment AB. AC and CB= 11 Ray WZ bisects Segment XY is a Bisector Find AC, CB, and Segment XY bisector of AB segment WZ If RS= 3x+1, ST= x= 13 Or 2x=2, and RT=64, RS= 40 A is the midpoint find the values of ST= 24 of segment XY x, RS, and ST If RS= 87+ 4, ST= Same as figure 3 y= 7 Angles 4y+8 and RT= RS= 60 157-9, find the ST= 36 value of y, RS, ST RT= 96 and RT If PT= 5x+3 and x= 6 TQ= 7x=9, find x, PT and TQ= 33 PT, and TQ Problem Final Answer If m angle ABD= 50 and m Angle ABC= 70 degrees Applying terms of if and then angle CBD= 20, find m angle ABC If m angle ABC= 85 and m Angle CBD= 48 degrees angle ABD= 37, find m angle CBD If m angle ABC= 85, m angle m angle CBD= 40 degrees ABD= x+30 and m angle m angle ABD= 45 degrees
Undefined Terms no formal definition can only be represented or described can also be dealt with through their properties which are taken up as postulates Point Line Line Segment Ray Opposite Rays Half Lines Plane Basic Terms Problem Figure Final Answer If DT= 60, find the value of x, DS and ST x= 16 DS= 24 ST= 36 C is the midpoint of Segment AB. Find AC, CB, and AB AB= 22 AC and CB= 11 If RS= 3x+1, ST= 2x=2, and RT=64, find the values of x, RS, and ST x= 13 RS= 40 ST= 24 If RS= 87+ 4, ST= 4y+8 and RT= 157-9, find the value of y, RS, ST and RT Same as figure 3 y= 7 RS= 60 ST= 36 RT= 96 If PT= 5x+3 and TQ= 7x=9, find x, PT, and TQ x= 6 PT and TQ= 33 Applying terms of if and then Hypothesis Conclusion Reason C-D-E CD+ DE= CF Betweenness BC= CD Segment BC is congruent to segment CD Congruence C is the midpoint of segment BD Segment BC is congruent to segment CD Midpoint Segment AC is congruent to segment CF AB= CF Congruent Segment Ray FG bisects segment BC C is the midpoint of segment BD Bisector Hypothesis Conclusion Reason W-A-Z WA+ AZ= WZ Betweenness Segment SA is congruent to segment AY XA= AY Congruent Segments A is the midpoint of segment WZ Segment WA = segment AZ Betweenness Ray WZ bisects Segment XY Segment XY is a bisector of segment WZ Or A is the midpoint of segment XY Bisector Angles Problem Final Answer If m angle ABD= 50 and m angle CBD= 20, find m angle ABC Angle ABC= 70 degrees If m angle ABC= 85 and m angle ABD= 37, find m angle CBD Angle CBD= 48 degrees If m angle ABC= 85, m angle ABD= x+30 and m angle m angle CBD= 40 degrees m angle ABD= 45 degrees
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