Practice Problems: The Normal Distribution 95% of students at school weigh between 62 kg and 90 kg. Assuming this data is normally distributed, what are the mean and standard deviation? Mean = 66 kg A S.D. = 7 kg Mean = 76 kg B S.D. = 7 kg Mean = 86 kg C S.D. = 7 kg Mean = 76 kg D S.D. = 14 kg A machine produces electrical components. 99.7% of the components have lengths between 1.176 cm and 1.224 cm. Assuming this data is normally distributed, what are the mean and standard deviation? Mean = 1.210 cm A S.D. = 0.008 cm Mean = 1.190 cm B S.D. = 0.008 cm Mean = 1.200 cm C S.D. = 0.004 cm Mean = 1.200 cm D S.D. = 0.008 cm 68% of the marks in a test are between 51 and 64. Assuming this data is normally distributed, what are the mean and standard deviation? Mean = 57 A S.D. = 6.5 Mean = 57 B S.D. = 7 Mean = 57.5 C S.D. = 6.5 Mean = 57.5 D S.D. = 13 The Fresha Tea Company pack tea in bags marked as 250 g. A large number of packs of tea were weighed and the mean and standard deviation were calculated as 255 g and 2.5 g respectively. Assuming this data is normally distributed, what percentage of packs are underweight?
Practice Problems: The Normal Distribution 95% of students at school weigh between 62 kg and 90 kg. Assuming this data is normally distributed, what are the mean and standard deviation? A Mean = 66 kg S.D. = 7 kg B Mean = 76 kg S.D. = 7 kg C Mean = 86 kg S.D. = 7 kg D Mean = 76 kg S.D. = 14 kg A machine produces electrical components. 99.7% of the components have lengths between 1.176 cm and 1.224 cm. Assuming this data is normally distributed, what are the mean and standard deviation? A Mean = 1.210 cm S.D. = 0.008 cm B Mean = 1.190 cm S.D. = 0.008 cm C Mean = 1.200 cm S.D. = 0.004 cm D Mean = 1.200 cm S.D. = 0.008 cm 68% of the marks in a test are between 51 and 64. Assuming this data is normally distributed, what are the mean and standard deviation? A Mean = 57 S.D. = 6.5 B Mean = 57 S.D. = 7 C Mean = 57.5 S.D. = 6.5 D Mean = 57.5 S.D. = 13 The Fresha Tea Company pack tea in bags marked as 250 g. A large number of packs of tea were weighed and the mean and standard deviation were calculated as 255 g and 2.5 g respectively. Assuming this data is normally distributed, what percentage of packs are underweight?
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