X= -3/2 1 Thus, required point = (-3/2, 0) 12 = 1 + - Using sin 32 = cos (90-32), cos68= sin(90-68) 1 = + - as cosec52= sec(90-52), tan 18= cot(90-18), 1 tan 35= cot(90-35) = 1 + 1 - = { as sec = 1/ cos & cot = 1/ tan ) 13 For correct figure 2 steps 1 14 2
X= -3/2 Thus, required point = (-3/2, 0) 1 12 = + - Using sin 32 = cos (90-32), cos68= sin(90-68) = + - as cosec52= sec(90-52), tan 18= cot(90-18), tan 35= cot(90-35) = 1 + 1 - = { as sec = 1/ cos & cot = 1/ tan ) 1 1 1 13 For correct figure steps 2 1 14 2
453216800class_x_sample_papers.docx