2 1 4 ⋅1 (30) a. = t ) 2 2 1 2(10 ≈ 1.20 seconds ⋅ 32 sin 30º cos − ≈ 1.69 hr = 1 30º 3 4 + ≈ 1.12 seconds − = 1 1 0.75 hr . (45) 32 sin 45º ⋅ cos 45º b. = t 4 tan 45o ) 2(10 ≈ 1.20 c. (60º ) = 1 + 2 − 1 T seconds (60) c. 3sin 60o 4 tan 60o t 32 sin 60º ⋅ cos 60º = Sally is on the paved road for ) 2(10 Use the formula 122. = 1 + 2 − 1 (θ ) = cosθ x 16 + 0.5 cos(2θ ) 3 ⋅ 3 4 ⋅ 3 + . 2 (30) (30º ) = cos x + (30º ) = cos + ≈ 4.897 cm 16 + 0.5 cos(2 ⋅ 30º ) (60º ) + 16 0.5 cos = + − 1 4 1 ≈ 1.63 hr 3 3 4 3 Sally is on the paved road for − ≈ 1 1 0.86 hr . 4 tan 60o
1 4 ⋅1 2 a. t (30) = 2(10 ) ≈ 1.20 seconds 2 2 1 32 sin 30º ⋅ cos 30º = 1 + − ≈ 1.69 hr 3 4 b. t (45) = c. t (60) = 2(10 ) ≈ 1.12 seconds 32 sin 45º ⋅ cos 45º 2(10 ) ≈ 1.20 seconds 32 sin 60º ⋅ cos 60º Sally is on the paved road for 1 − 1 = 0.75 hr . 4 tan 45o c. T (60º ) = 1 + 2 − 1 3sin 60o 4 tan 60o 122. Use the formula = 1 + 2 − 1 x (θ ) = cosθ + 16 + 0.5 cos(2θ ) . 3 ⋅ 3 4 ⋅ 3 2 x (30) = cos (30º ) + = cos (30º ) + ≈ 4.897 cm 16 + 0.5 cos(2 ⋅ 30º ) 16 + 0.5 cos (60º ) = 1 + 4 − 1 ≈ 1.63 hr 3 3 4 3 Sally is on the paved road for 1 − 1 ≈ 0.86 hr . 4 tan 60o
62514-0132318806_ISM_02-1.docx