π 4. 3; cosθ a θ cot = = cos a π 2π θ 6 3 θ sin b 5. 3; = θ )2 + cos2 131. θ φ θ φ = + + sin cos2 sin sin 6. True 2 2 2 θ cos2 θ (sin 7. False θ φ φ = sin (cos2 + sin ) + cos2 cosφ 2 2 θ )2 + 8. True θ (sin θ θ = sin + cos2 2 = sin crosses the at the 9. The graph of y x y-axis φ sin = 1 132 135. Answers will vary. – point (0, 0), so the is 0. y-intercept at the 10. The graph of crosses the y- = cos y x point (0, 1), so the is 1. y-intercept
4. 3; π a cosθ cot θ = a = cos θ 2π π b sin θ 5. 3; = 6 3 131. (sin θ cosφ )2 + (sin θ sin φ )2 + cos2 θ = sin 2 θ cos2 φ + sin 2 θ sin 2 φ + cos2 θ = sin 2 θ (cos2 φ + sin 2 φ ) + cos2 θ = sin 2 θ + cos2 θ = 1 6. True 7. False 8. True 9. The graph of y = sin x crosses the y-axis at the 132 – 135. Answers will vary. point (0, 0), so the y-intercept is 0. 10. The graph of y = cos x crosses the at the point (0, 1), so the y-intercept is 1. y-
62514-0132318806_ISM_02-1.docx