−2 of the of are and 6. f The x-intercepts ( ) = 0 x − −1 2 . The of the graph of are x-intercepts f 23. 3 4x2 + 9 − 12 = 0 x − and 2 . 2 G 3 4x −12x + = 9 0 ( ) = P x 19. (2 − 3)(2 − 3) = 0 x x 0 − = − = 2 3 0 or 2 3 0 − = x x 3 48 x2 0 3 3 = = x x 3( − 16) = x2 2 2 0 + − 3( 4)( 4) x x ( ) The only zero of = 4 + 9 is 3 . = 0 G x x2 2 −12 x + 4 = 0 or t − 4 = t = − t The only of the graph of is 3 . 0 x-intercept G 4 2 = 4 t ( ) = − −4 The zeros of 3 48 are and 4. P x x2 The of the graph of are −4 and 4. x-intercepts P
The x-intercepts of the of f are −2 and 6. − 2 . The x-intercepts of the graph of f are −1 3 and − 2 . 23. G ( x ) = 0 4x2 + 9 − 12 x = 0 2 3 4x −12x + 9 = 0 19. P ( x ) = 0 3 x2 − 48 = 0 (2 x − 3)(2 x − 3) = 0 2 x − 3 = 0 or 2 x − 3 = 0 3 3 3( x2 − 16) = 0 x = x = 2 2 3( x + 4)( x − 4) = 0 The only zero of G ( x ) = 4 x2 + 9 −12 x is 3 . 2 t + 4 = 0 or t = − 4 t − 4 = 0 t = 4 The only x-intercept of the graph of G is 3 . 2 The zeros of P ( x ) = 3 x2 − 48 are −4 and 4. The x-intercepts of the graph of P are −4 and 4.
Downloadable-Solution-Manual-for-Precalculus-Concepts-Through-1.docx