The equation of the line is: − − − 7 = 5 ( (− 2)) y x − = − ) 3 y y1 m( x x1 − = − − 7 5 10 y x 1 − (− 2) 3 b. Answers will vary. We select (–2,–4) and (1, 4). The slope of the line containing 3 3 these points is: 5 11 =− y = 4 − (− 4) = 8 . m 3 3
The equation of the line is: y − y1 = m( x − x1 ) y − 7 = − 5 ( x − (− 2)) 3 y − 7 = − 5 x − 10 b. Answers will vary. We select (–2,–4) and (1, 4). The slope of the line containing these points is: m = 4 − (− 4) = 8 . 1 − (− 2) 3 3 3 5 11 y =− 3 3
Downloadable-Solution-Manual-for-Precalculus-Concepts-Through-1.docx