than 40. Thus, the solution to ( > 50 is f x) {x Thus, = 2 . x > 40} or (40, ∞) . x ( ) ( ) ≤ b. when the graph of is below f x g x f e. The of the graph of y-coordinates or intersects the of Thus, the g. = ( y f x) are 80 when the are x-coordinates smaller than 88. Thus, the solution to {x (−∞, ≤ solution is 2} or 2] . x {x ( ≤ 80 is ≤ 88} or (−∞, 88] . f x) x 41. a. ( ) ( ) = when their graphs intersect. f x g x f. The of the graph of y-coordinates = ( y f x) Thus, = −6 . x are between 0 and 80 when the x-coordinates −40 are between and 88. Thus, the solution to ( ) ( ) ( ) b. ≤ < g x f x x {x < < −40 < < 0 ( 80 is 88} or f x) x when the graph of is above or intersects the f graph of and below the graph of Thus, g h. (−40, 88) . the solution is {x [−6, −6 ≤ < 5} or 5) . x
than 40. Thus, the solution to {x x > 40} or (40, ∞) . f ( x) > 50 is Thus, x = 2 . b. f ( x ) ≤ g ( x ) when the graph of f is below e. The y-coordinates of the graph of y = f ( x) or intersects the of g. Thus, the are 80 when the x-coordinates are smaller than 88. Thus, the solution to f ( x) ≤ 80 is {x x ≤ 88} or (−∞, 88] . 41. a. solution is {x x ≤ 2} or (−∞, 2] . f ( x ) = g ( x ) when their graphs intersect. f. The y-coordinates of the graph of y = f ( x) Thus, x = −6 . are between 0 and 80 when the x-coordinates are between −40 and 88. Thus, the solution to 0 < f ( x) < 80 is {x −40 < x < 88} or (−40, 88) . b. g ( x ) ≤ f ( x ) < ( x ) when the graph of f is above or intersects the graph of g and below the graph of h. Thus, the solution is {x −6 ≤ x < 5} or [−6, 5) .
Downloadable-Solution-Manual-for-Precalculus-Concepts-Through-1.docx