98 2 2 =  2 6 2 6 x 0 2 3 2 2 3x  2 = 2 6 3 0 8 2 3 = 1 3 3 6 = Example 3 a. Show that the length of the circumference of a circle of radius a is 2 π Solution (o, a) x2 + y2 = a2 B P 0 A (a, o) Figure 4 The equation of the circle of radius a is x2 + y2 = a2. Differentiating with respect to x, 2x dy dy x 2 dx dx y y 99 t of arc APB = h
98 = 2 0 2 6  2 2 6 x = 3 2 2  3x 2 2 6 3 2 0 = = 1 6 8 3 3 3 2 Example 3 Show that the length of the circumference of a circle of radius a is 2 π a. Solution (o, a) 0 B x2 + y2 = a2 P A (a, o) Figure 4 The equation of the circle of radius a is x2 + y2 = a2. Differentiating with respect to x, dy dy 2x x dx dx 2 y y 99 of arc APB = t h
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