(mass of an electron = 9.10939 x10-31kg) + + = E = mc2 E = = λ → λ = λ = 2.42x10-12m 10 . The most stable nucleus in terms of binding energy per nucleon is 56Fe. If the atomic mass of 56Fe is 55.9349 amu, calculate the binding energy per nucleon for 56Fe. (Neutron = 1.00866 amu, proton =1.00728 amu, electron = 5.486 x 10-4 amu) Binding energy is the energy required to break apart a nucleus into its individual nucleons 56Fe 26 protons + 30 neutrons + 26 electrons → = 26(1.00728 amu) + 30(1.00866 amu) + 26(5.486 x 10-4 amu) 55.9349 amu = 0.5284436 amu Δm – = = (0.5284436 amu x )(2.9979x108m/s)2 = 7.887x10-9 J ΔE Δmc2 ΔE Binding energy per nucleon = = 1.408x10-12 J/nucleon Equations: E = mc2 E = hc/λ ln[A] = -kt + ln[A]o rate = k[A] t½ =
(mass of an electron = 9.10939 x10-31kg) + → + E = mc2 E = λ = λ = λ = = 2.42x10-12m 10 . The most stable nucleus in terms of binding energy per nucleon is 56Fe. If the atomic mass of 56Fe is 55.9349 amu, calculate the binding energy per nucleon for 56Fe. (Neutron = 1.00866 amu, proton =1.00728 amu, electron = 5.486 x 10-4 amu) Binding energy is the energy required to break apart a nucleus into its individual nucleons 56Fe → 26 protons + 30 neutrons + 26 electrons Δm = 26(1.00728 amu) + 30(1.00866 amu) + 26(5.486 x 10-4 amu) – 55.9349 amu = 0.5284436 amu ΔE = Δmc2 ΔE = (0.5284436 amu x )(2.9979x108m/s)2 = 7.887x10-9 J Binding energy per nucleon = = 1.408x10-12 J/nucleon Equations: E = mc2 E = hc/λ ln[A] = -kt + ln[A]o rate = k[A] t½ =
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