49. Sampling distribution of The area below= 2.1 must be 1 - .05 = .95. An area of .95 in the standard normal table shows = 1.645. z Thus, for  50. = .28 p a. This is the graph of a normal distribution with = = .28 and E() p b. Within ± .04 means .24 .32 ≤ ≤ .32) = 1.38) = .9162 - .0838 = .8324 P(.24 P(-1.38 z ≤ ≤ c. Within ± .02 means .26 .30 ≤ ≤ .30) = .69) = .7549 - .2451 = .5098 P(.26 P(-.69 z ≤ ≤ 51. ( .375) = ? P  < -1.02) = .1539 P(z ( .375) = 1 - .1539 = .8461 P  52. a. Within ± .04 means .36 .44 ≤ ≤ .44) = 1.59) = .9441 - .0559 = .8882 P(.36 P(-1.59 z ≤ ≤ b. We want P(.45)
49. Sampling distribution of The area below= 2.1 must be 1 - .05 = .95. An area of .95 in the standard normal table shows z = 1.645. Thus, for  50. p = .28 a. This is the graph of a normal distribution with E() = p = .28 and b. Within ± .04 means .24 ≤ ≤ .32 P(.24 .32) = P(-1.38 ≤ z ≤ 1.38) = .9162 - .0838 = .8324 c. Within ± .02 means .26 ≤ ≤ .30 P(.26 .30) = P(-.69 ≤ z ≤ .69) = .7549 - .2451 = .5098 51. P (  .375) = ? P(z < -1.02) = .1539 P (  .375) = 1 - .1539 = .8461 52. a. Within ± .04 means .36 ≤ ≤ .44 P(.36 .44) = P(-1.59 ≤ z ≤ 1.59) = .9441 - .0559 = .8882 b. We want P(.45)
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