Note that    dx x c 5dx  5   2 xdx  c Example 2  Find (2x 3)(x 2)dx  Solution we find the product and then we integrate  (2x 3)(x 2)dx   = (2x2 6)dx  x x2 = 2 3 x2 6x   c 2 Example 3 2x3 5x2 8x 9    x Solution we divide each term by x and then we integrate 2x3 5x2 8x 9 2x3 5x2 8x 9      x x x x x 10 9 x 2x3 5x2 = 8x 9 ln    x  c 3 2 Example 4 5x 6 x2   (x 2)  Solution 2  x First we simplify the integrand
Note that dx  x  c 5dx  5 xdx  2  c Example 2 Find (2x  3)(x 2)dx Solution we find the product and then we integrate (2x  3)(x 2)dx = (2x2  x 6)dx = 2 x2 3  x2 2 6x  c Example 3 2x3  5x2  8x  9 x Solution we divide each term by x and then we integrate 2x3  5x2  8x  9 2x3 x x  5x2 x  8x x 9 x 10 9 x = 2x3 3  5x2 2  8x  9 ln x  c Example 4 x2  5x  6 (x  2) Solution First we simplify the integrand x  2     
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