To balance it, 50g weight should be kept on right hand side so as to produce a clockwise moment .Let its distance from fulcrum be d cm. Then, 100g x (50-40) cm + 50g x d =50g x (40-10)cm 1000g cm + 50g x d =1500 g cm 50 g x d= 500g cm So, d =10 cm By suspending the mass 50g at the mark 50 cm, it can be balanced. Exercise 1 (C) No Numerical Exercise 1 (D) No Numerical
To balance it, 50g weight should be kept on right hand side so as to produce a clockwise moment .Let its distance from fulcrum be d cm. Then, 100g x (50-40) cm + 50g x d =50g x (40-10)cm 1000g cm + 50g x d =1500 g cm 50 g x d= 500g cm So, d =10 cm By suspending the mass 50g at the mark 50 cm, it can be balanced. Exercise 1 (C) No Numerical Exercise 1 (D) No Numerical
Ch-1-Force-numerical.docx