A Customer would like to convey 100,000 lbs per hour of sand to a height of 105 feet. Determine the required HP. Solution: Given: Rate (G) = 100,000 (Pounds per Hour) Discharge Height (DH) = 105 (FT) Assumed: Tail Pulley Diameter (d) = 2 (FT) Leq = 7 Friction Factor Method Another way to account for the system friction is to add a multiplication factor to the calculated HP in Equation 13.3. This multiplication factor typically ranges from 10% to 30%, depending on the application. Consult your Bucket Elevator Supplier for additional information. Equation 13.6 Bucket Elevator Power Formula Friction Factor Method – – Where: P = (HP) G = Gravimetric Rate (PPH) DH = Discharge Height (FT) F = Friction Multiplication Factor Example 13.2: A Customer would like to convey 100,000 lbs per hour of sand to a height of 105 feet. Determine the required HP. Solution: Given: Rate (G) = 100,000 (Pounds per Hour) Discharge Height (DH) = 105 (FT) Assumed: Friction (F) = 1.15
A Customer would like to convey 100,000 lbs per hour of sand to a height of 105 feet. Determine the required HP. Solution: Given: Rate (G) = 100,000 (Pounds per Hour) Discharge Height (DH) = 105 (FT) Assumed: Tail Pulley Diameter (d) = 2 (FT) Leq = 7 Friction Factor Method Another way to account for the system friction is to add a multiplication factor to the calculated HP in Equation 13.3. This multiplication factor typically ranges from 10% to 30%, depending on the application. Consult your Bucket Elevator Supplier for additional information. Equation 13.6 – Bucket Elevator Power Formula – Friction Factor Method Where: P = (HP) G = Gravimetric Rate (PPH) DH = Discharge Height (FT) F = Friction Multiplication Factor Example 13.2: A Customer would like to convey 100,000 lbs per hour of sand to a height of 105 feet. Determine the required HP. Solution: Given: Rate (G) = 100,000 (Pounds per Hour) Discharge Height (DH) = 105 (FT) Assumed: Friction (F) = 1.15
Chapter-13-D2-CEMA-Bucket-Elevator-HP-and-Calculations.docx