(2) Second, we took the partial derivative with respect to and solved for = 0 = = = for = 0 If 0 ≠ (3) Finally, we solved by substituting values for (i.e., -1 SD and +1 SD values for or z recipients’ attachment avoidance) and re-centered the values (partners’ practical support) x against the true mean value.
(2) Second, we took the partial derivative with respect to and solved for = 0 = = = for = 0 If ≠ 0 (3) Finally, we solved by substituting values for (i.e., -1 SD and +1 SD values for z or recipients’ attachment avoidance) and re-centered the x values (partners’ practical support) against the true mean value.
YUGIRMESupplementaryMaterials.docx