Section III: For problems 12, 13, and 14 use the two equations below. = = Given that is 5 m/s and is 2 meters, find v r a. Originally, = 12 m/s2, then is doubled. Find the new value for a r a. Use the second equation to find when = 4 Nm, 2 m, and = 10 N. r = F θ τ Section IV: For problems 15 22, use the equations below. – = 1 = = 2 1 = = = 2 Use the first equation to solve for if = 12 kg and = 2 m/s. K m v If = 10 J, = 10 kg, and = 9.8 m/s2, find using the second equation. m g h ∆Ug = = 9.8 m/s2, and = 10 m. Find K g h v. ∆Ug, The third equation can be used to find if you know that is 10 N, is 12 m, and is 180°. W F ∆x θ Given = 12 joules, and = 0.5 m, find using the fourth equation. Us x k For = 2100 W, = 30 N, and = 0°, find using the last equation in this section. P F vavg θ Section V: For problems 23 25, use the equations below. – = = = is 12 kgm/s and is 25 kg. Find using the first equation. p m v means state minus initial state”. So, means and means Find using the vf vi pf pi. vf “∆” “final ∆v – ∆p – third equation if = 50 kgm/s, = 12 kg, and and are both zero. pf m vi pi Use the second and third equation together to find if = 0 m/s, = 95 kg, = 6000 N, and vi vf m F = 0.2 s. ∆t Section VI: For problems 26 28 use the three equations below. – = = = is 1 second and is 9.8 m/s2. Find using the second equation. Tp g l 8 kg and = 0.75 s. Solve for m = Ts k. Given that = 9.8 m/s2, and that 2 m, find (the units for are Hertz). Tp T, g = l = f f
Section III: For problems 12, 13, and 14 use the two equations below. = = Given that v is 5 m/s and r is 2 meters, find a. Originally, a = 12 m/s2, then r is doubled. Find the new value for a. Use the second equation to find θ when τ = 4 Nm, r = 2 m, and F = 10 N. Section IV: For problems 15 – 22, use the equations below. 1 = 2 = = = 1 = 2 = Use the first equation to solve for K if m = 12 kg and v = 2 m/s. If ∆Ug = 10 J, m = 10 kg, and g = 9.8 m/s2, find h using the second equation. K = ∆Ug, g = 9.8 m/s2, and h = 10 m. Find v. The third equation can be used to find W if you know that F is 10 N, ∆x is 12 m, and θ is 180°. Given Us = 12 joules, and x = 0.5 m, find k using the fourth equation. For P = 2100 W, F = 30 N, and θ = 0°, find vavg using the last equation in this section. Section V: For problems 23 – 25, use the equations below. = = = p is 12 kgm/s and m is 25 kg. Find v using the first equation. “∆” means “final state minus initial state”. So, ∆v means vf – vi and ∆p means pf – pi. Find vf using the third equation if pf = 50 kgm/s, m = 12 kg, and vi and pi are both zero. Use the second and third equation together to find vi if vf = 0 m/s, m = 95 kg, F = 6000 N, and ∆t = 0.2 s. Section VI: For problems 26 – 28 use the three equations below. = = = Tp is 1 second and g is 9.8 m/s2. Find l using the second equation. m = 8 kg and Ts = 0.75 s. Solve for k. Given that Tp = T, g = 9.8 m/s2, and that l = 2 m, find f (the units for f are Hertz).
2018-2019%20%20AP%20Physics1%20(Algebra-Based)%20%20SUMMER%20ASSOGNMENT%202018-2019.docx