(b) 6 (–8) = 14 – (c) (–9) = + 9 = 7 –2 – –2 (d) +2 (–2) = 4 – (e) (–6) (–3) = -3 – (f) (–5) (–5) = 0 – (g) 0 (–3) = 3 – (h) 11 (–7) (–1) = 18+1 = 19 – – 2 (a) 5 + 6 = 11 (b) (–2) (+7) = -9 – (c) 2 (+3) = -5 – – (d) 5 6 + 3 = -8 – – (e) 0 (–5) = 5 – (f) +4 + (–9) = -5 (g) 8 5 + 6 2 = 7 – – (h) 12 (–10) = 22 – At Thredbo the temperature was and then rose by 10°C. What is the –7°C 3 (a) new temperature? = 3 degrees celcius (b) What is the difference in temperature between 38°C and = 47 degrees –9°C? 4 many years were there between: (a) 1215 AD and 1994 AD? = 779 (b) 55 BC and 1215 AD? = 1270 5 If your bank balance was and you deposited a cheque for $97, what would your –$42 new balance be? = $55 Activity 16 Work out these products: (a) (–2)  (+8) = -16 (b) (–3)  (–3) = 9 (c) 3  4 = 12 (d) 6  (–5) = -30
(b) 6 – (–8) = 14 (c) –2 – (–9) = –2 + 9 = 7 (d) +2 – (–2) = 4 (e) (–6) – (–3) = -3 (f) (g) (h) (–5) – (–5) = 0 0 – (–3) = 3 11 – (–7) – (–1) = 18+1 = 19 2 (a) (b) (c) (d) (e) (f) (g) (h) 5 + 6 = 11 (–2) – (+7) = -9 – 2 – (+3) = -5 – 5 – 6 + 3 = -8 0 – (–5) = 5 +4 + (–9) = -5 8 – 5 + 6 – 2 = 7 12 – (–10) = 22 3 (a) At Thredbo the temperature was –7°C and then rose by 10°C. What is the new temperature? = 3 degrees celcius (b) What is the difference in temperature between 38°C and –9°C? = 47 degrees 4 many years were there between: (a) 1215 AD and 1994 AD? = 779 (b) 55 BC and 1215 AD? = 1270 5 If your bank balance was –$42 and you deposited a cheque for $97, what would your new balance be? = $55 Activity 16 Work out these products: (a) (–2) (b) (–3)  (+8) = -16  (–3) = 9 (c) 3 (d) 6  4 = 12  (–5) = -30
Workbook%20Solutions_FNSACC303A_v1.docx