(ii) All poles and zeros are not inside |z| = 1, the system is not phase. Unsolved ex:7.35(a) Find the transfer function of an inverse system and determine whether it can be both causal and stable = H(z) 1 8z−1 + 16z−2 − 12 14 1 + z−1 z−2 − (z − = H(z) 4)2
(ii) All poles and zeros are not inside |z| = 1, the system is not phase. Unsolved ex:7.35(a) Find the transfer function of an inverse system and determine whether it can be both causal and stable H(z) = 1 − 8z−1 + 16z−2 1 − 12 z−1 + 14 z−2 H(z) = (z − 4)2
U8-L47_Solved-Examples-on-Causality-stability-and-Inverse-systems.docx