Input = VI; Ia2ra = (I- Ish)2ra Constant losses Wc = VIo (Io Ish)2ra 7 – – …………… Total losses = (I- Ish)2ra + Wc Therefore "'( )* *"*,-./012 – efficiency of motor = ; = 8 ……. %& EFFICIENCY OF A GENERATOR: Output = VI Ia2ra = (I+Ish)2ra Total losses = Wc+(I+Ish)2ra 9 …………………………………….. %& Efficiency of generator = 10 #560 ……… 0'(= %&0&0&34 7
Input = VI; Ia2ra = (I- Ish)2ra Constant losses Wc = VIo – (Io – Ish)2ra …………… 7 Total losses = (I- Ish)2ra + Wc "'( )* – *"*,-./012 Therefore efficiency of motor = ; = ……. 8 %& EFFICIENCY OF A GENERATOR: Output = VI Ia2ra = (I+Ish)2ra Total losses = Wc+(I+Ish)2ra …………………………………….. 9 %& Efficiency of generator = 0'(= %&0&0&34 #560 7 ……… 10
U4-L20_Swinburne%e2%80%99s-Test.docx