MD4.5 TU x U (See Year 3) and HTU x U (Introduced in MD4.3 Sharing and grouping 30 Year 4 grade-level standards). ÷ 6 can be modelled as: Grouping groups of 6 away and the number of groups – counted e.g. Partition 23 x 4 = 92 6 + 6 + 6 + 6 + 6 + 0 6 12 18 24 30 23 x 4 = (20 x 4) + (3 x 4) = (80) + (12) Sharing sharing among 6, the number given to each = 92 – person. Use the grid method of multiplication Remainders 23 x 7 is approximately 20 x 10 = 200 Note three approaches below: 41 ÷ 4 = 10 r1 +40 +1 41 = (10 x 4) + 1 -1 - 40 MD4.5 TU ÷ U 72 ÷ 5 lies between 50 ÷ 5 = 10 and 100 ÷ 5 = 20 72 50 (10 groups) or (10 x 5) 22 20 (4 groups) or (4 x 5) 2 Answer: 14 remainder 2 MD4.5 HTU ÷ U Can progress from no remainder to remainders. Where remainders are involved, care needs to be taken to ensure they are interpreted correctly in context of problems. 256 ÷ 7 lies between 210 ÷ 7 = 30 and 280 ÷ 7 = 40 256 70 (10 groups) or (10 x 7) 186 140 (20 groups) or (20 x 7) 46 42 (6 groups) or (6 x 7) 4 (36 groups) or (36) Answer: 36 remainder 4 New Mathematics Calculation Policy: Year 5 and Year 6 The exemplification of formal methods here should be taken into account by all Key Stage 2 teachers so children are adequately prepared by Year 5 and into Year 6 to use the means of calculating specified in grade-level standards. Addition & Subtraction
MD4.5 TU x U (See Year 3) and HTU x U (Introduced in Year 4 grade-level standards). Partition 23 x 4 = 92 23 x 4 = (20 x 4) + (3 x 4) = (80) + (12) = 92 Use the grid method of multiplication 23 x 7 is approximately 20 x 10 = 200 MD4.3 Sharing and grouping 30 ÷ 6 can be modelled as: Grouping – groups of 6 away and the number of groups counted e.g. 6 + 6 + 6 + 6 + 6 + 0 6 12 18 24 30 Sharing – sharing among 6, the number given to each person. Remainders Note three approaches below: 41 ÷ 4 = 10 r1 +40 +1 41 = (10 x 4) + 1 -1 - 40 MD4.5 TU ÷ U 72 ÷ 5 lies between 50 ÷ 5 = 10 and 100 ÷ 5 = 20 72 50 (10 groups) or (10 x 5) 22 20 (4 groups) or (4 x 5) 2 Answer: 14 remainder 2 MD4.5 HTU ÷ U Can progress from no remainder to remainders. Where remainders are involved, care needs to be taken to ensure they are interpreted correctly in context of problems. 256 ÷ 7 lies between 210 ÷ 7 = 30 and 280 ÷ 7 = 40 256 70 (10 groups) or (10 x 7) 186 140 (20 groups) or (20 x 7) 46 42 (6 groups) or (6 x 7) 4 (36 groups) or (36) Answer: 36 remainder 4 New Mathematics Calculation Policy: Year 5 and Year 6 The exemplification of formal methods here should be taken into account by all Key Stage 2 teachers so children are adequately prepared by Year 5 and into Year 6 to use the means of calculating specified in grade-level standards. Addition & Subtraction
Stanley-Grove-New-Curriculum-Calculation-Policy.docx