Theoretical Competition Solution – – December 6, 2015 I. Chemical Oxygen Demand (COD) Test I-1 I-1-1 [0.5 points] (Answer) + a b/4 c/2 (Explanation) Balance the masses of O for both sides. + 2x = 2a + 0.5b [0.3 points] c = + 0.25b 0.5c [0.2 points] x a I-1-2. [0.5 points] (Answer) 8y (Explanation) Balance the charges for both (2)y (+1)z = 2y(+3) [0.3 points] + = 8y [0.2 points] z I-1-3. [0.5 points] (Answer) 2a/3 + b/6 c/3 (Explanation) Balance the masses of O. + 7y = 2a + 0.5b + 0.5z [0.2 points] c Substitute 8y for z 3y = 2a + 0.5b [0.2 points] c = 2a/3 + [0.1 points] y b/6 c/3 I-1-4. [0.5 points] (Answer) 3y/2 (Explanation) From the former questions, = + [0.1 points] x a b/4 c/2
Theoretical Competition – Solution – December 6, 2015 I. Chemical Oxygen Demand (COD) Test I-1 I-1-1 [0.5 points] (Answer) a + b/4 c/2 (Explanation) Balance the masses of O for both sides. c + 2x = 2a + 0.5b [0.3 points] x = a + 0.25b 0.5c [0.2 points] I-1-2. [0.5 points] (Answer) 8y (Explanation) Balance the charges for both (2)y + (+1)z = 2y(+3) [0.3 points] z = 8y [0.2 points] I-1-3. [0.5 points] (Answer) 2a/3 + b/6 c/3 (Explanation) Balance the masses of O. c + 7y = 2a + 0.5b + 0.5z [0.2 points] Substitute 8y for z 3y = 2a + 0.5b c [0.2 points] y = 2a/3 + b/6 c/3 [0.1 points] I-1-4. [0.5 points] (Answer) 3y/2 (Explanation) From the former questions, x = a + b/4 c/2 [0.1 points]
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