girls On three different sheets of paper find mean height on the sheet of paper , median height on the second and the modal height on the third sheet of paper. Let us find mean by step deviation method:- Class of Frequency Class mark U1= Fi x ui heights (in p xi a= 147.5,h=5 cm) 135-140 4 137.5 -2 -8 140-145 7 142.5 -1 -7 145-150 18 147.5 0 0 150-155 11 152.5 1 11 155-160 6 157.5 2 12 160-165 5 162.5 3 13 Mean=a+h x =147.5+5 x 23/51 =147.5+115/51 =(147.5+2.255)cm=149.755cm Let us find median of the data:- Class of height (in Frequency number of girls Cumulative cm) frequency 135-140 4 4 140-145 7 11=cf 145-150 18=f 29 150-155 11 40 155-160 6 46 160-165 5 51 Total n median=l+ x h=145 + x5 =145+14.5 x5 18 =145+4.028 =149.028cm Let us find mode of the data:- Class of heights (in cm) FREQUENCY (No of Girls) 135-140 4 140-145 7=f1 (Modal class) 145-150 18=fm Modal class is 145-150 150-155 11=f2 Thus l=145, h=5, fm=18, f1=7, f2=11 155-160 6 160-165 5 Mode=H xh=145 + x 5 Total 51
girls On three different sheets of paper find mean height on the sheet of paper , median height on the second and the modal height on the third sheet of paper. Let us find mean by step deviation method:- Class of heights (in cm) Frequency p Class mark xi U1= a= 147.5,h=5 Fi x ui 135-140 140-145 145-150 150-155 155-160 160-165 4 7 18 11 6 5 137.5 142.5 147.5 152.5 157.5 162.5 -2 -1 0 1 2 3 -8 -7 0 11 12 13 Mean=a+h x =147.5+5 x 23/51 =147.5+115/51 =(147.5+2.255)cm=149.755cm Let us find median of the data:- Class of height (in cm) Frequency number of girls Cumulative frequency 135-140 140-145 145-150 150-155 155-160 160-165 4 7 18=f 11 6 5 4 11=cf 29 40 46 51 Total n median=l+ x h=145 + x5 =145+14.5 x5 18 =145+4.028 =149.028cm Let us find mode of the data:- Class of heights (in cm) FREQUENCY (No of Girls) 135-140 140-145 145-150 150-155 155-160 160-165 4 7=f1 18=fm 11=f2 6 5 Total 51 (Modal class) Modal class is 145-150 Thus l=145, h=5, fm=18, f1=7, f2=11 Mode=H xh=145 + x 5
Study%20Material%20%20Class%20X(Mathematics)%20SA%201.docx