Ans: 0.22t + 1.12 > 1.56 2 t> 0.12t + 4.63 > 5.23 5 t> 2 and 5, so 5 t> t> t> 1994 + 5 = 1999 Section: 2.5 126. |x Solve: 10| = 2 – A) {12} B) {8, 12} C) {–12, 12} D) {8} Ans: B Section: 2.6 127. |3(x Solve: + 2) 4| = 1 – Ans: Section: 2.6 |–7 128. Solve: 12 = x| – – –13 A) {–31, 19} B) {–34, 20} C) {–32, 18} D) {–31, 21} Ans: C Section: 2.6 129. Solve: A) B) C) D) Ans: D Section: 2.6 |2 130. Solve: = 13. Show your work. x| –8 – – Ans: |2 = x| – –21 2 = 21 x – {23, –19} Section: 2.6 131. Graph the solution to the absolute value inequality and match your result with the correct answer below. A) B) C) D)
Ans: 0.22t + 1.12 > 1.56 t> 2 0.12t + 4.63 > 5.23 t> 5 t> 2 and t> 5, so t> 5 1994 + 5 = 1999 Section: 2.5 126. Solve: |x – 10| = 2 A) {12} B) {8, 12} C) {–12, 12} D) {8} Ans: B Section: 2.6 127. Solve: |3(x + 2) – 4| = 1 Ans: Section: 2.6 128. Solve: 12 – |–7 – x| = –13 A) {–31, 19} B) {–34, 20} C) {–32, 18} D) {–31, 21} Ans: C Section: 2.6 129. Solve: A) B) C) D) Ans: D Section: 2.6 130. Solve: –8 – |2 – x| = 13. Show your work. Ans: |2 – x| = –21 2 – x = 21 {23, –19} Section: 2.6 131. Graph the solution to the absolute value inequality and match your result with the correct answer below. A) B) C) D)
Test-Bank-Algebra-for-College-Students-5th-Edition-Mark-Dugopolski.docx