e. 1 + 1.78 + .11 + .44 + 1.78 + .11 = 5.22 f. z=== .875 ; therefore, the probability from the standard normal table is approximately .81. a. Note that the variability of some non-critical path activities is large. Consideration might be te== given to those paths. 9 Expected Activity a m b Time Variance b. A 4 7 10 7 1 B 2 8 20 9 9 = C 8 12 16 12 1.78 9.00 D 1 2 3 2 0.11 c. E 6 8 22 10 7.11 F 2 3 4 3 0.11 G 2 2 2 2 0 H 6 8 10 8 0.44 d. 40 I 4 8 12 8 1.78 J 1 2 3 2 0.11 153)
a. te== 9 b. = 9.00 c. d. 40 e. 1 + 1.78 + .11 + .44 + 1.78 + .11 = 5.22 f. z=== .875 ; therefore, the probability from the standard normal table is approximately .81. Note that the variability of some non-critical path activities is large. Consideration might be given to those paths. Activity a m b Expected Time Variance A 4 7 10 7 1 B 2 8 20 9 9 C 8 12 16 12 1.78 D 1 2 3 2 0.11 E 6 8 22 10 7.11 F 2 3 4 3 0.11 G 2 2 2 2 0 H 6 8 10 8 0.44 I 4 8 12 8 1.78 J 1 2 3 2 0.11 153)
Test-Bank-Operations-Management-9th-Edition-Krajewski.docx