Interval midpoint frequency (m) f(x) mf(x) $millions m (m (m )2 )2f(x) − – – 700 6 4200 67600 405600 600-800 −260 900 7 6300 3600 25200 800-1,000 −60 1100 5 5500 140 19600 1,000-1,200 1300 0 0 340 115600 0 1,200-1,400 1500 1 1500 540 291600 291600 1,400-1,600 1700 1 1700 740 547600 547600 1,600-1,800 19200 1368000 =  2= 19200/ 20 1368000/20 =960 =261.5 Estimated Mean = $960 million Estimated Variance = 68400 Estimated Standard Deviation = = $261.5 million 49. Interval Frequency (% change) (No. of States) to 4 −6 −3 to 0 0 −3+ 0+ to 3 12 3+ to 6 14 6+ to 9 15 9+ to 12 5 12+ to 15 1 50. a) = 100 strokes.100 here represents the central tendency of your golf scores 
Interval $millions midpoint (m) frequency f(x) mf(x) m − (m – )2 (m – )2f(x) 600-800 700 6 4200 −260 67600 405600 800-1,000 900 7 6300 −60 3600 25200 1,000-1,200 1100 5 5500 140 19600 1,200-1,400 1300 0 0 340 115600 0 1,400-1,600 1500 1 1500 540 291600 291600 1,600-1,800 1700 1 1700 740 547600 547600 19200 1368000  = 19200/ 20 =960 2= 1368000/20 =261.5 Estimated Mean = $960 million Estimated Variance = 68400 Estimated Standard Deviation = = $261.5 million Interval (% change) Frequency (No. of States) −6 to −3 4 −3+ to 0 0 0+ to 3 12 3+ to 6 14 6+ to 9 15 9+ to 12 5 12+ to 15 1 49. 50. a)  = 100 strokes.100 here represents the central tendency of your golf scores
Solution-Manual-Understanding-Business-Statistics-1st-Edition-Freed.docx