= = f(x) xn f ‘(x) =esx = f(x) f ‘(x) = ln(x) = f(x) f ‘(x) Today we’ll do the formula for the derivative of a product: You already know the derivative of What is it? x2. Show that you get the same derivative for as you did in #1 by writing as a product, = and using the x2 x2 x2 x∙x., product rule. Find the derivatives of the following: x2ex + q∙ln(q) q4 ln(t) e2t (q2 +3q + 12) eq Evaluate the following: if 4000 if = 3217 + 254 MC(10) C(q) qln(q).
f(x) = xn f ‘(x) = f(x) =esx f ‘(x) = f(x) = ln(x) f ‘(x) = Today we’ll do the formula for the derivative of a product: You already know the derivative of x2. What is it? Show that you get the same derivative for x2 as you did in #1 by writing x2 as a product, x2 = x∙x., and using the product rule. Find the derivatives of the following: x2ex q∙ln(q) + q4 e2t ln(t) (q2 +3q + 12) eq Evaluate the following: if 4000 MC(10) if C(q) = 3217 + 254 qln(q).
2-25-Selected%20%20answers%20for%20the%20Differentiation%20handouts.docx