14.1 by interpolation: span/depth Maximum span = 6.76 x 437.5 = 2960 mm say 3.0 m Chapter 15 Indeterminate structures and computers – E15.1 a. Each crossed member (2) adds a redundancy plus additional internal roller supports (2) answer 4. – – b. Simple cantilever is statically determinate so internal roller supports add two redundancies - answer 2 – c. A Three-pin portal is statically determinate so making two pins into rigid joints adds two redundancies - answer 2 – E15.2 M about A: -267 + (300 x 2) + 133 6RB = 0 – RB = 78 kN ` V = 0 RA = 300 78 – = 222 kN MC = 267 x 2) –(222 = 177 kNm Design moment, MEd = 267 kNm (i.e. biggest moment on beam) Wpl = 267 x 106/275 x 103 (M = 1.0) = 971 cm3 Use 406 x 178 x 54 kg/m universal beam (Wpl = 1050 cm3) E15.3
14.1 by interpolation: span/depth Maximum span = 6.76 x 437.5 = 2960 mm say 3.0 m Chapter 15 – Indeterminate structures and computers E15.1 a. Each crossed member (2) adds a redundancy plus additional internal roller supports (2) – answer – 4. b. Simple cantilever is statically determinate so internal roller supports add two redundancies - answer – 2 c. A Three-pin portal is statically determinate so making two pins into rigid joints adds two redundancies - answer – 2 E15.2 M about A: -267 + (300 x 2) + 133 – 6RB = 0 RB = 78 kN ` V = 0 RA = 300 – 78 = 222 kN MC = 267 –(222 x 2) = 177 kNm Design moment, MEd = 267 kNm (i.e. biggest moment on beam) Wpl = 267 x 106/275 x 103 (M = 1.0) = 971 cm3 Use 406 x 178 x 54 kg/m universal beam (Wpl = 1050 cm3) E15.3
Solutions-to-the-end-of-chapter-exercises.docx