= 3 · 2k 1 3 2 · 2k 2 + 2 – – – – = 3 · 2k 1 2k 1 1 – – – – = (3 1) · 2k 1 1 – – – = 2 · 2k 1 1 = 2k 1 = dk = L.H.S. – – – Question 12: Define a sequence by the formula , for all integers. Show that this sequence satisfies the recurrence relation , for all integers. Similarly solve the questions as 11.
= 3 · 2k – 1 – 3 – 2 · 2k – 2 + 2 = 3 · 2k – 1 – 2k – 1 – 1 = (3 – 1) · 2k – 1 – 1 = 2 · 2k – 1 – 1 = 2k – 1 = dk = L.H.S. Question 12: Define a sequence by the formula , for all integers. Show that this sequence satisfies the recurrence relation , for all integers. Similarly solve the questions as 11.
Solution%20of%20Practice%20questions%20Sequence%20and%20Series%20%20(19%20-22).docx