= 0.04 c. = P(GG) P(G) P(G) <ART FILE="02_16eq03.eps" W="38.194pt" H="19.401pt" XS="100%" YS="100%"/> = (0.5)(0.5) = 0.25 (the events are independent and d. =  P(R W) P(R) hence the conditional <ART probability equals the marginal FILE="02_16eq04.eps" probability) W="23.739pt" H="20.223pt" XS="100%" YS="100%"/> = 0.40 2-17. The distribution of the nails is as follows: Type of Nail Number in Bin 1 inch 651 2 inch 243 3 inch 41 4 inch 451 5 inch 333 Total 1,719 a. The probability of getting a 4-inch nail is <ART FILE="02_17eq01.eps" W="48.329pt" H="21.072pt" XS="100%" YS="100%"/> = 0.26 b. The probability of getting a 5-inch nail is <ART FILE="02_17eq02.eps" W="48.329pt" H="21.93pt" XS="100%" YS="100%"/> = 0.19 c. The probability of getting a nail 3 inches or shorter is the probability of getting a nail 1 inch, 2 inches, or 3 inches in length. The probability is thus or 2 or 3) P(1
= 0.04 c. P(GG) = P(G) P(G) <ART FILE="02_16eq03.eps" W="38.194pt" H="19.401pt" XS="100%" YS="100%"/> = (0.5)(0.5) = 0.25 d. P(R  W) = P(R) (the events are independent and hence the conditional probability equals the marginal probability) <ART FILE="02_16eq04.eps" W="23.739pt" H="20.223pt" XS="100%" YS="100%"/> = 0.40 2-17. The distribution of the nails is as follows: Type of Nail Number in Bin 1 inch 651 2 inch 243 3 inch 41 4 inch 451 5 inch 333 Total 1,719 a. The probability of getting a 4-inch nail is <ART FILE="02_17eq01.eps" W="48.329pt" H="21.072pt" XS="100%" YS="100%"/> = 0.26 b. The probability of getting a 5-inch nail is <ART FILE="02_17eq02.eps" W="48.329pt" H="21.93pt" XS="100%" YS="100%"/> = 0.19 c. The probability of getting a nail 3 inches or shorter is the probability of getting a nail 1 inch, 2 inches, or 3 inches in length. The probability is thus P(1 or 2 or 3)
solution-manual-quantitative-analysis-for-management-12th-edition-render.docx