A volume of 25.0 mL of 0.120M sulfuric acid neutralizes 40.0mL of a sodium hydroxide solution. What is the concentration of the sodium hydroxide solution? Review: Solve for in the following problems: ∆H Calculate for the reaction 2 Al (s) + 3 Cl2 (g) 2 AlCl3 (s) from the data. ∆H → 2 Al (s) + 6 HCl (aq) AlCl3 (aq) + 3 H2 (g) = -1049. kJ →2 ∆H HCl (aq) (g) = +74.8 kJ →HCl ∆H H2 (g) + Cl2 (g) 2 HCl (g) = -1845. kJ → ∆H AlCl3 (s) AlCl3 (aq) = -323. kJ → ∆H Determine using heats of formation. Hint: Make sure to balance the equation. ∆H NH3 (g) + O2 NO2 + H2O(g) → Determine for the combustion of ethane (C2H6) bond energies: C2H6 + 5O2 3CO2 + 4H2O ∆H → New Method: Solving for using Calorimetry ∆H When a 15.3 g sample of KOH dissolves in 70.0 g of in a calorimeter, the temperature rises from 22.4˚C to 66.4˚C. Calculate the for the process and write it on the correct side of the equation. ∆H
A volume of 25.0 mL of 0.120M sulfuric acid neutralizes 40.0mL of a sodium hydroxide solution. What is the concentration of the sodium hydroxide solution? Review: Solve for ∆H in the following problems: Calculate for ∆H the reaction 2 Al (s) + 3 Cl2 (g) → 2 AlCl3 (s) from the data. 2 Al (s) + 6 HCl (aq) →2 AlCl3 (aq) + 3 H2 (g) ∆H = -1049. kJ HCl (aq) →HCl (g) ∆H = +74.8 kJ H2 (g) + Cl2 (g) → 2 HCl (g) ∆H = -1845. kJ AlCl3 (s) → AlCl3 (aq) ∆H = -323. kJ Determine ∆H using heats of formation. Hint: Make sure to balance the equation. NH3 (g) + O2 → NO2 + H2O(g) Determine ∆H for the combustion of ethane (C2H6) bond energies: C2H6 + 5O2 → 3CO2 + 4H2O New Method: Solving for ∆H using Calorimetry When a 15.3 g sample of KOH dissolves in 70.0 g of in a calorimeter, the temperature rises from 22.4˚C to 66.4˚C. Calculate the ∆H for the process and write it on the correct side of the equation.
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