Boron is an acceptor: NA = 1016/cm3 and p = 318 cm2/V-s from equations with Fig. 2.8. Now we add donors until  = 4.5 (-cm) -1: Using trial and error: ND ND+ NA ND- NA n nn 8 x 1016 9 x 1016 752 7 x 1016 5.26 x 1019 5 x 1016 6 x 1016 845 4 x 1016 3.38 x 1019 4 x 1016 5 x 1016 885 3 x 1016 2.66 x 1019 4.2 x 1016 5.2 x 1016 877 3.2 x 1016 2.81 x 1019 2.42 Phosphorus is a ND = 1016/cm3 and = 1180 cm2/V-s from Fig. 2.8. n Now we add acceptors until = 5.0 (-cm)  -1: trial and error: NA ND+ NA NA- ND p pp 1.00E+17 1.10E+17 147 9.00E+16 1.33E+19 2.00E+17 2.10E+17 116 1.90E+17 2.20E+19 3.50E+17 3.60E+17 95.6 3.40E+17 3.25E+19 3.30E+17 3.40E+17 97.4 3.20E+17 3.12E+19 2.43 T (K) 50 75 100 150 200 250 300 350 400 VT 4.31 6.46 8.61 12.9 17.2 21.5 25.8 30.1 34.5 (mV) 2.44 2.45 2.46 2.47
Boron is an acceptor: NA = 1016/cm3 and p = 318 cm2/V-s from equations with Fig. 2.8. Now we add donors until  = 4.5 (-cm) -1: Using trial and error: ND ND+ NA n ND- NA nn 8 x 1016 9 x 1016 752 7 x 1016 5.26 x 1019 5 x 1016 6 x 1016 845 4 x 1016 3.38 x 1019 4 x 1016 5 x 1016 885 3 x 1016 2.66 x 1019 4.2 x 1016 5.2 x 1016 877 3.2 x 1016 2.81 x 1019 2.42 Phosphorus is a ND = 1016/cm3 and n = 1180 cm2/V-s from Fig. 2.8. Now we add acceptors until  = 5.0 (-cm) -1: trial and error: NA ND+ NA p NA- ND pp 1.00E+17 1.10E+17 147 9.00E+16 1.33E+19 2.00E+17 2.10E+17 116 1.90E+17 2.20E+19 3.50E+17 3.60E+17 95.6 3.40E+17 3.25E+19 3.30E+17 3.40E+17 97.4 3.20E+17 3.12E+19 2.43 T (K) 50 75 100 150 200 250 300 350 400 VT (mV) 4.31 6.46 8.61 12.9 17.2 21.5 25.8 30.1 34.5 2.44 2.45 2.46 2.47
Solution-Manual-Microelectronic-Circuit-Design-5th-Edition-Jaeger.docx