Substituting Equation 2.8 into each side of the relation = + 10.0 m, SOLUTION x2nd xleader we have that Rearranging the terms of this equation so it is in quadratic form, we have This equation can be solved the quadratic formula, with the result that . __________________________________________________________________________ 83. The time to make the entire trip is equal to the time that the golfer REASONING ttrip tcart rides in the golf cart plus the time that she walks; = + Therefore, the twalk ttrip tcart twalk. time that she walks is = (1) twalk ttrip tcart The average for the entire trip is equal to the total distance, + she travels xcart xwalk, divided by the time to make the entire trip (see Equation 2.1); Solving this equation for and substituting the resulting expression into Equation 1 ttrip yields (2) The distance traveled by the cart is , and the distance walked by the golfer is . Substituting these expressions for and into Equation 2 gives xcart xwalk The unknown variable appears on both sides of this equation. Algebraically solving twalk for this variable gives The time that the golfer spends walking is SOLUTION ______________________________________________________________________________ 84. The definition of average velocity is given by Equation 2.2 as the REASONING displacement divided by the elapsed time. When the velocity is constant, as it is for car A, the average velocity is the same as the constant velocity. We note that, since both displacement and time are the same for each car, this equation gives the same value for car B’s average velocity and car A’s constant velocity.
SOLUTION Substituting Equation 2.8 into each side of the relation x2nd = xleader + 10.0 m, we have that Rearranging the terms of this equation so it is in quadratic form, we have This equation can be solved the quadratic formula, with the result that . __________________________________________________________________________ 83. REASONING The time ttrip to make the entire trip is equal to the time tcart that the golfer rides in the golf cart plus the time twalk that she walks; ttrip = tcart + twalk. Therefore, the time that she walks is twalk = ttrip tcart (1) The average for the entire trip is equal to the total distance, xcart + xwalk, she travels divided by the time to make the entire trip (see Equation 2.1); Solving this equation for ttrip and substituting the resulting expression into Equation 1 yields (2) The distance traveled by the cart is , and the distance walked by the golfer is . Substituting these expressions for xcart and xwalk into Equation 2 gives The unknown variable twalk appears on both sides of this equation. Algebraically solving for this variable gives SOLUTION The time that the golfer spends walking is ______________________________________________________________________________ 84. REASONING The definition of average velocity is given by Equation 2.2 as the displacement divided by the elapsed time. When the velocity is constant, as it is for car A, the average velocity is the same as the constant velocity. We note that, since both displacement and time are the same for each car, this equation gives the same value for car B’s average velocity and car A’s constant velocity.
Solution%20Manual%20for%20Physics%209th%20Edition%20Cutnell.docx