25 30 750.00 0.49 14.70 −0.7 35 20 700.00 9.3 86.49 1729.80 45 15 675.00 19.3 372.49 5587.35 55 10 550.00 29.3 858.49 8584.90 65 5 325.00 39.3 1544.49 7722.45 totals 150 3850.00 37933.50 = =  2 3850/150 37933.5/150 = 25.7 = 252.89 75. a) * Note: The of each bar in a histogram should be proportional to the fraction of area the observations that fall in the bar’s class. Above we’reshowing a graph in which used to represent relative frequency, even though we have classes of heightsare unequal width. Although technically incorrect, this is fairly common practice. The graph below shows the more technically correct picture, with areas representing frequency. To give the proper proportional area, the first bar height has been raised in response to the bar’s relatively narrowwidth; the height of the last bar has been lowered because of itsrelatively greater width. These adjustments give a picture in which areas and not heights are proportional to the frequency of class membership.. Proper bar heights can be set by dividing class frequencies by class widths. (The vertical scale on the histogram would be a somewhat cumbersome per unit “frequency width.”)
25 30 750.00 −0.7 0.49 14.70 35 20 700.00 9.3 86.49 1729.80 45 15 675.00 19.3 372.49 5587.35 55 10 550.00 29.3 858.49 8584.90 65 5 325.00 39.3 1544.49 7722.45 totals 150 3850.00 37933.50  = 3850/150 2 = 37933.5/150 = 25.7 = 252.89 75. a) * Note: The area of each bar in a histogram should be proportional to the fraction of the observations that fall in the bar’s class. Above we’reshowing a graph in which heightsare used to represent relative frequency, even though we have classes of unequal width. Although technically incorrect, this is fairly common practice. The graph below shows the more technically correct picture, with areas representing frequency. To give the proper proportional area, the first bar height has been raised in response to the bar’s relatively narrowwidth; the height of the last bar has been lowered because of itsrelatively greater width. These adjustments give a picture in which areas and not heights are proportional to the frequency of class membership.. Proper bar heights can be set by dividing class frequencies by class widths. (The vertical scale on the histogram would be a somewhat cumbersome “frequency per unit width.”)
Solution-Manual-Understanding-Business-Statistics-1st-Edition-Freed.docx