b) = $13.20  c) median = 5.5th value ((10+1)/2 = 5.5) in the ordered list, halfway between the 5th and the 6th value = $12. d) = 10.96; = $3.31 2  ≈ f(x) x no. of xf(x) x− (x−)2 (x−)2 f(x) (price) IPOs 9 1 9 17.64 17.64 −4.2 10 2 20 10.24 20.48 −3.2 11 1 11 4.84 4.84 −2.2 12 2 24 1.44 2.88 −1.2 16 2 32 2.8 7.84 15.68 17 1 17 3.8 14.44 14.44 19 1 19 5.8 33.64 33.64 totals 10 132 109.6 = 132/10 = 109.6/10  2 = 10.96 = 13.2 27. a) Index proportion of value months x p(x) 86 2/20 = 0.10 87 3/20 = 0.15 88 4/20 = 0.2 89 4/20 = 0.2 90 4/20 = 0.2 91 3/20 = 0.15 b) 28. a) proportion of complaints days x p(x) 0 0.333 1 0.238 2 0.238 3 0.143
b)  = $13.20 c) median = 5.5th value ((10+1)/2 = 5.5) in the ordered list, halfway between the 5th and the 6th value = $12. d) 2 = 10.96;  = ≈ $3.31 x (price) f(x) no. of IPOs xf(x) x− (x−)2 (x−)2 f(x) 9 1 9 −4.2 17.64 17.64 10 2 20 −3.2 10.24 20.48 11 1 11 −2.2 4.84 4.84 12 2 24 −1.2 1.44 2.88 16 2 32 2.8 7.84 15.68 17 1 17 3.8 14.44 14.44 19 1 19 5.8 33.64 33.64 totals 10 132 109.6  = 132/10 2 = 109.6/10 = 10.96 = 13.2 27. a) Index value x proportion of months p(x) 86 2/20 = 0.10 87 3/20 = 0.15 88 4/20 = 0.2 89 4/20 = 0.2 90 4/20 = 0.2 91 3/20 = 0.15 b) 28. a) complaints x proportion of days p(x) 0 0.333 1 0.238 2 0.238 3 0.143
Solution-Manual-Understanding-Business-Statistics-1st-Edition-Freed.docx