Case- 2 Parallel Pipe f Length L Discharge Q1 D1 = D2 = d Q = Q1 + Q2 = 2Q1 (as both the diameter and length are same) 2 f  L  Q1  Q hf  hf     Q1   0.5  Q 1 2 2 g   A 2   D 2     2  hf  0.5 Q 0.0207 f L hf 2       1 Q   f L  2 9.81  d d     2 d 4   Equating the values of hfand hf1 from Eq.1 and Eq.2 Q.8 Define Pipes in Series (Dec 2013, Jan2015) Ans: Pipes in Series or Compound Pipe D1, D2, D3, D4 are diameters. L1, L2,L3, L4 are lengths of a number of Pipes connected in series (hf)1, (hf)2, (hf)3 &(hf)4 are the head loss due to friction for each pipe. The total head loss due to friction hf for the entire pipe system is given by     hf hf1 hf2 hf3 hf4 8 h  fL1Q 8 8 8 fL2Q fL3Q fL4Q g D5 g D5 g D5 g D5 2 2 2 2 f
Case- 2 Parallel Pipe f Length L Discharge Q1 D1 = D2 = d Q = Q1 + Q2 = 2Q1 (as both the diameter and length are same) 2 f  L  Q1  Q hf 1  hf 2     Q1   0.5  Q 2  g  D  A  2 2     2 hf 1  hf 2  f  L   0.5  Q   0.0207  f  L  Q 2  9.81 d    d 2  d  4  Equating the values of hfand hf1 from Eq.1 and Eq.2 Q.8 Define Pipes in Series (Dec 2013, Jan2015) Ans: Pipes in Series or Compound Pipe D1, D2, D3, D4 are diameters. L1, L2,L3, L4 are lengths of a number of Pipes connected in series (hf)1, (hf)2, (hf)3 &(hf)4 are the head loss due to friction for each pipe. The total head loss due to friction hf for the entire pipe system is given by hf  hf1  hf2  hf3  hf4 h  8 fL1Q 8 fL2Q 8 fL3Q 8 fL4Q f g 2 D5 g 2 D5 g 2 D5 g 2 D5
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