Students should be able to determine speed from a distance–time graph. 4.5.6.1.5 Acceleration The average acceleration of an object can be calculated using the equation: 82-4 67-8 84-6, 205-6 acceleration, a, in metres per second squared, m/s2 change in velocity, in metres per second, m/s ∆v, time, t, in seconds, s An object that slows down is decelerating. Students should be able to estimate the magnitude of everyday accelerations. The acceleration of an object can be calculated from the gradient of a graph. (HT only) The distance travelled by an object (or displacement of an object) can be calculated from the area under a velocity–time graph. Students should be able to: draw velocity–time graphs from measurements and interpret lines and slopes • to determine acceleration (HT only) interpret enclosed in velocity–time graphs to determine • distance travelled (or displacement) (HT only) measure, when appropriate, the area a velocity–time graph by • counting squares. The following equation applies to uniform acceleration: 82-84 67-8 84-6, 205-6 (final velocity)2 (initial velocity)2 = 2 × acceleration × distance – v2 u2 = 2 a s −
Students should be able to determine speed from a distance–time graph. 4.5.6.1.5 Acceleration The average acceleration of an object can be calculated using the equation: acceleration, a, in metres per second squared, m/s2 change in velocity, ∆v, in metres per second, m/s time, t, in seconds, s An object that slows down is decelerating. Students should be able to estimate the magnitude of everyday accelerations. The acceleration of an object can be calculated from the gradient of a graph. (HT only) The distance travelled by an object (or displacement of an object) can be calculated from the area under a velocity–time graph. Students should be able to: • draw velocity–time graphs from measurements and interpret lines and slopes to determine acceleration • (HT only) interpret enclosed in velocity–time graphs to determine distance travelled (or displacement) • (HT only) measure, when appropriate, the area a velocity–time graph by counting squares. 82-4 67-8 84-6, 205-6 The following equation applies to uniform acceleration: (final velocity)2 – (initial velocity)2 = 2 × acceleration × distance v2 − u2 = 2 a s 82-84 67-8 84-6, 205-6
scholastic-aqa-physics-gcse-map-1648371.docx