x-intercepts: 22. ( 3 x = −1)2 ( 0 3 x = −1)2 + ( y x = −1)2 ( x −1)2 = −3 y 3 − + vertex: (1, 3) The axis of symmetry is = x –2. x −1 = ±i 3 domain: (−∞, ∞) 1 x i = ± [−1, range: ∞) 3 No x-intercepts y-intercept: (0 3 y = −1)2 + = 24. 4 ( 5 1 f x)  x  = − − 4  2  The axis of symmetry is = 1. x 2 ( f x) 1 5  x  = − − +  2  4 vertex:  1 , 5  x-intercepts: 0  x = − − 1 5 2  + 4  (−∞, domain: = ∞) 1 2  x − 5 [3, range: 2 4   ∞) vertex: (–2, –1) 1 x = ± x-intercepts: 5 ( 0 2 2)2 5 23. x = + + = 2 1 4 y-intercept: −1 1 2 1 ( 2 2)2 1 x + = (0) 0  ( f f = − ( 2)2 1 x + = x) = − ( 2  x + 1 5 x − = ± 2)2 2 2 −1 2 1 2 x = −2 ± = −2 ± 2 1 x + = ± The axis of symmetry is . x 2 = 2 2 2 y-intercept: (0 (0) 2 2)2 f = + −1 = 7
22. y − 3 = ( x −1)2 y = ( x −1)2 + 3 vertex: (1, 3) x-intercepts: 0 = ( x −1)2 + 3 ( x −1)2 = −3 The axis of symmetry is x = –2. x −1 = ±i 3 x = 1 ± i 3 domain: (−∞, ∞) range: [−1, ∞) No x-intercepts y-intercept: y = (0 −1)2 + 3 = 4 24. f ( x) = 5 −  x − 1  4  2  The axis of symmetry is x = 1. 2 f ( x) = −  x − 1  + 5  2  4 vertex:  1 , 5  x-intercepts: 0 = −  x − 1 2 5  +  4 domain: (−∞, ∞)  x − 1 2 5 = range: [3, ∞)  2  4 23. f ( x) = 2 ( x + 2)2 −1 vertex: (–2, –1) x-intercepts: 0 = 2 ( x + 2)2 −1 2 ( x + 2)2 = 1 ( x + 2)2 = 1  x − 1 = ± 5 2 2 x = 1 ± 5 2 y-intercept: f (0) = −  0 − 1 2 5 + = 1 4 1 2 x + 2 = ± 1 2 x = −2 ± 1 = −2 ± 2 The axis of symmetry is x = . 2 2 2 y-intercept: f (0) = 2 (0 + 2)2 −1 = 7
Precalculus-Essentials-5th-Edition-Blitzer-Solutions-Manual.docx