Using the definition of Arccos. sin(45) = x = = x θ Why isn’t included? So, ArcCos = So, sin (cos-1 1 + tan-1 1) = = = Arcsin 1 θ θ sin-1 2 = x cos ( sin-1 ½ ) = x –
Using the definition of Arccos. = θ Why isn’t included? So, ArcCos = sin(45) = x = x So, sin (cos-1 1 + tan-1 1) = θ = θ = Arcsin 1 sin-1 2 = x cos ( – sin-1 ½ ) = x
Pre-Calculus-Unit-2.docx