Also Assesses MACC.912.S-CP.1.2 or Assessed by Item Types This benchmark will be assessed using MC items. Content Limit to real world contexts and age appropriate situations. Limits Benchmark Students will determine probable outcomes of events using the addition rule. Clarification Stimulus Test items may include illustrations of the following: tables, lists, tree Attributes diagrams, and other forms. Response Responses may be in decimal or reduced fraction form. Attributes Sample Item If = 0.24 and = 0.52 and A and B are independent, P(A) P(B) what is or B)? P(A (a) 0.1248 (b) 0.28 * (c) 0.6352 (d) 0.76 (e) The answer cannot be determined from the information given. Solution: 0.24 + 0.52 (0.24)(0.52) – Benchmark MACC.912.S-CP.2.8 Reporting Statistics and Probability Category Domain Conditional Probability & the Rules of Probability Benchmark MACC.912.S-CP.2.8 Number
Also Assesses or Assessed by MACC.912.S-CP.1.2 Item Types This benchmark will be assessed using MC items. Content Limits Limit to real world contexts and age appropriate situations. Benchmark Clarification Students will determine probable outcomes of events using the addition rule. Stimulus Attributes Test items may include illustrations of the following: tables, lists, tree diagrams, and other forms. Response Attributes Responses may be in decimal or reduced fraction form. Sample Item If P(A) = 0.24 and P(B) = 0.52 and A and B are independent, what is P(A or B)? (a) 0.1248 (b) 0.28 * (c) 0.6352 (d) 0.76 (e) The answer cannot be determined from the information given. Solution: 0.24 + 0.52 – (0.24)(0.52) Benchmark MACC.912.S-CP.2.8 Reporting Category Statistics and Probability Domain Conditional Probability & the Rules of Probability Benchmark Number MACC.912.S-CP.2.8
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