35. 2 4 3 ) 3 x2 x = + − − 13 ( 2( 2 f x) x2 x 2 = + = 3 3 1 x − ( f x) 3 ( 2( 2 1) f x) x2 x = + + − 13 3 2 2 − 1 = x − ( ( 2 1)2 5 9 f x) x = + − 3 (−1, vertex: 1 13 x −5) − = ± x-intercepts: 3 9 ( 0 2 x = +1)2 1 13 x = ± 3 3 5 − (0) 3(0)2 2(0) 4 ( 2 5 f = − − x +1)2 = (0) f = −4 ( 5 x +1)2 = 2 The axis of symmetry is 1 x . = 3 5 x +1 = ± 2 y-intercept: 10 x = −1 ± 2 y-intercept: (0) 2(0)2 4(0) 3 f = + − (0) f = −3 The axis of symmetry is x . = −1 (−∞, domain: ∞) range: − 13 ,  ∞ 3   2 2 x x2 − − 37. ( 2 2 f x) x2 x = − + − (−∞, domain: ∞) (x2  ( 2 1) 2 1 f x) x = − − + − + [−5, range: ∞) (x ( 1)2 1 f x) = − − − vertex: (1, –1) ( 3x2 2 f x) x = − − x-intercepts: ( f (x 4 0 1)2 1 = − − −  − ( 3 2 x) 36. f x) x2 x = − 4 = 3    ( 3 2 1 4 f x) x2 x  = − + − 1 − (x 1)2 − = −1 3 9 3   1 = ±i x –   ( 3 = 1 ±i f x) x x = 1 2 No x-intercepts. 13 − − y-intercept: 3 vertex:  1 , 13 − 
35. f ( x) = 2 x2 + 4 x − 3 f ( x) = 2( x2 + 2 x ) − 3 3 x − 1 3 2 13 = 3 f ( x) = 2( x2 + 2 x + 1) − 3 − 2 f ( x) = 2 ( x + 1)2 − 5 x − 1 3 2 13 = 9 vertex: (−1, −5) x − 1 = ± 13 x-intercepts: 0 = 2 ( x +1)2 − 5 3 9 x = 1 ± 13 3 3 2 ( x +1)2 = 5 ( x +1)2 = 5 2 x +1 = ± 5 2 y-intercept: f (0) = 3(0)2 − 2(0) − 4 f (0) = −4 The axis of symmetry is x = 1 . 3 x = −1 ± 10 2 y-intercept: f (0) = 2(0)2 + 4(0) − 3 f (0) = −3 The axis of symmetry is x = −1 . domain: (−∞, ∞) range: − 13 , ∞   3  36. domain: (−∞, ∞) range: [−5, ∞) f ( x) = 3x2 − 2 x − 4 f ( x) = 3 x2 − 2 x  − 4 37.  f ( x) = 2 x − x2 − 2 f ( x) = − x2 + 2 x − 2 f ( x) = − (x2 − 2 x + 1) − 2 + 1 f ( x) = − (x − 1)2 − 1 vertex: (1, –1) x-intercepts: 0 = − (x − 1)2 − 1  3   f ( x) = 3 x2 − 2 x + 1  − 4 − 1 (x − 1)2 = −1  3 9  3 x – 1 = ±i   f ( x) = 3 x − 1 2 − 13 3 x = 1 ±i No x-intercepts. y-intercept: vertex:  1 , − 13 
Precalculus-Essentials-5th-Edition-Blitzer-Solutions-Manual.docx