( 3)2 6 x + = 3 6 x + = ± 6 x = −3 ± y-intercept: (−∞, range: 4] (0) (0)2 6(0) 3 f = + + (0) 3 f = (−∞, domain: ∞) The axis of symmetry is x . = −3 32. x2 − domain: (−∞, ∞) ( 4 5 f x) x = −x2 − + [−6, range: ∞) ( f (x2 ( 4 4)+ f x) x = − + + ( 4 f x) x2 x x) = + −1 ( ( 4x 4) 4 f x) x2 = + + −1 − 5 4 + 2 = ( ( 2)2 9 f x) x 5 = − + + − 34. vertex: (–2, 9) 4 x x-intercepts: 0 ( 2)2 9 x = − + + ( 2)2 9 x + = ( ( 2) 5 f x) x = + − + 2 = ± 3 x (−2, vertex: = 1 x –5, −5) y-intercept: x-intercepts: (0) (0) 5 4 f = − − 0 ( 2)2 5 x (0)2 = + − 5 = ( )2 2 5 x + = The axis of symmetry is = x –2. 2 5 x + = ± 5 x = −2 ± y-intercept: (−∞,9] range: (0) (0)2 4(0) f = + −1 (0) f = −1 The axis of symmetry is x . = −2 (−∞, domain: ∞) 6 3 33. x + + (−∞, domain: ( ( 6 9) 3 ∞) f x) x2 x = + + + 9 [−5, − range: ∞) ( f ( ( 3)2 6 f x) x = + − x) (−3, vertex: −6) = x-intercepts: x2 ( 0 3)2 6 x = + −
( x + 3)2 = 6 x + 3 = ± 6 x = −3 ± 6 y-intercept: domain: (−∞, ∞) range: (−∞, 4] f (0) = (0)2 + 6(0) + 3 f (0) = 3 The axis of symmetry is x = −3 . 32. f ( x) = 5 − 4 x − x2 f ( x) = −x2 − 4 x + 5 f ( x) = − (x2 + 4 x + 4)+ 5 + 4 f ( x) = − ( x + 2)2 + 9 vertex: (–2, 9) x-intercepts: 0 = − ( x + 2)2 + 9 34. domain: (−∞, ∞) range: [−6, ∞) f ( x) = x2 + 4 x −1 f ( x) = ( x2 + 4x + 4) −1 − 4 2 ( x + 2)2 = 9 x + 2 = ± 3 x = –5, 1 y-intercept: f (0) = 5 − 4 (0) − (0)2 = 5 f ( x) = ( x + 2) − 5 vertex: (−2, −5) x-intercepts: 0 = ( x + 2)2 − 5 ( )2 x + 2 = 5 The axis of symmetry is x = –2. x + 2 = ± 5 x = −2 ± 5 y-intercept: domain: (−∞, ∞) range: (−∞,9] f (0) = (0)2 + 4(0) −1 f (0) = −1 The axis of symmetry is x = −2 . 33. f ( x) = x2 + 6 x + 3 f ( x) = ( x2 + 6 x + 9) + 3 − 9 f ( x) = ( x + 3)2 − 6 vertex: (−3, −6) x-intercepts: 0 = ( x + 3)2 − 6 domain: (−∞, ∞) range: [−5, ∞)
Precalculus-Essentials-5th-Edition-Blitzer-Solutions-Manual.docx