FUTURE CONNECTIONS (What will they use these skills for later?) Triangle congruency and transformations will be utilized to discover the characteristics of different quadrilaterals. ADDITIONAL EXTENSIONS OR EXPLANATIONS (What needs greater explanation?) Sequences of rigid motions will be used to discover congruence postulates for triangles. ASSESSMENTS (Questions that get to the heart of the objective multiple choice, short answer, multi-step) – Given find the values of x and y. ∆TUV ∆WXY, x = 8 and y = 16 Given that = (7n + 5)°, = (3n 5)°, and = 30°, what is the value of n? ∆PQR ≅ ∆XYZ, – n = 15 that JK = 3z + 21, KL = 2z + 25, LJ = 21 3z and ST = 5z + 31, what is the value of z? ∆JKL ≅ ∆RST, – z = -2 From CCSD Geometry Honors Semester 1 Practice Exam 2012 - 2013 On the coordinate plane, draw triangles and such that: ABC ABC (1) = A A (2) has been rotated 90°. ABC Answers will vary. Sample is shown at the right. In the diagram, is the perpendicular bisector of at and . m C, Prove . Given is the perpendicular bisector of and maps onto then maps onto and maps onto m D E, A B, C itself. Therefore ΔADC ≅ ΔBEC.
FUTURE CONNECTIONS (What will they use these skills for later?) Triangle congruency and transformations will be utilized to discover the characteristics of different quadrilaterals. ADDITIONAL EXTENSIONS OR EXPLANATIONS (What needs greater explanation?) Sequences of rigid motions will be used to discover congruence postulates for triangles. ASSESSMENTS (Questions that get to the heart of the objective – multiple choice, short answer, multi-step) Given ∆TUV ∆WXY, find the values of x and y. x = 8 and y = 16 Given that ∆PQR ≅ ∆XYZ, = (7n + 5)°, = (3n – 5)°, and = 30°, what is the value of n? n = 15 that ∆JKL ≅ ∆RST, JK = 3z + 21, KL = 2z + 25, LJ = 21 – 3z and ST = 5z + 31, what is the value of z? z = -2 From CCSD Geometry Honors Semester 1 Practice Exam 2012 - 2013 On the coordinate plane, draw triangles ABC and ABC such that: (1) A = A (2) ABC has been rotated 90°. Answers will vary. Sample is shown at the right. In the diagram, m is the perpendicular bisector of at C, and . Prove . Given m is the perpendicular bisector of and D maps onto E, then A maps onto B, and C maps onto itself. Therefore ΔADC ≅ ΔBEC.
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