0.43 ; = 0.3336. Conclude: A pˆ  P-value P-value 72 0.69 0.67   0.69 , so  of  z 104 0.67 0.33 104 0.3336 is greater than = 0.05, so we fail to reject there is insufficient evidence to  H0: conclude that the proportion of recent authors who support the system is greater than 67%. (b) If the true proportion of authors who support the system is 0.67, the probability of getting a sample proportion of authors as far or farther above 0.67 as our sample is 0.3336.
pˆ  72  0.69 , so z  0.69  0.67  0.43 ; P-value = 0.3336. Conclude: A P-value of 104 0.67 0.33 104 0.3336 is greater than  = 0.05, so we fail to reject H0: there is insufficient evidence to conclude that the proportion of recent authors who support the system is greater than 67%. (b) If the true proportion of authors who support the system is 0.67, the probability of getting a sample proportion of authors as far or farther above 0.67 as our sample is 0.3336.
Practice-Test-2191e1z.docx