Paper 1MA1: 2F Question Working Answer Mark Notes 17 98 P1 for process to find P(1), e.g. 1 0.17 0.18 0.09 0.15 0.1 (= 0.31) or for a process to find – – – – – P(1 or 3), e.g. 1 0.17 0.09 0.15 0.1 (= 0.49) – – – – P1 for process to find the number of 3s, e.g. 0.18 × 200 (=36) or process to find the number of 1s, e.g. P(1) × 200 (= 62), or process to find the number of (1 or 3)s, eg [P(1) + 0.18] × 200 or process to find any expected frequency, using any probability × 200, eg 0.17 × 200 A1 cao OR 98 P1 for process to find P(2 or 4 or 5 or 6), eg 0.17 + 0.09 + 0.15 + 0.1 (= 0.51) P1 for process to find the number of (2 or 4 or 5 or 6)’s, eg × 200 (= 102) “0.51” A1 cao Paper 1MA1: 2F Question Working Answer Mark Notes 18 Yes P1 for process to work out the total number of children, e.g. 117 × 4 (= 468) (supported) P1 (dep P1) for process to work out total number of adults or the total number of people, e.g. × 5 ÷ 2 (= 1170) or × 7 ÷ 2 (= 1638) “468” “468”
Paper 1MA1: 2F Question Working Answer Mark Notes 17 98 P1 for process to find P(1), e.g. 1 – 0.17 – 0.18 – 0.09 – 0.15 – 0.1 (= 0.31) or for a process to find P(1 or 3), e.g. 1 – 0.17 – 0.09 – 0.15 – 0.1 (= 0.49) P1 for process to find the number of 3s, e.g. 0.18 × 200 (=36) or process to find the number of 1s, e.g. P(1) × 200 (= 62), or process to find the number of (1 or 3)s, eg [P(1) + 0.18] × 200 or process to find any expected frequency, using any probability × 200, eg 0.17 × 200 A1 cao OR 98 P1 for process to find P(2 or 4 or 5 or 6), eg 0.17 + 0.09 + 0.15 + 0.1 (= 0.51) P1 for process to find the number of (2 or 4 or 5 or 6)’s, eg “0.51” × 200 (= 102) A1 cao Paper 1MA1: 2F Question Working Answer Mark Notes 18 Yes (supported) P1 for process to work out the total number of children, e.g. 117 × 4 (= 468) P1 (dep P1) for process to work out total number of adults or the total number of people, e.g. “468” × 5 ÷ 2 (= 1170) or “468” × 7 ÷ 2 (= 1638)
1ma1_2f_-_june_2017_mark_scheme.docx