d. Separation of two alleles Phenotype e. An inherited factor Gamete f. Results in 9:3:3:1 ratio in F2 generation of a dihybrid cross g. Specific form of an inherited factor Independent assortment h. Combination of alleles an individual has Dominant j. Haploid cell k. Diploid cell l. An observable characteristic m. Having two different alleles 2. Each scenario below describes the alleles for some gene that are present in a heterozygous individual. Match each one with the term from the list on the right that best describes the situation. One letter per blank, use the letters once only. a. Complete dominance Allele #1 encodes a functional enzyme; allele #2 encodes a version of the enzyme. The cell needs at least 40% of b. Incomplete dominance normal enzyme activity in order to have a normal phenotype. c. Overdominance d. Epistasis Allele #1 encodes a functional enzyme that makes a blue pigment; e. Codominance allele #2 encodes a non-functional version of the enzyme. The cell needs at least 90% of normal enzyme activity in order to be its normal, dark blue color. Allele #1 encodes functional tyrosinase. Allele #2 encodes a mutant version of tyrosinase that but can catalyze can’t bind pyrocatechol a different reaction involving phenylalanine.
d. Separation of two alleles e. An inherited factor f. Results in 9:3:3:1 ratio in F2 generation of a dihybrid cross g. Specific form of an inherited factor h. Combination of alleles an individual has j. Haploid cell k. Diploid cell l. An observable characteristic m. Having two different alleles Phenotype Gamete Independent assortment Dominant 2. Each scenario below describes the alleles for some gene that are present in a heterozygous individual. Match each one with the term from the list on the right that best describes the situation. One letter per blank, use the letters once only. Allele #1 encodes a functional enzyme; allele #2 encodes a version of the enzyme. The cell needs at least 40% of normal enzyme activity in order to have a normal phenotype. a. Complete dominance b. Incomplete dominance c. Overdominance d. Epistasis e. Codominance Allele #1 encodes a functional enzyme that makes a blue pigment; allele #2 encodes a non-functional version of the enzyme. The cell needs at least 90% of normal enzyme activity in order to be its normal, dark blue color. Allele #1 encodes functional tyrosinase. Allele #2 encodes a mutant version of tyrosinase that can’t bind pyrocatechol but can catalyze a different reaction involving phenylalanine.
Problems%20Mendel2.docx