or 4 × × M1 for a process to find the area of a quadrant eg. 0.25 × πx2 π (x/2)2 or 4 × 0.25 × (x/2)2. πx2 π = C1 for concluding the argument by showing that both πx2 πx2 areas equate to πx2/4. 22 × 230° 4 180 = 93 process for total women in swimming club × 180 (= P1 93) 180 + 13 = 166 − 27 process for total members in badminton club 180 + 13 166) P1 − 27 (= × 360 = 230° complete method for angle for badminton women × 360 M1 A1 cao 23 (a) 2 M1 correct length line or one correct end and line. -3 1 A1 cao (b) 4n > 22 5 > 4.25 2 M1 for subtracting 5 from both sides n – A1 cao 4n > 17 M1 > 17 ÷ 4 n 24 (a) (i) 2 B1 cao 10, 12, 14, 15, 16, 18 (ii) B1 cao 12, 18
πx2 or 4 × × π (x/2)2 πx2 = πx2 M1 C1 for a process to find the area of a quadrant eg. 0.25 × πx2 or 4 × 0.25 × π (x/2)2. for concluding the argument by showing that both areas equate to πx2/4. 22 × 180 = 93 180 + 13 − 27 = 166 × 360 = 230° 230° 4 P1 P1 M1 process for total women in swimming club × 180 (= 93) process for total members in badminton club 180 + 13 − 27 (= 166) complete method for angle for badminton women × 360 A1 cao 23 (a) (b) 4n > 22 – 5 4n > 17 M1 n > 17 ÷ 4 -3 1 n > 4.25 2 2 M1 A1 M1 A1 correct length line or one correct end and line. cao for subtracting 5 from both sides cao 24 (a) (i) (ii) 10, 12, 14, 15, 16, 18 12, 18 2 B1 B1 cao cao
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