Actual velocity calculation for average of times through photogate 1 and the average through (2 marks) photogate 2. = v d/t = (0.055 m)/(0.059 s) = 0.932 m/s 1 = _0.932 m/s_ v vphotogate = v d/t = (0.095 m)/(0.042 s) = 1.61 m/s 2 = _1.61 m/s__ v vphotogate Conservation of energy calculation to find theoretical speed at photogate 1. = + Ep Ep Ek + 1/2mv2 mgh = mgh [2(g(0.845 m) m))] = 3.30 m/s 1 = _3.30 m/s__ g(0.290 vphotogate – Conservation of energy calculation to find theoretical speed at photogate 2. = Ep Ek 1/2mv2 mgh = [2g(0.845 m)] = 4.07 m/s 2 = _4.07 m/s__ vphotogate Sample Data for of Energy in a Lab “Conservation Pendulum” = 3.0 cm = 0.177 s d t1 = 21.6 cm = 0.175 s = 0.176 s h1 t2 tave = 22.3 cm = 0.176 s h2 t3 = 500 g m actual maximum velocity (at equilibrium) = = 0.030 m / 0.176 s = 0.17 m/s v d/t v Potential Energy at maximum amplitude: = = (0.500 kg)(9.81 m/s2)(0.233 m 0.216 m) = 0.0834 J PE mgh – Theoretical Velocity from Conservation of Energy Calculation: = 1/2mv2 KE 0.0834 J = ½(0.500kg)(v2) = 0.578 m/s v
Actual velocity calculation for average of times through photogate 1 and the average through photogate 2. (2 marks) v = d/t v = (0.055 m)/(0.059 s) = 0.932 m/s vphotogate 1 = _0.932 m/s_ v = d/t v = (0.095 m)/(0.042 s) = 1.61 m/s vphotogate 2 = _1.61 m/s__ Conservation of energy calculation to find theoretical speed at photogate 1. Ep = Ep + Ek mgh = mgh + 1/2mv2 [2(g(0.845 m) – g(0.290 m))] = 3.30 m/s vphotogate 1 = _3.30 m/s__ Conservation of energy calculation to find theoretical speed at photogate 2. Ep = Ek mgh = 1/2mv2 [2g(0.845 m)] = 4.07 m/s vphotogate 2 = _4.07 m/s__ Sample Data for “Conservation of Energy in a Pendulum” Lab d = 3.0 cm t1 = 0.177 s h1 = 21.6 cm t2 = 0.175 s tave = 0.176 s h2 = 22.3 cm t3 = 0.176 s m = 500 g actual maximum velocity (at equilibrium) v = d/t v = 0.030 m / 0.176 s = 0.17 m/s Potential Energy at maximum amplitude: PE = mgh = (0.500 kg)(9.81 m/s2)(0.233 m – 0.216 m) = 0.0834 J Theoretical Velocity from Conservation of Energy Calculation: KE = 1/2mv2 0.0834 J = ½(0.500kg)(v2) v = 0.578 m/s
Physics_20_Laboratory_Manual.docx