a. b. c. d. Answer: a. A*162 5*161 B*160 + + = 10*256 + 5*16 + 11*1 = 2560+80 + 11 = 2651, is equivalent to b. 2*163 0*162+ 9*161 E*160 + + = 2*4096 + 0*256 + 9*16 + 14*1 = 8192 + 0 + 144 + 14 = 8350, hence is equivalent to c. 1*161 F*160 + +8*16-1 + A*16-2 = 1*16 + 15*1 + 8*.0625 + 10*.00390625 = 16 + 15 + 0.5 + 0.0390625 = 31.5390625, hence is equivalent to d. 1*162 A*161 8*160 2*16-1 8*16-2 + + + + = 1*256 + 10*16 + 8*1 + 2*.0625 + 8*.00390625 = 256 + 160 + 8 + 0.125 + 0.03125 = 424.15625, hence is equivalent to Q4. Convert the following decimal numbers (base 10) into binary (base 2). a. b. c. d.
a. b. c. d. Answer: a. A*162 + 5*161 + B*160 = 10*256 + 5*16 + 11*1 = 2560+80 + 11 = 2651, is equivalent to b. 2*163 + 0*162+ 9*161 + E*160 = 2*4096 + 0*256 + 9*16 + 14*1 = 8192 + 0 + 144 + 14 = 8350, hence is equivalent to c. 1*161 + F*160 +8*16-1 + A*16-2 = 1*16 + 15*1 + 8*.0625 + 10*.00390625 = 16 + 15 + 0.5 + 0.0390625 = 31.5390625, hence is equivalent to d. 1*162 + A*161 + 8*160 + 2*16-1 + 8*16-2 = 1*256 + 10*16 + 8*1 + 2*.0625 + 8*.00390625 = 256 + 160 + 8 + 0.125 + 0.03125 = 424.15625, hence is equivalent to Q4. Convert the following decimal numbers (base 10) into binary (base 2). a. b. c. d.
is_201-t3.a.docx