36 a C1 3 C1 for first equation M S = C1 C1 for second equation B =C C1 C1 for third equation S C + = 75 C B = M1 M1 for creating single equation with one unknown B + = 75 =75 B = 75 × = 20 S = 1.25B S = 1.25 × 20 = £25 C = 75 25 = £50 – B A1 A1 for £20 cao = £20 The method used was to find equations linking each two persons at a time, and then use those to create one equation that could S = £25 A1 A1 for £25 cao be solved. Once you had one solution you A1 A1 for £50 cao C = £50 could find the rest. b Answer checked by going back to beginning statements and ensuring each one works. They do. C2 C1 for clear explanation. C1 for matching explanation with the work done C1 C1 for clear explanation 10
36 a b S = B =C S + C = 75 C = B B + = 75 =75 B = 75 × = 20 S = 1.25B S = 1.25 × 20 = £25 C = 75 – 25 = £50 The method used was to find equations linking each two persons at a time, and then use those to create one equation that could be solved. Once you had one solution you could find the rest. Answer checked by going back to beginning statements and ensuring each one works. They do. B = £20 S = £25 C = £50 C1 C1 C1 M1 A1 A1 A1 C2 C1 3 C1 for first equation C1 for second equation C1 for third equation M1 for creating single equation with one unknown A1 for £20 cao A1 for £25 cao A1 for £50 cao C1 for clear explanation. C1 for matching explanation with the work done C1 for clear explanation M 10
Higher_Skills_Algebra_MarkScheme_Edexcel.docx