29 a False M1 2 M1 for finding a suitable comparison H So A1 A1 for showing it is false and stating such 42 = 16 True M1 M1 for showing the square of the limits b 52 = 25 A1 A1 for showing it is true and stating such So is between 4 and 5. M1 for showing M1 False So not less than but is equal to it. c is A1 for showing it is false and stating such A1 B1 for explaining they are in fact equal B1 = Consider 0.6 iv = True M1 for showing both in similar comparable terms M1 Hence > 0.6 A1 for showing it is true and stating such A1 B1 for clear concise communication of method B1 10 30 Odd one out is. M3 2 M1 for showing = H M1 for showing = M1 for showing 3–1 = A1 cao A1 4 31 M2 2 M1 for squaring both sides to make information clearer H Any example where is the square of x= y x y, M1 for considering only the denominator = e.g. = 1, = 1 x y Square both sides: = 4, = 2 x y A1 A1 for a correct example = = 9, = 3 x y Hence = √x y B1 B1 for clear progression through the solution Hence = x2 y 4
29 a b c iv So 42 = 16 52 = 25 So is between 4 and 5. So is not less than but is equal to it. = Consider 0.6 = Hence > 0.6 False True False True M1 A1 M1 A1 M1 A1 B1 M1 A1 B1 2 M1 for finding a suitable comparison A1 for showing it is false and stating such M1 for showing the square of the limits A1 for showing it is true and stating such M1 for showing A1 for showing it is false and stating such B1 for explaining they are in fact equal M1 for showing both in similar comparable terms A1 for showing it is true and stating such B1 for clear concise communication of method H 10 30 Odd one out is. M3 A1 2 M1 for showing = M1 for showing = M1 for showing 3–1 = A1 cao H 4 31 x= y = Square both sides: = Hence √x = y Hence x2 = y Any example where x is the square of y, e.g. x = 1, y = 1 x = 4, y = 2 x = 9, y = 3 M2 A1 B1 2 M1 for squaring both sides to make information clearer M1 for considering only the denominator A1 for a correct example B1 for clear progression through the solution H 4
Higher_Skills_Number_MarkScheme_AQA.docx