COMPONENTS TIME TASKS/ACTIVITIES CAPS From B draw BP perpendicular DC Circles • Make sure Therefore, AB = DP = 20 cm learners can So, PC = DC - DP identify the = (25 - 20) cm centre, radius, = 5 cm diameter and circumference of Now, area of trapezium ABCD = Area of rectangle ABPD + Area of the circle △BPC is right-angled at . • Spend time △BPC ∠BPC investigating the Therefore, using Pythagoras theorem, relationship BC² = BP² + PC² between radius, 13² = BP² + 5² circumference and diameter, so that 169 = BP² + 25 ⇒ REVIEW AND learners develop a 169 - 25 = BP² ⇒ CORRECTION OF 4 Min sense of where the 144 = BP² ⇒ HOMEWORK irrational number BP = 12 Pi (π) is derived ⇒ from. Now, area of trapezium ABCD = Area of rectangle ABPD + Area of ∆BPC • Develop an understanding of = AB × BP + 1/2 × PC × BP π, making sure = 20 × 12 + 1/2 × 5 × 12 learners = 240 + 30 understand that: - = 270 cm² π represents the value of the circumference divided by the diameter, for any circle - π is an irrational number
COMPONENTS TIME TASKS/ACTIVITIES CAPS REVIEW AND CORRECTION OF HOMEWORK 4 Min From B draw BP perpendicular DC Therefore, AB = DP = 20 cm So, PC = DC - DP = (25 - 20) cm = 5 cm Now, area of trapezium ABCD = Area of rectangle ABPD + Area of △BPC △BPC is right-angled at ∠BPC Therefore, using Pythagoras theorem, BC² = BP² + PC² 13² = BP² + 5² ⇒ 169 = BP² + 25 ⇒ 169 - 25 = BP² ⇒ 144 = BP² ⇒ BP = 12 Now, area of trapezium ABCD = Area of rectangle ABPD + Area of ∆BPC = AB × BP + 1/2 × PC × BP = 20 × 12 + 1/2 × 5 × 12 = 240 + 30 = 270 cm² Circles • Make sure learners can identify the centre, radius, diameter and circumference of the circle . • Spend time investigating the relationship between radius, circumference and diameter, so that learners develop a sense of where the irrational number Pi (π) is derived from. • Develop an understanding of π, making sure learners understand that: - π represents the value of the circumference divided by the diameter, for any circle - π is an irrational number
Grade_8_Term_2_Lesson_PLans_Final.docx