See annexure B for graph 6.4 M() Estimation accepted (0,5; 2,5) Correct answer 1 mark TOTAL 7 marks QUESTION SOLUTIONS MARK ALLOCATION 7 7.1.1 + 62° + 42° = 180° 76° 1 mark = 76° interior angles of triangle Reason 1 mark 7.1.2 Angles are equal 1 mark 7.1.3 PQR /// TMS 1 mark 10 1 mark 1 mark 1 mark 10 7.2 In ABD and CBD is: AB = CB 1 mark AB = CB given 1 mark given BD = BD 1 mark BD = BD common SAS 1 mark ABD CBD SAS TOTAL 10 marks QUESTION SOLUTIONS MARK ALLOCATION 8 8.1.1 = 63° angles opposite equal sides = 63° 1 mark 63° + 63° exterior angles of triangle 126° Reason 1 mark OR 126° 1 mark = 63° angles opposite equal sides Reason 1 mark BC + + 63°= 180° interior angles of BC + = 180° angles on straight line = 126° 8.1.2 = 63° alternate angles, DA//BC = 63° 1 mark alternate angles, DA//BC 1 mark 8.2 AC 1 mark 8.3.1 Triangular prism Correct answer 1 mark 8.3.2 PQ² = QS² - PS² Pythagoras Substitution 1 mark = (12 cm)² - (6 cm)² = 144 cm² - 36 cm² 108 cm² 1 mark = 108 cm² PQ = cm OR 6 cm Correct answer 1 mark 8.3.3 V = Substitution 1 mark = (12 cm)(10,4 cm)(40 cm) = 2496 Correct answer 1 mark cm³
See annexure B for graph 6.4 M() Estimation accepted (0,5; 2,5) Correct answer 1 mark TOTAL 7 marks QUESTION 7 SOLUTIONS MARK ALLOCATION 7.1.1 + 62° + 42° = 180° = 76° interior angles of triangle 76° 1 mark Reason 1 mark 7.1.2 Angles are equal 1 mark 7.1.3 PQR /// TMS 10 1 mark 10 1 mark 1 mark 1 mark 7.2 In ABD and CBD is: AB = CB given given BD = BD common ABD CBD SAS AB = CB 1 mark 1 mark BD = BD 1 mark SAS 1 mark TOTAL 10 marks QUESTION 8 SOLUTIONS MARK ALLOCATION 8.1.1 = 63° angles opposite equal sides 63° + 63° exterior angles of triangle 126° OR = 63° angles opposite equal sides BC + + 63°= 180° interior angles of BC + = 180° angles on straight line = 126° = 63° 1 mark Reason 1 mark 126° 1 mark Reason 1 mark 8.1.2 = 63° alternate angles, DA//BC = 63° 1 mark alternate angles, DA//BC 1 mark 8.2 AC 1 mark 8.3.1 Triangular prism Correct answer 1 mark 8.3.2 PQ² = QS² - PS² Pythagoras = (12 cm)² - (6 cm)² = 144 cm² - 36 cm² = 108 cm² PQ = cm OR 6 cm Substitution 1 mark 108 cm² 1 mark Correct answer 1 mark 8.3.3 V = = (12 cm)(10,4 cm)(40 cm) = 2496 cm³ Substitution 1 mark Correct answer 1 mark
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