Question Working Answer Mark Notes 15 Proof M1 Correct expansion or factorisation of a suitable expression for 2 consecutive integers,, e.g. (n + 1)2 = + 2n + 1 or n2 n2 n2 – – (n + 1)2 = (n + 1 + + 1 n2 n)(n n) – – Expansion or factorisation correctly simplified,, e.g. 2n + 1 or 2n + 3 A1 Correct conclusion drawn from fully correct working C1 16 Enlargement, B2 Enlargement, scale factor centre (4, 6) –2, scale factor –2, (B1) (For 2 correct aspects) centre (4, 6) NB score B0 for more than one transformation 17 No with P1 for one correct bound, e.g. 69.5, 70.5, 39.5, 40.5, 121.5, 122.5, 13.5, 14.5 justification P1 for complete process to find the upper bound for the volume of the tank, e.g. 120.5 × 40.5 × 70.5 (= 344057.625) for complete process to find the upper bound for the number of buckets, P1 (upper bound for volume of tank ÷ lower bound for volume of bucket) e.g. ÷ 13500. Must be in consistent units “344057.625” correct process to compare the lower bound for 25 buckets of water OR with the upper bound for the volume of the tank, e.g. 13.5 × 1000 × 25 (=337500) C1 Correct conclusion based on correct calculations
Question Working Answer Mark Notes 15 Proof M1 A1 C1 Correct expansion or factorisation of a suitable expression for 2 consecutive integers,, e.g. (n + 1)2 – n2 = n2 + 2n + 1 – n2 or (n + 1)2 – n2 = (n + 1 + n)(n + 1 – n) Expansion or factorisation correctly simplified,, e.g. 2n + 1 or 2n + 3 Correct conclusion drawn from fully correct working 16 Enlargement, scale factor –2, centre (4, 6) B2 (B1) Enlargement, scale factor –2, centre (4, 6) (For 2 correct aspects) NB score B0 for more than one transformation 17 No with justification P1 P1 P1 C1 for one correct bound, e.g. 69.5, 70.5, 39.5, 40.5, 121.5, 122.5, 13.5, 14.5 for complete process to find the upper bound for the volume of the tank, e.g. 120.5 × 40.5 × 70.5 (= 344057.625) for complete process to find the upper bound for the number of buckets, (upper bound for volume of tank ÷ lower bound for volume of bucket) e.g. “344057.625” ÷ 13500. Must be in consistent units OR correct process to compare the lower bound for 25 buckets of water with the upper bound for the volume of the tank, e.g. 13.5 × 1000 × 25 (=337500) Correct conclusion based on correct calculations
GCSE%201MA1%20Mark%20Scheme%202H%20Mock%20Set%202.docx