19 51 & 27 M1 42 ÷ 14 (= 3) M1 (dep M1) for × 17 or × 9 “3” “3” A1 51 and 27 correctly assigned 20 < 3.55 B2 cao x 3.45 ≤ (B1) for 3.45 and 3.55 21 0.23 P1 for 45 ÷ 300 (= 0.15) for 0.62 × 300 (= 186) P1 (dep P1) for 1 (0.62 + (dep P1) for 300 + 45) – “0.15”) – (“186” A1 oe oe 22 11 P1 Process to find total cycling,, e.g. 100 52 35 (= 13) – – P1 Complete process to find female running, e.g. 45 (30 + – (“13” −9)) A1 cao OR P1 process to find male Gym (22) or male total (55) P1 complete process to find female running, e.g. 35 9) – (“55” – “22” – A1 cao Note: the two-way table (or frequency tree) does not need to be fully complete
19 51 & 27 M1 42 ÷ 14 (= 3) M1 (dep M1) for “3” × 17 or “3” × 9 A1 51 and 27 correctly assigned 20 3.45 ≤ x < 3.55 B2 cao (B1) for 3.45 and 3.55 21 0.23 P1 for 45 ÷ 300 (= 0.15) for 0.62 × 300 (= 186) P1 (dep P1) for 1 – (0.62 + “0.15”) (dep P1) for 300 – (“186” + 45) A1 oe oe 22 11 P1 Process to find total cycling,, e.g. 100 – 52 – 35 (= 13) P1 Complete process to find female running, e.g. 45 – (30 + (“13” −9)) A1 cao OR P1 process to find male Gym (22) or male total (55) P1 complete process to find female running, e.g. 35 – (“55” – “22” – 9) A1 cao Note: the two-way table (or frequency tree) does not need to be fully complete
gcse_1ma1_mark_scheme_2f__mock_set_2_.docx