A1 for = 60° from correct working CAD C2 C2 for all correct reasons stated (C1) (C1 for one appropriate reason linked to a circle theorem used) Alternate segment theorem. Opposite angles of a cyclic quadrilateral add up to 180. Angles in a triangle add up to 180 Angles on a straight line add up to 180 21 M1 gf(x) = or f(4) = 48 A1 oe 22 = + 8 P1 process to expand (a + given at least 3 terms correct c a2 √8)2 = 4a d A1 = + 8 c a2 A1 = 4a d
A1 for CAD = 60° from correct working C2 C2 for all correct reasons stated (C1) (C1 for one appropriate reason linked to a circle theorem used) Alternate segment theorem. Opposite angles of a cyclic quadrilateral add up to 180. Angles in a triangle add up to 180 Angles on a straight line add up to 180 21 M1 gf(x) = or f(4) = 48 A1 oe 22 c = a2 + 8 d = 4a P1 process to expand (a + √8)2 given at least 3 terms correct A1 c = a2 + 8 A1 d = 4a
gcse_1ma1_mark_scheme_2h__mock_set_2_.docx