Set 2: r20 = r40 = 1 = r20 r0 = 2 = r20 r0 = r0 = – – o, o, o, o, o Set 3: ………… Calculations: Calculate the average value of and 1 2. From Eq. 8 with ignored, since n is constant, the thickness of the glass plate can be derived and the resultant equation is given below. ----- Eq. 12 o (Cos1 ) N1N2 t 2 (1 ) (1 )Cos2 N1Cos1 N2 where = 632.8 nm, N1 = 20, = 40, = the angle from the 0o position to make 20 o 1 fringe transitions and = the angle from the 0o position to make 40 fringe transitions. 2 (Cognitive Analysing, Level 4) – [5 marks] Determine the thickness of the glass plate with Eq. 12. Compare with the theoretical value. (Cognitive Evaluating, Level 5) – [5 marks] Determine the refractive index of the glass plate with Eq. 11 (ignore term). Compare with the theoretical value. (Cognitive Evaluating, Level 5) – [5 marks]
Set 2: r0 = o, r20 = o, r40 = o, 1 = r20 – r0 = o, 2 = r20 – r0 = o Set 3: ………… Calculations: Calculate the average value of 1 and 2. From Eq. 8 with ignored, since n is constant, the thickness of the glass plate can be derived and the resultant equation is given below. t o N1N2 (Cos1 ) ----- Eq. 12 2 N1Cos1 (1 ) (1 )Cos2 where o = 632.8 nm, N1 = 20, N2 = 40, 1 = the angle from the 0o position to make 20 fringe transitions and 2 = the angle from the 0o position to make 40 fringe transitions. (Cognitive – Analysing, Level 4) [5 marks] Determine the thickness of the glass plate with Eq. 12. Compare with the theoretical value. (Cognitive – Evaluating, Level 5) [5 marks] Determine the refractive index of the glass plate with Eq. 11 (ignore term). Compare with the theoretical value. (Cognitive – Evaluating, Level 5) [5 marks]
EOP3056_Exp_OM1.docx