3. Solve this linear system by substitution. = x – y –2 = y x – Solutions Method 1 = x y – –2 = y x – Write an equivalent system with integer coefficients. For equation : = Multiply each term by 10. x y – –2 Simplify. 5x 8y = – –20 For equation : = Multiply each term by 8. y x – Simplify. 8y = 2x 3 – Substitute for 8y in equation . 5x 8y = – –20 5x (2x 3) Solve for = x. – – –20 5x 2x + 3 = 20 – – 3x = –23 = x (Solution continues.)
3. Solve this linear system by substitution. x – y = –2 y = x – Solutions Method 1 x – y = –2 y = x – Write an equivalent system with integer coefficients. For equation : x – y = –2 Multiply each term by 10. Simplify. 5x – 8y = –20 For equation : y = x – Multiply each term by 8. Simplify. 8y = 2x – 3 Substitute for 8y in equation . 5x – 8y = –20 5x – (2x – 3) = –20 Solve for x. 5x – 2x + 3 = – 20 3x = –23 x = (Solution continues.)
miap_ch_7_notes_answer_key.docx