Let’s say a coffee shop has some coffee that contains 90% of a really expensive bean. They also carry a mixture that contains only 20% of that same really expensive bean. You want something in between. You want a 50% blend and you want 5 pounds of it. Here’s what you do: Let x = the amount (lbs) of the 90% blend needed for the new mixture. Then 5-x = the amount (lbs) of the 20% blend needed for the new mixture. So, you would need 2.14 lb of the 90% strength and 2.186 lb of the 20% strength. Solid Dilutions As we did in liquid dilutions you can use the formula “quantity/concentration” (Q1) (C1) = (Q2) (C2). Practice Problem 6.1 #2 A solution of 1:400 concentration 250 mL is diluted to 10000 mL. What is the new ratio strength? First change the ratio to a percent (actually, we will use a decimal), then use the Q/C formula.
Let’s say a coffee shop has some coffee that contains 90% of a really expensive bean. They also carry a mixture that contains only 20% of that same really expensive bean. You want something in between. You want a 50% blend and you want 5 pounds of it. Here’s what you do: Let x = the amount (lbs) of the 90% blend needed for the new mixture. Then 5-x = the amount (lbs) of the 20% blend needed for the new mixture. So, you would need 2.14 lb of the 90% strength and 2.186 lb of the 20% strength. Solid Dilutions As we did in liquid dilutions you can use the “quantity/concentration” formula (Q1) (C1) = (Q2) (C2). Practice Problem 6.1 #2 A solution of 1:400 concentration 250 mL is diluted to 10000 mL. What is the new ratio strength? First change the ratio to a percent (actually, we will use a decimal), then use the Q/C formula.
MTH64Ch6Dilutions_0.docx