Short division of TU ÷ U For 81 ÷ 3, the dividend of 81 is into 60, the highest multiple of 3 that is also a multiple 10 and less than 81, to give 60 + 21. Each number is then divided by 3. 81 ÷ 3 60 (3x20) 21 (3x7) ans=27 This is then shortened to: The carry digit represents the 2 tens that have been exchanged for 20 ones. In the first ‘2’ recording above it is written in front of the 1 to show that 21 is to be divided by 3. In second it is written as a superscript. The 27 written the line represents the answer: 20 + 7, or 2 tens and 7 ones. To find 196 ÷ 6, start by multiplying 6 by 10, 20, 30, to find that 6 × 30 = 180 and … 6 × 40 = 240. The multiples of 180 and 240 trap the number 196. This tells us that the answer to 196 ÷ 6 is between 30 and 40. Start the division by first subtracting 180, leaving 16, and then subtracting the largest possible multiple of 6, which is 12, leaving 4. The quotient 32 (with a remainder of 4) lies between 30 and 40, as predicted.
Short division of TU ÷ U For 81 ÷ 3, the dividend of 81 is into 60, the highest multiple of 3 that is also a multiple 10 and less than 81, to give 60 + 21. Each number is then divided by 3. 81 ÷ 3 60 (3x20) 21 (3x7) ans=27 This is then shortened to: The carry digit ‘2’ represents the 2 tens that have been exchanged for 20 ones. In the first recording above it is written in front of the 1 to show that 21 is to be divided by 3. In second it is written as a superscript. The 27 written the line represents the answer: 20 + 7, or 2 tens and 7 ones. To find 196 ÷ 6, start by multiplying 6 by 10, 20, 30, … to find that 6 × 30 = 180 and 6 × 40 = 240. The multiples of 180 and 240 trap the number 196. This tells us that the answer to 196 ÷ 6 is between 30 and 40. Start the division by first subtracting 180, leaving 16, and then subtracting the largest possible multiple of 6, which is 12, leaving 4. The quotient 32 (with a remainder of 4) lies between 30 and 40, as predicted.
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