If you drew this correctly, you should have three forces acting on the car, with the forces in the y direction canceling out. b) Find the Fg acting on the car. If you completed this correctly, you should get -14700 N. If you had trouble with this, go back and look at the weight section of your notes. c) Find the normal force. This one is easy. Look at your free body diagram. The car isn’t moving up, so your Fnet, y = 0N. You should get +14700 N. d) Find the force of friction acting on the car. If you did this correctly, you should get -11760 N. Did you get these answers? If so, good for you! So far, we’ve looked at forces that only act up and down or left and right. Now, we’re going to look at some more interesting forces. Let’s practice finding forces that don’t act completely vertically or horizontally. Find the net force acting on the object below. Here we have two forces acting on the box. On is pulling the object straight to the left (10 N). There is no vertical component to this vector- it is pulling the block entirely horizontally. The force (30 N) is pulling the block up and to the right- this means it has a vertical component (it is pulling the block up) and a horizontal component (it is pulling the block to the right. How could we add these guys together? I’ll walk you through it. are long, and they can be arduous, but once you get the hang of them they aren’t that bad. Plus, if anyone sees the work you’re doing, you will look like a genius. Divide your in half and we’ll go through piece by piece. First, let’s deal with the 30 N, because it is pulling What you do: at a strange angle. Break this vector down into its For the horizontal component: components. For the vertical component: Now, that we know the components, draw them on You should do this: a coordinate plane. Notice now, I don’t keep writing the 30 N. I’ve already broken it down into its components. I
If you drew this correctly, you should have three forces acting on the car, with the forces in the y direction canceling out. b) Find the Fg acting on the car. If you completed this correctly, you should get -14700 N. If you had trouble with this, go back and look at the weight section of your notes. c) Find the normal force. This one is easy. Look at your free body diagram. The car isn’t moving up, so your Fnet, y = 0N. You should get +14700 N. d) Find the force of friction acting on the car. If you did this correctly, you should get -11760 N. Did you get these answers? If so, good for you! So far, we’ve looked at forces that only act up and down or left and right. Now, we’re going to look at some more interesting forces. Let’s practice finding forces that don’t act completely vertically or horizontally. Find the net force acting on the object below. Here we have two forces acting on the box. On is pulling the object straight to the left (10 N). There is no vertical component to this vector- it is pulling the block entirely horizontally. The force (30 N) is pulling the block up and to the right- this means it has a vertical component (it is pulling the block up) and a horizontal component (it is pulling the block to the right. How could we add these guys together? I’ll walk you through it. are long, and they can be arduous, but once you get the hang of them they aren’t that bad. Plus, if anyone sees the work you’re doing, you will look like a genius. Divide your in half and we’ll go through piece by piece. First, let’s deal with the 30 N, because it is pulling at a strange angle. Break this vector down into its components. What you do: For the horizontal component: For the vertical component: Now, that we know the components, draw them on a coordinate plane. You should do this: Notice now, I don’t keep writing the 30 N. I’ve already broken it down into its components. I
notes_ap_physics_2_summer_prep.docx