Since (h, lies on the curve = 4y, we have = 4k. k) x2 h2 From equation (i), we have: Hence, the equation of the normal is given as: The correct answer is A. The points on the 9y2 = where the normal to the curve makes equal intercepts with Q.24 x3, the axes are (A) (B) ( C) (D) The equation of the given curve is 9y2 = x3. Differentiating with respect to we have: x, The slope of the normal to the given curve at point is The equation of the normal to the curve at is ∴ It is given that the normal makes equal intercepts with the axes. Therefore, We have: Also, the pointlies on the curve, so we have From (i) and (ii), we have:
Since (h, k) lies on the curve x2 = 4y, we have h2 = 4k. From equation (i), we have: Hence, the equation of the normal is given as: The correct answer is A. Q.24 The points on the 9y2 = x3, where the normal to the curve makes equal intercepts with the axes are (A) (B) ( C) (D) The equation of the given curve is 9y2 = x3. Differentiating with respect to x, we have: The slope of the normal to the given curve at point is ∴ The equation of the normal to the curve at is It is given that the normal makes equal intercepts with the axes. Therefore, We have: Also, the pointlies on the curve, so we have From (i) and (ii), we have:
misc_application-diff.docx