CHAPTER 4 GRADIENT, DIVERGENCE CURL AND Example 4.3  2xz  4 (2,-2,3) Find the unit normal to the surface x y at the point 2  2xy 2ziˆ 2xkˆ     x ˆj 2 4 4kˆ    at ˆj Unit normal to the surface   iˆ   kˆ ˆj 13 23 23  If and are differentiable scalars, then we have;  1.)       2.)    Example 4.4   (2,1,3). If    , evaluate at the point x yz xz and xy z z 2 2 2 3        y  k 2xyzˆ    zˆ 2 2 2 2 2   303ˆ 12 25k 2121ˆ 12 16k ˆ ˆ  3  Example 4.5 Find r 3 2 2 2 3 2 2 3 1 3 3 3 2 2 1 1 1 2 2 2 2 1 2
CHAPTER 4 GRADIENT, DIVERGENCE AND CURL Example 4.3 Find the unit normal to the surface x 2 y  2xz  4 at the point (2,-2,3)   2xy  2ziˆ  x 2 ˆj  2xkˆ   4 ˆj  4kˆ at Unit normal to the surface   13 iˆ  23 ˆj  23 kˆ If  and are differentiable scalars, then we have; 1.) 2.)           Example 4.4 If   x 2 yz  xz 2 and  xy 2 z z 3 , evaluate  at the point (2,1,3).        y 2 zˆ  2xyzˆ   k  2 2 2 2  303ˆ 12 ˆ 25k 2121ˆ 12 ˆ 16k   3  Example 4.5 Find r 3 1 3 3 2 2 2 2 2 3 3 3 2 2 1 1 1 2 2 2 2 1 2