(1 Point) (2 Points) (3 Points) (4 Points) 1 The student has The student calculates The student calculates The student correctly neither the correct the volume incorrectly the volume for one calculates the volume 5.MD.3 volume nor the correct for both figures but figure correctly and and uses the correct 5.MD.4 unit of measure for uses the correct unit of uses the correct unit of unit of measure for either figure. measure. measure for both. both: a. 12 in3 b. 8 in3 2 The student is unable The student makes an The student explains The student correctly to explain the attempt to explain the the equivalence explains the equivalence of the two equivalence of the two between the two equivalence between 5.MD.5a approaches and is approaches but uses approaches by the two approaches by 5.MD.5b unable to find the faulty logic and is explaining that the explaining the sides volume of the prism in unable to find the sides may be multiplied may be multiplied in Part (b) using Jack’s volume of the prism in in any order because any order because any method. Part (b) using Jack’s any face can be used as face can be used as the method. the base of the figure base of the figure. The but is unable to use student also uses Jack’s Jack’s method to method to correctly calculate the volume of calculate the area of the prism in Part (b). the prism in Part (b) as The student may not (3 × 2) × 5 = 30 ft3. score more than 3 points if the student does not label Part (b) as cubic feet (ft3). A Progression Toward Mastery 3 The student is neither The student uses a The student uses a The student correctly able to calculate the correct method for correct method for answers 1,440 cm3 and volume of the figure finding the volume of finding the volume of is able to explain the 5.MD.5a nor explain the the cube but does not the cube and is able to reasoning used. reasoning used. consider the size of the explain the reasoning cubes (2 cm side used but does not lengths) and does not consider the size of the
(1 Point) (2 Points) (3 Points) (4 Points) 1 5.MD.3 5.MD.4 The student has neither the correct volume nor the correct unit of measure for either figure. The student calculates the volume incorrectly for both figures but uses the correct unit of measure. The student calculates the volume for one figure correctly and uses the correct unit of measure for both. The student correctly calculates the volume and uses the correct unit of measure for both: a. 12 in3 b. 8 in3 2 5.MD.5a 5.MD.5b The student is unable to explain the equivalence of the two approaches and is unable to find the volume of the prism in Part (b) using Jack’s method. The student makes an attempt to explain the equivalence of the two approaches but uses faulty logic and is unable to find the volume of the prism in Part (b) using Jack’s method. The student explains the equivalence between the two approaches by explaining that the sides may be multiplied in any order because any face can be used as the base of the figure but is unable to use Jack’s method to calculate the volume of the prism in Part (b). The student may not score more than 3 points if the student does not label Part (b) as cubic feet (ft3). The student correctly explains the equivalence between the two approaches by explaining the sides may be multiplied in any order because any face can be used as the base of the figure. The student also uses Jack’s method to correctly calculate the area of the prism in Part (b) as (3 × 2) × 5 = 30 ft3. A Progression Toward Mastery 3 5.MD.5a The student is neither able to calculate the volume of the figure nor explain the reasoning used. The student uses a correct method for finding the volume of the cube but does not consider the size of the cubes (2 cm side lengths) and does not The student uses a correct method for finding the volume of the cube and is able to explain the reasoning used but does not consider the size of the The student correctly answers 1,440 cm3 and is able to explain the reasoning used.