θ = -1 Tan θ = 135o Section Two: Calculator-assumed (25 marks) Question 7 (4 marks) Task Solution Marks (S/C) (a) 4860 (b) Behaviours: (a) Selects the correct coefficient from the expanded expression on a calculator 1 S (b) Recognises combinations as coefficients of expansion 1 S Allows for power of the coefficients in original expression 1 C Question 8 (5 marks) Task Solution Behaviours Marks (S/C) Uses combination notation and calculates 1 S (a) number of combinations Identifies number of ways for girls 1 S (b) Multiplies this by number of ways for boys 1 S Selects number of ways these two girls can be 1 C chosen (c) Divides by the number of ways that eight girls 1 C can be chosen Question 9 (7 marks) Task Solution Behaviours Marks (S/C) 0.9 x 0.7 = 0.63 so 63% Uses the multiplication principle 1 S (a) 1 – (0.1 x 0.4) = 0.96 so 96% Identifies those failing both tests 1 S (b) Uses the fact that probability sums to 1 1 S
Tan θ = -1 θ = 135o Section Two: Calculator-assumed (25 marks) Question 7 (4 marks) Solution Marks Task (S/C) (a) 4860 (b) (a) (b) Behaviours: Selects the correct coefficient from the expanded expression on a calculator Recognises combinations as coefficients of expansion Allows for power of the coefficients in original expression 1 1 1 S S C Question 8 (5 marks) Solution Behaviours Marks Task (S/C) (a) Uses combination notation and calculates number of combinations 1 S (b) Identifies number of ways for girls Multiplies this by number of ways for boys 1 1 S S (c) Selects number of ways these two girls can be chosen Divides by the number of ways that eight girls can be chosen 1 1 C C Question 9 (7 marks) Solution Behaviours Marks Task (S/C) (a) 0.9 x 0.7 = 0.63 so 63% Uses the multiplication principle 1 S (b) 1 – (0.1 x 0.4) = 0.96 so 96% Identifies those failing both tests Uses the fact that probability sums to 1 1 1 S S