QUESTION 1 Ques Solution Explanation 1.1.1 2A answer 0 (a) (2) (b) 0 0 0 1 3 3 8 24 25 34 137 1M order Median (Q2) = 3 1A answer (2) 1M addition (c) mean = 1M dividing by 10 = = 21,45 1CA answer (3) 1A answer (3) 1.1.2 Mean 2J reason It is more representative of smaller and bigger numbers/ it gives a better reflection of the seriousness of the situation. 1.1.3 % decrease between 2011 and 2012: 2 % decrease (3) 1 conclusion The newspaper report is incorrect 1.2.1 Range = max value min value 1M method – (a) = 252 0 – = 252 1A answer (2) (b) 0 4 6 6 9 11 21 31 34 75 252 1A order (4) Q1 = 6 1A Q1 Q2 = 11 1A Q2 Q3 = 34 1A Q3 1M method (c) Interquartile range (IQR) = Q3 Q1 – 1CA values = 34 6 – 1CA answer = 28 (3) 1.2.2 The difference between the and the IQR is very big 2A any suitable answer ( 218 = 252 28). (2) – This is the result of an extreme outlier (252). [24]
QUESTION 1 Ques Solution Explanation 1.1.1 (a) 0 2A answer (2) (b) 0 0 0 1 3 3 8 24 25 34 137 Median (Q2) = 3 1M order 1A answer (2) (c) mean = = = 21,45 1M addition 1M dividing by 10 1CA answer (3) 1.1.2 Mean It is more representative of smaller and bigger numbers/ it gives a better reflection of the seriousness of the situation. 1A answer 2J reason (3) 1.1.3 % decrease between 2011 and 2012: The newspaper report is incorrect 2 % decrease 1 conclusion (3) 1.2.1 (a) Range = max value – min value = 252 – 0 = 252 1M method 1A answer (2) (b) 0 4 6 6 9 11 21 31 34 75 252 Q1 = 6 Q2 = 11 Q3 = 34 1A order 1A Q1 1A Q2 1A Q3 (4) (c) Interquartile range (IQR) = Q3 – Q1 = 34 – 6 = 28 1M method 1CA values 1CA answer (3) 1.2.2 The difference between the and the IQR is very big ( 218 = 252 – 28). This is the result of an extreme outlier (252). 2A any suitable answer (2) [24]