E 0 mole 0.0100 mole Total Volume = 200 mL = 0.200 L Molarity = 0.0100 mole = 0.0500 M 0.200 L 11. A empty beaker has a mass of 29.86 g. The same beaker is filled with 0.250 L with a solution of CaCl2 and weighs 87.26 g. The solution is evaporated to dryness and the mass of the beaker and solid is 62.31 g. Calculate the molarity of the solution. Mass of CaCl2 = 62.31 29.86 = 32.45g – Molarity = 32.45g x 1 mole 111.1g = 1.17 M .250 L 12. Complete the reaction equations. i) Formula Equation/Chemical Equation 2AgNO3 + Na2SO4 Ag2SO4(s) + 2NaNO3(aq) (aq) (aq) → ii) Total Ionic Equation 2Ag+(aq) + 2NO3- + 2Na+(aq) + SO42- Ag2SO4(s) + 2Na+(aq) + 2NO3-(aq) → iii) Net Ionic Equation 2Ag+(aq) + SO42- Ag2SO4(s) → 13. Complete the formula equation: 2H3PO4(aq) + 3Sr(OH)2(aq) Sr3(PO4)2(s) + 6HOH(l) → Complete the complete ionic equation: 6H+(aq) + 2PO43- + 3Sr2+(aq) + 6OH- Sr3(PO4)2(s) + 6HOH(l) →
E 0 mole 0.0100 mole Total Volume = 200 mL = 0.200 L Molarity = 0.0100 mole = 0.0500 M 0.200 L 11. A empty beaker has a mass of 29.86 g. The same beaker is filled with 0.250 L with a solution of CaCl2 and weighs 87.26 g. The solution is evaporated to dryness and the mass of the beaker and solid is 62.31 g. Calculate the molarity of the solution. Mass of CaCl2 = 62.31 – 29.86 = 32.45g Molarity = 32.45g x 1 mole 111.1g = 1.17 M .250 L 12. Complete the reaction equations. i) Formula Equation/Chemical Equation 2AgNO3 (aq) + Na2SO4 (aq) → Ag2SO4(s) + 2NaNO3(aq) ii) Total Ionic Equation 2Ag+(aq) + 2NO3- + 2Na+(aq) + SO42- → Ag2SO4(s) + 2Na+(aq) + 2NO3-(aq) iii) Net Ionic Equation 2Ag+(aq) + SO42- → Ag2SO4(s) 13. Complete the formula equation: 2H3PO4(aq) + 3Sr(OH)2(aq) → Sr3(PO4)2(s) + 6HOH(l) Complete the complete ionic equation: 6H+(aq) + 2PO43- + 3Sr2+(aq) + 6OH- → Sr3(PO4)2(s) + 6HOH(l)