Review Inference on Means WS Answers 1) H0: = 5 t = 2 = .01   Ha: > 5 p-value = .0267 fail to reject  2) (4.15, 4.79) Yes, since the interval does not contain 4.8 & is below 4.8. 3) H0: = 54 t = 1.786 = .05   Ha: > 54 p-value = .0433 reject  4) (2.31, 2.69) 5) (2.46, 4.95) 6) H0: = 6.9 z = 1.077 = .05   Ha: > 6.9 p-value = .1408 fail to reject  7) H0: = 3.12 t = .518 = .1   Ha: > 3.12 = .3031 fail to reject  σ 8) a) Assumptions: SRS was used, Given that it is a normal distribution, unknown. H0: = 1.73  Ha: > 1.73  t-value: = .80 (right tail test) p-value: tcdf(.80, 1E99, 24) = .216
Review Inference on Means WS Answers 1) H0:  = 5 t = 2  = .01 Ha:  > 5 p-value = .0267 fail to reject 2) (4.15, 4.79) Yes, since the interval does not contain 4.8 & is below 4.8. 3) H0:  = 54 t = 1.786  = .05 Ha:  > 54 p-value = .0433 reject 4) (2.31, 2.69) 5) (2.46, 4.95) 6) H0:  = 6.9 z = 1.077  = .05 Ha:  > 6.9 p-value = .1408 fail to reject 7) H0:  = 3.12 t = .518  = .1 Ha:  > 3.12 = .3031 fail to reject 8) a) Assumptions: SRS was used, Given that it is a normal distribution, σ unknown. H0:  = 1.73 Ha:  > 1.73 t-value: = .80 (right tail test) p-value: tcdf(.80, 1E99, 24) = .216