2 2 p1  2 1   Z1 2  g 1 p2 2   Z H w 2 2 L  g w 9  0  p2 16  2.15 2.65 19.62    1  w 19.62 19.577m p2  of  water column w i.e. p1< p2 Case-2: When flow the is Upward: Applying Bernoulli’s Equation between and assuming section-2 as datum ‘1’ ‘2’ 2 2 p1   p2  1 1 Z1  H  Z 2  2    g 2 w w L g 2 2 9 1 2.65 0   p2  16 2.15  19.62 19.62    w 24.877 p2  m of  water column w Q.5. Figure shows nozzle at the end of a pipe line discharging oil from a tank to atmosphere. Estimate the discharge from the nozzle when the head in the tank is ‘H’ 4m. The loss in the pipe can be taken as 20 V2/2g, where is the velocity in the ‘V’ pipe. The loss of energy in the nozzle can be assumed to be zero. Also, determine the pressure at the base of the nozzle. (July 2013,2014 july 2015) Fig.Q5.(a) Ans: Let be the velocity in 100mm diameter pipe and be the velocity of flow at ‘V’ ‘VN’ the exit of the nozzle (25mm dia.) The relationship between the V and VN can be derived from the continuity equation
p1 Z1  w 2  1 2  g 2  Z 2 p2  w 2  1 2  g 2 H L 16  2.15  9 19.62  0  p2  w  1 19.62  2.65 p2  19.577m of  w water column Case-2: When flow the is Upward: i.e. p1< p2 Applying Bernoulli’s Equation between ‘1’ and ‘2’ assuming section-2 as datum Z1  p1   w 2 1 2  g 2 H L  Z 2  p2   w 2 1 2  g 2 16  2.15  9 19.62  2.65  0  p2   w 1 19.62 p2  24.877 m of  w water column Q.5. Figure shows nozzle at the end of a pipe line discharging oil from a tank to atmosphere. Estimate the discharge from the nozzle when the head ‘H’ in the tank is 4m. The loss in the pipe can be taken as 20 V2/2g, where ‘V’ is the velocity in the pipe. The loss of energy in the nozzle can be assumed to be zero. Also, determine the pressure at the base of the nozzle. (July 2013,2014 july 2015) Fig.Q5.(a) Ans: Let ‘V’ be the velocity in 100mm diameter pipe and ‘VN’ be the velocity of flow at the exit of the nozzle (25mm dia.) The relationship between the V and VN can be derived from the continuity equation