  a    CC c   a  But V CV Value of Cc will be generally more than 0.62 Torricelli’s equation: (H ) hL   HxCV (1 )  hL H CV Equation for Coefficient of Velocity (CV) (Trajectory method) Consider a point P on the centre line of the jet, such that its horizontal and vertical coordinates are x and y respectively. By definition, velocity Jet y x  V x t x t a Va Since, the jet falls through a vertical distance y under the action of gravity during this time (t) gt2  y  1 y  2   t    (2) 2   g But, 1 2   x y 2  Va CV      2gH   CV x 1 g CV  2 1 1 x 1 1 1 22 22 g H y 2 2 2
 a  CC   c   a  But V  CV Value of Cc will be generally more than 0.62 Torricelli’s equation: hL  (H  HxCV ) hL  H (1 CV ) Equation for Coefficient of Velocity (CV) (Trajectory method) Consider a point P on the centre line of the jet, such that its horizontal and vertical coordinates are x and y respectively. By definition, velocity Jet y V  x a t x t x Va Since, the jet falls through a vertical distance y under the action of gravity during this time (t) gt2 1  y  y  t   2    (2) But, 2  g  1 x  2 y  2 Va  CV      CV 2gH   x CV  1 1 1 g 2 1 x 1 1 22 g 2 H 2 22 y 2