Question Answer Guidance Marks Spec ref. / AO number 01.1 electrons 1 AO1 P2.5.1 negative 1 01.2 Diode 1 AO1 P2.1.1 measures current 1 1 01.3 To avoid misinterpretation 1 AO3 WS 3.5 02.1 To keep temperature constant 1 AO2 WS 2.3 02.2 Wire material/cross-section 1 AO3 WS 2.3 02.3 Low voltage power 1 AO3 WS 1.5 02.4 Any three from: 3 AO2 WS 2.2 Connect and turn on power. Take readings on ammeter and voltmeter. Repeat for different lengths Resistance or draw graph.  5. Repeat readings. 02.5 potential difference = current × Accept 1 AO1 V = I R resistance P2.1.3 02.6 0.25 72 Accept 18 V with no 1 AO2 working shown for 2 18 (V) 1 P2.1.3 marks. 03.1 Correct order 1 AO1 P2.2 A1 A2  1 V1 V2  03.2 Less than 1 AO1 P2.2 03.3 Thermistor Accept temperature 1 AO2 P2.1.4 dependant resistor 03.4 30–50 1 AO2 WS 3.2 Ω 03.5 As the temperature goes up the 1 AO3 P2.1.4 resistance goes down. 1 WS 3.5 They are not directly proportional. 04.1 charge flow = current × time Accept 1 AO1 Q = I T P2.1.2 04.2 4 30 1 1×AO1 = 120 1 2×AO2 C OR coulombs 1 P2.1.2 WS 3.3
Question number Answer Guidance Marks Spec ref. / AO 01.1 electrons negative 1 1 AO1 P2.5.1 01.2 Diode measures current 1 1 1 AO1 P2.1.1 01.3 To avoid misinterpretation 1 AO3 WS 3.5 02.1 To keep temperature constant 1 AO2 WS 2.3 02.2 Wire material/cross-section 1 AO3 WS 2.3 02.3 Low voltage power 1 AO3 WS 1.5 02.4 Any three from: Connect and turn on power. Take readings on ammeter and voltmeter. Repeat for different lengths Resistance  or draw graph. 5. Repeat readings. 3 AO2 WS 2.2 02.5 potential difference = current × resistance Accept V = I R 1 AO1 P2.1.3 02.6 0.25 72 18 (V) Accept 18 V with no working shown for 2 marks. 1 1 AO2 P2.1.3 03.1 A1  A2 V1  V2 Correct order 1 1 AO1 P2.2 03.2 Less than 1 AO1 P2.2 03.3 Thermistor Accept temperature dependant resistor 1 AO2 P2.1.4 03.4 30–50 Ω 1 AO2 WS 3.2 03.5 As the temperature goes up the resistance goes down. They are not directly proportional. 1 1 AO3 P2.1.4 WS 3.5 04.1 charge flow = current × time Accept Q = I T 1 AO1 P2.1.2 04.2 4 30 = 120 C OR coulombs 1 1 1 1×AO1 2×AO2 P2.1.2 WS 3.3