Triangle ADG is congruent to AEG (AG common to both) SSS triangles to prove that So angle EAG = DAG triangles are similar or Therefore AG is the angle bisector of CAB congruent CLASSWORK Prove that CD bisects AB at M Arcs lie on the circumference of circles of equal radii. AC = AD = BC = BD (radii of the same circle). Triangles ACD and BCD are congruent with CD common to both (SSS). So Angle ACD = BCD Triangles CAM and CBM are congruent (SAS) Therefore AM = BM
Triangle ADG is congruent to AEG (AG common to both) SSS So angle EAG = DAG Therefore AG is the angle bisector of CAB triangles to prove that triangles are similar or congruent CLASSWORK Prove that CD bisects AB at M Arcs lie on the circumference of circles of equal radii. AC = AD = BC = BD (radii of the same circle). Triangles ACD and BCD are congruent with CD common to both (SSS). So Angle ACD = BCD Triangles CAM and CBM are congruent (SAS) Therefore AM = BM