16 1.08 and 5 B1 finds a bound of 6.425 or 6.435 or 6.434999... a: explanation or a bound of 5.5135 or 5.5145 or 5.5144999.. b: P1 uses UB and LB in equation P1 process of choosing correct bounds, e.g. or A1 for 1.079... and 1.080... both values must clearly come from correct working C1 for 1.08 from 1.079... and 1.080... and LB and UB to “both 1.08” 17 5x 3 P1 starts process by substituting to find volume of cylinder and volume of sphere e.g. × (3x)2 × and × (x)3 h π π P1 for forming a correct equation A1 cao
16 1.08 and explanation 5 B1 finds a bound of a: 6.425 or 6.435 or 6.434999... or a bound of b: 5.5135 or 5.5145 or 5.5144999.. P1 uses UB and LB in equation P1 process of choosing correct bounds, e.g. or A1 for 1.079... and 1.080... both values must clearly come from correct working C1 for 1.08 from 1.079... and 1.080... and “both LB and UB to 1.08” 17 5x 3 P1 starts process by substituting to find volume of cylinder and volume of sphere e.g. π × (3x)2 × h and π × (x)3 P1 for forming a correct equation A1 cao