{−2, set: 2} . ( ) x = a. = 0 f x = = − + 4 = p x x2 0 − 3 x 4 − = 0 x2 x (2 ) (2 ) − + = 0 x x + 2 x {x The solution set is − 2 < < 3} or, using x (−2, interval notation, 3) .
a. f ( x ) = 0 − x2 + 4 = 0 4 − x2 = 0 (2 − x ) (2 + x ) = 0 x = x = set: {−2, 2} . p x = x − 3 x + 2 The solution set is {x − 2 < x < 3} or, using interval notation, (−2, 3) .