2(2) − −1 (2 2 )2 4(2) ) = 0 x 54. = −2 ± + = −2 ± + − = 2 8 8 2 16 6 7 20 0 x2 x 4 4 (3x f (2 − 4) + 5) = 0 x − = + = 3x ( 4 0 or 2 5 x = −2 ± = − ± 2 4 2 2 0 4 2 − 2 − 2 are ( ) = 4 − x The zeros of = 2x 1 G x x2 2 2 = − 5 x + 3 2 and . The of the graph of − 2 + 2 x-intercepts G 2 The of 2 ( ) = 6 + 7 − 20 are f x x2 x are and − − 2 2 and . 4 . − 2 + 2 3 − 5 The of the graph of are x-intercepts f − 5 2 and . 4 2 2 3
(2 2 )2 − 4(2) −1 2(2) 54. f ( x ) = 0 6 x2 + 7 x − 20 = 0 (3x − 4) (2 x + 5) = 0 3x − 4 = 0 or 2 x + 5 = 0 = −2 2 ± 8 + 8 = −2 2 ± 16 4 4 = −2 2 ± 4 = − 2 ± 2 4 2 x = 4 x = − 5 The zeros of G ( x ) = x2 + 2x − 1 2 are − 2 − 2 2 3 2 and − 2 + 2 . The x-intercepts of the graph of G The of f ( x ) = 6 x2 + 7 x − 20 are − 5 2 and 4 . 3 are 2 − 2 − 2 and − 2 + 2 . The x-intercepts of the graph of f are − 5 2 and 4 . 2 2 3