= − = θ = ⎛ ⎞ + = + = 1 25 144 sec2 1 1 1 1 10 ⎜ 13 ⎟ 169 169 ⎜ ⎟ 3 9 9 ⎝ ⎠ secθ =± 10 = ± 10 cosθ =± 144 = ± 12 9 3 169 13 θ Note that secθ must be negative since lies in θ Note that cosθ must be positive because lies 10 =− quadrant III. Thus, secθ . in quadrant IV. Thus, cosθ = 12 . 3 13 ⎝ ⎠ θ sin 13 ⎞ 5 5 ⎛ − 5 θ tan = = 13 ⎜ ⎟ = − = − cosθ = 1 = 1 = − 3 ⋅ 10 = − 3 10 cosθ 10 10 10 10 12 secθ − ⎝ ⎠ 13 12 12 = = = − cscθ 1 1 13 3 θ sin 5 θ θ tan = sin , so 13 secθ = 1 = 1 = 13 cosθ cosθ 12 1 ⎛ 3 10 ⎞ 10 ⎜ − ⎟ = − ( ) (cosθ ) θ θ sin = tan = θ cot = 1 = 1 = − 12 3 ⎝ 10 ⎠ 10 θ tan 1 = 1 =− 10 =− 10 5 cscθ = 12 10 θ sin − 10 10 θ cot = 1 = 1 = 3 θ tan 1
= 1 − 25 = 144 sec2 θ = ⎛ 1 ⎞ + 1 = 1 + 1 = 10 ⎜ 13 ⎟ 169 169 ⎜ 3 ⎟ 9 9 ⎝ ⎠ cosθ =± 144 = ± 12 169 13 Note that cosθ must be positive because θ lies in quadrant IV. Thus, cosθ = 12 . 13 ⎝ ⎠ secθ =± 10 = ± 10 9 3 Note that secθ must be negative since θ lies in 10 quadrant III. Thus, secθ =− . 3 sin θ − 5 5 ⎛ 13 ⎞ 5 tan θ = = 13 = − ⎜ ⎟ = − cosθ = 1 = 1 = − 3 ⋅ 10 = − 3 10 cosθ 12 13 ⎝ 12 ⎠ 12 secθ − 10 10 10 10 cscθ = 1 = 1 = − 13 3 sin θ 5 13 tan θ = sin θ , so secθ = 1 = 1 = 13 cosθ cosθ 12 sin θ = ( tan θ ) (cosθ ) = 1 ⎛ 3 10 ⎞ 10 ⎜ − ⎟ = − cot θ = 1 = 1 = − 12 3 ⎝ 10 ⎠ 10 tan θ 5 12 cscθ = 1 = 1 =− 10 =− 10 sin θ − 10 10 10 cot θ = 1 = 1 = 3 tan θ 1