Where t is thickness of plate, µe-µo or µo-µe △= △= Unit-02/Lecture-13 The distance between the slit and biprism and between biprism and screen are 50 cm each. The angle of biprism is 179°and its refractive index is 1.5. If the distance between successive fringes is 0.0135cm, calculate the wavelength of light. In a biprism experiment the distance between slit and screen is biprism is 40 cm away from the slit and its refractive index is 1.52. When a source of wavelength 5893A is used the fringe width is found to be 0.01 cm. Find the angle of prism. A parallel beam of light 5890A is incident on a thin glass plate µ=1.5 such that the λ= angle of refraction into the plate is 60°. Calculate the smallest thickness of the glass plate which will appear dark by reflection. In Newton’s rings experiment the diameter of the 10th dark ring is 0.433cm. Find the wavelength of incident light, if the radius of curvature of the lens is 70cm. A Newton’s rings arrangement is used with a source emitting two wavelengths and and it is found that nth dark ring due to coincides with λ1=6000A λ2=4500A λ1 the (n+1)th dark ring of If radius of curvature of curved surface is 90cm , find the λ2. diameter of nth dark ring for λ1. Newton’s are observed by keeping a spherical surface of 100cm radius on a plane glass plate. If the diameter of the 16th bright ring is0.590cm what is the wavelength if light used. In Newton’s experiment, the diameter of the 4th and 12th dark rings is 0.400cm and 0.700cm respectively. Find the diameter of 20th dark ring. Newton’s rings are formed in reflected light of wavelength 6000a with a liquid between the plane and curved surfaces. If the diameter of 6th bright ring is 3.1mm and radius of curvature of the curved surface is 100cm calculate the refractive index of the liquid.
Where t is thickness of plate, △= µe-µo or △= µo-µe Unit-02/Lecture-13 The distance between the slit and biprism and between biprism and screen are 50 cm each. The angle of biprism is 179°and its refractive index is 1.5. If the distance between successive fringes is 0.0135cm, calculate the wavelength of light. In a biprism experiment the distance between slit and screen is biprism is 40 cm away from the slit and its refractive index is 1.52. When a source of wavelength 5893A is used the fringe width is found to be 0.01 cm. Find the angle of prism. A parallel beam of light λ= 5890A is incident on a thin glass plate µ=1.5 such that the angle of refraction into the plate is 60°. Calculate the smallest thickness of the glass plate which will appear dark by reflection. In Newton’s rings experiment the diameter of the 10th dark ring is 0.433cm. Find the wavelength of incident light, if the radius of curvature of the lens is 70cm. A Newton’s rings arrangement is used with a source emitting two wavelengths λ1=6000A and λ2=4500A and it is found that nth dark ring due to λ1 coincides with the (n+1)th dark ring of λ2. If radius of curvature of curved surface is 90cm , find the diameter of nth dark ring for λ1. Newton’s are observed by keeping a spherical surface of 100cm radius on a plane glass plate. If the diameter of the 16th bright ring is0.590cm what is the wavelength if light used. In Newton’s experiment, the diameter of the 4th and 12th dark rings is 0.400cm and 0.700cm respectively. Find the diameter of 20th dark ring. Newton’s rings are formed in reflected light of wavelength 6000a with a liquid between the plane and curved surfaces. If the diameter of 6th bright ring is 3.1mm and radius of curvature of the curved surface is 100cm calculate the refractive index of the liquid.