model 2: X ~ Y (a) b1(model1) = b1(model2) (b) b1(model1) = 1 / b1(model2) (c) b1(model1) = - 1 / b1(model2) (d) b1(model1) = - b1(model2) (e) b1(model1) b1(model2) ≠ SLR 7b. If the null hypothesis (that β1=0) is true (and b1=0), our SSE reduces to: (a) (i - ) 2 ∑ (b) (Yi i) 2 ∑ – (c) (Yi - ) 2 ∑
model 2: X ~ Y (a) b1(model1) = b1(model2) (b) b1(model1) = 1 / b1(model2) (c) b1(model1) = - 1 / b1(model2) (d) b1(model1) = - b1(model2) (e) b1(model1) ≠ b1(model2) SLR 7b. If the null hypothesis (that β1=0) is true (and b1=0), our SSE reduces to: (a) ∑ (i - ) 2 (b) ∑ (Yi – i) 2 (c) ∑ (Yi - ) 2