A B D ….. ……………….………. C ……….……………… ………………… ….……… y=2 x=- x= 2 2 Figure 9 Solving y = x2 and y =2 we get x2 = 2 and x = and x = - and y =2. Since the 2 2 complete area required is above the x axis we get the required area. – 2  A ydx 2 2  2 2 x3 2 3 2 3 4 2 3 sq This is the area the curve and the x axis. – The shaded area = Area of the rectangle ABCD - 4 2 3 79 22 2  4 2 3 4 2 4 2  3
A B ….. ……………….………. ……….……………… ………………… ….……… D C y=2 x=- 2 x= 2 Figure 9 Solving y = x2 and y =2 we get x2 = 2 and x = 2 and x = - 2 and y =2. Since the complete area required is above the x – axis we get the required area. A  2 ydx 2  2 2 2 x3 3 2 2 3 4 2 3 sq This is the area the curve and the x – axis. The shaded area = Area of the rectangle ABCD - 79 4 2 3  22 2 4 2 3  4 2 4 2 3