PiXL Pre Public Examination, March 2017, 2F, Edexcel Style Mark Scheme Qn Working Answer Mark Notes 1 12.167 1 B1 cao 2 3:5 1 B1 cao 3 1 B1 correctly drawn sector 4 1 B1 for complete kite drawn 5 CH,CO; CH,PC; 2 B1 for 8 correct combinations CH,BB; CH,RS; B1 for all combinations TS,CO; TS, PC; TS,BB; TS,RS; CT,CO; CT,PC; CT,BB; CT,RS; CS,CO; CS,PC; CS,BB; CS,RS; 6 (a) Yes with 1 C1 for (227 3)÷7=32 – explanation (b) 1 B1 (7x3)+3 =24 which is a multiple of 3. 7 4 + 4 + 3 =11 48cm2 2 P1 for lengths of rectangle being 4 & 3cm. 4 + 3 =7 A1 cao Therefore lengths are 4 & 3 (4×3) × 4 = 48cm2 Qn Working Answer Mark Notes 8 70000 x 6.25 = 4.375km 3 P1 for starting the process eg. 70000 x 6.25 437500 437500 ÷ 100000 = 4.375km M1 for 437500cm
PiXL Pre Public Examination, March 2017, 2F, Edexcel Style Mark Scheme Qn Working Answer Mark Notes 1 12.167 1 B1 cao 2 3:5 1 B1 cao 3 1 B1 correctly drawn sector 4 1 B1 for complete kite drawn 5 CH,CO; CH,PC; CH,BB; CH,RS; TS,CO; TS, PC; TS,BB; TS,RS; CT,CO; CT,PC; CT,BB; CT,RS; CS,CO; CS,PC; CS,BB; CS,RS; 2 B1 B1 for 8 correct combinations for all combinations 6 (a) (b) Yes with explanation 1 1 C1 B1 for (227 – 3)÷7=32 (7x3)+3 =24 which is a multiple of 3. 7 4 + 4 + 3 =11 4 + 3 =7 Therefore lengths are 4 & 3 (4×3) × 4 = 48cm2 48cm2 2 P1 A1 for lengths of rectangle being 4 & 3cm. cao Qn Working Answer Mark Notes 8 70000 x 6.25 = 437500 437500 ÷ 100000 = 4.375km 4.375km 3 P1 M1 for starting the process eg. 70000 x 6.25 for 437500cm