2(−0.04) 2.12 4(−0.04)(6.1) − 55.3 or x ≈ 60. 3.2x 6 x y ≈ −2.8 = −0.8x2 + + a. The information needed is found at the vertex. The maximum horizontal distance is 55.3 feet. of vertex x-coordinate The initial height can be found at 0. c. x = 2 x = −b = −3.2 = 2.1x 6.1 y = −0.04x2 + + 2.1(0) 6.1 y = −0.04(0)2 + + = (−0.8) 2a 2 6.1 The shot was released at a height of 6.1 feet. of vertex y-coordinate 3.2(2) 6 9.2 y = −0.8(2)2 + + = The vertex is (2, 9.2). The maximum height of the ball is 9.2 feet. This occurs 2 feet from its release.
2.12 − 4(−0.04)(6.1) 2(−0.04) x ≈ 55.3 or x ≈ −2.8 60. y = −0.8x2 + 3.2x + 6 The maximum horizontal distance is 55.3 feet. c. The initial height can be found at x = 0. y = −0.04x2 + 2.1x + 6.1 a. The information needed is found at the vertex. x-coordinate of vertex x = −b = −3.2 = 2 y = −0.04(0)2 + 2.1(0) + 6.1 = 6.1 2a 2 (−0.8) The shot was released at a height of 6.1 feet. y-coordinate of vertex y = −0.8(2)2 + 3.2(2) + 6 = 9.2 The vertex is (2, 9.2). The maximum height of the ball is 9.2 feet. This occurs 2 feet from its release.