26 a Area increases by 32.25%. M1 2 M1 for use of correct multiplier showing 15% increase M New area is (a × 1.15)2 A1 A1 cao = × 1.152 a2 = 1.3225a2 Percentage increase = (1.3225 1) × 100% – b M1 M1 for use of correct multiplier showing 15% length increase and 5% width decrease Area = × 1.15 × × 0.95 a b = × 1.15 × 0.95 = 1.0925ab ab Percentage increase (1.0925 1) × 100% – Area increases by 9.25%. A1 A1 cao 4 27 a Yes, there is sufficient information. C1 2 C1 if all three ratios are shown as part of the M explanation and justification of answer = = 0.8 = = 3.4 This also means that == 4.25 So yes there is enough information. 13 items e.g. b C1 C1 for clear explanation of as many values entered as possible such that one variable remains isolated from the other two oe One variable is isolated from the other two. 9 items e.g.
26 a b New area is (a × 1.15)2 = a2 × 1.152 = 1.3225a2 Percentage increase = (1.3225 – 1) × 100% Area = a × 1.15 × b × 0.95 = ab × 1.15 × 0.95 = 1.0925ab Percentage increase (1.0925 – 1) × 100% Area increases by 32.25%. Area increases by 9.25%. M1 A1 M1 A1 2 M1 for use of correct multiplier showing 15% increase A1 cao M1 for use of correct multiplier showing 15% length increase and 5% width decrease A1 cao M 4 27 a b = = 0.8 = = 3.4 This also means that == 4.25 So yes there is enough information. 13 items e.g. One variable is isolated from the other two. 9 items e.g. Yes, there is sufficient information. C1 C1 2 C1 if all three ratios are shown as part of the explanation and justification of answer C1 for clear explanation of as many values entered as possible such that one variable remains isolated from the other two oe M