(OR) = 1 =-+ = - 1 2 1 1 ½ 19. P= , Q= ½ I.F= The solution is y(I.F) = ½ y(1+x2) = 1 y(1+x2) = tan-1x+c 1 (OR) substitute x =vy 1 Log (ev+v)= -logy+ log c 1 ½ ½ 1 1
(OR) = =-+ = - 1 1 2 1 1 19. ½ P= , Q= I.F= The solution is y(I.F) = y(1+x2) = 1 y(1+x2) = tan-1x+c (OR) substitute x =vy Log (ev+v)= -logy+ log c ½ ½ 1 1 1 ½ ½ 1 1