<s>[INST] Now, I'll try to solve the problem using math.
Suppose the number of dairy cows in the first area is x and the total number of cows in the second area is y. The sum of cows is x+y= 8,000,000. 

Also, there is a piece of information that 75% of all cows are in the second area. 
75% of x+y = y 
So (0.75)(x+y) = y
(0.75)x + (0.75)y = y
(0.75)x = y-(0.75)y
(0.75)x = (0.25)y
x = (0.25)y / (0.75)
x = (1/3) y 

I'll also use the fact that x+y = 8,000,000. Since x = (1/3)y, I'll substitute x=(1/3)y into x+y = 8,000,000. 

(1/3)y + y = 8,000,000
(1/3)y + (3/3)y = 8,000,000 
(4/3)y = 8,000,000
y = (8,000,000)(3/4) 
y = 6,000,000 

If y = 6000000, we can solve for x. 
x+y = 8,000,000 
x+6000000 = 8,000,000 
x = 8,000,000 - 6,000,000
x = 2,000,000 

That means that the total number of cows which are dairy are 2,000,000, the total number of cows are 6,000,000 and the total number of cows are 8,000,000.

Is my working correct?[/INST]