<s>[INST] In how many ways can you arrange 3 sets of numbers with 3 digits: $0-9$, $0-10$, and $0-11$
The first digit can't be 0, except for the second set which can be 0.

Let $d = 0-9$, $e = 0-10$, $f = 0-11$.

This is my attempt:
$$10\times11\times12$$

The first digit can be any of $1-9$ (10 options), the second digit can be any of $0-10$ (11 options), and the third digit can be any of $0-11$ (12 options). Is this correct?[/INST]