<s>[INST] This code is solving a classic sliding window problem.
It appears to be testing all possible subarray lengths for each starting index `i`. So, it has a time complexity of O(sum of all subarray lengths), which can be simplified to O(n^2).

However, I think we can further optimize this solution. Let's modify the code inside the while loop. Assuming the input array 'arr' contains distinct elements (meaning no repeated elements), how can we break out of the inner while loop early?[/INST]