设集合$$S=\left { x\textbar{{x}^{2}}-5x-6\textless{}0 \right },  T=\left { x\textbar\left\textbar{} x+2 \right\textbar\leqslant 3 \right }$$，则$$S\cap T=$$．
选项为:A:$$\left { x\textbar-5\leqslant x\textless{}-1 \right }$$  B:$$\left { x\textbar-5\leqslant x\textless{}5 \right }$$  C:$$\left { x\textbar-1\textless{}x\leqslant 1 \right }$$  D:$$\left { x\textbar1\leqslant x\textless{}5 \right }$$  请回答其中一个选项.