$$2003-AMC12B-11$$  Cassandra sets her watch to the correct time at noon. At the actual time of $$1:00$$ PM, she notices that her watch reads $$12:57$$ and $$36$$ seconds. Assuming that her watch loses time at a constant rate, what will be the actual time when her watch first reads $$10:00$$ PM?  卡桑德拉将手表调到中午的正确时间。 在 $$1:00$$ PM 的实际时间，她注意到她的手表显示 $$12:57$$ : $$36$$ 。 假设她的手表以恒定的速率走时，当她的手表第一次显示 $$10:00$$PM 时的实际时间是多少？
选项为:A:$$10:22$$ PM and $$24$$ seconds  B:$$10:24$$ PM  C:$$10:25$$ PM  D:$$10:27$$ PM  E:$$10:30$$ PM  请回答其中一个选项.