2017 AMC10A P13  Define a sequence recursively by $$F_0 =0$$, $$F_1=1$$, and $$F_n=$$the remainder when $$F_{n-1}+ F_{n-2}$$ is divided by $$3$$, for all $$n≥ 2$$. Thus the sequence starts $$0$$, $$1$$, $$1$$, $$2$$, $$0$$, $$2$$, $$\cdots$$ What is $$F_{2017}+F_{2018}+F_{2019}+F_{2020}+F_{2021}+F_{2022}+F_{2023}+F_{2024}$$?  用$F_0=0$$，$$F1=1$$，以及Fn=F_{n-1}+ F_{n-2}$除以$3$$时的余数来递归地定义一个数列(n≥2)。$$F_{2017}+F_{2018}+F_{2019}+F_{2020}+F_{2021}+F_{2022}+F_{2023}+F_{2024}$$?=?
选项为:A:$$6$$  B:$$7$$  C:$$8$$  D:$$9$$  E:$$10$$  请回答其中一个选项.