2002AMC12B, 22  For all integers $$n$$ greater than $$1$$, define $$a_{n}=\frac{1}{\log _{n}2002}$$.  Let $$b=a_{2}+a_{3}+a_{4}+a_{5}$$ and $$c=a_{10}+a_{11}+a_{12}+a_{13}+a_{14}$$. Then $$b-c$$ equals．  对于大于$$1$$的所有整数$$n$$，定义$$a_{n}=\frac{1}{\log _{n}2002}$$。令 $$b=a_{2}+a_{3}+a_{4}+a_{5}$$，$$c=a_{10}+a_{11}+a_{12}+a_{13} +a_{14}$$。则 $$b-c$$ 等于．
选项为:A:$$-2$$  B:$$-1$$  C:$$\frac{1}{2002}$$  D:$$\frac{1}{1001}$$  E:$$\frac{1}{2}$$  请回答其中一个选项.