2013年$$AMC10$$竞赛$$B$$第$$15$$题  A wire is cut into two pieces, one of length $$a$$ and the other of length $$b$$. The piece of length $$a$$ is bent to form an equilateral triangle, and the piece of length $$b$$ is bent to form a regular hexagon. The triangle and the hexagon have equal area. What is $$\frac ab$$?  一根电线被切成两块，一块长度为 $$a$$，另一块长度为 $$b$$。 长度$$a$$ 弯曲形成等边三角形，长度$$b$$ 弯曲形成正六边形。 三角形和六边形的面积相等。 求 $$\frac ab$$？
选项为:A:$$1$$  B:$$\frac{\sqrt{6}}{2}$$  C:$$\sqrt{3}$$  D:$$2$$  E:$$\frac{3\sqrt{2}}{2}$$  请回答其中一个选项.