Three frogs are trying to hop across the road. The first frog takes 4 times as many hops as the second. The second frog takes twice as many as the third. If the three frogs took a total of 99 hops, how many hops did it take the second frog to cross the road?
A step-by-step solution is:
18
Let x represent the number of hops it took the third frog.

The second frog:2x.

First frog:4(2x) = 8x.

Total:x + 2x + 8x = 99.

11x = 99.

x = 9.

Second frog:2(9) = 18 hops.

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So, the final answer is 18