I'll give you a question, please answer with step-by-step reasoning process.
Antonella has ten Canadian coins in her purse that are either loonies or toonies. A loonie equals $1 and a toonie equals $2. If she bought a $3 Frappuccino and still has $11, how many toonies did she initially have?

4
If Antonella spent $3 and now has $11, that means initially she had $3 + $11 = $14.

Let the number of loonies Antonella had be L and the number of toonies be T.

Initially she had in her purse a total of 1L + 2T = $14.

We also know that she had 10 coins in total or 10 = L + T.

That means initially she had T = 10 - L toonies.

Combining both equations we know that 14 = 1L + 2 * (10 - L).

If we multiply through the parentheses, we get 14 = 1L + 20 - 2L.

If we combine the variables on one side and the constants on another, we get - 6 = - 1L or L = 6.

Knowing the value of L, we can solve for T = 10 - L = 10 - 6 = 4.

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So, the final answer is 4