Let the second number be 3x, so that the first number is 6x and the third number is 2x.\nOptions:\n(A) 22\n(B) 77\n(C) 98\n(D) 27\n(E) 36
Think hard. Detailed solution:
(E)
∴ 6x + 3x + 2x = 132 ⇒ x = 12.

Second number = 3x = 3×12 = 36.

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So, the final answer is (E)