Andy is a lawyer who's working on two lawsuits. The first lawsuit has a 30% chance of paying out $5,000,000 upon a win and $0 if he loses it. The second lawsuit has a 50% chance of paying out $1,000,000 if Andy loses and a 50% chance of paying out $2,000,000 if he wins. Expressed as a percentage, how much more likely is it that Andy loses both lawsuits compared to winning both of them?
Use reasoning to answer the following question.
20
First find the probability that Andy will lose the first lawsuit: 100% - 30% = 70%.

Then multiply that probability by the probability he loses the second lawsuit: 70% * 50% = 35%.

Then multiply the probabilities of Andy winning each lawsuit to find the probability he wins them both: 30% * 50% = 15%.

Then subtract the probability Andy wins both lawsuits from the probability he loses both lawsuits to find the difference: 35% - 15% = 20%.

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The final answer: 20