There are 3 teams each with 8 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?\nOptions:\n(A) 50\n(B) 23\n(C) 192\n(D) 28\n(E) 45
Let's be accurate as possible. Think before you answer.
(C)
There are altogether three arrangements, which are we can select two members each from team A and B, each from team A and C, and each from team B and C.

For each arrangement, there are altogether 64 possibilities (8*8) since each team has 8 players.

So there are a total of 192 possibilities (64*3).

I hope this method is easier for you to understand.

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The final answer: (C)