How many digits are in the number 50^8 × 8^3 × 11?\nOptions:\n(A) 18\n(B) 20\n(C) 19\n(D) 22\n(E) 17
Stream of thoughts:
(A)
Whenever you are asked to find the number of digits, try to bring the number in multiples of 10.

This way, we can wasily calculate the umber of 0's through the powers of 10\n50^8 × 8^3 × 11 = (5^2*2)^8*2^9*11 = 5^16*2^17*11 = 2*11*10^16 = 22*10^16\nHence we would have 16 trailing 0's and the three digits from 22\nTotal digits = 2 + 16 = 18.

So, the answer is (A)