['Turn to 341° onto Acanthus Street and walk 96m.', 'Turn to 352° onto Harcourt Road and walk 157m.', 'Turn to 74° onto Ipswich Road and walk 1270m.', 'Turn to 76° onto Ipswich Road and walk 815m.', 'Turn to 77° onto Ipswich Road and walk 618m.', 'Turn to 64° onto Ipswich Road and walk 2275m.', 'Turn to 101° onto Granard Road and walk 1287m.', 'Turn to 87° onto Riawena Road and walk 2259m.', 'Turn to 98° onto Kessels Road and walk 1938m.', 'Turn to 92° onto Kessels Road and walk 716m.', 'Turn to 134° onto Macgregor Street and walk 301m.']
What is the shortest path from 101007391 to 11114552068?
Answer: Turn to 341° onto Acanthus Street and walk 96m. Turn to 352° onto Harcourt Road and walk 157m. Turn to 74° onto Ipswich Road and walk 1270m. Turn to 76° onto Ipswich Road and walk 815m. Turn to 77° onto Ipswich Road and walk 618m. Turn to 64° onto Ipswich Road and walk 2275m. Turn to 101° onto Granard Road and walk 1287m. Turn to 87° onto Riawena Road and walk 2259m. Turn to 98° onto Kessels Road and walk 1938m. Turn to 92° onto Kessels Road and walk 716m. Turn to 134° onto Macgregor Street and walk 301m.