Can you solve the BOWL RIDDLE? ft. Kurt Hugo Schneider Part 1/3

How about rotating the bowl, slowly spinning it up to rotational rate omega; in this fashion the water surface becomes parabolic, following expression g * (z - Zref) = (1/2) omega^2 * r^2. This corresponds to an apparent potential of Utotal = U gravitational + Ucentrifugal = m * [g * (z - Zref) - (1/2) * omega^2 * r^2]. The floating ball will follow Archimedes Law in this apparent potential, staying at the surface, while also dropping to the stable floating body energy minimum at the r=0 centre; this is where equipotential spacing is sparsest and vector force magnitude finds its minimum. Archimedes also says the lowest point on the floating ball is below the water level; we only need to ramp up rotational frequency until respective low point touches bottom.