public JsonObject add(String name, org.jmxtrans.agent.util.json.JsonValue value) {
    if (name == null) {
      throw new NullPointerException("name is null");
    }
    if (value == null) {
      throw new NullPointerException("value is null");
    }
    table.add(name, names.size());
    names.add(name);
    values.add(value);
    return this;
  }
public JsonObject add(String name, org.jmxtrans.agent.util.json.JsonValue value) {
    if (name == null) {
      throw new NullPointerException("name is null");
    }
    if (value == null) {
      throw new NullPointerException("value is null");
    }
    table.add(name, names.size());
    names.add(name);
    values.add(value);
    return this;
  }
public JsonObject add ( String name , org . jmxtrans . agent . util . json . JsonValue value ) { if ( name == null ) { throw new NullPointerException ( "name is null" ) ; } if ( value == null ) { throw new NullPointerException ( "value is null" ) ; } table . add ( name , names . size ( ) ) ; names . add ( name ) ; values . add ( value ) ; return this ; }
Appends a new member to the end of this object, with the specified name and the specified JSON
value.
<p>
This method <strong>does not prevent duplicate names</strong>. Calling this method with a name
that already exists in the object will append another member with the same name. In order to
replace existing members, use the method <code>set(name, value)</code> instead. However,
<strong> <em>add</em> is much faster than <em>set</em></strong> (because it does not need to
search for existing members). Therefore <em>add</em> should be preferred when constructing new
objects.
</p>

@param name
the name of the member to add
@param value
the value of the member to add, must not be <code>null</code>
@return the object itself, to enable method chaining
Appends a new member to the end of this object with the specified name and the specified JSON value . <p > This method <strong > does not prevent duplicate names< / strong > . Calling this method with a name that already exists in the object will append another member with the same name . In order to replace existing members use the method <code > set ( name value ) < / code > instead . However <strong > <em > add< / em > is much faster than <em > set< / em > < / strong > ( because it does not need to search for existing members ) . Therefore <em > add< / em > should be preferred when constructing new objects . < / p >