**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
for _ in range(int(input())):
    can = 1
    n,m,q = list(map(int,input().split(' ')))
    arr = list(map(int,input().split(' ')))
    b = list(map(int,input().split(' ')))

    done = set()
    idx = 0
    can = 1
    done.add(arr[0])
    for slide in b:
        if slide not in done:
            if can:
                for i in range(idx,n):
                    if arr[i] not in done:
                        done.add(arr[i])
                        idx=i
                        break
                if slide not in done:
                    can = 0
                    break

    print('YA' if can else'TIDAK')

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To create a challenging test input that exposes the bug in the given code, we need to consider the following aspects:

1. **Initial Configuration**: The initial order of the members and the required presentation order should be such that the algorithm has to make significant changes to the lineup to meet the requirements.
2. **Edge Cases**: Consider cases where the initial lineup is almost correct but requires a specific member to be moved to the front, or where the required presentation order is very different from the initial lineup.
3. **Constraints**: Ensure the test case fits within the constraints provided (e.g., \(1 \le n, m \le 2 \cdot 10^5\); \(q = 0\)).

Let's construct a test input that fits these criteria:

1. **Initial Lineup**: We will have a lineup where the first member is not the one required to present the first slide.
2. **Required Presentation Order**: The required order will be such that the first member needs to be moved to the front multiple times to meet the requirements.

Here is a small-scale test input that should expose the bug:

```plaintext
1
4 3 0
2 3 4 1
1 2 3
```

**Explanation**:
- **Test Case 1**:
  - **n = 4**: 4 members.
  - **m = 3**: 3 slides.
  - **q = 0**: No updates.
  - **Initial Lineup**: `2 3 4 1`
  - **Required Presentation Order**: `1 2 3`

**Expected Output**:
- **Output**: `TIDAK`

**Reasoning**:
- The initial lineup is `2 3 4 1`.
- The required order is `1 2 3`.
- To present the first slide, member `1` needs to be moved to the front, but this is not possible without changing the order of the rest of the members.
- Therefore, the presentation cannot be good, and the output should be `TIDAK`.

This test input should expose the bug in the given code, as it requires the first member to be moved to the front, which the code does not handle correctly.


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
import os
import sys
from io import BytesIO, IOBase
from collections import deque

BUFSIZE = 8192

class FastIO(IOBase):
    newlines = 0
    def __init__(self, file):
        self._file = file
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)

class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")

sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip(b"\r\n")

class FastReader:
    def __init__(self):
        self.tokens = deque()

    def next(self):
        while not self.tokens:
            self.tokens = deque(input().strip().split())
        return self.tokens.popleft()

    def nextInt(self):
        return int(self.next())

def solve(in_reader, out):
    n = in_reader.nextInt()
    m = in_reader.nextInt()
    q = in_reader.nextInt()

    not_used = set(xrange(1, n + 1))
    pos = {}

    for i in xrange(1, n + 1):
        a = in_reader.nextInt()
        pos[a] = i

    failed = False

    for _ in xrange(m):
        b = in_reader.nextInt()
        x = pos[b]
        if not_used and min(not_used) < x:
            failed = True
            break
        not_used.discard(x)

    out.write("TIDAK\n" if failed else "YA\n")

def main():
    in_reader = FastReader()
    out = sys.stdout

    tests = in_reader.nextInt()

    for _ in xrange(tests):
        solve(in_reader, out)

    out.flush()

if __name__ == "__main__":
    main()

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To generate a challenging test input that exposes the bug in the provided code, we need to focus on the logic that checks if the slideshow can be presented according to the given constraints. The key points to consider are:

1. **Initial Order of Members**: Ensure the initial order of members is such that it might not be trivial to satisfy the presentation requirements.
2. **Presentation Order**: Create a sequence of presentations that requires specific members to present, which might be difficult to achieve if the initial order is not favorable.
3. **Edge Cases**: Consider edge cases where the initial order and presentation order are such that the minimum position of unused members is less than the position of the current presenter.

Given these considerations, let's construct a small-scale test input:

1. **Initial Order of Members**: `[2, 1, 3]`
2. **Presentation Order**: `[1, 2, 3]`
3. **Number of Test Cases**: `1`

This setup ensures that the initial order is not in the same order as the presentation order, which will challenge the algorithm to determine if the slideshow can be good.

Here is the test input:

```plaintext
1
3 3 0
2 1 3
1 2 3
```

Let's break down why this input is challenging:
- The initial order is `[2, 1, 3]`.
- The presentation order is `[1, 2, 3]`.
- The first slide requires member `1` to present, but `1` is not at the front of the line.
- The second slide requires member `2` to present, but `2` is at the front of the line.
- The third slide requires member `3` to present, but `3` is at the back of the line.

The correct solution should determine if it's possible to move members to satisfy the presentation order. In this case, it is possible to achieve the required order by moving members as follows:
1. Move member `1` to the front: `[1, 2, 3]`.
2. No movement needed for the second slide.
3. No movement needed for the third slide.

However, the provided code might fail to correctly handle the initial order and presentation order, leading to an incorrect output of "TIDAK" instead of "YA".

This test input should effectively expose any issues in the code's logic for handling the initial and required presentation orders.


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
for _ in range(int(input())):
    a,b,c=map(int,input().split())
    t=list(map(int,input().split()))
    m=list(map(int,input().split()))
    x=[]
    for i in t:
        if i in m:

            x.append(m.index(i))
    if x!=sorted(x):
        print("TIDAK")
    else:
        print("YA")

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
1
3 3 0
1 2 3
3 2 1
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
import java.util.*;
public class adjustThePresentation {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int t=sc.nextInt();

        while(t-->0) {
            int n = sc.nextInt();
            int m = sc.nextInt();
            int q = sc.nextInt();

            int[] member = new int[n];
            int[] section = new int[m];
            for (int i = 0; i < n; i++) {
                member[i] = sc.nextInt();
            }
            for (int i = 0; i < m; i++) {
                section[i] = sc.nextInt();
            }
            ArrayList<Integer> lst = new ArrayList<>();
            if (m == 1) {
                lst.add(section[0]);
            }
            else{
            for (int i = 0; i < m - 1; i++) {
                if (section[i] != section[i + 1]) {
                    lst.add(section[i]);
                }
            }
            if (section[m - 2] != section[m - 1]) {
                lst.add(section[m - 1]);
            }
        }

            boolean flag=true;
            if(member.length<=lst.size()){
                for(int i=0;i<member.length;i++){
                    if(member[i]!=lst.get(i)){
                        System.out.println("TIDAK");
                        flag=false;
                        break;
                    }
                }
                if(flag==true){
                    System.out.println("YA");
                }
            }
            else{
                for(int i=0;i< lst.size();i++){
                    if(lst.get(i)!=member[i]){
                        System.out.println("TIDAK");
                        flag=false;
                        break;
                    }
                }
                if(flag==true){
                    System.out.println("YA");
                }
            }
        }
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
1
3 4 0
1 2 3
1 2 3 1
```

### Explanation:
This test input is designed to expose a potential issue in the given buggy code. Here’s how it works:

1. **Test Case Setup:**
   - `t = 1`: Only one test case.
   - `n = 3`: Three members.
   - `m = 4`: Four slides.
   - `q = 0`: No updates to the array `b`.

2. **Initial Order of Members:**
   - `a = [1, 2, 3]`: Members are initially ordered as 1, 2, 3.

3. **Array `b` (Slides to be presented by members):**
   - `b = [1, 2, 3, 1]`: Slide 1 should be presented by member 1, slide 2 by member 2, slide 3 by member 3, and slide 4 by member 1.

4. **Expected Output:**
   - The output should be "YA" because it is possible to present the slides in the required order. The steps to achieve this are:
     - Slide 1: Member 1 presents the slide. Line: [1, 2, 3].
     - Slide 2: Member 2 presents the slide. Move member 1 to the end. Line: [2, 3, 1].
     - Slide 3: Member 3 presents the slide. Move member 2 to the end. Line: [3, 1, 2].
     - Slide 4: Member 1 presents the slide. Move member 3 to the end. Line: [1, 2, 3].

### How It Exposes the Bug:
The buggy code has a logic that only considers the unique members in the `section` array and checks if they match the initial order of `member`. However, it fails to consider the possibility of repeated members in the `section` array and the dynamic nature of the line changes.

By providing a test case where the same member (member 1) needs to present multiple slides, we can see if the code correctly handles this scenario. The buggy code might fail to recognize this and output "TIDAK" instead of "YA".


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
// Source: https://usaco.guide/general/io

import java.io.*;
import java.util.*;

public class Main {
	public static void main(String[] args) throws IOException {
		Scanner sc = new Scanner(System.in);
		int T = sc.nextInt();
		while(T-- > 0){
			int N = sc.nextInt();
			int M = sc.nextInt();
			int Q = sc.nextInt();
			int[] a = new int[N];
			int[] b = new int[M];
			for(int i = 0; i < N; i++){
				a[i] = sc.nextInt();
			}
			int currIndex = 0;
			boolean valid = true;
			Set<Integer> used = new HashSet<Integer>();
			for(int i = 0; i < M; i++){
				b[i] = sc.nextInt();
				if(currIndex < N && b[i] == a[currIndex]){
					used.add(a[currIndex]);
					currIndex++;
				}
				else if(used.contains(b[i])){
					// Anything recycled previously could definitely work as you could just push it back to desired position
					;
				}
				else{
					valid = false;
					break;
				}
			}
			System.out.println(valid ? "YA" : "TIDAK");
		}

	}
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
1
4 4 0
1 2 3 4
4 3 2 1
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
#define F first
#define S second
#define pb push_back
#define pob pop_back
#define REP(i,a,b) for (ll i =a; (i<=b); ++i)
#define REPdec(i,a,b) for (ll i =a; (i>=b); --i)
#define REPO(a) for (auto x:a)cout<<x<<" "
#define REPI(n,a) REP(i,0,n-1)cin>>a[i]
#define fast ios_base::sync_with_stdio(0);cin.tie(NULL);cout.tie(NULL)
const ll mod = 1000000007;

int main(){
    ll t;
    cin>>t;
    while (t--)
    {
        ll n , m ,q;
        cin>>n>>m>>q;
        vector<ll > a(n);
        REPI(n,a);
        vector<ll> b(m);
        REPI(m,b);
        ll j=0;
        vector<bool> vis(n+1,false);
        bool isPossible=false;
        for (ll i=0;i<m && j<n;i++){
                        isPossible=false;

            // cout<<i<<j<<endl;
            // REPO(vis);
            // cout<<endl;
            while (i<m && vis[b[i]] ){

                i++;
                isPossible=true;
            }
            // REPO(vis);
            // cout<<endl;
                        // cout<<i<<j<<endl;

            // cout<<i<<j<<endl;
            while (i<m && a[j]==b[i]){
                i++;
                isPossible=true;
                vis[a[j]]=true;
            }
                        // cout<<i<<j<<endl;
            // if (i==3 && j==2 )cout<<isPossible<<endl;

            if (!isPossible){
                break;
            }
            i--;

            j++;
                                    // cout<<i<<j<<endl;

        }
        if (!isPossible){
            cout<<"TIDAK"<<endl;
        }
        else cout<<"YA"<<endl;
    }

}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
1
4 4 0
1 2 3 4
4 3 2 1
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
#include<bits/stdc++.h>
using namespace std;
void solve()
{
    int n,m,q;
    cin>>n>>m>>q;
    vector<int>a(n+100);
    vector<int>b(m+100);
    for(int i=1;i<=n;i++)
    cin>>a[i];
     for(int j=1;j<=m;j++)
    cin>>b[j];

    map<int,int>id;
    for(int i=1;i<=n;i++)
    id[a[i]]=i;

    set<int>has;
    has.insert(id[b[1]]);
    for(int i=2;i<=m;i++)
    {
        if(has.count(id[b[i]]))
        {
            continue;
        }
        else
        {

            if(*has.rbegin()>id[b[i]])
            {
                cout<<"TIDAK\n";
                return;
            }
            else has.insert(id[b[i]]);
        }
    }
    cout<<"YA\n";
}
signed main()
{
    #ifndef ONLINE_JUDGE
    freopen("c1.in","a+",stdin);
    #endif
    int T;
    cin>>T;
    while(T--)solve();
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To generate a challenging test input that exposes the bug in the provided buggy code, we need to focus on scenarios where the code might fail. The buggy code uses a set to keep track of the positions of the members who have already presented a slide. It checks if the current member to present a slide is in the set or if its position is greater than the maximum position in the set. If not, it outputs "TIDAK".

Let's consider the following scenarios:
1. **Repetition of the same member**: If the same member is required to present multiple slides, the set will not correctly handle this.
2. **Non-sequential presentation**: If the members are not presented in a strictly increasing order of their initial positions, the set might incorrectly determine that the presentation is not possible.

### Challenging Test Input

We will create a test case where the same member is required to present multiple slides, and the order of presentation is not strictly increasing. This should expose the bug in the set-based check.

```plaintext
3
4 4 0
1 2 3 4
1 2 1 3
4 4 0
1 2 3 4
1 2 3 4
4 4 0
1 2 3 4
1 3 2 4
```

### Explanation

1. **Test Case 1**:
   - `n = 4`, `m = 4`, `q = 0`
   - Initial order of members: `1 2 3 4`
   - Slides to be presented: `1 2 1 3`
   - The member `1` presents slides `1` and `3`, and the member `2` presents slide `2`, and the member `3` presents slide `4`.
   - The set will correctly handle this, but the code will fail because it does not handle the repetition of member `1`.

2. **Test Case 2**:
   - `n = 4`, `m = 4`, `q = 0`
   - Initial order of members: `1 2 3 4`
   - Slides to be presented: `1 2 3 4`
   - This is a straightforward case where the presentation is good. The set will correctly handle this.

3. **Test Case 3**:
   - `n = 4`, `m = 4`, `q = 0`
   - Initial order of members: `1 2 3 4`
   - Slides to be presented: `1 3 2 4`
   - The member `1` presents slide `1`, the member `3` presents slide `2`, the member `2` presents slide `3`, and the member `4` presents slide `4`.
   - The set will incorrectly determine that the presentation is not possible because the order is not strictly increasing.

This test input should expose the bug in the provided code.


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
t = int(input())
for _ in range(t):
    n, m, q = map(int, input().split())
    a = list(map(int, input().split()))
    b = list(map(int, input().split()))

    good = True  # Assume the presentation is good

    # Check for non-adjacency based on the clarified criteria
    for i in range(m - 1):
        if abs(b[i + 1] - b[i]) > 1:  # Check if they are not adjacent
            good = False
            break

    print("YA" if good else "TIDAK")

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
1
4 4 0
1 2 3 4
1 3 2 4
```

### Explanation:
1. **Test Case 1:**
   - **n = 4**: There are 4 members.
   - **m = 4**: There are 4 slides.
   - **q = 0**: No updates to the array `b`.

2. **Initial Order of Members (a):**
   - `a = [1, 2, 3, 4]`: Members are initially in the order 1, 2, 3, 4.

3. **Slide Presenters (b):**
   - `b = [1, 3, 2, 4]`: The sequence of members who should present each slide is 1, 3, 2, 4.

### Why This Input is Challenging:
- The buggy code checks if the difference between consecutive elements in `b` is greater than 1. If so, it concludes that the presentation is not good.
- For the input `b = [1, 3, 2, 4]`, the differences are:
  - `|3 - 1| = 2` (greater than 1)
  - `|2 - 3| = 1` (not greater than 1)
  - `|4 - 2| = 2` (greater than 1)
- The buggy code will incorrectly determine that the presentation is not good because it sees differences greater than 1.

### Correct Solution:
- The correct solution should consider the ability to move the front member to any position in the lineup. For the input `b = [1, 3, 2, 4]`, the presentation can be made good by the following steps:
  - Slide 1: Member 1 presents, lineup remains `[1, 2, 3, 4]`.
  - Slide 2: Move member 1 to the back, lineup becomes `[2, 3, 4, 1]`. Member 3 presents, lineup becomes `[2, 4, 1, 3]`.
  - Slide 3: Move member 3 to the back, lineup becomes `[2, 4, 1, 3]`. Member 2 presents, lineup becomes `[4, 1, 3, 2]`.
  - Slide 4: Move member 2 to the back, lineup becomes `[4, 1, 3, 2]`. Member 4 presents, lineup becomes `[1, 3, 2, 4]`.

Thus, the correct output for this test case should be "YA". The buggy code will output "TIDAK", exposing the bug.


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
def f():
    n,m,q=map(int,input().strip().split())
    a=list(map(int,input().strip().split()))
    b=list(map(int,input().strip().split()))
    temp=[]
    for k in range(m):
        if (len(a)==1):
            break
        elif (b[k]==a[0]):
            continue
        elif (b[k]==a[1]):
            temp.append(a[0])
            a.pop(0)
        elif (b[k] in temp):
            continue
        else:
            return "TIDAK"
    return "YA"

t=int(input())
for _ in range(t):
    print(f())

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
1
3 3 0
1 2 3
2 1 3
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
import java.util.Scanner;

public class C{
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int t=sc.nextInt();
        while(t-->0){
            int n=sc.nextInt(),m=sc.nextInt(),q=sc.nextInt(),l=0;
            int[]a=new int[n],b=new int[m];
            String s="YA";
            for(int i=0;i<n;i++)a[i]=sc.nextInt();
            for(int i=0;i<m;i++)b[i]=sc.nextInt();
            for(int i=0;i<m&&l<n;i++){
                if(a[l]==b[i])l++;
                else if(l==0||b[i]!=a[l-1]){
                    s="TIDAK";
                    break;
                }
            }
            System.out.println(s);
        }
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To generate a test input that exposes the bug in the given code, let's analyze the code and identify the potential issues:

### Code Analysis:
1. **Initialization and Input Reading:**
   - The code reads the number of test cases, the number of members, slides, and updates.
   - It reads the initial order of members and the required presenters for each slide.

2. **Logic to Check if the Slide Show is Good:**
   - The code iterates through the slides and checks if the current member at the front of the line can present the slide.
   - If the current member at the front of the line can present the slide, it moves to the next member.
   - If the current member cannot present the slide and the previous member cannot present it, the code sets the result to "TIDAK" and breaks.

### Potential Bugs:
- **Edge Case:** The code does not handle cases where the required presenter is not in the initial lineup.
- **Edge Case:** The code does not handle cases where the required presenter is not at the front of the line but can be moved to the front.

### Test Input:
To expose the bug, we need a test case where the required presenter is not at the front of the line but can be moved to the front. This will test the logic that should allow moving the member to the front of the line.

### Example Test Input:
```plaintext
1
4 4 0
1 2 3 4
4 3 2 1
```

### Explanation:
- **n = 4**: 4 members.
- **m = 4**: 4 slides.
- **q = 0**: No updates.
- **a = [1, 2, 3, 4]**: Initial order of members.
- **b = [4, 3, 2, 1]**: Required presenters for each slide.

### Expected Output:
- **YA**: The slide show can be good if the members are moved to the front of the line in the correct order.

### Why This Test Input Exposes the Bug:
- The initial member at the front of the line (1) cannot present the first slide (4).
- The code should allow moving member 4 to the front, but it does not handle this case correctly, leading to a "TIDAK" output instead of "YA".

This test input should help identify the bug in the given code.


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
import java.util.*;
public class AdjustThePresentation_Easy_Version {
	public static void main(String[]args) {
		Scanner scan=new Scanner(System.in);
		int t=scan.nextInt();

		while(t-->0) {
			int n=scan.nextInt();
			int m=scan.nextInt();
			int q=scan.nextInt();
			Stack <Integer>s=new Stack<>();

			int a[]=new int[n];
			int b[]=new int[m];
			for(int i=0;i<n;i++)a[i]=scan.nextInt();
			for(int j=0;j<m;j++) {
				b[j]=scan.nextInt();
				if(!s.contains(b[j]))s.add(b[j]);
			}
//			System.out.println(s);
			int vis[]=new int[s.size()+1];

			while(!s.isEmpty()) {
				int c=s.pop();
//				System.out.println(c);
				vis[c]=-1;
			}
//			System.out.println(Arrays.toString(vis));
			int i=0,j=0;
			boolean flag=true;
			int prev=-1;

			while(i<a.length&&j<b.length) {

				if(a[i]==b[j]) {
					prev=a[i];
					vis[b[j]]=1;

					i++;
					j++;
				}else {
					if(prev==b[j]) {
						vis[b[j]]=1;
						j++;

					}
					else if(vis[b[j]]==1&&(prev!=b[j]&&a[i]!=b[j])) {

						i++;
						j++;
					}
					else {
						flag=false;
						break;
					}
				}
			}
			if(!flag)System.out.println("TIDAK");
			else System.out.println("YA");
		}
	}
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
1
4 4 0
1 2 3 4
4 3 2 1
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
#include <bits/stdc++.h>

void Numerator() {
    int64_t n, m, q;
    std::cin >> n >> m >> q;
    std::vector<int64_t> a(n);
    std::vector<int64_t> b(m);
    std::set<int64_t> s;
    for (int i = 0; i < n; ++i) {
        std::cin >> a[i];
    }
    for (int i = 0; i < m; ++i) {
        std::cin >> b[i];
        s.insert(b[i]);
    }

    int i = 0;
    for (auto it: s) {
        if (it != a[i++]) {
            std::cout << "TIDAK" << std::endl;
            return;
        }
    }
    std::cout << "YA" << std::endl;
}

int main() {
    std::ios_base::sync_with_stdio(false);
    std::cin.tie(nullptr);
    std::cout.tie(nullptr);
    std::cout << std::fixed << std::setprecision(25);
    int64_t t = 1;
    std::cin >> t;
    while (t-- > 0) {
        Numerator();
    }
    return 0;
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
3 3 0
1 2 3
2 1 3
4 4 0
1 2 3 4
1 2 3 4
5 5 0
1 2 3 4 5
5 4 3 2 1
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
#pragma GCC optimize("O3,unroll-loops")
#include <bits/stdc++.h>
using namespace std;
long long t;
long long n, m, q;

void read(deque <long long> &A, vector <long long> &B)
{
    cin >> n >> m >> q;

    long long num;

    for(long long i = 0; i < n; i++)
    {
        cin >> num;
        A.push_back(num);
    }

    for(long long i = 0; i < m; i++)
    {
        cin >> num;
        B.push_back(num);
    }
}

int main()
{
    //freopen("CAU1.INP", "r", stdin);
    //freopen("CAU1.OUT", "w", stdout);

    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);

    cin >> t;

    while(t--)
    {
        deque <long long> A;
        vector <long long> B;

        read(A, B);

        bool check = 1;
        vector <long long> num(n + 1, 0);

        for(long long b = 0; b < m; b++)
        {
            if(A.front() != B[b])
            {
                num[A.front()] = 1;
                A.pop_front();

                if(num[B[b]] == 0 && A.front() != B[b])
                {
                    check = 0;
                    break;
                }
                else
                {
                    if(A.front() != B[b])
                    {
                        A.push_front(B[b]);
                        num[B.front()] = 0;
                    }
                }
            }
        }

        if(check == 1) cout << "YA\n";
        else cout << "TIDAK\n";
    }

    return 0;
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
1
3 3 0
1 2 3
2 1 3
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
A = int(input())
z = []
l = []
m = []
for j in range(A):
    m.append(input())
    l.append(input())
    z.append(input())
for n in range(len(z)):
    obs = list(map(lambda x:int(x),z[n].split()))
    obs1=[obs[0]]
    arr = list(map(lambda x:int(x),l[n].split()))
    for y in range(1,len(obs)):
        if obs[y]!=obs[y-1]:
            obs1.append(obs[y])
    arr1 = obs1
    TOGGLE = 0
    ans = set()
    i = 0
    j = 0
    while j<len(arr1):
        if i<len(arr) and arr[i]==arr1[j]:
            i+=1
            j+=1
            ans.add(arr[i-1])
        elif arr1[j] in ans:
            ans.remove(arr1[j])
            j+=1
        else:
            print("TIDAK")
            TOGGLE = 1
            break
    if TOGGLE==0:
        print("Ya")

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
4 4 0
1 2 3 4
1 2 3 4
4 4 0
1 2 3 4
4 3 2 1
5 5 0
1 2 3 4 5
1 2 2 3 4
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Adjust The Presentation (Easy Version)
time_limit_ms: 2000
memory_limit_mb: 256
Description: This is the easy version of the problem. In the two versions, the constraints on $$$q$$$ and the time limit are different. In this version, $$$q=0$$$. You can make hacks only if all the versions of the problem are solved.

A team consisting of $$$n$$$ members, numbered from $$$1$$$ to $$$n$$$, is set to present a slide show at a large meeting. The slide show contains $$$m$$$ slides.

There is an array $$$a$$$ of length $$$n$$$. Initially, the members are standing in a line in the order of $$$a_1, a_2, \ldots, a_n$$$ from front to back. The slide show will be presented in order from slide $$$1$$$ to slide $$$m$$$. Each section will be presented by the member at the front of the line. After each slide is presented, you can move the member at the front of the line to any position in the lineup (without changing the order of the rest of the members). For example, suppose the line of members is $$$[\color{red}{3},1,2,4]$$$. After member $$$3$$$ presents the current slide, you can change the line of members into either $$$[\color{red}{3},1,2,4]$$$, $$$[1,\color{red}{3},2,4]$$$, $$$[1,2,\color{red}{3},4]$$$ or $$$[1,2,4,\color{red}{3}]$$$.

There is also an array $$$b$$$ of length $$$m$$$. The slide show is considered good if it is possible to make member $$$b_i$$$ present slide $$$i$$$ for all $$$i$$$ from $$$1$$$ to $$$m$$$ under these constraints.

However, your annoying boss wants to make $$$q$$$ updates to the array $$$b$$$. In the $$$i$$$-th update, he will choose a slide $$$s_i$$$ and a member $$$t_i$$$ and set $$$b_{s_i} := t_i$$$. Note that these updates are persistent, that is changes made to the array $$$b$$$ will apply when processing future updates.

For each of the $$$q+1$$$ states of array $$$b$$$, the initial state and after each of the $$$q$$$ updates, determine if the slideshow is good.

Input: Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains three integers $$$n$$$, $$$m$$$ and $$$q$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$; $$$q=0$$$) — the number of members, the number of sections and the number of updates.

The second line of each test case contains $$$n$$$ integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \le a_i \le n$$$) — the initial order of the members from front to back. It is guaranteed that each integer from $$$1$$$ to $$$n$$$ appears exactly once in $$$a$$$.

The third line of each test case contains $$$m$$$ integers $$$b_1, b_2, \ldots, b_m$$$ ($$$1 \le b_i \le n$$$) — the members who should present each section.

It is guaranteed that the sum of $$$n$$$ and the sum of $$$m$$$ over all test cases do not exceed $$$2 \cdot 10^5$$$ respectively.

Output: For each test case, output $$$q+1$$$ lines corresponding to the $$$q+1$$$ states of the array $$$b$$$. Output "YA" if the slide show is good, and "TIDAK" otherwise.

You can output the answer in any case (upper or lower). For example, the strings "yA", "Ya", "ya", and "YA" will be recognized as positive responses.

Examples:
input:
3
4 2 0
1 2 3 4
1 1
3 6 0
1 2 3
1 1 2 3 3 2
4 6 0
3 1 4 2
3 1 1 2 3 4
output:
YA
YA
TIDAK

Note: For the first test case, you do not need to move the members as both slides are presented by member $$$1$$$, who is already at the front of the line.

For the second test case, the following is a possible way to move members so that the presentation is good:

1. $$$[1,2,3]$$$, do not move member $$$1$$$.
2. $$$[1,2,3]$$$, move member $$$1$$$ after member $$$3$$$.
3. $$$[2,3,1]$$$, move member $$$2$$$ after member $$$3$$$.
4. $$$[3,2,1]$$$, do not move member $$$3$$$.
5. $$$[3,2,1]$$$, move member $$$3$$$ after member $$$1$$$.
6. $$$[2,1,3]$$$, do not move member $$$2$$$.

Buggy Code:
import heapq, math, threading
from bisect import *
from collections import *
from sys import stdin

input = lambda: stdin.readline().rstrip()
linput = lambda: input().split()
ilinput = lambda: list(map(int, linput()))

def solve():
    n, m, _ = ilinput()
    a = ilinput()
    b = ilinput()
    seen = set()
    indx = 0
    for i in range(n):
        if indx == m:
            break
        if b[indx] != a[i] and b[indx] not in seen:
            print("TIDAK")
            return
        while indx < m and b[indx] == a[i]:
            indx += 1
        while indx < m and b[indx] in seen:
            indx += 1
        seen.add(a[i])
    print("YA")

if __name__ == "__main__":
    t = int(input())
    for _ in range(t):
        solve()

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To generate a challenging test input that exposes the bug in the given buggy code, we need to consider edge cases and scenarios that maximize the probability of failure. Let's analyze the buggy code and identify potential issues:

### Buggy Code Analysis:
1. **Initialization and Input Reading:**
   - The code reads the input values for `n`, `m`, and `q`.
   - It reads the initial order of members `a` and the required presentation order `b`.

2. **Processing:**
   - The code uses a set `seen` to keep track of members who have already presented.
   - It iterates through the members in the initial order and checks if the current member can present the current slide.
   - If a member is required to present a slide but has not yet been seen, the code immediately prints "TIDAK" and returns.

3. **Potential Issues:**
   - The code does not handle cases where a member required to present a slide is not in the initial order.
   - The code does not correctly handle cases where a member is required to present multiple slides in a row.

### Challenging Test Input:
To expose the bug, we can create a test case where:
- The initial order of members does not match the required presentation order.
- A member is required to present multiple slides in a row.

### Example Test Input:
```plaintext
1
4 3 0
1 2 3 4
4 4 1
```

### Explanation:
- **Test Case:**
  - `n = 4`, `m = 3`, `q = 0`
  - Initial order of members: `a = [1, 2, 3, 4]`
  - Required presentation order: `b = [4, 4, 1]`

- **Expected Output:**
  - The slide show is not good because member 4 is required to present the first two slides, but member 4 is not at the front of the line initially, and there is no way to move member 4 to the front without changing the order of the rest of the members.

### Why This Test Input is Challenging:
- The initial order of members does not allow member 4 to present the first two slides without reordering.
- The code will fail to handle this case correctly, as it will not be able to move member 4 to the front of the line and will incorrectly print "TIDAK" when it should print "YA" if the member 4 is allowed to present multiple slides in a row.

This test input should effectively expose the bug in the given buggy code.