**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: K-Sort
time_limit_ms: 1000
memory_limit_mb: 256
Description: You are given an array of integers $a$ of length $n$.

You can apply the following operation any number of times (maybe, zero):

  * First, choose an integer $k$ such that $1 \le k \le n$ and pay $k + 1$ coins.    * Then, choose exactly $k$ indices such that $1 \le i_1 < i_2 < \ldots < i_k \le n$.    * Then, for each $x$ from $1$ to $k$, increase $a_{i_x}$ by $1$.

Find the minimum number of coins needed to make $a$ non-decreasing. That is, $a_1 \le a_2 \le \ldots \le a_n$.

Input: Each test contains multiple test cases. The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer $n$ ($1 \le n \le 10^5$) — the length of the array $a$.

The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^9$) — the elements of the array $a$.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

Output: For each test case, output a single integer — the minimum number of coins needed to make $a$ non-decreasing.

Examples:
input:
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
output:
0
3
2
0
1821

Note: In the first test case, $a$ is already sorted, so you don't have to spend any coins.

In the second test case, the optimal sequence of operations is:

  * Choose $k = 2$ and the indices $2$ and $5$: $[ 2, \color{red}{1}, 4, 7, \color{red}{6} ] \rightarrow [2, 2, 4, 7, 7]$. This costs $3$ coins.

It can be proven that it is not possible to make $a$ non-decreasing by spending less than $3$ coins.

Buggy Code:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.List;

public class CF1987B {
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int numberOfTestCases = Integer.parseInt(br.readLine());
        for (int x = 0; x < numberOfTestCases; x++) {
            int arrayLength = Integer.parseInt(br.readLine());
            String[] line = br.readLine().split(" ");
            int arr[] = new int[arrayLength];
            for (int i = 0; i < arrayLength; i++) {
                arr[i] = Integer.parseInt(line[i]);
            }
            if (arrayLength == 35) {
                System.out.println(Arrays.toString(arr));
            }
            int set = 0;
            int current = arr[0];
            List<Integer> toBeFiguredOut = new ArrayList<>();
            while (set != arrayLength) {
                if (arr[set] < current) {
                    toBeFiguredOut.add(current - arr[set]);
                } else {
                    current = arr[set];
                }
                set++;
            }
            int ans = 0;
            int diff = 0;
            while (!toBeFiguredOut.isEmpty()) {
                int smallest = Collections.min(toBeFiguredOut);
                ans += (smallest - diff) * (toBeFiguredOut.size() + 1);
                diff = smallest;
                toBeFiguredOut.remove(Integer.valueOf(smallest));
            }
            System.out.println(ans);
        }
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: K-Sort
time_limit_ms: 1000
memory_limit_mb: 256
Description: You are given an array of integers $a$ of length $n$.

You can apply the following operation any number of times (maybe, zero):

  * First, choose an integer $k$ such that $1 \le k \le n$ and pay $k + 1$ coins.    * Then, choose exactly $k$ indices such that $1 \le i_1 < i_2 < \ldots < i_k \le n$.    * Then, for each $x$ from $1$ to $k$, increase $a_{i_x}$ by $1$.

Find the minimum number of coins needed to make $a$ non-decreasing. That is, $a_1 \le a_2 \le \ldots \le a_n$.

Input: Each test contains multiple test cases. The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer $n$ ($1 \le n \le 10^5$) — the length of the array $a$.

The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^9$) — the elements of the array $a$.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

Output: For each test case, output a single integer — the minimum number of coins needed to make $a$ non-decreasing.

Examples:
input:
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
output:
0
3
2
0
1821

Note: In the first test case, $a$ is already sorted, so you don't have to spend any coins.

In the second test case, the optimal sequence of operations is:

  * Choose $k = 2$ and the indices $2$ and $5$: $[ 2, \color{red}{1}, 4, 7, \color{red}{6} ] \rightarrow [2, 2, 4, 7, 7]$. This costs $3$ coins.

It can be proven that it is not possible to make $a$ non-decreasing by spending less than $3$ coins.

Buggy Code:
import java.util.*;
public class Main {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int t=sc.nextInt();
        while(t>0){
            int n=sc.nextInt();
            int[] arr=new int[n];
            for(int i=0; i<n; i++){
                arr[i]=sc.nextInt();
            }
            ArrayList<Integer> list=new ArrayList<>();
            int max=arr[0];
            for(int i=1; i<n; i++){
                if(max>arr[i]){
                    list.add(max-arr[i]);
                }
                else{
                    max=arr[i];
                }
            }
            Collections.sort(list);
            int diff=0;
            int ans=0;
            for(int i=0; i<list.size(); i++){
                int temp=list.get(i)-diff;
                if(temp>0){
                ans=ans+(temp*(list.size()-i+1));
                diff=diff+temp;
                }
            }
            System.out.println(ans);
            t--;
        }
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
4
1 3 2 4
5
2 1 4 7 6
6
1 3 2 4 5 6
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: K-Sort
time_limit_ms: 1000
memory_limit_mb: 256
Description: You are given an array of integers $a$ of length $n$.

You can apply the following operation any number of times (maybe, zero):

  * First, choose an integer $k$ such that $1 \le k \le n$ and pay $k + 1$ coins.    * Then, choose exactly $k$ indices such that $1 \le i_1 < i_2 < \ldots < i_k \le n$.    * Then, for each $x$ from $1$ to $k$, increase $a_{i_x}$ by $1$.

Find the minimum number of coins needed to make $a$ non-decreasing. That is, $a_1 \le a_2 \le \ldots \le a_n$.

Input: Each test contains multiple test cases. The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer $n$ ($1 \le n \le 10^5$) — the length of the array $a$.

The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^9$) — the elements of the array $a$.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

Output: For each test case, output a single integer — the minimum number of coins needed to make $a$ non-decreasing.

Examples:
input:
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
output:
0
3
2
0
1821

Note: In the first test case, $a$ is already sorted, so you don't have to spend any coins.

In the second test case, the optimal sequence of operations is:

  * Choose $k = 2$ and the indices $2$ and $5$: $[ 2, \color{red}{1}, 4, 7, \color{red}{6} ] \rightarrow [2, 2, 4, 7, 7]$. This costs $3$ coins.

It can be proven that it is not possible to make $a$ non-decreasing by spending less than $3$ coins.

Buggy Code:
t = int(input())
for i in range (t):
  n = int(input())
  a = list(map(int,input().split()))
  cnt = 0
  while a!=sorted(a):
    y = []
    j = 0
    while j<n:
      k = j+1
      while k<n and a[k]<a[j]:
        y.append(k)
        k+=1
      j = k
    for p in y:
      a[p]+=1
    cnt += len(y)+1
    # print (cnt)
  print (cnt)

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: K-Sort
time_limit_ms: 1000
memory_limit_mb: 256
Description: You are given an array of integers $a$ of length $n$.

You can apply the following operation any number of times (maybe, zero):

  * First, choose an integer $k$ such that $1 \le k \le n$ and pay $k + 1$ coins.    * Then, choose exactly $k$ indices such that $1 \le i_1 < i_2 < \ldots < i_k \le n$.    * Then, for each $x$ from $1$ to $k$, increase $a_{i_x}$ by $1$.

Find the minimum number of coins needed to make $a$ non-decreasing. That is, $a_1 \le a_2 \le \ldots \le a_n$.

Input: Each test contains multiple test cases. The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer $n$ ($1 \le n \le 10^5$) — the length of the array $a$.

The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^9$) — the elements of the array $a$.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

Output: For each test case, output a single integer — the minimum number of coins needed to make $a$ non-decreasing.

Examples:
input:
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
output:
0
3
2
0
1821

Note: In the first test case, $a$ is already sorted, so you don't have to spend any coins.

In the second test case, the optimal sequence of operations is:

  * Choose $k = 2$ and the indices $2$ and $5$: $[ 2, \color{red}{1}, 4, 7, \color{red}{6} ] \rightarrow [2, 2, 4, 7, 7]$. This costs $3$ coins.

It can be proven that it is not possible to make $a$ non-decreasing by spending less than $3$ coins.

Buggy Code:
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
    newlines = 0
    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()
    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()
    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
import math
from math import *
from collections import *
from heapq import *
inf=float('inf')

def solve():
    n=int(input())
    a=list(map(int,input().split()))
    flag=0
    for i in range(n-1):
        if a[i]>a[i+1]:
            flag=-1
            break
    if flag==0:
        print(0)
    else:
        ans=0
        c=0
        d=[]
        for i in range(n):
            if a[i]<c:
                d.append(c-a[i])
            if a[i]>c:
                c=a[i]
        d.sort()
        f=0
        for i in range(len(d)):
            d[i]-=f
            if d[i]<=0:
                break
            ans+=d[i]*(len(d)-i+1)
            f+=d[i]
        print(ans)

for _ in range(int(input())):
    solve()

'''
1
abcdeecd
dced
'''

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To generate a challenging test input that exposes the bug in the provided buggy code, we need to focus on scenarios that highlight issues in the algorithm. The buggy code has a few potential issues:

1. **Incorrect handling of non-decreasing sequences**: The code should correctly identify if the array is already non-decreasing and return 0 if it is.
2. **Incorrect calculation of the minimum number of coins**: The code might not correctly calculate the minimum number of coins needed to make the array non-decreasing.

Let's consider the following test case:

### Test Case
- **Array**: `[1, 3, 2, 4]`
- **Expected Output**: `2`

### Explanation
- The array `[1, 3, 2, 4]` is not non-decreasing because `3 > 2`.
- To make it non-decreasing, we need to perform the following operations:
  - Choose `k = 1` and the index `3` to increase `a[2]` by 1. The array becomes `[1, 3, 3, 4]`. This costs `2` coins.
  - Choose `k = 1` and the index `3` to increase `a[2]` by 1. The array becomes `[1, 3, 4, 4]`. This costs `2` coins.
- The total cost is `2` coins.

This test case should expose any issues in the buggy code related to the correct calculation of the minimum number of coins needed to make the array non-decreasing.

### Test Input
```plaintext
1
4
1 3 2 4
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: K-Sort
time_limit_ms: 1000
memory_limit_mb: 256
Description: You are given an array of integers $a$ of length $n$.

You can apply the following operation any number of times (maybe, zero):

  * First, choose an integer $k$ such that $1 \le k \le n$ and pay $k + 1$ coins.    * Then, choose exactly $k$ indices such that $1 \le i_1 < i_2 < \ldots < i_k \le n$.    * Then, for each $x$ from $1$ to $k$, increase $a_{i_x}$ by $1$.

Find the minimum number of coins needed to make $a$ non-decreasing. That is, $a_1 \le a_2 \le \ldots \le a_n$.

Input: Each test contains multiple test cases. The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer $n$ ($1 \le n \le 10^5$) — the length of the array $a$.

The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^9$) — the elements of the array $a$.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

Output: For each test case, output a single integer — the minimum number of coins needed to make $a$ non-decreasing.

Examples:
input:
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
output:
0
3
2
0
1821

Note: In the first test case, $a$ is already sorted, so you don't have to spend any coins.

In the second test case, the optimal sequence of operations is:

  * Choose $k = 2$ and the indices $2$ and $5$: $[ 2, \color{red}{1}, 4, 7, \color{red}{6} ] \rightarrow [2, 2, 4, 7, 7]$. This costs $3$ coins.

It can be proven that it is not possible to make $a$ non-decreasing by spending less than $3$ coins.

Buggy Code:
import java.util.*;

public class Ques{
    public static void main(String[] args) {
        Scanner in=new Scanner(System.in);
        int t=in.nextInt();
        while(t>0){
            int n=in.nextInt();
            int[] arr=new int[n];
            for(int i=0;i<n;i++){
                arr[i]=in.nextInt();
            }
            int[] narr=new int[n];
            for(int i=0;i<n;i++){
                narr[i]=arr[i];
            }
            int k=0;
            for(int i=0;i<n-1;i++){
                if(arr[i+1]<arr[i]){
                    k=k+arr[i]-arr[i+1];
                    arr[i+1]=arr[i];
                }
            }
            int x= Integer.MIN_VALUE;
            for(int i=0;i<n;i++){
                x=Math.max(x,arr[i]-narr[i]);
            }
            if(k==0){
                System.out.println(k);
            } else{
                System.out.println(k+x);
            }
            t--;
        }

    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
5
1 2 3 4 5
5
5 4 3 2 1
5
1 1 1 1 1
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: K-Sort
time_limit_ms: 1000
memory_limit_mb: 256
Description: You are given an array of integers $a$ of length $n$.

You can apply the following operation any number of times (maybe, zero):

  * First, choose an integer $k$ such that $1 \le k \le n$ and pay $k + 1$ coins.    * Then, choose exactly $k$ indices such that $1 \le i_1 < i_2 < \ldots < i_k \le n$.    * Then, for each $x$ from $1$ to $k$, increase $a_{i_x}$ by $1$.

Find the minimum number of coins needed to make $a$ non-decreasing. That is, $a_1 \le a_2 \le \ldots \le a_n$.

Input: Each test contains multiple test cases. The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer $n$ ($1 \le n \le 10^5$) — the length of the array $a$.

The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^9$) — the elements of the array $a$.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

Output: For each test case, output a single integer — the minimum number of coins needed to make $a$ non-decreasing.

Examples:
input:
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
output:
0
3
2
0
1821

Note: In the first test case, $a$ is already sorted, so you don't have to spend any coins.

In the second test case, the optimal sequence of operations is:

  * Choose $k = 2$ and the indices $2$ and $5$: $[ 2, \color{red}{1}, 4, 7, \color{red}{6} ] \rightarrow [2, 2, 4, 7, 7]$. This costs $3$ coins.

It can be proven that it is not possible to make $a$ non-decreasing by spending less than $3$ coins.

Buggy Code:
import java.util.*;

public class Epic_2024_B {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int t = Integer.parseInt(scanner.next());
        for (int k = 0; k < t; k++) {
            int n = Integer.parseInt(scanner.next());
            int[] a = new int[n];
            for (int i = 0; i < n; i++) {
                a[i] = Integer.parseInt(scanner.next());
            }
            System.out.println(ans(n, a));
        }
    }

    private static int ans(int n, int[] a) {
        List<Integer> list = new ArrayList<>();
        int coins = 0;
        for (int i = 1; i < n; i++) {
            if (a[i] < a[i - 1]) {
                list.add(a[i - 1] - a[i]);
                a[i] = a[i - 1];
            }
        }
        int m = list.size();
        Collections.sort(list);
        int[] bb = new int[m];
        for (int i = 0; i < m; i++) {
            bb[i] = list.get(i);
        }
        int i = 0;
        int j = 0;
        int level = 0;
        while (i < m) {
            while (j < m && bb[j] == bb[i]) {
                j++;
            }
            coins += (m - i + 1) * (bb[i] - level);
            level = bb[i];
            i = j;

        }
        return coins;
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: K-Sort
time_limit_ms: 1000
memory_limit_mb: 256
Description: You are given an array of integers $a$ of length $n$.

You can apply the following operation any number of times (maybe, zero):

  * First, choose an integer $k$ such that $1 \le k \le n$ and pay $k + 1$ coins.    * Then, choose exactly $k$ indices such that $1 \le i_1 < i_2 < \ldots < i_k \le n$.    * Then, for each $x$ from $1$ to $k$, increase $a_{i_x}$ by $1$.

Find the minimum number of coins needed to make $a$ non-decreasing. That is, $a_1 \le a_2 \le \ldots \le a_n$.

Input: Each test contains multiple test cases. The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer $n$ ($1 \le n \le 10^5$) — the length of the array $a$.

The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^9$) — the elements of the array $a$.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

Output: For each test case, output a single integer — the minimum number of coins needed to make $a$ non-decreasing.

Examples:
input:
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
output:
0
3
2
0
1821

Note: In the first test case, $a$ is already sorted, so you don't have to spend any coins.

In the second test case, the optimal sequence of operations is:

  * Choose $k = 2$ and the indices $2$ and $5$: $[ 2, \color{red}{1}, 4, 7, \color{red}{6} ] \rightarrow [2, 2, 4, 7, 7]$. This costs $3$ coins.

It can be proven that it is not possible to make $a$ non-decreasing by spending less than $3$ coins.

Buggy Code:
#include <bits/stdc++.h>
#define int long long
using namespace std;
signed main() {
    int t;
    cin>>t;
    while(t--){
    int n;int k;
    cin>>n;
    int arr[n];vector<int>v;int sum=0;
    for(int i=0;i<n;i++){
        cin>>arr[i];
    }
    for(int i=1;i<n;i++){
       int max=*max_element(arr,arr+i);
        if(arr[i]<max){
           v.push_back(max-arr[i]);
        }
       }
    sort(v.begin(),v.end());
    for(int i=0;i<v.size();i++){
        if(i==0)
         sum=sum+(v.size()-i+1)*v[i];
         else
        sum=sum+(v.size()-i+1)*v[i]-(v.size()-i+1)*v[i-1];
    }
    cout<<sum<<endl;
    }

    return 0;

}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
5
1 2 3 4 5
5
5 4 3 2 1
5
2 3 1 4 5
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: K-Sort
time_limit_ms: 1000
memory_limit_mb: 256
Description: You are given an array of integers $a$ of length $n$.

You can apply the following operation any number of times (maybe, zero):

  * First, choose an integer $k$ such that $1 \le k \le n$ and pay $k + 1$ coins.    * Then, choose exactly $k$ indices such that $1 \le i_1 < i_2 < \ldots < i_k \le n$.    * Then, for each $x$ from $1$ to $k$, increase $a_{i_x}$ by $1$.

Find the minimum number of coins needed to make $a$ non-decreasing. That is, $a_1 \le a_2 \le \ldots \le a_n$.

Input: Each test contains multiple test cases. The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer $n$ ($1 \le n \le 10^5$) — the length of the array $a$.

The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^9$) — the elements of the array $a$.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

Output: For each test case, output a single integer — the minimum number of coins needed to make $a$ non-decreasing.

Examples:
input:
5
3
1 7 9
5
2 1 4 7 6
4
1 3 2 4
1
179
9
344 12 37 60 311 613 365 328 675
output:
0
3
2
0
1821

Note: In the first test case, $a$ is already sorted, so you don't have to spend any coins.

In the second test case, the optimal sequence of operations is:

  * Choose $k = 2$ and the indices $2$ and $5$: $[ 2, \color{red}{1}, 4, 7, \color{red}{6} ] \rightarrow [2, 2, 4, 7, 7]$. This costs $3$ coins.

It can be proven that it is not possible to make $a$ non-decreasing by spending less than $3$ coins.

Buggy Code:
#include <iostream>
#include <algorithm>
#include <vector>
#include <string>
#include <cmath>
#include <map>
#include <set>
#include <stack>
#include <queue>
#define ll long long
using namespace std;
int main()
{
    int t;
    cin >> t;
    while (t--)
    {
        ll n;
        cin >> n;
        vector<ll> a(n);
        for (ll i = 0; i < n; i++)
        {
            cin >> a[i];
        }
        vector<ll>increment;
        for (ll i = 0; i < n-1; i++)
        {
            if (a[i] > a[i + 1])
            {
                increment.push_back(a[i] - a[i + 1]);
                a[i + 1] = a[i];
            }

        }
        ll coins=0;
        sort(increment.rbegin(),increment.rend());
        int s=increment.size();
        while(s>0){
            coins+=(s+1)*increment.back();
            for(ll i=0;i<s;i++){
                increment[i]-=increment.back();
            }
            increment.pop_back();
            s--;

        }
        cout<<coins<<endl;
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To generate a challenging test input that exposes the bug in the provided buggy code, we need to focus on edge cases or scenarios where the algorithm might fail. The primary issue in the buggy code is that it does not correctly handle the incremental operations and the cost calculations. Specifically, the code does not efficiently manage the incremental values and the subsequent cost calculations.

Let's consider a test case that could expose this issue:

1. **Array with a large initial difference**: This will force the algorithm to perform a large number of operations, potentially exposing issues in the cost calculation.
2. **Array with a sequence of decreasing values**: This will test the algorithm's ability to handle multiple increments in a row.

Here is a small-scale test input that fits these criteria:

```plaintext
1
5
1 1000000000 1 1000000000 1
```

### Explanation:
- **Test Case 1**:
  - **Array**: `[1, 1000000000, 1, 1000000000, 1]`
  - **Expected Output**: A large number of coins, as the algorithm will need to increment the values significantly to make the array non-decreasing.

This test case is designed to:
- **Expose the large initial difference**: The large difference between `1` and `1000000000` will force the algorithm to perform a significant number of operations.
- **Test multiple increments**: The repeating pattern of `1` and `1000000000` will require multiple increments, which can help identify issues in the cost calculation and management of incremental values.

This test input should effectively highlight the issues in the buggy code.


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
#include <stdio.h>
#include <string.h>
int main(){
    int t;
    scanf("%d",&t);
    while(t--){
         int n,m;
         scanf("%d %d",&n,&m);
         char arr[n][10];
         for(int i=0;i<n;i++){
            scanf("%s",arr[i]);
         }
         int len=0;
         int x=0;
         for(int i=0;;i++){
            len=len+strlen(arr[i]);
            if(len>m){
                break;
            }
            x++;
         }
         printf("%d\n",x);
    }
    return 0;
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
5 10
a
b
c
d
e
5 5
abc
def
ghi
jkl
mno
5 15
longword
short
medium
tiny
verylongword
```

3
5 10
a
b
c
d
e
5 5
abc
def
ghi
jkl
mno
5 15
longword
short
medium
tiny
verylongword


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
#include<iostream>
#include<vector>
using namespace std;

int main(){
  int t;
  cin >> t;
  while(t--){
    int n,m;
    cin>>n>>m;
    vector<int> x(n);
    x[0]=0;
    int k=0;
    string temp;
    for(int i=1;i<=n;i++){
      cin>>temp;
      x[i]=temp.size()+x[i-1];
      if(m>=x[i])
      k++;
    }
    cout<< k<<endl;
  }
  return 0;
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
5 10
abc
def
ghi
jkl
mno
2 1
a
b
3 3
abc
def
ghi
```

3
5 10
abc
def
ghi
jkl
mno
2 1
a
b
3 3
abc
def
ghi


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
#include <iostream>
#include <string>
#include <queue>
using namespace std;
int main() {
	int t;
	cin >> t;
	while (t > 0) {
		t--;
		int n, m;
		cin >> n >> m;
		queue<string>q;
		while (n--) {
			string s;
			cin >> s;
			q.push(s);
		}
		long long total = 0;
		int cnt = 0;
		while (total < m) {
			total += (q.front()).size();
			q.pop();
			if (total <= m) {
				cnt++;
			}
			else {
				break;
			}
		}
		cout << cnt << endl;
	}
	return 0;
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
5
3 10
a
bc
def
2 10
abc
def
4 10
a
b
c
d
3 10
abc
def
ghi
3 10
abc
def
ghi
```

5
3 10
a
bc
def
2 10
abc
def
4 10
a
b
c
d
3 10
abc
def
ghi
3 10
abc
def
ghi


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
T=int(input())
for _ in range(T):
    cnt=0
    c=[]
    n,m=map(int,input().split())
    for j in range(n):
        a=input()
        b=len(a)
        c.append(b)
    for i in c:
        m-=i
        cnt+=1
        if m==0:
            print(cnt)
            break
        if m<0:
            print(cnt-1)
            break

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
```

5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
for _ in range(int(input())):
    n,m = map(int,input().split())
    words = [input() for i in range(n)]
    c = len(words[0])
    count=1
    for i in range(1,n):
        if c==m:
            print(count)
            break
        if c>m:
            print(count-1)
            break
        c+=len(words[i])
        count+=1
    else:
        if count<=m:
            print(count)
        else:
            print(count-1)

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
5
3 10
abc
def
ghi
4 11
abcd
efgh
ijkl
mnop
2 10
abcde
fghij
3 3
abc
def
ghi
2 1
a
b
```

5
3 10
abc
def
ghi
4 11
abcd
efgh
ijkl
mnop
2 10
abcde
fghij
3 3
abc
def
ghi
2 1
a
b


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
t = int(input())
for _ in range(t):
    n, m = map(int, input().split())
    lista = [input().strip() for _ in range(n)]

    if len(lista[0]) > m:
        print(0)
    else:
        s = 0
        nb = 0
        for j in range(len(lista)):
            if s + len(lista[j]) <= m:
                s += len(lista[j])
                nb += 1
        print(nb)

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
10 50
a
b
c
d
e
f
g
h
i
j
10 10
a
bb
ccc
dddd
eeeee
ffffff
ggggggg
hhhhhhhh
iiiiiiiii
jjjjjjjjjj
1 1
a
```

3
10 50
a
b
c
d
e
f
g
h
i
j
10 10
a
bb
ccc
dddd
eeeee
ffffff
ggggggg
hhhhhhhh
iiiiiiiii
jjjjjjjjjj
1 1
a


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
import java.util.Arrays;
    //import java.util.ArrayList;
    //import java.util.Collection;
    //import java.util.HashMap;
    //import java.util.Map;
    import java.util.Scanner;
    //import java.util.Set;

    public class Main {
        public static void main(String[] args)
        {
        	Scanner S = new Scanner(System.in);
        	int t= S.nextInt();
        	while(t>0) {
        		t--;
        		int n = S.nextInt();
        		int m = S.nextInt();
        		String[] a = new String[n];
        		for(int i =0;i<n;i++) {
        			a[i] = S.next();
        		}
        		int ans = 0;
        		int sum = 0;
        		while(sum<=m && ans <= n-1) {
        			sum = sum + a[ans].length();
        			ans = ans + 1;
        		}
        		if(ans !=n) {
        			System.out.println(ans-1);
        		}
        		else {
        			System.out.println(n);
        		}
        	}
        }
    }

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To generate a challenging test input that exposes the bug in the given buggy code, let's consider the following aspects:

1. **Edge Cases:**
   - The first strip can exactly fit the sum of the lengths of the words.
   - The first strip can fit all but the last word.
   - The first strip can fit only one word.
   - The first strip cannot fit any words.

2. **Special Cases:**
   - All words are of the same length.
   - Words have varying lengths.
   - The sum of the lengths of the first few words is exactly equal to the strip length.

3. **Test Case Structure:**
   - Number of test cases: 1 (to keep it simple and focused).
   - Number of words: 5 (a small but manageable number).
   - Maximum length of the first strip: 10 (a value that can be easily exceeded or exactly matched).

Given these considerations, let's create a test input that will challenge the buggy code:

```plaintext
1
5 10
abc
def
ghi
jkl
mno
```

### Explanation:
- **Test Case:**
  - **Number of words (n):** 5
  - **Maximum length of the first strip (m):** 10
  - **Words:**
    - "abc" (length 3)
    - "def" (length 3)
    - "ghi" (length 3)
    - "jkl" (length 3)
    - "mno" (length 3)

### Expected Output:
- The total length of the first three words is \(3 + 3 + 3 = 9\), which fits within the 10-character limit of the first strip.
- The total length of the first four words is \(3 + 3 + 3 + 3 = 12\), which exceeds the 10-character limit.

Thus, the expected output should be:
```plaintext
3
```

This test case will help expose the bug in the given code, particularly in the loop condition and the final output logic.


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
import java.util.Scanner;
public class A_Line_Breaks{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        sc.nextLine();
        while(t-->0){
            int n = sc.nextInt();
            int m = sc.nextInt();
            sc.nextLine();

            int  len = 0;
            int count = 0;String str[] = new String[n];
            for(int i=0;i<n;i++){
                str[i]  = sc.next();
            }

            for(int i=0;i<n;i++){
                len += str[i].length();
                count++;
                if(len == m){
                   System.out.println(count);
                   break;
                }else if(len>m){
                    System.out.println(count-1);
                    break;

                }else if(i==0 && len>m){
                    System.out.println(0);
                    break;
                }

            }
        }
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
3 10
longword
short
tiny
2 20
hello
world
4 5
a
b
c
d
```

3
3 10
longword
short
tiny
2 20
hello
world
4 5
a
b
c
d


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
#include <bits/stdc++.h>
#define f first
#define s second
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define pi pair<int, int>
#define bg begin()
#define en end()
#define sz(x) (int)x.size()
#define all(x) x.begin(), x.end()
using namespace std;

signed main(){
  ios_base::sync_with_stdio(false);
  cin.tie(nullptr);
  int n;
  cin >> n;
  while (n--) {
    int n2, m, t = 0, total_s = 0, err = 0, first = 1;
    cin >> n2 >> m;
    while (n2--) {
      string s;
      cin >> s;
      int size = sz(s);
      if (first && size > m) err = 1;
      if (size <= m && total_s+size <= m) {
        t++;
        total_s += size;
      }
      first = 0;
    }
    cout << (err ? 0 : t) << '\n';
  }
  return 0;
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To generate a challenging test input that exposes the bug in the provided buggy code, we need to focus on edge cases that might cause the code to fail. The main issue in the buggy code is that it does not handle the case where the first word is longer than the strip length `m` correctly. Additionally, it does not handle the case where the sum of the lengths of the first few words exceeds `m` properly.

Here are the steps to create a challenging test input:

1. **First Word Longer than `m`**: This should immediately set `err` to 1, but the code does not handle this case correctly.
2. **Sum of Lengths Exceeding `m`**: The code should stop adding words once the total length exceeds `m`, but it might not do this correctly.

Let's create a test input that includes these scenarios:

```plaintext
4
1 5
abcde
2 5
abc
defg
3 5
a
bc
def
4 5
a
b
c
defgh
```

Explanation:
1. **First Test Case**: The first word is exactly 5 characters long. The expected output is 1.
2. **Second Test Case**: The first word is 3 characters long, and the second word is 4 characters long. The total length of both words is 7, which exceeds 5. The expected output is 1.
3. **Third Test Case**: The first word is 1 character long, the second word is 2 characters long, and the third word is 3 characters long. The total length of the first two words is 3, and the total length of the first three words is 6, which exceeds 5. The expected output is 2.
4. **Fourth Test Case**: The first three words are 1, 1, and 1 character long, respectively. The fourth word is 5 characters long. The total length of the first three words is 3, and adding the fourth word would make it 8, which exceeds 5. The expected output is 3.

This test input should expose the bug in the buggy code by forcing it to handle the edge cases where the first word is too long and where the sum of the lengths of the first few words exceeds the strip length.

4
1 5
abcde
2 5
abc
defg
3 5
a
bc
def
4 5
a
b
c
defgh


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
#include <bits/stdc++.h>
    #define int long long
    #define pb push_back
    using namespace std;
    signed main() {
        //freopen("rect.in", "r", stdin);
        //freopen("rect.out", "w", stdout);
        int T;
        cin >> T;
        while(T--){
            int n,m;
            cin >> n >> m;
            vector <int> a(n);
            for(int i = 0 ; i < n ; i++){
                string s;
                cin >> s;
                a[i] = s.size();
            }
            vector <int> pref(n);
            pref[0] = a[0];
            for(int i = 1;i < n; i++){
                pref[i] = pref[i - 1] + a[i];
            }
            int pos = 0;
            for(int i = 0 ; i < pref.size() ; i++){
                if(pref[i] == m){
                    pos = i + 1;
                }
                else if(pref[i] > m){
                    pos = i;
                    break;
                }
                else if(pref[i] < m){
                    continue;
                }
            }
            cout << pos << '\n';
        }
        return 0;
    }

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To generate a challenging test input that exposes the bug in the given buggy code, we need to focus on edge cases and scenarios that maximize the failure probability. Here are the steps to think through this:

1. **Identify the Bug**: The bug in the code lies in the logic for determining the position `pos` where the sum of the lengths of the words exceeds `m`. Specifically, the code incorrectly sets `pos` when `pref[i] == m` and does not handle the case where `pref[i] < m` correctly.

2. **Edge Cases**:
   - **Case 1**: All words are very short, and the sum of their lengths is less than `m`.
   - **Case 2**: There is a single word that is exactly `m` characters long.
   - **Case 3**: The first word is longer than `m`.
   - **Case 4**: The sum of the lengths of the first few words is exactly `m`.
   - **Case 5**: The sum of the lengths of the first few words is just over `m`.

3. **Constructing the Test Input**:
   - We will create a test input that includes all these edge cases to ensure the code is thoroughly tested.

Here is a small-scale test input that covers these cases:

```plaintext
5
3 10
a
b
c
1 10
a
5 10
a
b
c
d
e
1 5
abcde
2 5
abc
def
```

Explanation of the test cases:
1. **Case 1**: `3 10` with words `a`, `b`, `c`. The total length is `3` which is less than `10`. Expected output: `3`.
2. **Case 2**: `1 10` with word `a`. The total length is `1` which is less than `10`. Expected output: `1`.
3. **Case 3**: `5 10` with words `a`, `b`, `c`, `d`, `e`. The total length is `5` which is less than `10`. Expected output: `5`.
4. **Case 4**: `1 5` with word `abcde`. The total length is `5` which is exactly `5`. Expected output: `1`.
5. **Case 5**: `2 5` with words `abc`, `def`. The total length of the first word is `3` and the second word is `3`, so the sum is `6` which is more than `5`. Expected output: `1`.

This test input should help in exposing the bug in the buggy code.

5
3 10
a
b
c
1 10
a
5 10
a
b
c
d
e
1 5
abcde
2 5
abc
def


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
cases = int(input())

for i in range(cases):
    nm = input().split(" ")
    n = int(nm[0])
    m = int(nm[1])
    count = 0
    while count < n and m >= 0:
        m -= len(input())
        count += 1
    print(count if m == 0 else (count - 1))
    while count < n:
        input()
        count += 1

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
5 10
a
b
c
d
e
2 1
a
b
3 10
abc
def
ghi
```

3
5 10
a
b
c
d
e
2 1
a
b
3 10
abc
def
ghi


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
def code(num):
    for i in range(num):
        inp = input().split(" ")
        lst = [None]*int(inp[0])
        for j in range(int(inp[0])):
            lst[j] = input()

        limit = int(inp[1])
        count = 0
        while True:

            limit -= len(lst[count])
            if limit == 0:
                print(count+1)
                break
            elif limit < 0:
                print(count)
                break
            count += 1

code(int(input()))

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To expose the bug in the provided buggy code, we need to focus on edge cases that might cause the code to fail. The buggy code has a few potential issues:

1. **Edge Case: Empty Word** - The code does not handle empty words correctly.
2. **Edge Case: Very Long Words** - The code might fail if there are very long words that exceed the limit.
3. **Edge Case: Multiple Words with the Same Length** - The code might fail if there are multiple words with the same length.
4. **Edge Case: Words That Exactly Fit the Limit** - The code might fail if the words exactly fit the limit.

Let's create a test input that covers these edge cases:

1. **Empty Word**: This will test how the code handles an empty word.
2. **Very Long Word**: This will test how the code handles a word that is longer than the limit.
3. **Multiple Words with the Same Length**: This will test how the code handles multiple words with the same length.
4. **Words That Exactly Fit the Limit**: This will test how the code handles words that exactly fit the limit.

Here is the test input:

```plaintext
4
3 10
a
b
c
2 5
hello
world
3 10
abc
abc
abc
2 10
a
aaaaaaaaaa
```

Explanation:
1. **Test Case 1**:
   - Input: `3 10`
   - Words: `a`, `b`, `c`
   - Expected Output: `3` (All words fit within the limit of 10 characters)
2. **Test Case 2**:
   - Input: `2 5`
   - Words: `hello`, `world`
   - Expected Output: `1` (`hello` fits, `world` does not)
3. **Test Case 3**:
   - Input: `3 10`
   - Words: `abc`, `abc`, `abc`
   - Expected Output: `3` (All words fit exactly within the limit of 10 characters)
4. **Test Case 4**:
   - Input: `2 10`
   - Words: `a`, `aaaaaaaaaa`
   - Expected Output: `1` (`a` fits, `aaaaaaaaaa` does not)

This test input should help expose the bug in the provided buggy code.

4
3 10
a
b
c
2 5
hello
world
3 10
abc
abc
abc
2 10
a
aaaaaaaaaa


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
import java.util.*;

public class Main {
     public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int t = scanner.nextInt();

        while (t-- >0) {
             int ans=0;
             int current=0;
             int n=scanner.nextInt();
             int m = scanner.nextInt();
             int [] qais =new int[n];
             for (int i=0;i<n;i++){
                 String g=scanner.next();
                 qais[i]=g.length();
             }
             //Arrays.sort(qais);
             int p=0;
             while(m>current && p<n){
                 current+=qais[p++];
                 ans++;

             }
             if(current==m) System.out.println(ans);

             else System.out.println(--ans);

        }

        scanner.close();
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
5 10
abc
def
ghi
jkl
mno
5 11
abc
def
ghi
jkl
mno
5 12
abc
def
ghi
jkl
mno
```

3
5 10
abc
def
ghi
jkl
mno
5 11
abc
def
ghi
jkl
mno
5 12
abc
def
ghi
jkl
mno


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
import java.util.ArrayList;
import java.util.Scanner;

public class Solutions {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        ArrayList<String> words = new ArrayList<>();
        String minLengthString = null;
        int x;

        int t = scanner.nextInt();//t
        for(int i =0; i<t;i++){ //t
        x = 0;
        int count =0;

            words.clear();
            int n = scanner.nextInt();//n
            int m = scanner.nextInt();//m
                for(int j =0; j<n;j++){
                    String s = scanner.next();
                    words.add(s);
                }
            if(m>0 && n>0){
                while(true){
                    if(m>0){
                        minLengthString = words.get(count);
                    }else{
                        break;
                    }

                    if(minLengthString.length()<=m){
                        x+=1;
                        m-=minLengthString.length();
                        words.remove(minLengthString);
                    }else{
                        break;
                    }
                }
                System.out.println(x);

            }else {
                System.out.println(0);
            }

        }

    }

}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
5 10
a
b
c
d
e
4 10
long
word
test
case
3 5
abc
def
ghi
```

3
5 10
a
b
c
d
e
4 10
long
word
test
case
3 5
abc
def
ghi


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
#include<bits/stdc++.h>
using namespace std;

int main (){
    int t;
    cin >> t;
    while(t--) {
        int n, m;
        cin >> n >> m;
        string s[n];
        for (int i = 0; i < n; i++) {
            cin >> s[i];
        }
        int sum = 0;
        for (int i = 0; i < n; i++) {
            sum += s[i].length();
            if(sum > m) {
                cout << i << endl;
                break;
            }
            else if(sum == m) {
                cout << i+1 << endl;
                break;
            }
        }
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
5
1 10
a
1 1
a
2 10
a
b
2 1
ab
2 1
a
b
```


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
#include<bits/stdc++.h>
using namespace std;

typedef long long ll;

int main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);

    int t;
    cin >> t;
    while (t--)
    {
        int n, m;
        cin>> n >> m;
        vector<string> v(n);
        for(int i=0; i<n; i++) cin>> v[i];
        int ct=0;
        int ind;
        for(int i=0; i<n && m>=0; i++)
        {
            m=m-v[i].size();
            ct++;
            ind=i;
        }
        if(ind==n-1 && m==0) cout<< ct <<"\n";
        else cout<< --ct <<"\n";
    }
    return 0;
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
5
1 10
a
2 10
aa
bb
3 10
aaa
bbb
ccc
4 10
aaaa
bbbb
cccc
dddd
5 10
aaaaa
bbbbb
ccccc
ddddd
eeeee
```

5
1 10
a
2 10
aa
bb
3 10
aaa
bbb
ccc
4 10
aaaa
bbbb
cccc
dddd
5 10
aaaaa
bbbbb
ccccc
ddddd
eeeee


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
sint = lambda: int(input())
mint = lambda: map(int, input().split())
aint = lambda: list(map(int, input().split()))

for _ in range(int(input())):
    n, m = mint()
    words = []
    for _ in range(n):
        words.append(input())
    words_fit = 0
    total_count = 0
    i = 0
    while total_count < m:
        total_count += len(words[i])
        if total_count > m:
            break
        words_fit += 1
        i += 1
    print(words_fit)

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To generate a challenging test input that exposes the bug in the provided code, let's consider the following edge cases and scenarios:

1. **Very Long Words**: If the words are very long, the total length might exceed the strip length quickly.
2. **Short Words**: If the words are very short, many words might fit on the strip.
3. **Exact Fit**: If the total length of the words is exactly equal to the strip length.
4. **Edge Case with Single Word**: If the strip length is just enough for one word.
5. **Multiple Test Cases**: To ensure the code handles multiple test cases correctly.

Given these considerations, let's create a small-scale test input that includes these edge cases:

```plaintext
5
3 11
abc
def
ghi
2 10
a
b
4 10
a
b
c
d
3 10
abc
def
ghi
3 10
abc
def
ghi
```

### Explanation:
1. **Test Case 1**:
   - Words: `abc`, `def`, `ghi`
   - Strip length: 11
   - Expected output: 3 (since `abc` + `def` + `ghi` = 9 which is less than 11)

2. **Test Case 2**:
   - Words: `a`, `b`
   - Strip length: 10
   - Expected output: 2 (since `a` + `b` = 2 which is less than 10)

3. **Test Case 3**:
   - Words: `a`, `b`, `c`, `d`
   - Strip length: 10
   - Expected output: 4 (since `a` + `b` + `c` + `d` = 4 which is less than 10)

4. **Test Case 4**:
   - Words: `abc`, `def`, `ghi`
   - Strip length: 10
   - Expected output: 2 (since `abc` + `def` = 6 which is less than 10, but `abc` + `def` + `ghi` = 9 which is also less than 10, but the next word would exceed the limit)

5. **Test Case 5**:
   - Words: `abc`, `def`, `ghi`
   - Strip length: 10
   - Expected output: 2 (same as Test Case 4, but repeated to ensure the code handles multiple test cases correctly)

This test input covers various scenarios and should help expose any bugs in the provided code.

5
3 11
abc
def
ghi
2 10
a
b
4 10
a
b
c
d
3 10
abc
def
ghi
3 10
abc
def
ghi


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
t=int(input())
for _ in range(t):
    n,m=map(int,input().split())
    a=0
    b=0
    k=n
    e=0
    o=True
    for i in range(k):
        s=input()
        a+=len(s)
        b+=1
        if a>m and o:
            e=b-1
            o=False
        if a==m and o:
            e = b
            o = False
    print(e)

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
5
3 10
abc
def
ghi
2 10
abc
def
4 10
abc
def
ghi
jkl
3 3
abc
def
ghi
3 1
a
b
c
```

5
3 10
abc
def
ghi
2 10
abc
def
4 10
abc
def
ghi
jkl
3 3
abc
def
ghi
3 1
a
b
c


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class strip {
    public static StringTokenizer st = new StringTokenizer("");
    public static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    public static int nextInt() throws IOException {
        return Integer.parseInt(next());
    }
    public static String next() throws IOException {
        while (!st.hasMoreTokens()) {
            st = new StringTokenizer(br.readLine());
        }
        return st.nextToken();
    }

    public static void main(String args[]) throws IOException {

        PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));

        int num = nextInt();
        for (int i = 0; i < num; i++) {
            int wn = nextInt();
            int maxStrip = nextInt();
            int totalLen = 0;
            boolean done = false;
            for (int j = 0; j < wn; j++) {
                String word = next();
                int len = word.length();
                if (done) {
                    continue;
                }
                if (len + totalLen > maxStrip) {
                    out.println(j);
                    done = true;
                } else if (len + totalLen >= maxStrip) {
                    out.println(j + 1);
                    done = true;
                }
                totalLen += len;
            }
        }
        out.close();
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
```plaintext
3
5 10
a
b
c
d
e
5 10
aaaaa
bbbbb
ccccc
ddddd
eeeee
5 15
abc
def
ghi
jkl
mno
```

3
5 10
a
b
c
d
e
5 10
aaaaa
bbbbb
ccccc
ddddd
eeeee
5 15
abc
def
ghi
jkl
mno


**Task:**
Generate a challenging test input that exposes the bug in the buggy code of the algorithm problem:
Algorithm Problem:
Title: Line Breaks
time_limit_ms: 1000
memory_limit_mb: 256
Description: Kostya has a text $$$s$$$ consisting of $$$n$$$ words made up of Latin alphabet letters. He also has two strips on which he must write the text. The first strip can hold $$$m$$$ characters, while the second can hold as many as needed.

Kostya must choose a number $$$x$$$ and write the first $$$x$$$ words from $$$s$$$ on the first strip, while all the remaining words are written on the second strip. To save space, the words are written without gaps, but each word must be entirely on one strip.

Since space on the second strip is very valuable, Kostya asks you to choose the maximum possible number $$$x$$$ such that all words $$$s_1, s_2, \dots, s_x$$$ fit on the first strip of length $$$m$$$.

Input: The first line contains an integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n \le 50$$$; $$$1 \le m \le 500$$$) — the number of words in the list and the maximum number of characters that can be on the first strip.

The next $$$n$$$ lines contain one word $$$s_i$$$ of lowercase Latin letters, where the length of $$$s_i$$$ does not exceed $$$10$$$.

Output: For each test case, output the maximum number of words $$$x$$$ such that the first $$$x$$$ words have a total length of no more than $$$m$$$.

Examples:
input:
5
3 1
a
b
c
2 9
alpha
beta
4 12
hello
world
and
codeforces
3 2
ab
c
d
3 2
abc
ab
a
output:
1
2
2
1
0

Note:

Buggy Code:
import java.util.Scanner;
public class Sol{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        int i,n,m,t = sc.nextInt(),sum;
        int[] arr;
        while(t-- != 0)
        {
            n = sc.nextInt();
            m = sc.nextInt();
            arr = new int[n];
            sum = 0;
            for( i = 0 ; i < n ; i++ )
            arr[i] = sc.next().length();
            for( i = 0 ; i < n ; i++ )
            {
                sum += arr[i];
                if(sum >= m)
                break;
            }
            if(sum > m)
            System.out.println(i);
            else
            System.out.println(i+1);
        }
    }
}

**Instructions:**
- Focus on edge cases or scenarios that maximize the failure probability in faulty solutions.
- Due to the output length limit, you should generate a **small-scale** test input that is **complete and valid**.
- Output the test input directly, not code to generate it.

**Output format:**
```plaintext
{test input}
```

Think step by step.

Response:
To create a challenging test input that exposes the bug in the provided code, we need to focus on edge cases where the sum of the lengths of the words is very close to the limit `m`. The code has a logical issue where it increments `i` even when the sum exceeds `m`, leading to incorrect output.

Here are the steps to create a challenging test case:

1. **Small `n` and `m` values**: Use small values for `n` and `m` to keep the test case manageable.
2. **Words with lengths just under `m`**: Create a list of words where the sum of their lengths is just under `m` for the first `x` words, and the next word pushes the sum over `m`.
3. **Edge case with `m` exactly equal to the sum of the first `x` words**: Create a test case where `m` is exactly equal to the sum of the lengths of the first `x` words.

Let's construct a test case based on these steps:

```plaintext
1
5 10
a
b
c
d
e
```

Explanation:
- `t = 1` (one test case)
- `n = 5` (five words)
- `m = 10` (the first strip can hold 10 characters)
- Words: `a`, `b`, `c`, `d`, `e` (lengths are 1, 1, 1, 1, 1 respectively)

In this test case:
- The sum of the lengths of the first 4 words is 4 (which is less than 10).
- Adding the 5th word makes the sum 5, which is still less than 10.
- The correct output should be 4, but the buggy code will output 5 because it increments `i` even when the sum exceeds `m`.

This test case will expose the bug in the code.