output_description: Print the number of the Shichi-Go numbers that are divisors of N!.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      N
attempt: n = int(input())
  
  l = [0]*(n+1)
  for i in range(2, n+1):
    cur = i
    for j in range(2, i+1):
      while cur % j == 0:
        cur //= j
        l[j] == 1
  
  def num(s):
    return len(list(filter(lambda x: m-1 =< x, l)))
  
  print(num(75)+num(25)*(num(3)-1)+num(15)*(num(5)-1)+(num(5)*(num(5)-1)*(num(3)-2))//2)
  
problem_description: Statement
  
  You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ...
  \times N), how many _Shichi-Go numbers_ (literally "Seven-Five numbers") are
  there?
  
  Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.
samples: [{"input": "9", "output": "0\n    \n\nThere are no Shichi-Go numbers among the divisors of 9! = 1 \\times 2 \\times\n... \\times 9 = 362880.\n\n* * *"}, {"input": "10", "output": "1\n    \n\nThere is one Shichi-Go number among the divisors of 10! = 3628800: 32400.\n\n* * *"}, {"input": "100", "output": "543"}]