output_description: If it is possible to change S into `AKIHABARA`, print `YES`; otherwise, print
  `NO`.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      S
attempt: # coding: utf-8
  import re
  import math
  from collections import defaultdict
  import itertools
  from copy import deepcopy
  import random
  from heapq import heappop, heappush
  import time
  import os
  import queue
  import sys
  import datetime
  from functools import lru_cache
  
  readline = sys.stdin.readline
  sys.setrecursionlimit(2000)
  # import numpy as np
  alphabet = "abcdefghijklmnopqrstuvwxyz"
  mod = int(10**9 + 7)
  inf = int(10**20)
  
  
  def yn(b):
      if b:
          print("yes")
      else:
          print("no")
  
  
  def Yn(b):
      if b:
          print("Yes")
      else:
          print("No")
  
  
  def YN(b):
      if b:
          print("YES")
      else:
          print("NO")
  
  
  class union_find:
      def __init__(self, n):
          self.n = n
          self.P = [a for a in range(N)]
          self.rank = [0] * n
  
      def find(self, x):
          if x != self.P[x]:
              self.P[x] = self.find(self.P[x])
          return self.P[x]
  
      def same(self, x, y):
          return self.find(x) == self.find(y)
  
      def link(self, x, y):
          if self.rank[x] < self.rank[y]:
              self.P[x] = y
          elif self.rank[y] < self.rank[x]:
              self.P[y] = x
          else:
              self.P[x] = y
              self.rank[y] += 1
  
      def unite(self, x, y):
          self.link(self.find(x), self.find(y))
  
      def size(self):
          S = set()
          for a in range(self.n):
              S.add(self.find(a))
          return len(S)
  
  
  def is_power(a, b):  # aはbの累乗数か
      now = b
      while now < a:
          now *= b
      if now == a:
          return True
      else:
          return False
  
  
  def bin_(num, size):
      A = [0] * size
      for a in range(size):
          if (num >> (size - a - 1)) & 1 == 1:
              A[a] = 1
          else:
              A[a] = 0
      return A
  
  
  def get_facs(n, mod_=0):
      A = [1] * (n + 1)
      for a in range(2, len(A)):
          A[a] = A[a - 1] * a
          if mod > 0:
              A[a] %= mod_
      return A
  
  
  def comb(n, r, mod, fac):
      if n - r < 0:
          return 0
      return (fac[n] * pow(fac[n - r], mod - 2, mod) * pow(fac[r], mod - 2, mod)) % mod
  
  
  def next_comb(num, size):
      x = num & (-num)
      y = num + x
      z = num & (~y)
      z //= x
      z = z >> 1
      num = y | z
      if num >= (1 << size):
          return False
      else:
          return num
  
  
  def get_primes(n, type="int"):
      A = [True] * (n + 1)
      A[0] = False
      A[1] = False
      for a in range(2, n + 1):
          if A[a]:
              for b in range(a * 2, n + 1, a):
                  A[b] = False
      if type == "bool":
          return A
      B = []
      for a in range(n + 1):
          if A[a]:
              B.append(a)
      return B
  
  
  def is_prime(num):
      if num <= 2:
          return False
      i = 2
      while i * i <= num:
          if num % i == 0:
              return False
          i += 1
      return True
  
  
  def ifelse(a, b, c):
      if a:
          return b
      else:
          return c
  
  
  def join(A, c=" "):
      n = len(A)
      A = list(map(str, A))
      s = ""
      for a in range(n):
          s += A[a]
          if a < n - 1:
              s += c
      return s
  
  
  def factorize(n, type_="dict"):
      b = 2
      list_ = []
      while b * b <= n:
          while n % b == 0:
              n //= b
              list_.append(b)
          b += 1
      if n > 1:
          list_.append(n)
      if type_ == "dict":
          dic = {}
          for a in list_:
              if a in dic:
                  dic[a] += 1
              else:
                  dic[a] = 1
          return dic
      elif type_ == "list":
          return list_
      else:
          return None
  
  
  def floor_(n, x=1):
      return x * (n // x)
  
  
  def ceil_(n, x=1):
      return x * ((n + x - 1) // x)
  
  
  def hani(x, min_, max_):
      ret = x
      if x < min_:
          ret = min_
      if x > max_:
          ret = max_
      return ret
  
  
  def seifu(x):
      return x // abs(x)
  
  
  ###################################################
  def main():
      s = "AKIHABARA"
      ss = input()
      f = True
      if len(list(set(s) - set(ss))) != 1 or list(set(s) - set(ss))[0] != "A":
          f = False
      if set(ss) - set(s):
          f = False
      YN(f)
  
  
  main()
  
problem_description: Statement
  
  You are given a string S.
  
  Takahashi can insert the character `A` at any position in this string any
  number of times.
  
  Can he change S into `AKIHABARA`?
samples: [{"input": "KIHBR", "output": "YES\n    \n\nInsert one `A` at each of the four positions: the beginning, immediately after\n`H`, immediately after `B` and the end.\n\n* * *"}, {"input": "AKIBAHARA", "output": "NO\n    \n\nThe correct spell is `AKIHABARA`.\n\n* * *"}, {"input": "AAKIAHBAARA", "output": "NO"}]