output_description: Print the minimum possible number of subarrays after division of A.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      N
      A_1 A_2 ... A_N
attempt: n = int(input())
  l = [0] + list(map(int, input().split())) + [0]
  a, s = 0, 0
  for i in range(1, n + 1):
      fa, fs = 1, 1
      if l[i - 1] <= l[i]:
          fa = 0
      if l[n - i] >= l[n - i + 1]:
          fs = 0
      a += fa
      s += fs
  print(min(a, s) + 1)
  
problem_description: Statement
  
  You are given an array A of length N. Your task is to divide it into several
  contiguous subarrays. Here, all subarrays obtained must be sorted in either
  non-decreasing or non-increasing order. At least how many subarrays do you
  need to divide A into?
samples: [{"input": "6\n    1 2 3 2 2 1", "output": "2\n    \n\nOne optimal solution is to divide the array into [1,2,3] and [2,2,1].\n\n* * *"}, {"input": "9\n    1 2 1 2 1 2 1 2 1", "output": "5\n    \n\n* * *"}, {"input": "7\n    1 2 3 2 1 999999999 1000000000", "output": "3"}]