output_description: If 9 is contained in the decimal notation of N, print `Yes`; if not, print
  `No`.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      N
attempt: import math, string, itertools, fractions, heapq, collections, re, array, bisect, sys, random, time, copy, functools
  
  sys.setrecursionlimit(10**7)
  inf = 10**20
  gosa = 1.0 / 10**10
  mod = 10**9 + 7
  
  
  def LI():
      return [int(x) for x in sys.stdin.readline().split()]
  
  
  def LI_():
      return [int(x) - 1 for x in sys.stdin.readline().split()]
  
  
  def LF():
      return [float(x) for x in sys.stdin.readline().split()]
  
  
  def LS():
      return sys.stdin.readline().split()
  
  
  def I():
      return int(sys.stdin.readline())
  
  
  def F():
      return float(sys.stdin.readline())
  
  
  def S():
      return input()
  
  
  def main():
      n = I()
      if n % 10 == 9 or n // 10 == 9:
          return "Yes"
  
      return "No"
  
  
  print(main())
  
problem_description: Statement
  
  It is September 9 in Japan now.
  
  You are given a two-digit integer N. Answer the question: Is 9 contained in
  the decimal notation of N?
samples: [{"input": "29", "output": "Yes\n    \n\nThe one's digit of 29 is 9.\n\n* * *"}, {"input": "72", "output": "No\n    \n\n72 does not contain 9.\n\n* * *"}, {"input": "91", "output": "Yes"}]