output_description: If there is an integer C between 1 and 3 that satisfies the condition, print
  `Yes`; otherwise, print `No`.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      A B
attempt: list1 = list(map(int, input().split()))
  h = list1[0]
  w = list1[1]
  a = list()
  i = 0
  n = 0
  ans = list()
  while i <= h - 1:
      a.append(list(map(int, input().split())))
      i += 1
  for i in range(h):
      for j in range(w - 1):
          if a[i][j] % 2 != 0:
              a[i][j] -= 1
              a[i][j + 1] += 1
              n += 1
              ans.append([i + 1, j + 1, i + 1, j + 2])
  for i in range(h - 1):
      if a[i][w - 1] % 2 != 0:
          a[i][w - 1] -= 1
          a[i + 1][w - 1] += 1
          ans.append([i + 1, w, i + 2, w])
          n += 1
  print(n)
  for i in range(n):
      print(ans[i][0], ans[i][1], ans[i][2], ans[i][3])
  
problem_description: Statement
  
  You are given integers A and B, each between 1 and 3 (inclusive).
  
  Determine if there is an integer C between 1 and 3 (inclusive) such that A
  \times B \times C is an odd number.
samples: [{"input": "3 1", "output": "Yes\n    \n\nLet C = 3. Then, A \\times B \\times C = 3 \\times 1 \\times 3 = 9, which is an\nodd number.\n\n* * *"}, {"input": "1 2", "output": "No\n    \n\n* * *"}, {"input": "2 2", "output": "No"}]