output_description: Print the number of the positive divisors of N!, modulo 10^9+7.
  
  * * *
input_description: The input is given from Standard Input in the following format:
  
      
      
      N
attempt: def kjsoinscount(n):
      res_ls = []
      for i in range(n):  # nの階乗
          if i + 1 > 1:
              N = i + 1
              for j in range(i + 1):  # 階乗の各要素について素因数分解
                  if j + 1 > 1:
                      while N % (j + 1) == 0:
                          res_ls.append(j + 1)
                          N = N / (j + 1)
      return res_ls + [1]
  
  
  def yakspattern(soins_ls):
      import itertools
      from operator import mul
      from functools import reduce
  
      yaks_ls = {}
      for i in range(len(soins_ls)):
          if i > 0:
              comb_tup = itertools.combinations(soins_ls, i + 1)
              for j in comb_tup:
                  # print(j)
                  a = reduce(mul, j)
                  a = str(a)
                  if a not in yaks_ls:
                      # print(j)
                      yaks_ls[a] = "ok"
      for i in soins_ls:
          q = str(i)
          yaks_ls[q] = "ok"
      yaks_ls
      return yaks_ls.keys
  
  
  def kjyakscount(n):
      import itertools
      from operator import mul
      from functools import reduce
  
      yaks_ls = []
      kj_ls = [i + 1 for i in range(n)]
      for i in range(n):
          if i > 0:
              comb_tup = itertools.combinations(kj_ls, i + 1)
              for j in comb_tup:
                  # print(j)
                  yaks_ls.append(reduce(mul, j))
                  # print(set(yaks_ls))
      return set(kj_ls + yaks_ls)
      # return(yaks_ls.extend(kj_ls))
  
  
  n = int(input())
  kj = 1
  for i in range(n):
      kj = kj * (i + 1)
  
  print(len(yakspattern(kjsoinscount(n))))
  
problem_description: Statement
  
  You are given an integer N. Find the number of the positive divisors of N!,
  modulo 10^9+7.
samples: [{"input": "3", "output": "4\n    \n\nThere are four divisors of 3! =6: 1, 2, 3 and 6. Thus, the output should be 4.\n\n* * *"}, {"input": "6", "output": "30\n    \n\n* * *"}, {"input": "1000", "output": "972926972"}]