output_description: Print the number of days from 2018-1-1 through 2018-a-b that are Takahashi.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      a b
attempt: # import
  import numpy as np
  import sys
  
  sys.setrecursionlimit(10**6)
  
  # input
  H, W = map(int, input().split())
  
  Mtmp = []
  for _ in range(H):
      tmp = list(input())
      Mtmp.append(tmp)
  
  M = np.array(Mtmp)
  S = np.array([[0] * W] * H)
  
  # print(M)
  
  digtmp = np.array([[0, 1], [1, 0], [0, -1], [-1, 0]])
  
  
  def dfs(i, j):
      global ngflag
      global searchflag
      if S[i, j] == 1:
          return
      S[i, j] = 1
      if M[i, j] == ".":
          return
      # print("i:{}, j:{}".format(i, j))
      searchflag = 1
      dig = digtmp + np.array([i, j])
      for d in dig:
          if 0 <= d[0] < H and 0 <= d[1] < W:
              if M[d[0], d[1]] == "#":
                  ngflag = 0
                  dfs(d[0], d[1])
  
  
  searchflag = 0
  ngflag = 1
  
  while True:
      if 0 not in S:
          if M[target[0], target[1]] == ".":
              ngflag = 0
          break
      target = list(zip(*np.where(S == 0)))[0]
      # print("sf:{}, ng:{}".format(searchflag, ngflag))
      if M[target[0], target[1]] == "#":
          ngflag = 1
      dfs(target[0], target[1])
      if M[target[0], target[1]] == "#" and searchflag == 1 and ngflag == 1:
          break
  
  
  # print("sf:{}, ng:{}".format(searchflag, ngflag))
  
  if searchflag == 1 and ngflag == 0:
      ans = "Yes"
  elif searchflag == 1 and ngflag == 1:
      ans = "No"
  else:
      ans = "Yes"
  
  print(ans)
  
problem_description: Statement
  
  In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the
  "year-month-day" order, or the "month-day" order without the year.  
  For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.
  
  In this country, a date is called _Takahashi_ when the month and the day are
  equal as numbers. For example, 5-5 is Takahashi.  
  How many days from 2018-1-1 through 2018-a-b are Takahashi?
samples: [{"input": "5 5", "output": "5\n    \n\nThere are five days that are Takahashi: 1-1, 2-2, 3-3, 4-4 and 5-5.\n\n* * *"}, {"input": "2 1", "output": "1\n    \n\nThere is only one day that is Takahashi: 1-1.\n\n* * *"}, {"input": "11 30", "output": "11\n    \n\nThere are eleven days that are Takahashi: 1-1, 2-2, 3-3, 4-4, 5-5, 6-6, 7-7,\n8-8, 9-9, 10-10 and 11-11."}]