output_description: Print the integer obtained by replacing each occurrence of `1` with `9` and
  each occurrence of `9` with `1` in n.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      n
attempt: N = int(input())
  num = []
  while N != 0:
      num.append(N % 10)
      N -= N % 10
      N /= 10
  num.reverse()
  a = num[0]
  b = num[1]
  c = num[2]
  if a == b >= c:
      print(int(100 * a + 11 * b))
  if a == b < c or a < b:
      print(int((a + 1) * 111))
  if a > b:
      print(int(a * 111))
  
problem_description: Statement
  
  Cat Snuke is learning to write characters. Today, he practiced writing digits
  `1` and `9`, but he did it the other way around.
  
  You are given a three-digit integer n written by Snuke. Print the integer
  obtained by replacing each digit `1` with `9` and each digit `9` with `1` in
  n.
samples: [{"input": "119", "output": "991\n    \n\nReplace the `9` in the ones place with `1`, the `1` in the tens place with `9`\nand the `1` in the hundreds place with `9`. The answer is `991`.\n\n* * *"}, {"input": "999", "output": "111"}]