output_description: Print the number of Taro's paths from Square (1, 1) to (H, W), modulo 10^9 +
  7.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      H W
      a_{1, 1}\ldotsa_{1, W}
      :
      a_{H, 1}\ldotsa_{H, W}
attempt: # -*- coding: utf-8 -*-
  
  #############
  # Libraries #
  #############
  
  import sys
  
  input = sys.stdin.readline
  
  import math
  
  # from math import gcd
  import bisect
  import heapq
  from collections import defaultdict
  from collections import deque
  from collections import Counter
  from functools import lru_cache
  
  #############
  # Constants #
  #############
  
  MOD = 10**9 + 7
  INF = float("inf")
  AZ = "abcdefghijklmnopqrstuvwxyz"
  
  #############
  # Functions #
  #############
  
  
  ######INPUT######
  def I():
      return int(input().strip())
  
  
  def S():
      return input().strip()
  
  
  def IL():
      return list(map(int, input().split()))
  
  
  def SL():
      return list(map(str, input().split()))
  
  
  def ILs(n):
      return list(int(input()) for _ in range(n))
  
  
  def SLs(n):
      return list(input().strip() for _ in range(n))
  
  
  def ILL(n):
      return [list(map(int, input().split())) for _ in range(n)]
  
  
  def SLL(n):
      return [list(map(str, input().split())) for _ in range(n)]
  
  
  ######OUTPUT######
  def P(arg):
      print(arg)
      return
  
  
  def Y():
      print("Yes")
      return
  
  
  def N():
      print("No")
      return
  
  
  def E():
      exit()
  
  
  def PE(arg):
      print(arg)
      exit()
  
  
  def YE():
      print("Yes")
      exit()
  
  
  def NE():
      print("No")
      exit()
  
  
  #####Shorten#####
  def DD(arg):
      return defaultdict(arg)
  
  
  #####Inverse#####
  def inv(n):
      return pow(n, MOD - 2, MOD)
  
  
  ######Combination######
  kaijo_memo = []
  
  
  def kaijo(n):
      if len(kaijo_memo) > n:
          return kaijo_memo[n]
      if len(kaijo_memo) == 0:
          kaijo_memo.append(1)
      while len(kaijo_memo) <= n:
          kaijo_memo.append(kaijo_memo[-1] * len(kaijo_memo) % MOD)
      return kaijo_memo[n]
  
  
  gyaku_kaijo_memo = []
  
  
  def gyaku_kaijo(n):
      if len(gyaku_kaijo_memo) > n:
          return gyaku_kaijo_memo[n]
      if len(gyaku_kaijo_memo) == 0:
          gyaku_kaijo_memo.append(1)
      while len(gyaku_kaijo_memo) <= n:
          gyaku_kaijo_memo.append(
              gyaku_kaijo_memo[-1] * pow(len(gyaku_kaijo_memo), MOD - 2, MOD) % MOD
          )
      return gyaku_kaijo_memo[n]
  
  
  def nCr(n, r):
      if n == r:
          return 1
      if n < r or r < 0:
          return 0
      ret = 1
      ret = ret * kaijo(n) % MOD
      ret = ret * gyaku_kaijo(r) % MOD
      ret = ret * gyaku_kaijo(n - r) % MOD
      return ret
  
  
  ######Factorization######
  def factorization(n):
      arr = []
      temp = n
      for i in range(2, int(-(-(n**0.5) // 1)) + 1):
          if temp % i == 0:
              cnt = 0
              while temp % i == 0:
                  cnt += 1
                  temp //= i
              arr.append([i, cnt])
      if temp != 1:
          arr.append([temp, 1])
      if arr == []:
          arr.append([n, 1])
      return arr
  
  
  #####MakeDivisors######
  def make_divisors(n):
      divisors = []
      for i in range(1, int(n**0.5) + 1):
          if n % i == 0:
              divisors.append(i)
              if i != n // i:
                  divisors.append(n // i)
      return divisors
  
  
  #####MakePrimes######
  def make_primes(N):
      max = int(math.sqrt(N))
      seachList = [i for i in range(2, N + 1)]
      primeNum = []
      while seachList[0] <= max:
          primeNum.append(seachList[0])
          tmp = seachList[0]
          seachList = [i for i in seachList if i % tmp != 0]
      primeNum.extend(seachList)
      return primeNum
  
  
  #####GCD#####
  def gcd(a, b):
      while b:
          a, b = b, a % b
      return a
  
  
  #####LCM#####
  def lcm(a, b):
      return a * b // gcd(a, b)
  
  
  #####BitCount#####
  def count_bit(n):
      count = 0
      while n:
          n &= n - 1
          count += 1
      return count
  
  
  #####ChangeBase#####
  def base_10_to_n(X, n):
      if X // n:
          return base_10_to_n(X // n, n) + [X % n]
      return [X % n]
  
  
  def base_n_to_10(X, n):
      return sum(int(str(X)[-i - 1]) * n**i for i in range(len(str(X))))
  
  
  def base_10_to_n_without_0(X, n):
      X -= 1
      if X // n:
          return base_10_to_n_without_0(X // n, n) + [X % n]
      return [X % n]
  
  
  #####IntLog#####
  def int_log(n, a):
      count = 0
      while n >= a:
          n //= a
          count += 1
      return count
  
  
  #############
  # Main Code #
  #############
  
  H, W = IL()
  data = SLs(H)
  
  dp = [[0 for i in range(W)] for j in range(H)]
  dp[0][0] = 1
  
  for j in range(1, H):
      if data[j][0] != "#":
          dp[j][0] = dp[j - 1][0]
  for i in range(1, W):
      if data[0][i] != "#":
          dp[0][i] = dp[0][i - 1]
  
  for j in range(1, H):
      for i in range(1, W):
          if data[i][j] != "#":
              dp[i][j] = dp[i - 1][j] + dp[i][j - 1]
              dp[i][j] %= MOD
  
  print(dp[-1][-1])
  
problem_description: Statement
  
  There is a grid with H horizontal rows and W vertical columns. Let (i, j)
  denote the square at the i-th row from the top and the j-th column from the
  left.
  
  For each i and j (1 \leq i \leq H, 1 \leq j \leq W), Square (i, j) is
  described by a character a_{i, j}. If a_{i, j} is `.`, Square (i, j) is an
  empty square; if a_{i, j} is `#`, Square (i, j) is a wall square. It is
  guaranteed that Squares (1, 1) and (H, W) are empty squares.
  
  Taro will start from Square (1, 1) and reach (H, W) by repeatedly moving right
  or down to an adjacent empty square.
  
  Find the number of Taro's paths from Square (1, 1) to (H, W). As the answer
  can be extremely large, find the count modulo 10^9 + 7.
samples: [{"input": "3 4\n    ...#\n    .#..\n    ....", "output": "3\n    \n\nThere are three paths as follows:\n\n![](https://img.atcoder.jp/dp/grid_0_0_muffet.png)\n\n* * *"}, {"input": "5 2\n    ..\n    #.\n    ..\n    .#\n    ..", "output": "0\n    \n\nThere may be no paths.\n\n* * *"}, {"input": "5 5\n    ..#..\n    .....\n    #...#\n    .....\n    ..#..", "output": "24\n    \n\n* * *"}, {"input": "20 20\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................\n    ....................", "output": "345263555\n    \n\nBe sure to print the count modulo 10^9 + 7."}]