output_description: Print the integer obtained by replacing each occurrence of `1` with `9` and
  each occurrence of `9` with `1` in n.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      n
attempt: n = input()
  v = input().split()
  # vin=[int(i) for i in v]
  nlis = list(n)
  nint = int(n)
  part_num = int((nint / 2))
  ev_num = []
  for i in range(part_num):
      ev = 2 * i
      ev_num.extend(v[ev])
  count_ev = []
  for i in range(part_num):
      count = 0
      count_ev.append(ev_num.count(ev_num[i]))
  
  ans_ev = min(count_ev)
  
  od_num = []
  for i in range(part_num):
      od = (2 * i) + 1
      od_num.extend(v[od])
  count_od = []
  for i in range(part_num):
      count = 0
      count_od.append(od_num.count(od_num[i]))
  ans_od = min(count_od)
  
  if v.count(v[0]) == len(v):
      ans = part_num
  else:
      ans = ans_ev + ans_od
  print(ans)
  
problem_description: Statement
  
  Cat Snuke is learning to write characters. Today, he practiced writing digits
  `1` and `9`, but he did it the other way around.
  
  You are given a three-digit integer n written by Snuke. Print the integer
  obtained by replacing each digit `1` with `9` and each digit `9` with `1` in
  n.
samples: [{"input": "119", "output": "991\n    \n\nReplace the `9` in the ones place with `1`, the `1` in the tens place with `9`\nand the `1` in the hundreds place with `9`. The answer is `991`.\n\n* * *"}, {"input": "999", "output": "111"}]