output_description: Print the value \sum_{K=1}^N K\times f(K).
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      N
attempt: n = int(open(0))
  print(sum(n // i * (n // i + 1) * i // 2 for i in range(1, n + 1)))
  
problem_description: Statement
  
  For a positive integer X, let f(X) be the number of positive divisors of X.
  
  Given a positive integer N, find \sum_{K=1}^N K\times f(K).
samples: [{"input": "4", "output": "23\n    \n\nWe have f(1)=1, f(2)=2, f(3)=2, and f(4)=3, so the answer is 1\\times 1 +\n2\\times 2 + 3\\times 2 + 4\\times 3 =23.\n\n* * *"}, {"input": "100", "output": "26879\n    \n\n* * *"}, {"input": "10000000", "output": "838627288460105\n    \n\nWatch out for overflows."}]