output_description: If \sqrt{a} + \sqrt{b} < \sqrt{c}, print `Yes`; otherwise, print `No`.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      a \ b \ c
attempt: #!python3.4
  # -*- coding: utf-8 -*-
  # panasonic2020/panasonic2020_c
  import sys
  from math import sqrt
  
  s2nn = lambda s: [int(c) for c in s.split(" ")]
  ss2nn = lambda ss: [int(s) for s in list(ss)]
  ss2nnn = lambda ss: [s2nn(s) for s in list(ss)]
  i2s = lambda: sys.stdin.readline().rstrip()
  i2n = lambda: int(i2s())
  i2nn = lambda: s2nn(i2s())
  ii2ss = lambda n: [i2s() for _ in range(n)]
  ii2nn = lambda n: ss2nn(ii2ss(n))
  ii2nnn = lambda n: ss2nnn(ii2ss(n))
  
  
  def main():
      a, b, c = i2nn()
      print("Yes" if sqrt(a) + sqrt(b) < sqrt(c) else "No")
      return
  
  
  main()
  
problem_description: Statement
  
  Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?
samples: [{"input": "2 3 9", "output": "No\n    \n\n\\sqrt{2} + \\sqrt{3} < \\sqrt{9} does not hold.\n\n* * *"}, {"input": "2 3 10", "output": "Yes\n    \n\n\\sqrt{2} + \\sqrt{3} < \\sqrt{10} holds."}]