output_description: Print the answer as an integer.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      A B
attempt: def solve(a, b):
      if b == 0 or a == "0":
          return 0
      alist = list(reversed(a))
      count = 0
      k = 0
      res = []
      for s in alist:
          tmp = int(s)
          if count < 2:
              k += tmp * b * 10 ** (count)
          else:
              k += tmp * b * 100
              k = int(k)
              res.append(str(k % 10))
              k = k // 10
          count += 1
      k = int(k)
      while k > 0:
          res.append(str(k % 10))
          k = k // 10
      res.reverse()
      ans = "".join(res)
      if ans == "":
          return 0
      return ans
  
  
  if __name__ == "__main__":
      s = input().split()
      a = s[0]
      b = float(s[1])
      print(solve(a, b))
  
problem_description: Statement
  
  Compute A \times B, truncate its fractional part, and print the result as an
  integer.
samples: [{"input": "198 1.10", "output": "217\n    \n\nWe have 198 \\times 1.10 = 217.8. After truncating the fractional part, we have\nthe answer: 217.\n\n* * *"}, {"input": "1 0.01", "output": "0\n    \n\n* * *"}, {"input": "1000000000000000 9.99", "output": "9990000000000000"}]