output_description: Among A, B and C, print the integer that is different from the rest.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      A B C
attempt: n, k = map(int, input().split())
  
  x = [0 for _ in range(n)]
  y = [0 for _ in range(n)]
  for i in range(n):
      x[i], y[i] = map(int, input().split())
  
  min_x = min(x)
  min_y = min(y)
  for i in range(n):
      x[i] -= min_x
      y[i] -= min_y
  
  sx = sorted(x)
  sy = sorted(y)
  
  if n == k:
      print(sx[n - 1] * sy[n - 1])
      exit()
  
  d = [[0 for _ in range(n + 1)] for _ in range(n + 1)]
  for i in range(n):
      d[sx.index(x[i]) + 1][sy.index(y[i]) + 1] = 1
  
  # for p in d: print(p)
  
  for i in range(n + 1):
      for j in range(1, n + 1):
          d[i][j] += d[i][j - 1]
  
  for i in range(n + 1):
      for j in range(1, n + 1):
          d[j][i] += d[j - 1][i]
  
  sx = [0] + sx
  sy = [0] + sy
  
  a = 0
  b = 1
  ans = sx[n] * sy[n]
  temp = 0
  for p in range(n):
      for q in range(p + 1, n + 1):
          for a in range(n):
              for b in range(a + 1, n + 1):
                  temp = d[q][b] - d[q][a] - d[p][b] + d[p][a]
                  if temp >= k:
                      break
              if temp >= k:
                  ans = min(
                      ans, max(1, (sx[b] - sx[a + 1])) * max(1, (sy[q] - sy[p + 1]))
                  )
  
  print(ans)
  
problem_description: Statement
  
  You are given three integers, A, B and C.  
  Among them, two are the same, but the remaining one is different from the
  rest.  
  For example, when A=5,B=7,C=5, A and C are the same, but B is different.  
  Find the one that is different from the rest among the given three integers.
samples: [{"input": "5 7 5", "output": "7\n    \n\nThis is the same case as the one in the statement.\n\n* * *"}, {"input": "1 1 7", "output": "7\n    \n\nIn this case, C is the one we seek.\n\n* * *"}, {"input": "-100 100 100", "output": "-100"}]