output_description: Replace the first four characters in S with `2018` and print it.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      S
attempt: import copy
  
  n, hp = map(int, input().split(" "))
  la = [0 for i in range(n)]
  lb = [0 for i in range(n)]
  for i in range(n):
      la[i], lb[i] = map(int, input().split(" "))
  cnt = 0
  ma = max(la)
  lma = [i for i, x in enumerate(la) if x == ma]
  mib = 10**9
  for i in lma:
      if lb[i] < mib:
          mib = lb[i]
          k = i
  tmp = copy.deepcopy(lb)
  while max(tmp) > ma:
      hp -= max(tmp)
      tmp.remove(max(tmp))
      cnt += 1
      if hp < 0:
          print(cnt)
          exit(0)
  if lb[k] > ma:
      hp += lb[k]
  if lb[k] > ma:
      hp -= lb[k]
      cnt += 1
  if hp % ma == 0:
      print(cnt + int(hp / ma))
  else:
      print(cnt + int(hp / ma) + 1)
  
problem_description: Statement
  
  On some day in January 2018, Takaki is writing a document. The document has a
  column where the current date is written in `yyyy/mm/dd` format. For example,
  January 23, 2018 should be written as `2018/01/23`.
  
  After finishing the document, she noticed that she had mistakenly wrote `2017`
  at the beginning of the date column. Write a program that, when the string
  that Takaki wrote in the date column, S, is given as input, modifies the first
  four characters in S to `2018` and prints it.
samples: [{"input": "2017/01/07", "output": "2018/01/07\n    \n\n* * *"}, {"input": "2017/01/31", "output": "2018/01/31"}]