output_description: Print the answer.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      N K
      A_1 A_2 \dots A_N
attempt: def getProduct(n, m):
      product = 1
      for i in range(2, len(n)):
          product *= pow(n[i], m[i])
      return product
  
problem_description: Statement
  
  We have N integers A_1, A_2, ..., A_N.
  
  There are \frac{N(N-1)}{2} ways to choose two of them and form a pair. If we
  compute the product of each of those pairs and sort the results in ascending
  order, what will be the K-th number in that list?
samples: [{"input": "4 3\n    3 3 -4 -2", "output": "-6\n    \n\nThere are six ways to form a pair. The products of those pairs are 9, -12, -6,\n-12, -6, 8.\n\nSorting those numbers in ascending order, we have -12, -12, -6, -6, 8, 9. The\nthird number in this list is -6.\n\n* * *"}, {"input": "10 40\n    5 4 3 2 -1 0 0 0 0 0", "output": "6\n    \n\n* * *"}, {"input": "30 413\n    -170202098 -268409015 537203564 983211703 21608710 -443999067 -937727165 -97596546 -372334013 398994917 -972141167 798607104 -949068442 -959948616 37909651 0 886627544 -20098238 0 -948955241 0 -214720580 277222296 -18897162 834475626 0 -425610555 110117526 663621752 0", "output": "448283280358331064"}]