output_description: Print the answers in order, with space in between.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      N M K
      A_1 B_1
      \vdots
      A_M B_M
      C_1 D_1
      \vdots
      C_K D_K
attempt: N, M, K = map(int, input().split())
  AB = [list(map(int, input().split())) for i in range(M)]
  CD = [list(map(int, input().split())) for i in range(K)]
  AB.sort()
  CD.sort()
  friend = [N - 1] * N
  anti = []
  ans = []
  count = 1
  cnt = 1
  # print(AB)
  # print(CD)
  m = 0
  n = 0
  while m < M:
      friend[AB[m][0] - 1] -= 1
      friend[AB[m][1] - 1] -= 1
      m += 1
  while n < K:
      friend[CD[n][0] - 1] -= 1
      friend[CD[n][1] - 1] -= 1
      n += 1
  """for i in range(M-1):
      if AB[i][0]==AB[i+1][0]:
          count+=1
      else:
          friend[AB[i][0]]-=count
          count=1
  for j in range(K-1):
      if CD[j][0]==CD[j+1][0]:
          cnt+=1
      else:
          friend[CD[j][0]]-=cnt
          cnt=1
  while True:
      if len(friend)<N:
          friend.append([0,0])
          break
  while True:
      if len(anti)<K:
          anti.append([0,0])
          break"""
  
  print(*friend)
  """while m<len(friend):
      if friend[m]==
  print(ans)"""
  
problem_description: Statement
  
  An SNS has N users - User 1, User 2, \cdots, User N.
  
  Between these N users, there are some relationships - M _friendships_ and K
  _blockships_.
  
  For each i = 1, 2, \cdots, M, there is a bidirectional friendship between User
  A_i and User B_i.
  
  For each i = 1, 2, \cdots, K, there is a bidirectional blockship between User
  C_i and User D_i.
  
  We define User a to be a _friend candidate_ for User b when all of the
  following four conditions are satisfied:
  
    * a \neq b.
    * There is not a friendship between User a and User b.
    * There is not a blockship between User a and User b.
    * There exists a sequence c_0, c_1, c_2, \cdots, c_L consisting of integers between 1 and N (inclusive) such that c_0 = a, c_L = b, and there is a friendship between User c_i and c_{i+1} for each i = 0, 1, \cdots, L - 1.
  
  For each user i = 1, 2, ... N, how many friend candidates does it have?
samples: [{"input": "4 4 1\n    2 1\n    1 3\n    3 2\n    3 4\n    4 1", "output": "0 1 0 1\n    \n\nThere is a friendship between User 2 and 3, and between 3 and 4. Also, there\nis no friendship or blockship between User 2 and 4. Thus, User 4 is a friend\ncandidate for User 2.\n\nHowever, neither User 1 or 3 is a friend candidate for User 2, so User 2 has\none friend candidate.\n\n* * *"}, {"input": "5 10 0\n    1 2\n    1 3\n    1 4\n    1 5\n    3 2\n    2 4\n    2 5\n    4 3\n    5 3\n    4 5", "output": "0 0 0 0 0\n    \n\nEveryone is a friend of everyone else and has no friend candidate.\n\n* * *"}, {"input": "10 9 3\n    10 1\n    6 7\n    8 2\n    2 5\n    8 4\n    7 3\n    10 9\n    6 4\n    5 8\n    2 6\n    7 5\n    3 1", "output": "1 3 5 4 3 3 3 3 1 0"}]