output_description: Print the minimum number of elements that needs to be replaced.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      n
      v_1 v_2 ... v_n
attempt: n = int(input())
  
  seq = list(map(int, input().split()))
  oddlist = []
  evenlist = []
  
  for i in range(n):
      if (i + 1) % 2 != 0:
  
          oddlist.append(seq[i])
      else:
          evenlist.append(seq[i])
  print(seq)
  print(oddlist)
  print(evenlist)
  maxi = n / 2
  mini = n / 2
  if oddlist != evenlist:
      for j in set(evenlist):
          if evenlist.count(j) == int(n / 2):
              maxi = 0
          else:
              if evenlist.count(j) < maxi:
                  maxi = evenlist.count(j)
              else:
                  maxi = maxi
  
      for k in set(oddlist):
          if oddlist.count(k) == int(n / 2):
              mini = 0
          else:
  
              if oddlist.count(k) < mini:
                  mini = oddlist.count(k)
              else:
                  mini = mini
  
      print(maxi + mini)
  else:
      print(2)
  
problem_description: Statement
  
  A sequence a_1,a_2,... ,a_n is said to be /\/\/\/ when the following
  conditions are satisfied:
  
    * For each i = 1,2,..., n-2, a_i = a_{i+2}.
    * Exactly two different numbers appear in the sequence.
  
  You are given a sequence v_1,v_2,...,v_n whose length is even. We would like
  to make this sequence /\/\/\/ by replacing some of its elements. Find the
  minimum number of elements that needs to be replaced.
samples: [{"input": "4\n    3 1 3 2", "output": "1\n    \n\nThe sequence 3,1,3,2 is not /\\/\\/\\/, but we can make it /\\/\\/\\/ by replacing\none of its elements: for example, replace the fourth element to make it\n3,1,3,1.\n\n* * *"}, {"input": "6\n    105 119 105 119 105 119", "output": "0\n    \n\nThe sequence 105,119,105,119,105,119 is /\\/\\/\\/.\n\n* * *"}, {"input": "4\n    1 1 1 1", "output": "2\n    \n\nThe elements of the sequence 1,1,1,1 are all the same, so it is not /\\/\\/\\/."}]