output_description: Print the sum of the integers between 1 and N (inclusive), whose sum of digits
  written in base 10 is between A and B (inclusive).
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      N A B
attempt: import math
  import sys
  
  
  def getinputdata():
  
      # 配列初期化
      array_result = []
  
      data = input()
  
      array_result.append(data.split(" "))
  
      flg = 1
  
      try:
  
          while flg:
  
              data = input()
  
              array_temp = []
  
              if data != "":
  
                  array_result.append(data.split(" "))
  
                  flg = 1
  
              else:
  
                  flg = 0
      finally:
  
          return array_result
  
  
  arr_data = getinputdata()
  
  n = int(arr_data[0][0])
  a = int(arr_data[0][1])
  b = int(arr_data[0][2])
  
  # print(n,a,b)
  mysum = 0
  i = 1
  while i <= n:
  
      #    print(i)
      strtemp = str(i)
  
      sum_temp = 0
      for v in strtemp:
  
          sum_temp += int(v)
      else:
  
          if sum_temp >= a and sum_temp <= b:
              #
              #            print(i)
              #
              mysum += i
  
      i += 1
  
  
  print(mysum)
  
problem_description: Statement
  
  Find the sum of the integers between 1 and N (inclusive), whose sum of digits
  written in base 10 is between A and B (inclusive).
samples: [{"input": "20 2 5", "output": "84\n    \n\nAmong the integers not greater than 20, the ones whose sums of digits are\nbetween 2 and 5, are: 2,3,4,5,11,12,13,14 and 20. We should print the sum of\nthese, 84.\n\n* * *"}, {"input": "10 1 2", "output": "13\n    \n\n* * *"}, {"input": "100 4 16", "output": "4554"}]