output_description: Print the maximum possible amount of money that M-kun can have in the end, as
  an integer.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      N
      A_1 A_2 \cdots A_N
attempt: N = int(input())
  A_list = list(map(int, input().split()))
  
  money = (1000, 0)
  stock = (0, 0)
  
  for A in A_list:
      mm = money
      ms = (money[0] % A, money[0] // A)
      sm = (stock[0] + stock[1] * A, 0)
      ss = (stock[0] % A, stock[1] + stock[0] // A)
  
      if mm[0] > sm[0] or (mm[0] == sm[0] and mm[1] > sm[1]):
          money = mm
      else:
          money = sm
  
      if ms[1] > ss[1] or (ms[1] == ss[1] and ms[0] > ss[0]):
          stock = ms
      else:
          stock = ss
  
  print(money[0])
  
problem_description: Statement
  
  To become a millionaire, M-kun has decided to make money by trading in the
  next N days. Currently, he has 1000 yen and no stocks - only one kind of stock
  is issued in the country where he lives.
  
  He is famous across the country for his ability to foresee the future. He
  already knows that the price of one stock in the next N days will be as
  follows:
  
    * A_1 yen on the 1-st day, A_2 yen on the 2-nd day, ..., A_N yen on the N-th day.
  
  In the i-th day, M-kun can make the following trade **any number of times**
  (possibly zero), **within the amount of money and stocks that he has at the
  time**.
  
    * Buy stock: Pay A_i yen and receive one stock.
    * Sell stock: Sell one stock for A_i yen.
  
  What is the maximum possible amount of money that M-kun can have in the end by
  trading optimally?
samples: [{"input": "7\n    100 130 130 130 115 115 150", "output": "1685\n    \n\nIn this sample input, M-kun has seven days of trading. One way to have 1685\nyen in the end is as follows:\n\n  * Initially, he has 1000 yen and no stocks.\n  * Day 1: Buy 10 stocks for 1000 yen. Now he has 0 yen.\n  * Day 2: Sell 7 stocks for 910 yen. Now he has 910 yen.\n  * Day 3: Sell 3 stocks for 390 yen. Now he has 1300 yen.\n  * Day 4: Do nothing.\n  * Day 5: Buy 1 stock for 115 yen. Now he has 1185 yen.\n  * Day 6: Buy 10 stocks for 1150 yen. Now he has 35 yen.\n  * Day 7: Sell 11 stocks for 1650 yen. Now he has 1685 yen.\n\nThere is no way to have 1686 yen or more in the end, so the answer is 1685.\n\n* * *"}, {"input": "6\n    200 180 160 140 120 100", "output": "1000\n    \n\nIn this sample input, it is optimal to do nothing throughout the six days,\nafter which we will have 1000 yen.\n\n* * *"}, {"input": "2\n    157 193", "output": "1216\n    \n\nIn this sample input, it is optimal to buy 6 stocks in Day 1 and sell them in\nDay 2, after which we will have 1216 yen."}]