output_description: When the minimum required number of recorders is x, print the value of x.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      N C
      s_1 t_1 c_1
      :
      s_N t_N c_N
attempt: # -*- coding: utf-8 -*-
  
  import sys
  from itertools import accumulate
  
  
  def input():
      return sys.stdin.readline().strip()
  
  
  def list2d(a, b, c):
      return [[c] * b for i in range(a)]
  
  
  def list3d(a, b, c, d):
      return [[[d] * c for j in range(b)] for i in range(a)]
  
  
  def list4d(a, b, c, d, e):
      return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
  
  
  def ceil(x, y=1):
      return int(-(-x // y))
  
  
  def INT():
      return int(input())
  
  
  def MAP():
      return map(int, input().split())
  
  
  def LIST(N=None):
      return list(MAP()) if N is None else [INT() for i in range(N)]
  
  
  def Yes():
      print("Yes")
  
  
  def No():
      print("No")
  
  
  def YES():
      print("YES")
  
  
  def NO():
      print("NO")
  
  
  sys.setrecursionlimit(10**9)
  INF = 10**18
  MOD = 10**9 + 7
  
  N, M = MAP()
  C = [[] for i in range(M)]
  for i in range(N):
      l, r, c = MAP()
      c -= 1
      C[c].append((l, r))
  
  # 同チャンネルで連続する区間をまとめる
  LR = []
  for i in range(M):
      if C[i]:
          C[i].sort()
          LR.append(C[i][0])
          for j in range(1, len(C[i])):
              l1, r1 = C[i][j - 1]
              l2, r2 = C[i][j]
              if r1 == l2:
                  LR.pop()
                  LR.append((l1, r2))
                  # 3連続以上を考慮して更新
                  C[i][j] = (l1, r2)
              else:
                  LR.append((l2, r2))
  
  # いもす法
  MAX = 10**5 + 7
  imos = [0] * MAX
  for l, r in LR:
      imos[l - 1] += 1
      imos[r] -= 1
  imos = list(accumulate(imos))
  print(max(imos))
  
problem_description: Statement
  
  Joisino is planning to record N TV programs with recorders.
  
  The TV can receive C channels numbered 1 through C.
  
  The i-th program that she wants to record will be broadcast from time s_i to
  time t_i (including time s_i but not t_i) on Channel c_i.
  
  Here, there will never be more than one program that are broadcast on the same
  channel at the same time.
  
  When the recorder is recording a channel from time S to time T (including time
  S but not T), it cannot record other channels from time S-0.5 to time T
  (including time S-0.5 but not T).
  
  Find the minimum number of recorders required to record the channels so that
  all the N programs are completely recorded.
samples: [{"input": "3 2\n    1 7 2\n    7 8 1\n    8 12 1", "output": "2\n    \n\nTwo recorders can record all the programs, for example, as follows:\n\n  * With the first recorder, record Channel 2 from time 1 to time 7. The first program will be recorded. Note that this recorder will be unable to record other channels from time 0.5 to time 7.\n  * With the second recorder, record Channel 1 from time 7 to time 12. The second and third programs will be recorded. Note that this recorder will be unable to record other channels from time 6.5 to time 12.\n\n* * *"}, {"input": "3 4\n    1 3 2\n    3 4 4\n    1 4 3", "output": "3\n    \n\nThere may be a channel where there is no program to record.\n\n* * *"}, {"input": "9 4\n    56 60 4\n    33 37 2\n    89 90 3\n    32 43 1\n    67 68 3\n    49 51 3\n    31 32 3\n    70 71 1\n    11 12 3", "output": "2"}]