output_description: If there is an integer C between 1 and 3 that satisfies the condition, print
  `Yes`; otherwise, print `No`.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      A B
attempt: from collections import defaultdict, deque, Counter
  from heapq import heappush, heappop, heapify
  from itertools import (
      permutations,
      accumulate,
      combinations,
      combinations_with_replacement,
  )
  from math import sqrt, ceil, floor, factorial
  from bisect import bisect_left, bisect_right, insort_left, insort_right
  from copy import deepcopy
  from operator import itemgetter
  from functools import reduce
  from fractions import gcd
  import sys
  
  
  def input():
      return sys.stdin.readline().rstrip()
  
  
  def I():
      return int(input())
  
  
  def Is():
      return map(int, input().split())
  
  
  def LI():
      return list(map(int, input().split()))
  
  
  def TI():
      return tuple(map(int, input().split()))
  
  
  def IR(n):
      return [I() for _ in range(n)]
  
  
  def LIR(n):
      return [LI() for _ in range(n)]
  
  
  def TIR(n):
      return [TI() for _ in range(n)]
  
  
  def S():
      return input()
  
  
  def Ss():
      return input().split()
  
  
  def LS():
      return list(input())
  
  
  def SR(n):
      return [S() for _ in range(n)]
  
  
  def SsR(n):
      return [Ss() for _ in range(n)]
  
  
  def LSR(n):
      return [LS() for _ in range(n)]
  
  
  sys.setrecursionlimit(10**6)
  MOD = 10**9 + 7
  INF = 10**18
  # ----------------------------------------------------------- #
  
  a, b = Is()
  if a * b % 2 != 0:
      print("Yes")
  else:
      print("No")
  
problem_description: Statement
  
  You are given integers A and B, each between 1 and 3 (inclusive).
  
  Determine if there is an integer C between 1 and 3 (inclusive) such that A
  \times B \times C is an odd number.
samples: [{"input": "3 1", "output": "Yes\n    \n\nLet C = 3. Then, A \\times B \\times C = 3 \\times 1 \\times 3 = 9, which is an\nodd number.\n\n* * *"}, {"input": "1 2", "output": "No\n    \n\n* * *"}, {"input": "2 2", "output": "No"}]