output_description: Print the probability that a is odd. Your output will be considered correct
  when its absolute or relative error from the judge's output is at most
  10^{-6}.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      N
attempt: A, B = map(int, input().split())
  i = 2
  cnt = 0
  tmpA, tmpB = A, B
  while i**2 <= min(tmpA, tmpB) and i <= min(A, B):
      if A % i == 0 and B % i == 0:
          cnt += 1
          while A % i == 0 and B % i == 0:
              A //= i
              B //= i
      i += 1
  if cnt == 0 and min(A, B) != 1:
      cnt += 1
  if cnt == 0 and max(A, B) % min(A, B) == 0:
      cnt += 1
  print(cnt + 1)
  
problem_description: Statement
  
  Given is an integer N.
  
  Takahashi chooses an integer a from the positive integers not greater than N
  with equal probability.
  
  Find the probability that a is odd.
samples: [{"input": "4", "output": "0.5000000000\n    \n\nThere are four positive integers not greater than 4: 1, 2, 3, and 4. Among\nthem, we have two odd numbers: 1 and 3. Thus, the answer is \\frac{2}{4} = 0.5.\n\n* * *"}, {"input": "5", "output": "0.6000000000\n    \n\n* * *"}, {"input": "1", "output": "1.0000000000"}]