output_description: Print the minimum number of elements that needs to be replaced.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      n
      v_1 v_2 ... v_n
attempt: from collections import Counter
  
  n = int(input())
  V = [int(n) for n in input().split()]
  
  if len(set(V)) == 1:
      ans = len(V) // 2
  else:
      vp_ = [v for i, v in enumerate(V) if i%2 == 0] 
      vn_ = [v for i, v in enumerate(V) if i%2 != 0] 
  
      vp = Counter(vp_).most_common()
      vn = Counter(vn_).most_common()
  
      if vp[0][0] != vn[0][0]:
          gp = vp[0][1]
          gn = vn[0][1]
      else:
          if vp[0][1] > vn[0][1]:
              gp = vp[0][1]
              gn = vn[1][1]
          elif vp[0][1] < vn[0][1]:
              gp = vp[1][1]
              gn = vn[0][1]
          else vp[0][1] == vn[0][1]:
              if vp[1][1] >= vn[1][1]:
                  gp = vp[1][1]
                  gn = vn[0][1]
              else:
                  gp = vp[0][1]
                  gn = vn[1][1]
   
      ans = n - gp - gn
  print(ans)
problem_description: Statement
  
  A sequence a_1,a_2,... ,a_n is said to be /\/\/\/ when the following
  conditions are satisfied:
  
    * For each i = 1,2,..., n-2, a_i = a_{i+2}.
    * Exactly two different numbers appear in the sequence.
  
  You are given a sequence v_1,v_2,...,v_n whose length is even. We would like
  to make this sequence /\/\/\/ by replacing some of its elements. Find the
  minimum number of elements that needs to be replaced.
samples: [{"input": "4\n    3 1 3 2", "output": "1\n    \n\nThe sequence 3,1,3,2 is not /\\/\\/\\/, but we can make it /\\/\\/\\/ by replacing\none of its elements: for example, replace the fourth element to make it\n3,1,3,1.\n\n* * *"}, {"input": "6\n    105 119 105 119 105 119", "output": "0\n    \n\nThe sequence 105,119,105,119,105,119 is /\\/\\/\\/.\n\n* * *"}, {"input": "4\n    1 1 1 1", "output": "2\n    \n\nThe elements of the sequence 1,1,1,1 are all the same, so it is not /\\/\\/\\/."}]