output_description: If S is a KEYENCE string, print `YES`; otherwise, print `NO`.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      S
attempt: s = str(input())
  st = list(s)
  l = len(st)
  if (
      st[0] == "k"
      and st[1] == "e"
      and st[2] == "y"
      and st[3] == "e"
      and st[4] == "n"
      and st[5] == "c"
      and st[6] == "e"
  ):
      print("YES")
  elif (
      st[l - 7] == "k"
      and st[l - 6] == "e"
      and st[l - 5] == "y"
      and st[l - 4] == "e"
      and st[l - 3] == "n"
      and st[l - 2] == "c"
      and st[l - 1] == "e"
  ):
      print("YES")
  elif (
      st[0] == "k"
      and st[l - 6] == "e"
      and st[l - 5] == "y"
      and st[l - 4] == "e"
      and st[l - 3] == "n"
      and st[l - 2] == "c"
      and st[l - 1] == "e"
  ):
      print("YES")
  elif (
      st[0] == "k"
      and st[1] == "e"
      and st[l - 5] == "y"
      and st[l - 4] == "e"
      and st[l - 3] == "n"
      and st[l - 2] == "c"
      and st[l - 1] == "e"
  ):
      print("YES")
  elif (
      st[0] == "k"
      and st[1] == "e"
      and st[2] == "y"
      and st[l - 4] == "e"
      and st[l - 3] == "n"
      and st[l - 2] == "c"
      and st[l - 1] == "e"
  ):
      print("YES")
  elif (
      st[0] == "k"
      and st[1] == "e"
      and st[2] == "y"
      and st[3] == "e"
      and st[l - 3] == "n"
      and st[l - 2] == "c"
      and st[l - 1] == "e"
  ):
      print("YES")
  elif (
      st[0] == "k"
      and st[1] == "e"
      and st[2] == "y"
      and st[3] == "e"
      and st[4] == "n"
      and st[l - 2] == "c"
      and st[l - 1] == "e"
  ):
      print("YES")
  elif (
      st[0] == "k"
      and st[1] == "e"
      and st[2] == "y"
      and st[3] == "e"
      and st[4] == "n"
      and st[5] == "c"
      and st[l - 1] == "e"
  ):
      print("YES")
  else:
      print("NO")
  
problem_description: Statement
  
  A string is called a KEYENCE string when it can be changed to `keyence` by
  removing its contiguous substring (possibly empty) only once.
  
  Given a string S consisting of lowercase English letters, determine if S is a
  KEYENCE string.
samples: [{"input": "keyofscience", "output": "YES\n    \n\n`keyence` is an abbreviation of `key of science`.\n\n* * *"}, {"input": "mpyszsbznf", "output": "NO\n    \n\n* * *"}, {"input": "ashlfyha", "output": "NO\n    \n\n* * *"}, {"input": "keyence", "output": "YES"}]