output_description: If \sqrt{a} + \sqrt{b} < \sqrt{c}, print `Yes`; otherwise, print `No`.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      a \ b \ c
attempt: # coding: utf-8
  # Your code here!
  # coding: utf-8
  import sys
  
  sys.setrecursionlimit(10000000)
  
  
  # const
  # my functions here!
  def pin(type=int):
      return map(type, input().rstrip().split())
  
  
  def resolve():
      a, b, c = pin()
      from math import sqrt
  
      cond = sqrt(a) + sqrt(b) < sqrt(c)
      print(["No", "Yes"][cond])
  
  
  """
  #printデバッグ消した？
  #前の問題の結果見てないのに次の問題に行くの？
  """
  """
  お前カッコ閉じるの忘れてるだろ
  """
  import sys
  from io import StringIO
  import unittest
  
  
  class TestClass(unittest.TestCase):
      def assertIO(self, input, output):
          stdout, stdin = sys.stdout, sys.stdin
          sys.stdout, sys.stdin = StringIO(), StringIO(input)
          resolve()
          sys.stdout.seek(0)
          out = sys.stdout.read()[:-1]
          sys.stdout, sys.stdin = stdout, stdin
          self.assertEqual(out, output)
  
      def test_入力例_1(self):
          input = """2 3 9"""
          output = """No"""
          self.assertIO(input, output)
  
      def test_入力例_2(self):
          input = """2 3 10"""
          output = """Yes"""
          self.assertIO(input, output)
  
  
  if __name__ == "__main__":
      resolve()
  
problem_description: Statement
  
  Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?
samples: [{"input": "2 3 9", "output": "No\n    \n\n\\sqrt{2} + \\sqrt{3} < \\sqrt{9} does not hold.\n\n* * *"}, {"input": "2 3 10", "output": "Yes\n    \n\n\\sqrt{2} + \\sqrt{3} < \\sqrt{10} holds."}]