output_description: Print the K-th character from the left in Mr. Infinity's string after 5 \times
  10^{15} days.
  
  * * *
input_description: Input is given from Standard Input in the following format:
  
      
      
      S
      K
attempt: s = input()
  k = int(input())
  onesum = 0
  while s[0] == "1" and len(s) > 0
      s = s[1:]
      onesum += 1
  if k <= onesum:
      print(1)
  else:
      print(s[0])
  
problem_description: Statement
  
  Mr. Infinity has a string S consisting of digits from `1` to `9`. Each time
  the date changes, this string changes as follows:
  
    * Each occurrence of `2` in S is replaced with `22`. Similarly, each `3` becomes `333`, `4` becomes `4444`, `5` becomes `55555`, `6` becomes `666666`, `7` becomes `7777777`, `8` becomes `88888888` and `9` becomes `999999999`. `1` remains as `1`.
  
  For example, if S is `1324`, it becomes `1333224444` the next day, and it
  becomes `133333333322224444444444444444` the day after next. You are
  interested in what the string looks like after 5 \times 10^{15} days. What is
  the K-th character from the left in the string after 5 \times 10^{15} days?
samples: [{"input": "1214\n    4", "output": "2\n    \n\nThe string S changes as follows:\n\n  * Now: `1214`\n  * After one day: `12214444`\n  * After two days: `1222214444444444444444`\n  * After three days: `12222222214444444444444444444444444444444444444444444444444444444444444444`\n\nThe first five characters in the string after 5 \\times 10^{15} days is\n`12222`. As K=4, we should print the fourth character, `2`.\n\n* * *"}, {"input": "3\n    157", "output": "3\n    \n\nThe initial string is `3`. The string after 5 \\times 10^{15} days consists\nonly of `3`.\n\n* * *"}, {"input": "299792458\n    9460730472580800", "output": "2"}]