SNR = 10<i>log(Ps&#x2F;Pw), solving<p>Ps&#x2F;Pw =  10^(SNR&#x2F;10) = 10^(20&#x2F;10) == 100<p>A signal 20db above the noise, you could put your eye out with it.<p>db is confusing, when you&#x27;re talking voltage it&#x27;s 20</i>log(Vs&#x2F;Vw) And in absolute terms engineers talk about the power over 1mW.<p>Myself I get miffed a bit because people have been conditioned to think in terms of  trying to pull facts out of crappy data sets using poorly thought out statistics. However in a lot of engineering and physics fields the data is often really good. Often good enough that you can work off a single measurement.