Statistics are funny. Both are right I&#x27;d say<p>If the chance of biasing it T&gt;H is 50% and biasing the other way is also 50% then <i>the average</i> is 1&#x2F;2 (in a Schroedinger&#x27;s cat kind of way)<p>At the same time the frequentist is right. p(heads) <i>for the specific coin you&#x27;re given</i> is not 1&#x2F;2