Wait, the median P&#x2F;E is three times higher than the <i>average</i>?  That does not sound right.  Because the P&#x2F;E cannot go below zero, the ability of a small number of stocks to throw the average off is limited..  In fact I can&#x27;t think of <i>any</i> way for the average to be more than twice the median, even if half the stocks (minus one) had a P&#x2F;E of zero.  How would that work, mathematically?