I&#x27;m guessing very small train, probably 30ton weight. Max speed 33m&#x2F;s. So accelerating 30,000 kg to 33m&#x2F;s... what<p>E = 1&#x2F;2 * 30000 * 33^2 = 16335000J or 4.5kwhr at $0.20 kwhr that&#x27;s about $0.90 in electricity costs.