I &quot;roughly&quot; got it using the DOI txt I linked above.<p>I tried again with the pre-mapped text you linked to, and got `e o a p s p` which is an anagram for `appose`... perhaps that is the word? &quot;Appose&quot; means &quot;to place (something) in proximity to or juxtaposition with something else.&quot; Maybe I&#x27;m grasping at straws here...<p>Offset of +1 yields `b s a i t h` which is an anagram for habits.<p>Offset of -1 yields `a t a l b t` which is an anagram for Alt-Tab (which is roughly what I&#x27;m doing right now to get out of this :p)<p>I also tried all offsets within 0-7 for each character, to see if &quot;CIPHER&quot; could fit in that range. CI_H_R is possible but there is no P or E within +&#x2F;- 7 offset of 201 or 337.<p>Here&#x27;s the python:<p><pre><code>    txt=&quot;&quot;&quot;&lt;&lt;Pasted from http:&#x2F;&#x2F;cipherfoundation.org&#x2F;older-ciphers&#x2F;beale-papers&#x2F;beale-papers-transcription&#x2F;&gt;&gt;&quot;&quot;&quot;

    import re

    codes = txt.split(&#x27; &#x27;)
    codes = filter(None, codes)

    code2word = {}

    words = []
    for code in codes[0:-1]:
        try:
            index = re.search(re.compile(ur&#x27;\((\d+)\)&#x27;), code).group(1)
        except:
            index = index + 1

        word = code.replace(&#x27;(%d)&#x27; % int(index), &#x27;&#x27;)

        code2word[int(index)] = word

        print index, word

    for code in [89, 263, 201, 500, 337, 480]:
        word = code2word[code]
        print word[0],
</code></pre>
Good luck