FizzBuzz from 1 to N (supplied as command-line argument) and exiting gracefully without using loops, conditionals, or segfaults - in C:<p><pre><code>    #include &lt;stdio.h&gt;
    #include &lt;stdlib.h&gt;
    
    int i(const int i) { printf(&quot;%d\n&quot;, i); return i; }
    int f(const int i) { printf(&quot;Fizz\n&quot;); return i; }
    int b(const int i) { printf(&quot;Buzz\n&quot;); return i; }
    int fb(const int i) { printf(&quot;FizzBuzz\n&quot;); return i; }
    int (* PC[15])(int i) = { i,i,f,i,b,f,i,i,f,b,i,f,i,i,fb }; &#x2F;&#x2F; Printer Cycle
    
    int go(const int arg) {
        return PC[(arg - 1) % 15](arg) + 1;
    }
    
    int stop(const int arg) {
        PC[(arg - 1) % 15](arg);
        exit(0);
    }
    
    int (* LC[2]) (int index) = { go, stop }; &#x2F;&#x2F; Logic Cycle
    
    void recurse(const int i, const int kill_num) {
        recurse(LC[!(i % kill_num)](i), kill_num);
    }
    
    int main(const int argc, const char *argv[]) {
        recurse(1, atoi(argv[1]));
    }</code></pre>