Oops, sorry, I didn&#x27;t mean to say you used a RBF kernel.  I edited my comment above.  I meant to say your embedding resembles the polynomial kernel (not RBF, which was just meant as a generalisation of such neat tricks :)).<p>What I meant to say was that you didn&#x27;t need to compute the embedding explicitly.  Since you embed into a space that has a nice structure, you can compute the dot product of the embedded vectors without having to compute the embedding explicitly.