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1) That looks right. 2) Step 1: Moles=Mass/Mr, so it's 144/72= 2mol. Step 2: Stoichiometry means the ratio of oxygen to pentane is 1:8 so moles of oxygen is moles of pentane times 8. 2*8=16mol of oxygen. Step 3: 16= 9.6*10^24. 3) The ratio of oxygen to carbon in CO2 is 1:2. so it's 192/3 = 64.
a. the stoichiometric ratio of moles H2 to moles O2. b. the actual moles H2 to moles O2 when 1.50 mol H2 is mixed with 1.00 mol O2. c. the limiting reactant (H2 or O2) for the mixture in part (b) d. the theoretical yield, in moles, of H2O for the mixture in part (b) Solution. a. The stoichiometric ratio is given by using the coefficients of the balanced equation.