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1) That looks right. 2) Step 1: Moles=Mass/Mr, so it's 144/72= 2mol. Step 2: Stoichiometry means the ratio of oxygen to pentane is 1:8 so moles of oxygen is moles of pentane times 8. 2*8=16mol of oxygen. Step 3: 16= 9.6*10^24. 3) The ratio of oxygen to carbon in CO2 is 1:2. so it's 192/3 = 64.
4) Use a ratio and proportion: 2 moles hydrogen is to 1 mole methane as x liters of hydrogen is to 20.0 L of methane. x = 40.0 L of hydrogen. Problem #3: 2.35 L of oxygen gas reacts with 3.72 L of hydrogen gas, forming water.) Use PV = nRT to determine moles of methane: (1.00 atm) (50.0 L) = (n) (0.08206 L atm molÂ¯ 1 KÂ¯ 1) (298 K). n = 2.044665 mol. Note: in this problem, I am taking room temperature to be 25.0 Â°C since RTP means room temperature and pressure.