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1) That looks right. 2) Step 1: Moles=Mass/Mr, so it's 144/72= 2mol. Step 2: Stoichiometry means the ratio of oxygen to pentane is 1:8 so moles of oxygen is moles of pentane times 8. 2*8=16mol of oxygen. Step 3: 16= 9.6*10^24. 3) The ratio of oxygen to carbon in CO2 is 1:2. so it's 192/3 = 64.
Exercises for Rate of Combustion. 1. Write a balanced equation for the combustion of pentane. Pentane is C5 H12. Identify the fuel and the oxide, and include heat on the appropriate side of the equation. 2. Draw a reaction profile in which H reactants = 100 kJ, the activation energy is 50 kJ, and DH = -25 kJ.