Place your online order of $25 or more*. Ship to an address within the United States (including U.S. territories) Your shipment should arrive within 2-6 business days from your order. Your total purchase must reach the designated amount after any discounts are applied and prior to the costs of shipping and tax.
So using the standard equation: E = hf, we can find the relationship between light intensity and wavelength as follows: c = lambda x f Therefore, f = c/lambda substitute this in the standard equation to get: E = (h c)/lambda Where h = planks constant, and c = speed of light.
up vote 5 down vote. The light intensity $I$ is the power $P$, that irradiates an area $A$, $I=P/A$, therefore the units $\mathrm{W}\mathrm{m}^{-2}$. This means, that if you have two beams with equal intensities, the area is the same and the power has to be the same as well.You are probably confused by the relation between frequency and energy of a photon, $E_\nu = h\nu$. But this says just, what the energy of a single photon is.s @daaxix says, you have used intensity to mean irradiance. Irradiance is the amount of power the wave has delivered per unit area and hence, $W/m^2$. Both are quite similar in their definitions. Or in other words, the amplitude of the wave determines the irradiance.